Use Probability for Trait Frequency

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1

In a population of beetles, color is controlled by one gene with two alleles: $G$ and $g$. After a drought, survival probabilities differ by genotype: $GG$: 80% survive, $Gg$: 70% survive, $gg$: 20% survive. Assuming survivors reproduce, which allele is expected to increase in frequency in the next generation?

Both alleles increase in frequency because more beetles survive overall

Allele $G$ increases because genotypes with $G$ have higher survival probabilities

Allele $g$ increases because recessive alleles are favored under stress

Neither allele changes because survival only affects individuals, not populations

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates predictable changes in allele frequencies: if individuals with allele G have higher survival probabilities (GG: 80%, Gg: 70%) while individuals with gg have 20% survival (large probability difference), then G-carrying individuals contribute disproportionately more offspring to the next generation, causing G allele frequency to increase and g allele frequency to decrease. The direction of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the rate depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). For this beetle population, the survival probabilities show that genotypes with at least one G allele (GG and Gg) have much higher chances of surviving the drought (80% and 70%) compared to gg (20%), so more G alleles will be passed on, leading to an increase in G frequency over generations. Choice B correctly predicts that allele G increases because genotypes with G have higher survival probabilities, accurately connecting the probability differences to frequency shifts. Choice A fails by incorrectly assuming recessive alleles are favored under stress, ignoring that selection here favors the dominant allele due to survival advantages. Predicting frequency changes from probabilities: (1) Identify survival probabilities for each genotype: GG: 80%, Gg: 70%, gg: 20%. (2) Compare probabilities: Genotypes with G have higher survival. (3) Predict direction: G frequency increases, g decreases. (4) Assess magnitude: Large difference (80-70% vs 20%) means rapid change. Real-world example: like peppered moths during industrialization, where darker moths had higher survival probabilities in polluted areas, leading to rapid increase in dark allele frequency!

2

In a population of beetles, color is controlled by two alleles: $G$ (green) and $g$ (brown). After a drought, survival probabilities differ by genotype: $GG$ = 90% survive, $Gg$ = 70% survive, $gg$ = 20% survive. Assuming survivors are the ones that reproduce, which allele’s frequency is expected to increase in the next generation?

Allele $g$ will increase because rare alleles always increase after selection.

Both alleles will increase because more beetles survive overall.

Allele $G$ will increase because genotypes with $G$ have higher survival probabilities.

Neither allele will change because survival affects individuals, not populations.

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this beetle population, the survival probabilities show that genotypes with more G alleles (GG at 90%, Gg at 70%) have higher chances of surviving the drought compared to gg at 20%, so G-carrying individuals are more likely to reproduce and pass on the G allele, leading to an increase in its frequency. Choice B correctly predicts that allele G will increase by recognizing that higher survival probabilities for G-containing genotypes lead to increasing frequencies of G. Choice A fails by incorrectly assuming rare alleles always increase, but actually, selection favors alleles linked to higher survival regardless of rarity, so here G increases even if it wasn't rare. Keep up the great work—remember this strategy for predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities for each genotype: GG 90%, Gg 70%, gg 20%; (2) COMPARE which allele is associated with HIGHER survival (G in GG and Gg); (3) PREDICT direction: G frequency INCREASES, g DECREASES; (4) ASSESS magnitude: large differences (90% vs 20%) mean rapid change, just like in antibiotic resistance where huge survival gaps cause fast evolution!

3

In a flowering plant, allele $P$ produces purple flowers and allele $p$ produces white flowers. Pollinators visit purple flowers more often, so plants with at least one $P$ allele produce more seeds. Seed production (average offspring) is: $PP$: 40 seeds, $Pp$: 40 seeds, $pp$: 10 seeds. Over time, what is the most likely outcome for allele frequencies?

Allele $P$ will increase because genotypes with $P$ contribute more offspring to the next generation.

Allele $p$ will increase because white flowers produce fewer seeds and therefore face less competition.

Allele frequencies will not change because reproduction differences do not affect evolution.

Allele $P$ will decrease because selection always favors recessive alleles.

