Modeling Higher-Order Differential Equations - Differential Equations
Card 1 of 4
For the initial value problem
Which if the following intervals containing 
do NOT guarantees the existence of a unique solution?
For the initial value problem
Which if the following intervals containing
Tap to reveal answer
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
. The choice that is not a subset of these is 
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
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For the initial value problem
Which if the following intervals containing do NOT guarantees the existence of a unique solution?
For the initial value problem
Which if the following intervals containing
Tap to reveal answer
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
. The choice that is not a subset of these is
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
← Didn't Know|Knew It →
For the initial value problem
Which if the following intervals containing do NOT guarantees the existence of a unique solution?
For the initial value problem
Which if the following intervals containing
Tap to reveal answer
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
. The choice that is not a subset of these is
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
← Didn't Know|Knew It →
For the initial value problem
Which if the following intervals containing do NOT guarantees the existence of a unique solution?
For the initial value problem
Which if the following intervals containing
Tap to reveal answer
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
. The choice that is not a subset of these is
Putting the equation in standard form we get that
We need to find where these coefficients are simultaneously continuous. This is where
← Didn't Know|Knew It →