Predict Rate Changes

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Chemistry › Predict Rate Changes

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1

In a lab, magnesium ribbon reacts with hydrochloric acid to produce hydrogen gas (bubbling):

$\text{Mg(s)} + 2\text{HCl(aq)} \rightarrow \text{MgCl}_2\text{(aq)} + \text{H}_2\text{(g)}$

A student runs the reaction at 22°C using 1.0 M HCl and the same length of magnesium ribbon each time. They propose warming the acid to 35°C while keeping everything else the same.

How will the reaction rate change, and why (use collision theory)?

The rate increases because higher temperature makes particles move faster, leading to more frequent and more energetic collisions.

The rate decreases because warming the solution reduces the concentration of HCl particles in the same volume.

The rate stays the same because temperature does not affect reaction rate unless a catalyst is added.

The rate decreases because higher temperature lowers the number of collisions between particles.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting temperature effects: increasing temperature speeds up reactions (sometimes doubling or tripling the rate for a 10°C increase!) because hot particles move faster, leading to more frequent collisions AND more energetic collisions (both frequency and effectiveness increase). Decreasing temperature slows reactions by the same logic—cold particles move sluggishly, collide less often and less energetically. This is why we refrigerate food (slow down decay reactions) and why heating makes reactions go faster (cooking, chemical processes). The temperature effect is reliable and powerful! In this case, warming the HCl from 22°C to 35°C will make the HCl and Mg particles move faster, increasing both the number of collisions per second and the fraction that have enough energy to react, so the rate should increase. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because higher temperature actually increases collisions, not lowers them—remember, heat speeds things up! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking "which change would most increase rate," temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

2

A student adds equal masses of calcium carbonate (CaCO$_3$) to identical cups containing 100 mL of 1.0 M vinegar (acetic acid) at 22°C. In Cup A, the CaCO$_3$ is in large chips. In Cup B, the CaCO$_3$ is crushed into a fine powder. All other conditions are the same. Which prediction about reaction rate is best supported by collision theory?

Cup A reacts faster because larger chips have more total surface area than powder.

Both cups react at the same rate because surface area affects only the final amount of CO$_2$ produced.

Cup B reacts faster because crushing increases surface area, allowing more acid–solid collisions per second.

Cup B reacts slower because smaller particles collide less often with the acid.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting surface area effects: increasing surface area (breaking solid into smaller pieces or powder) dramatically speeds reactions because it exposes more reactant particles at the surface where collisions can occur—the total amount of substance stays the same, but more particles are accessible for collisions. In this setup, crushing CaCO₃ into powder in Cup B exposes far more surface for acid molecules to collide with, compared to the large chips in Cup A where most material is hidden inside. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because larger chips actually have less total surface area than powder for the same mass—think of how a whole apple has less exposed area than sliced pieces! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking 'which change would most increase rate,' temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

3

Hydrogen peroxide breaks down faster in the presence of a catalyst such as manganese(IV) oxide:

$2\text{H}_2\text{O}_2\text{(aq)} \rightarrow 2\text{H}_2\text{O(l)} + \text{O}_2\text{(g)}$

A student has 3% $\text{H}_2\text{O}_2$ at 25°C. They add a small amount of $\text{MnO}_2$ powder while keeping temperature and concentration the same.

What happens to the reaction rate, and why?

The rate stays the same because catalysts only change the amount of product formed, not the speed.

The rate decreases because a catalyst makes collisions less energetic.

The rate increases because adding $\text{MnO}_2$ increases the concentration of $\text{H}_2\text{O}_2$.

The rate increases because the catalyst provides an alternative pathway so a larger fraction of collisions leads to reaction.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Adding a catalyst speeds up reactions because it lowers the activation energy, making a larger fraction of collisions effective (successful) without changing frequency—more collisions have enough energy to react. Introducing MnO2 provides an alternative reaction pathway with lower energy barrier, so more H2O2 collisions result in decomposition, increasing the rate. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because catalysts actually make collisions more effective, not less energetic—they help reactions happen with less energy needed! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking 'which change would most increase rate,' temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

4

A strip of iron reacts slowly with oxygen in air to form rust (iron oxide). A student compares two samples of iron of the same mass:

  • Sample 1: one solid iron nail
  • Sample 2: iron filings (many small pieces)

Both are kept at the same temperature and exposed to the same air.

Which sample rusts faster, and why (rate concept)?

The filings rust slower because oxygen cannot reach the surface of small particles as well.

The filings rust faster because they have much greater surface area exposed to oxygen, increasing collision opportunities at the surface.

They rust at the same rate because surface area does not affect solid–gas reactions.

The nail rusts faster because larger pieces have more total collisions with oxygen.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting surface area effects: increasing surface area (breaking solid into smaller pieces or powder) dramatically speeds reactions because it exposes more reactant particles at the surface where collisions can occur—the total amount of substance stays the same, but more particles are accessible for collisions. The iron filings have vastly more surface area than the nail, exposing more iron atoms to oxygen collisions, so rusting happens faster. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because larger pieces actually have less surface area per mass, leading to fewer collisions, not more—think of why dust explodes but a log doesn't! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking 'which change would most increase rate,' temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

5

A student is trying to slow down the reaction between iron and oxygen that produces rust. Two identical pieces of damp iron wool are placed in separate containers with air. Container 1 is kept at 25°C. Container 2 is kept in a refrigerator at 4°C. The amount of oxygen and the surface area of the iron wool are the same. What happens to the rusting rate in Container 2 compared with Container 1?

