Relate Enthalpy to Reactions

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Chemistry › Relate Enthalpy to Reactions

Questions 1 - 10
1

For a reaction at constant pressure, $\Delta H$ is defined as $\Delta H = H(\text{products}) - H(\text{reactants})$. If $\Delta H = -30\ \text{kJ}$, which statement must be true?

The products have 30 kJ more enthalpy than the reactants.

The products have 30 kJ less enthalpy than the reactants, and heat is released.

The reaction is endothermic because the negative sign indicates heat absorbed.

The reaction cannot occur unless 30 kJ of activation energy is supplied.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! Given ΔH = -30 kJ, which equals H(products) - H(reactants), the negative value means products have less enthalpy (by 30 kJ), so heat is released, making it exothermic. Choice B correctly interprets ΔH by recognizing that negative values mean products have lower enthalpy and heat is released. Choice A fails by claiming products have more enthalpy, which would be for positive ΔH. The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

2

A neutralization reaction is measured to have $\Delta H = -57\ \text{kJ}$ for the reaction as written. What should happen to the temperature of the surroundings during the reaction (assuming heat is not lost to the outside environment)?

The temperature should not change because $\Delta H$ relates only to entropy.

The surroundings warm up only if $\Delta H$ is positive.

The surroundings should warm up because the system releases heat.

The surroundings should cool down because the system absorbs heat.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For this neutralization reaction with ΔH = -57 kJ, the negative sign means it's exothermic, so the system releases heat, warming the surroundings. Choice B correctly interprets ΔH by recognizing that negative values indicate exothermic (heat released), leading to warmer surroundings. Choice A fails by claiming surroundings cool down, which would be for positive ΔH (endothermic). The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

3

An instant cold pack works because a salt dissolves in water and the process has $\Delta H = +25\ \mathrm{kJ}$.

What should happen to the temperature of the surroundings (your hand holding the pack) when it is activated?

The surroundings should not change temperature because $\Delta H$ only affects reaction rate.

The surroundings should cool down because the process absorbs heat from them.

The surroundings should warm up because positive $\Delta H$ means exothermic.

The surroundings should warm up because the process releases heat.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For the cold pack with ΔH = +25 kJ, the positive sign means the dissolution is endothermic, absorbing 25 kJ from the surroundings, which should cause the surroundings (like your hand) to cool down as heat is drawn in. Choice B correctly interprets ΔH by predicting the surroundings cool down due to heat absorption in an endothermic process. Choice A fails by reversing the effect, saying surroundings warm up, but positive ΔH means absorption—associate positive with 'pulling in' heat to correct this! The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

4

Melting ice is represented by:

$\mathrm{H_2O(s) \rightarrow H_2O(l)}$

$\Delta H = +6.0\ \mathrm{kJ/mol}$

Which statement is correct?

Melting requires no energy because it is a physical change, not a chemical reaction.

Melting is exothermic because the temperature increases during melting.

Melting is endothermic; 6.0 kJ of heat is absorbed per mole of ice melted.

Melting is exothermic; 6.0 kJ of heat is released per mole of ice melted.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For melting ice with ΔH = +6.0 kJ/mol, the positive sign shows it's endothermic, absorbing 6.0 kJ per mole from the surroundings to break intermolecular forces, which is why ice feels cold as it melts. Choice A correctly interprets ΔH by stating melting is endothermic and absorbs 6.0 kJ per mole. Choice B fails by calling it exothermic and releasing heat, but positive ΔH indicates absorption—remember, phase changes like melting require energy input! The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

5

An instant cold pack works because a salt dissolves in water with $\Delta H = +25\ \mathrm{kJ}$ (per mole of salt dissolved).

What should happen to the temperature of the surroundings (your hand) when the pack is activated?

The surroundings warm up because a positive $\Delta H$ means heat is given off.

The surroundings warm up because the process releases heat.

The surroundings do not change temperature because $\Delta H$ refers only to the system, not heat flow.