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if plants with allele P produce 40 seeds (both PP and Pp) while pp plants produce only 10 seeds, then P-carrying plants contribute disproportionately more offspring to next generation, causing P allele frequency to INCREASE and p allele frequency to DECREASE. The mechanism here is differential reproduction rather than survival, but the probability logic is identical—higher reproductive output means more genetic contribution to future generations. Choice C correctly predicts that allele P will increase because genotypes with P contribute more offspring (40 seeds vs 10 seeds) to the next generation. Choice A incorrectly reasons that producing fewer seeds means less competition (missing that fewer seeds means fewer genetic contributions); B wrongly claims reproduction differences don't affect evolution when they're a primary driver; D falsely states selection favors recessive alleles when selection actually favors traits that increase fitness regardless of dominance. Predicting frequency changes from reproduction: (1) IDENTIFY reproductive output: PP: 40 seeds, Pp: 40 seeds, pp: 10 seeds. (2) COMPARE: P-containing plants produce 4× more offspring! (3) PREDICT: P frequency INCREASES, p frequency DECREASES. (4) ASSESS magnitude: 4-fold reproduction difference = STRONG selection, expect rapid frequency change. This pollinator-mediated selection is common in flowering plants!

4

A bacterial population contains two types: antibiotic-resistant (R) and antibiotic-susceptible (S). Before treatment, most bacteria are S. During antibiotic treatment, 90% of R bacteria survive, but only 5% of S bacteria survive. After treatment, what will most likely happen to the frequency of resistance in the population that regrows?

Resistance will become less common because antibiotics cause mutations that remove resistance.

Resistance frequency will change randomly with no predictable direction because survival probabilities do not matter.

Resistance frequency will stay the same because antibiotics only affect individuals, not populations.

Resistance will become more common because R bacteria have a much higher survival probability.

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if resistant bacteria have 90% survival probability while susceptible bacteria have only 5% survival probability (HUGE probability difference), then resistant bacteria contribute disproportionately more offspring to next generation, causing resistance frequency to INCREASE dramatically and susceptibility frequency to DECREASE. Example: if 100 bacteria, 10 resistant (10%) and 90 susceptible (90%), antibiotic kills 95% of susceptible (only ~5 survive) but kills only 10% of resistant (9 survive), then next generation starts with ~5 susceptible + ~9 resistant = ~14 total, with ~64% resistant (9/14)—resistance frequency jumped from 10% to 64% in one generation! Choice A correctly predicts that resistance will become more common because R bacteria have a much higher survival probability (90% vs 5%). Choice B incorrectly claims antibiotics cause mutations that remove resistance, when actually antibiotics SELECT FOR existing resistance; C wrongly states antibiotics only affect individuals not populations, missing how differential survival changes population frequencies. Predicting frequency changes: (1) IDENTIFY survival probabilities: R bacteria: 90% survive, S bacteria: 5% survive. (2) COMPARE: R has MUCH HIGHER survival (85 percentage point difference!). (3) PREDICT: R frequency INCREASES rapidly, S frequency DECREASES rapidly. This extreme selection pressure explains why antibiotic resistance spreads so quickly in real populations!

5

Hardy-Weinberg equilibrium is a baseline idea that allele frequencies stay the same when no evolutionary forces act. A mouse population had stable fur-color allele frequencies for many generations. Then a new predator arrives and mice with dark fur have a 70% chance to survive to reproduce, while mice with light fur have a 30% chance. What is the most likely outcome over the next several generations?

Individuals will change from light to dark fur during their lifetime to avoid predation

The dark-fur allele will increase in frequency because dark mice survive and reproduce more often

The light-fur allele will increase in frequency because predators remove dark mice more easily

Allele frequencies will remain constant because Hardy-Weinberg predicts no change

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this mouse population, the new predator creates differential survival: dark-fur mice have 70% survival probability while light-fur mice have only 30% survival probability—this 40 percentage point difference means dark mice contribute more than twice as many offspring to the next generation, causing dark-fur allele frequency to increase over time. Choice B correctly predicts that the dark-fur allele will increase in frequency because dark mice survive and reproduce more often under the new predation pressure. Choice A incorrectly invokes Hardy-Weinberg (which assumes NO selection), C gets the direction backwards (dark mice survive better, not worse), and D misunderstands evolution (individuals don't change their genes during their lifetime—populations evolve through differential survival/reproduction). Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: Dark fur: 70% survive to reproduce. Light fur: 30% survive to reproduce. (2) COMPARE probabilities: Dark fur mice have 2.3× higher survival (70% vs 30%). (3) PREDICT direction: Higher probability variant (dark fur) → frequency INCREASES. Lower probability variant (light fur) → frequency DECREASES. (4) ASSESS magnitude: LARGE probability difference (40 percentage points) → RAPID frequency change (strong selection). This violates Hardy-Weinberg equilibrium because we now have differential survival (selection), one of the key forces that causes evolution! Real-world example: the famous peppered moths in England—when industrial pollution darkened tree bark, dark moths had higher survival than light moths (better camouflage), so dark allele frequency increased rapidly from rare to common in just decades!