It increases because cooling increases oxygen concentration in the container.

It decreases because lower temperature reduces particle speed and lowers the number of effective collisions.

It stays the same because temperature does not affect reaction rates.

It increases because colder temperatures make oxygen molecules stick to iron more strongly.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Decreasing temperature slows reactions by the same logic—cold particles move sluggishly, collide less often and less energetically. Cooling Container 2 to 4°C reduces the speed and energy of oxygen and water molecules, leading to fewer and less effective collisions with iron compared to 25°C. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because colder temperatures actually weaken interactions by slowing particles—it's why fridges prevent spoilage by slowing reactions! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking 'which change would most increase rate,' temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

6

Hydrogen peroxide breaks down into water and oxygen gas:

$2\text{H}_2\text{O}_2\text{(aq)} \rightarrow 2\text{H}_2\text{O(l)} + \text{O}_2\text{(g)}$

A student has a beaker of hydrogen peroxide solution at 20°C. They do NOT change the concentration. They propose placing the beaker in a warm water bath to raise it to 35°C.

What is the expected effect on the decomposition rate, and why?

The rate increases, because higher temperature increases particle motion and the number of effective collisions per second.

The rate increases, because heating increases the concentration of hydrogen peroxide molecules.

The rate decreases, because warmer temperatures reduce collision frequency in liquids.

No change, because temperature only affects reactions involving gases.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting temperature effects: increasing temperature speeds up reactions (sometimes doubling or tripling the rate for a 10°C increase!) because hot particles move faster, leading to more frequent collisions AND more energetic collisions (both frequency and effectiveness increase). Decreasing temperature slows reactions by the same logic—cold particles move sluggishly, collide less often and less energetically. This is why we refrigerate food (slow down decay reactions) and why heating makes reactions go faster (cooking, chemical processes). The temperature effect is reliable and powerful! Raising the hydrogen peroxide from 20°C to 35°C will increase the speed and energy of H2O2 molecules, boosting collision frequency and the proportion of successful collisions, thus increasing the decomposition rate. Choice C correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice D fails because heating doesn't change concentration—it affects motion and energy, not particle count per volume! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking "which change would most increase rate," temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

7

A student performs the reaction of magnesium with hydrochloric acid at 25°C using identical pieces of magnesium:

$\text{Mg(s)} + 2\text{HCl(aq)} \rightarrow \text{MgCl}_2\text{(aq)} + \text{H}_2\text{(g)}$

They compare two acid concentrations while keeping all other conditions the same:

  • Trial A: 0.50 M HCl
  • Trial B: 1.5 M HCl

Which trial has the faster reaction rate, and why?

Trial A is faster because dilution increases the energy of collisions.

Both are the same rate because concentration changes yield, not reaction speed.

Trial A is faster because lower concentration gives particles more room to move and collide more often.

Trial B is faster because higher concentration means more HCl particles per volume, increasing collision frequency with magnesium.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting concentration effects: increasing concentration speeds up reactions because more reactant particles per unit volume means more crowding, which increases collision frequency—particles bump into each other more often when there are more of them in the same space. Decreasing concentration (dilution) slows reactions because particles are farther apart and collide less frequently. The effect is roughly proportional: double the concentration, roughly double the collision frequency, roughly double the rate. This is why concentrated cleaning products work faster than diluted ones! Trial B with 1.5 M HCl has more HCl particles per volume than Trial A's 0.50 M, leading to more frequent collisions with Mg and a faster rate. Choice B correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice A fails because lower concentration actually decreases collisions by reducing crowding, not increases them—more particles mean more bumps! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking "which change would most increase rate," temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

8

A student reacts iron filings with an acid solution at $25^\circ\text{C}$. They repeat the experiment with the same mass of iron but as a single iron nail instead of filings. The acid concentration, acid volume, and temperature are unchanged. What happens to the reaction rate when using the nail, and why?

It stays the same because the mass of iron is the same, so collision frequency is unchanged.

It decreases because the nail has less surface area exposed than filings, so fewer collisions occur at the solid surface per second.

It increases because a nail is heavier and therefore collides more often with acid particles.

