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This deck focuses on Analyze Population Data For Evolution, giving you a quick way to review the definitions, rules, and examples that matter most for Biology.
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What is genotype frequency in a population?
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Proportion of individuals with a specific genotype. Calculated by dividing individuals with that genotype by total individuals.
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This deck focuses on Analyze Population Data For Evolution, giving you a quick way to review the definitions, rules, and examples that matter most for Biology.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Proportion of individuals with a specific genotype. Calculated by dividing individuals with that genotype by total individuals.
Answer: Fitness depends on how common or rare a phenotype is. Selection strength varies with phenotype abundance in population.
Answer: Evolution is occurring in that population. Frequency changes indicate evolutionary forces are acting.
Answer: Evolution is occurring in that population. Frequency changes indicate evolutionary forces are acting.
Answer: p=0.60. p=2(100)2(36)+48=200120=0.60
Answer: Population is very large (minimizes genetic drift). Large populations reduce random sampling effects.
Answer: p=2N2AA+Aa. Counts each homozygote twice and heterozygote once for allele A.
Answer: Allele frequencies remain constant when no evolution occurs. Predicts frequencies when evolutionary forces are absent.
Answer: Genetic drift (bottleneck effect). Population crashes cause random allele loss through sampling effects.
Answer: Heterozygotes have highest fitness, maintaining both alleles. Balancing selection maintains genetic diversity.
Answer: Genetic drift (founder effect). Few founding individuals create non-representative gene pools.
Answer: Change in allele frequencies in a population over time. This is the quantitative definition used in population genetics studies.
Answer: Population is very large (minimizes genetic drift). Large populations reduce random sampling effects.
Answer: q2. Frequency of aa genotype in Hardy-Weinberg equilibrium.
Answer: Environmental factor that causes differential survival or reproduction. Environmental factors create fitness differences between phenotypes.
Answer: Gene flow. Migration homogenizes allele frequencies between populations over time.
Answer: p=2N2AA+Aa. Counts each homozygote twice and heterozygote once for allele A.
Answer: q2=0.04. q2=(0.20)2=0.04
Answer: Genetic drift (bottleneck effect). Population crashes cause random allele loss through sampling effects.
Answer: Source of new alleles via DNA sequence changes. Introduces novel alleles but usually at low rates.
Answer: Allele frequencies remain constant when no evolution occurs. Predicts frequencies when evolutionary forces are absent.
Answer: Consistent allele frequency change correlated with a selective pressure. Correlation between selection pressure and frequency change indicates causation.
Answer: 2pq=0.18. 2pq=2(0.90)(0.10)=0.18
Answer: Directional selection. Consistent shift toward one extreme indicates directional selection.
Answer: Δp=0.12. Δp=0.62−0.50=0.12
Answer: Mate choice/inbreeding changes genotype frequencies, not allele frequencies directly. Affects Hardy-Weinberg genotype predictions without changing allele frequencies.
Answer: At least one Hardy–Weinberg condition is violated (evolution likely). Deviations indicate evolutionary forces are acting on the population.
Answer: Small populations. Smaller populations have greater sampling variance.
Answer: Mating is random. Prevents preferential mating patterns that alter genotype frequencies.
Answer: p=0.70. Since p+q=1, then p=1−0.30=0.70
Answer: q=0.40. q=2(100)2(16)+48=20080=0.40
Answer: p2. Frequency of AA genotype in Hardy-Weinberg equilibrium.
Answer: 2pq. Frequency of Aa genotype; factor of 2 accounts for both combinations.
Answer: Directional selection. Consistent shift toward one extreme indicates directional selection.
Answer: Consistent allele frequency change correlated with a selective pressure. Correlation between selection pressure and frequency change indicates causation.
Answer: At least one Hardy–Weinberg condition is violated (evolution likely). Deviations indicate evolutionary forces are acting on the population.
Answer: No mutations occur. Mutations would change allele frequencies over time.
Answer: No migration; no gene flow into or out of the population. Migration introduces or removes alleles from the population.
Answer: Stabilizing selection. Intermediate optimization indicates selection against extremes.
Answer: Positive selection increased the allele's frequency. Rapid increase after environmental change indicates adaptive advantage.
Answer: Proportion of all gene copies that are a specific allele. Calculated by dividing copies of that allele by total gene copies.
Answer: No migration; no gene flow into or out of the population. Migration introduces or removes alleles from the population.
Answer: p=0.70. Since p+q=1, then p=1−0.30=0.70
Answer: 2pq=0.18. 2pq=2(0.90)(0.10)=0.18
Answer: No evidence of evolution at that locus in that population. Meeting Hardy-Weinberg expectations indicates no evolutionary change.
Answer: No natural selection; equal fitness among genotypes. All genotypes must have equal reproductive success.
Answer: Nonrandom allele frequency change due to differential survival/reproduction. Fitness differences cause predictable frequency changes.
Answer: Stabilizing selection. Intermediate optimization indicates selection against extremes.
Answer: Heterozygotes have highest fitness, maintaining both alleles. Balancing selection maintains genetic diversity.
Answer: p2=0.49. p2=(0.70)2=0.49
Answer: Trait variation correlates between parents and offspring. Parent-offspring correlation indicates genetic basis for the trait.
Answer: q=0.30. Since q2=0.09, then q=0.09=0.30
Answer: Trait variation correlates between parents and offspring. Parent-offspring correlation indicates genetic basis for the trait.
Answer: p2+2pq+q2=1. Expands (p+q)2 to show all genotype frequencies.
Answer: q2. Frequency of aa genotype in Hardy-Weinberg equilibrium.
Answer: Random change in allele frequencies due to chance. Sampling error causes unpredictable frequency changes.
Answer: No natural selection; equal fitness among genotypes. All genotypes must have equal reproductive success.
Answer: Negative frequency-dependent selection. Rare phenotypes gain advantage specifically from their rarity.
Answer: Balancing selection via heterozygote advantage. Heterozygote advantage maintains harmful alleles in populations.
Answer: p+q=1. The two allele frequencies must sum to 1.
Answer: Disruptive selection. Both extremes increasing indicates selection against intermediate forms.
Answer: All alleles present in the population. The collective genetic variation available for evolution.
Answer: Mating is random. Prevents preferential mating patterns that alter genotype frequencies.
Answer: 2pq=0.48. 2pq=2(0.60)(0.40)=0.48
Answer: Balancing selection via heterozygote advantage. Heterozygote advantage maintains harmful alleles in populations.
Answer: Movement of alleles between populations via migration and breeding. Homogenizes allele frequencies between connected populations.
Answer: Positive selection increased the allele's frequency. Rapid increase after environmental change indicates adaptive advantage.
Answer: q=2N2aa+Aa. Counts each homozygote twice and heterozygote once for allele a.