6

A rabbit population has two coat colors: white and brown. In a snowy habitat, white rabbits have a 75% chance of surviving to reproduce, while brown rabbits have a 25% chance. If the habitat stays snowy, which outcome is most likely after many generations?

Individual brown rabbits will turn white during winter, increasing white frequency without selection

Brown coat color becomes more common because it is currently less common

Coat color frequencies do not change because survival is not related to reproduction

White coat color becomes more common because white rabbits are more likely to survive and reproduce

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this snowy habitat, white rabbits have 75% survival probability while brown rabbits have only 25% survival probability—this 50 percentage point difference means white rabbits contribute three times as many offspring to future generations, causing white coat color frequency to increase over time. Choice C correctly predicts that white coat color becomes more common because white rabbits are more likely to survive and reproduce in the snowy environment. Choice A incorrectly assumes rare traits increase (selection favors beneficial traits regardless of current frequency), B wrongly claims survival doesn't affect reproduction (survivors are the ones who reproduce!), and D misunderstands evolution (individuals can't change their genes—populations evolve through differential survival). Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: White coat: 75% survive to reproduce. Brown coat: 25% survive to reproduce. (2) COMPARE probabilities: White rabbits have 3× higher survival (75% vs 25%). (3) PREDICT direction: Higher probability variant (white) → frequency INCREASES. Lower probability variant (brown) → frequency DECREASES. (4) ASSESS magnitude: LARGE probability difference (50 percentage points) → RAPID frequency change. Real-world example: snowshoe hares change from brown in summer to white in winter, but with climate change reducing snow cover, brown hares now survive better during shorter winters, causing evolutionary change in molt timing—probability of survival drives evolution!

7

A bacterial population contains 10% antibiotic-resistant cells and 90% susceptible cells. When an antibiotic is applied, 95% of susceptible cells die, while only 5% of resistant cells die. After treatment, what happens to the frequency of resistance in the surviving population?

Resistance frequency increases because resistant cells have a much higher survival probability

Resistance frequency stays the same because antibiotics do not affect allele frequencies

Resistance frequency decreases because most bacteria were susceptible to begin with

Resistance frequency changes randomly with no predictable direction

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates predictable changes in allele frequencies: if resistant bacteria have 95% survival while susceptible have 5% (huge probability difference), then resistant individuals contribute disproportionately more to the next generation, causing resistance frequency to increase dramatically. The direction of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the rate depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this bacterial population, starting with 10% resistant, the antibiotic creates a massive survival difference (95% resistant survive vs 5% susceptible), so the surviving population will have a much higher proportion of resistant cells, increasing the resistance frequency. Choice A correctly predicts that resistance frequency increases because resistant cells have a much higher survival probability, directly linking the probability gap to the frequency shift. Choice B fails by suggesting resistance decreases due to initial majority of susceptible cells, overlooking how differential survival disproportionately favors resistant ones. Predicting frequency changes from probabilities: (1) Identify survival probabilities: resistant 95%, susceptible 5%. (2) Compare: resistant much higher. (3) Predict direction: resistance increases. (4) Assess magnitude: Huge difference (90 percentage points) means rapid change, like in the example where resistance jumps from 10% to about 68% in one generation! This is why antibiotic resistance evolves so quickly in real-world bacterial populations under treatment.

8

In a fish species, a gene has two alleles: $F$ and $f$. In polluted water, survival probabilities are: $FF$: 60%, $Ff$: 60%, $ff$: 20%. If pollution continues for many generations, what is the most likely trend in allele frequencies?