The surroundings cool down because the process absorbs heat.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For the cold pack with ΔH = +25 kJ per mole, the positive sign means it's endothermic, absorbing heat from the surroundings (your hand), causing them to cool down as the pack activates. Choice B correctly interprets ΔH by recognizing that positive values indicate heat absorption, leading to cooling of the surroundings. Choice A fails by confusing the sign, suggesting warming for a positive ΔH, but positive means absorbed, so cooling occurs—sign determines direction! The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

6

Burning methane is represented by the reaction:

$\mathrm{CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)}$

$\Delta H = -890\ \mathrm{kJ/mol}$

Which statement best interprets the sign and meaning of $\Delta H$ for this reaction (per mole of methane burned)?

The reaction has an activation energy of 890 kJ, so it will proceed very slowly.

The reaction is exothermic, but only 890 kJ is absorbed by the system.

The reaction is endothermic and absorbs 890 kJ from the surroundings.

The reaction is exothermic and releases 890 kJ of heat to the surroundings.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For this methane combustion reaction with ΔH = -890 kJ/mol, the negative sign indicates it's exothermic, meaning the reaction releases 890 kJ of heat per mole of methane to the surroundings, which aligns with combustion processes that produce heat and light. Choice B correctly interprets ΔH by recognizing that the negative value indicates an exothermic reaction that releases 890 kJ of heat to the surroundings. Choice A fails by reversing the sign interpretation, claiming it's endothermic and absorbs heat, but remember, negative ΔH always means exothermic—keep practicing to avoid this common mix-up! The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

7

A student compares two processes:

Process A: $\Delta H = +18\ \text{kJ}$

Process B: $\Delta H = +75\ \text{kJ}$

Which statement is correct about the amount of heat absorbed (as written)?

Both absorb the same heat because both $\Delta H$ values are positive.

Process B absorbs more heat because it has the larger positive $\Delta H$.

Process A releases more heat because its $\Delta H$ is smaller.

Process A absorbs more heat because 18 is greater than 75 in absolute value.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! Comparing Process A with ΔH = +18 kJ and Process B with ΔH = +75 kJ, both are positive (endothermic), but Process B has a larger magnitude (75 kJ > 18 kJ), so it absorbs more heat. Choice B correctly interprets ΔH by recognizing that for endothermic processes, the larger positive value means more heat absorbed. Choice A fails by incorrectly comparing absolute values and claiming 18 > 75, but for absorption, larger positive is more. The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

8

Melting ice can be written as:

$\text{H}_2\text{O}(s) \rightarrow \text{H}_2\text{O}(l) \quad \Delta H = +6.0\ \text{kJ/mol}$

Which statement best describes what this means?

Melting is endothermic; 6.0 kJ is absorbed for each mole of ice that melts.

Because $\Delta H$ is positive, the products have lower enthalpy than the reactants.

Melting is exothermic; 6.0 kJ/mol is released to the surroundings.

Melting happens only if the activation energy is 6.0 kJ/mol.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For melting ice with ΔH = +6.0 kJ/mol, the positive sign indicates it's endothermic, absorbing 6.0 kJ per mole from the surroundings. Choice B correctly interprets ΔH by recognizing that positive values indicate endothermic (heat absorbed) and the magnitude specifies the amount per mole. Choice A fails by claiming it's exothermic and releases heat, reversing the sign interpretation. The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

9

The decomposition of water is represented as:

$2\text{H}_2\text{O}(l) \rightarrow 2\text{H}_2(g) + \text{O}_2(g) \quad \Delta H = +572\ \text{kJ}$

Which observation is most consistent with this $\Delta H$ value when the reaction is forced to occur?

Energy must be supplied; the system absorbs 572 kJ of heat (endothermic).

The reaction rate increases because $\Delta H$ is positive.

The surroundings warm up because 572 kJ of heat is released.