It increases because a smooth surface makes collisions more effective than a rough surface.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Decreasing surface area (using a single nail instead of filings) dramatically slows reactions because it reduces the number of iron atoms exposed at the surface where acid particles can collide with them—iron filings have thousands of tiny particles with enormous total surface area, while a nail has most iron atoms buried inside where acid can't reach them. Even though the total mass is the same, only the outer layer of the nail can react at any moment, while essentially all atoms in the fine filings are accessible for reaction! Choice B correctly predicts the rate decrease by properly applying collision theory to explain how reduced surface area means fewer collision sites between acid and iron atoms. Choice A incorrectly claims weight affects collision frequency (mass doesn't determine rate—exposed surface does!), C wrongly states same mass means same rate regardless of form, and D makes the false claim that smooth surfaces increase collision effectiveness. The rate change prediction recipe: (1) Identify what's changing: iron form changes from filings (huge surface area) to nail (small surface area). (2) Connect to particles: nail → most iron atoms buried inside, few exposed. (3) Connect to collisions: fewer exposed atoms → fewer possible collision sites with acid. (4) Predict rate: fewer collision opportunities → SLOWER rate. This is why iron filings can react explosively with air while iron nails rust slowly—surface area makes a huge difference in reaction rate!

9

A student reacts a strip of magnesium ribbon with $25,\text{mL}$ of $1.0,\text{M}$ hydrochloric acid (HCl) at $22^\circ\text{C}$. The bubbling (hydrogen gas) is steady and the magnesium disappears in about 60 seconds. The student then repeats the reaction but warms the acid to $35^\circ\text{C}$, keeping the acid volume, concentration, and magnesium strip the same. Based on collision theory, how will the reaction rate change?

The rate stays the same because temperature only affects the amount of product, not the speed.

The rate decreases because warming the acid reduces the concentration of HCl particles in solution.

The rate decreases because higher temperature lowers the frequency of collisions.

The rate increases because particles move faster at higher temperature, leading to more frequent and more energetic collisions.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Increasing temperature speeds up reactions (sometimes doubling or tripling the rate for a 10°C increase!) because hot particles move faster, leading to more frequent collisions AND more energetic collisions (both frequency and effectiveness increase). When the student warms the HCl from 22°C to 35°C (a 13°C increase), the acid particles and dissolved ions move significantly faster, colliding with the magnesium surface more frequently and with greater energy—this means more collisions per second AND a higher fraction of collisions have enough energy to break bonds and form products. Choice B correctly predicts the rate increase by properly applying collision theory to explain how the temperature increase affects both collision frequency and effectiveness. Choice A incorrectly claims temperature increase lowers collision frequency (backwards!), C wrongly states temperature doesn't affect rate, and D makes the false claim that warming reduces concentration. The rate change prediction recipe: (1) Identify what's changing: temperature is going up from 22°C to 35°C. (2) Connect to particles: higher temperature → particles move faster. (3) Connect to collisions: faster particles → more frequent AND more energetic collisions. (4) Predict rate: more effective collisions → FASTER rate. Remember that temperature is the most powerful rate-changing factor because it affects both how often particles collide AND whether those collisions have enough energy to react!

10

A student investigates the reaction between sodium thiosulfate and hydrochloric acid (the mixture turns cloudy as sulfur forms). The student keeps temperature constant at 25°C and uses the same volumes each time. They change only the concentration of sodium thiosulfate from 0.10 M to 0.20 M.

Based on collision theory, how should the reaction rate change?

The rate increases because higher concentration means more reactant particles in the same volume, increasing collision frequency.

The rate decreases because higher concentration makes particles collide less effectively.

The rate stays the same because concentration only affects equilibrium, not rate.

The rate stays the same because temperature is constant, so collisions cannot change.

Explanation

This question tests your ability to predict how changes in reaction conditions (temperature, concentration, surface area) will affect reaction rate using collision theory reasoning. Predicting concentration effects: increasing concentration speeds up reactions because more reactant particles per unit volume means more crowding, which increases collision frequency—particles bump into each other more often when there are more of them in the same space. Doubling the sodium thiosulfate concentration from 0.10 M to 0.20 M packs more particles into the same volume, boosting collision frequency with HCl and speeding up the rate. Choice A correctly predicts the rate change by properly applying collision theory to explain how the condition change affects collision frequency or effectiveness. Choice B fails because higher concentration increases collision effectiveness by increasing frequency, not decreases it—more particles mean more chances to react! The rate change prediction recipe: (1) Identify what's changing: Is temperature going up or down? Is concentration increasing or decreasing? Is surface area getting larger (smaller pieces) or smaller (bigger chunks)? (2) Connect to particles: Temperature change → particle speed changes. Concentration change → particle density changes. Surface area change → number of exposed particles changes. (3) Connect to collisions: Faster/more particles → more frequent collisions. Higher energy particles → more effective collisions. More exposed particles → more possible collisions. (4) Predict rate: More or more effective collisions → FASTER rate. Fewer or less effective collisions → SLOWER rate. This four-step chain works for any condition change! Quick prediction rules (use collision theory to understand WHY these work): INCREASE to speed up reaction: raise temperature (most powerful!), increase concentration, increase surface area (for solids), add catalyst (if available). DECREASE to slow down reaction: lower temperature (refrigeration!), decrease concentration (dilute), decrease surface area (use larger pieces), remove catalyst. For exam questions asking 'which change would most increase rate,' temperature increase usually wins because it affects BOTH collision frequency AND effectiveness. Concentration and surface area mainly affect frequency only. This is why we cook with heat, not just by adding more ingredients!

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