Allele $f$ increases because $ff$ fish are removed, freeing resources for $f$ alleles

Allele $F$ increases because genotypes with at least one $F$ have higher survival than $ff$

Both alleles increase because $FF$ and $Ff$ survive at 60%

No allele changes because $FF$ and $Ff$ have the same survival

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this fish population under pollution, survival probabilities are FF: 60%, Ff: 60%, ff: 20%—notice that any genotype containing at least one F allele (FF and Ff) has 60% survival, while ff has only 20% survival, creating a 40 percentage point advantage for F-containing fish, so F allele frequency will increase over generations. Choice B correctly predicts that allele F increases because genotypes with at least one F have higher survival than ff, leading to more F alleles in the next generation. Choice A incorrectly suggests f increases (but ff has lowest survival!), C wrongly claims no change because FF and Ff are equal (but both are much higher than ff), and D misunderstands that both alleles can't increase simultaneously. Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: FF: 60%, Ff: 60%, ff: 20%. (2) COMPARE probabilities: F-containing genotypes (FF, Ff) have 3× higher survival than ff (60% vs 20%). (3) PREDICT direction: Since F appears in high-survival genotypes, F frequency INCREASES. Since ff has low survival, f frequency DECREASES. (4) ASSESS magnitude: LARGE probability difference (40 percentage points) → RAPID frequency change. Real-world example: heavy metal tolerance in plants near mines—if TT and Tt plants survive toxic soil at 70% while tt plants survive at 10%, the T (tolerance) allele rapidly increases, eventually making most plants near the mine tolerant!

9

In a bird species, a gene has two alleles, $A$ and $a$. A new predator arrives. Birds with genotype $AA$ have a 60% chance of surviving to reproduce, $Aa$ have a 60% chance, and $aa$ have a 30% chance. Which statement best predicts how allele frequencies will change over generations if these survival rates continue?

Allele frequencies will not change because $AA$ and $Aa$ have the same survival

Both alleles will increase because $AA$ and $Aa$ survive equally well

Allele $a$ will increase because it is recessive

Allele $A$ will increase because genotypes carrying $A$ survive more often than $aa$

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates predictable changes in allele frequencies: if individuals with allele A (AA and Aa) have 60% survival while aa have 30% (notable difference), then A-carrying individuals contribute more offspring, causing A frequency to increase and a to decrease. The direction of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the rate depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). Here, the predator introduces selection where AA and Aa birds survive at 60% (same rate), but aa at only 30%, so over generations, more A alleles will be passed on as aa individuals are less likely to reproduce, increasing A frequency. Choice B correctly predicts that allele A will increase because genotypes carrying A survive more often than aa, recognizing the selection against the recessive homozygote. Choice C fails by claiming no change since AA and Aa have the same survival, ignoring that the lower survival of aa still drives A frequency up. Predicting frequency changes from probabilities: (1) Identify survival: AA 60%, Aa 60%, aa 30%. (2) Compare: A-carriers higher than aa. (3) Predict direction: A increases, a decreases. (4) Assess magnitude: 30% difference means moderate selection strength. Real-world example: like sickle-cell anemia, where heterozygotes have malaria resistance (higher survival), leading to balanced frequencies in affected regions!

10

In a lizard population, a gene has alleles $H$ and $h$. Under normal conditions (no new predators, no drought, no disease), survival and reproduction are similar for all genotypes, so allele frequencies are stable. If conditions remain the same, what does Hardy-Weinberg equilibrium predict about allele frequencies?

They will stay approximately constant because no selection (or other forces) is acting

They will change only if individual lizards choose mates with the same genotype

They will change because evolution happens every generation no matter what

They will always shift toward whichever allele is rarer

Explanation

This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this lizard population under normal conditions with no selection pressures, all genotypes have similar survival and reproduction—this means NO differential probabilities, so no genotype contributes disproportionately to the next generation, and Hardy-Weinberg equilibrium predicts allele frequencies remain constant over time. Choice A correctly predicts that allele frequencies will stay approximately constant because no selection (or other evolutionary forces) is acting—this is the fundamental prediction of Hardy-Weinberg equilibrium. Choice B incorrectly suggests rare alleles are favored (no mechanism for this without selection), C wrongly claims evolution always happens (it requires differential survival/reproduction or other forces), and D misunderstands that mate choice patterns alone don't change allele frequencies without differential reproduction. Predicting frequency changes from probabilities: (1) IDENTIFY survival/reproduction probabilities: All genotypes have SIMILAR survival and reproduction. (2) COMPARE probabilities: NO significant differences between genotypes. (3) PREDICT direction: No probability differences → NO directional change in frequencies. (4) This is Hardy-Weinberg equilibrium: when survival/reproduction probabilities are equal, allele frequencies stay constant! The five conditions for Hardy-Weinberg: no selection (equal survival/reproduction), no mutation, no migration, large population (no drift), random mating. When these hold, allele frequencies remain stable generation after generation—evolution requires breaking at least one condition!

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