The reaction releases 572 kJ because the products have lower enthalpy than the reactants.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For the decomposition of water with ΔH = +572 kJ, the positive sign means it's endothermic, so the system absorbs 572 kJ of heat, which must be supplied. Choice B correctly interprets ΔH by recognizing that positive values indicate endothermic (heat absorbed) and the magnitude shows a large amount of energy needed. Choice A fails by claiming heat is released and surroundings warm up, which is the opposite for positive ΔH. The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

10

A reaction occurs at constant pressure with $\Delta H = +65\ \text{kJ}$. Which statement correctly describes the heat flow for the reaction as written?

Heat is absorbed by the system from the surroundings (endothermic).

The reaction must be fast because $\Delta H$ is positive.

Heat is released by the system to the surroundings (exothermic).

No heat is involved because $\Delta H$ is not zero.

Explanation

This question tests your understanding of enthalpy change (ΔH)—a measure of heat absorbed or released during a chemical reaction—and how to interpret its sign and magnitude to determine whether reactions are exothermic or endothermic. Enthalpy change (ΔH) for a reaction tells you the direction and amount of heat transfer: ΔH is calculated as H(products) minus H(reactants), so NEGATIVE ΔH means products have less enthalpy than reactants (energy was released to surroundings during reaction—exothermic), while POSITIVE ΔH means products have more enthalpy than reactants (energy was absorbed from surroundings—endothermic). The magnitude (absolute value) indicates HOW MUCH heat is involved: ΔH = -890 kJ means 890 kJ released (highly exothermic, very hot), while ΔH = -10 kJ means only 10 kJ released (mildly exothermic, slightly warm). For endothermic, ΔH = +50 kJ means 50 kJ absorbed (moderately endothermic), while ΔH = +500 kJ means 500 kJ absorbed (highly endothermic, very cold). Sign tells direction (released vs absorbed), magnitude tells amount! For this reaction with ΔH = +65 kJ, the positive sign indicates it's endothermic, meaning the system absorbs heat from the surroundings. Choice A correctly interprets ΔH by recognizing that positive values indicate endothermic (heat absorbed) and negative values indicate exothermic (heat released), with magnitude showing energy amount. Choice B fails by reversing the sign, claiming heat is released, which is incorrect for positive ΔH. The ΔH interpretation checklist: (1) CHECK THE SIGN: Is ΔH negative (has minus sign or is less than zero)? → EXOTHERMIC (heat released, surroundings warm up). Is ΔH positive (has plus sign or is greater than zero)? → ENDOTHERMIC (heat absorbed, surroundings cool down). The sign is THE indicator—negative out, positive in! (2) CHECK THE MAGNITUDE (size of number, ignoring sign): Compare absolute values to see which reaction involves more heat. ΔH = -200 kJ involves more heat than ΔH = -50 kJ (200 kJ vs 50 kJ). ΔH = -100 kJ and ΔH = +100 kJ involve the SAME AMOUNT of heat (both 100 kJ), just different directions. (3) PREDICT OBSERVATIONS: Negative ΔH (exo) → expect reaction mixture to warm up, may be hot to touch. Positive ΔH (endo) → expect reaction mixture to cool down, may be cold to touch. Larger |ΔH| → more dramatic temperature change. Sign-magnitude integration: when comparing reactions, you might ask "which is MORE exothermic?" This means comparing the magnitude among the negative ΔH values—more negative = more exothermic. ΔH = -500 kJ is MORE exothermic than ΔH = -100 kJ (releases more heat). Don't confuse "more negative" with "larger number"—on a number line, -500 is actually SMALLER than -100, but its MAGNITUDE is larger (|-500| = 500 > |-100| = 100), meaning it releases more energy. For endothermic, more positive = more endothermic: ΔH = +200 kJ is more endothermic than ΔH = +50 kJ (absorbs more heat). The thermochemical convention: chemists write ΔH with the reaction: CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ means "this reaction as written releases 890 kJ." The negative sign and the energy value are both crucial: negative tells you it's exothermic (releases), 890 tells you how much (large amount). Always read both the sign AND the number!

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