Linear Transformations and Matrices

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AP Precalculus › Linear Transformations and Matrices

Questions 1 - 6
1

A poster is uniformly scaled by $k=0.5$ using $S=0.5\ 0;\ 0\ 0.5$. Based on the scenario, what changes occur to the dimensions?

Width doubles; height doubles.

Width unchanged; height halves.

Width halves; height halves.

Width halves; height doubles.

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A uniform scaling matrix has the form S=[k 0; 0 k], where k is the scaling factor applied equally to both dimensions. In this scenario, the transformation matrix S=[0.5 0; 0 0.5] scales a poster uniformly by factor 0.5, which means both width and height are multiplied by 0.5. Choice A is correct because a scaling factor of 0.5 reduces both dimensions to half their original size, so width halves and height halves. Choice B is incorrect because it suggests doubling, which would require a scaling factor of 2, not 0.5. To help students: Remember that scaling factors less than 1 reduce size, while factors greater than 1 increase size. Practice interpreting scaling matrices in real-world contexts like image resizing.

2

A CAD tool rotates a model about the $z$-axis by $90^\circ$ using $R=0\ -1\ 0;\ 1\ 0\ 0;\ 0\ 0\ 1$. Based on the scenario, what is $R\langle 2,1,5\rangle$?

$\langle -1,2,5\rangle$

$\langle 2,1,5\rangle$

$\langle 1,-2,5\rangle$

$\langle -2,-1,5\rangle$

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A rotation matrix about the z-axis by 90° counterclockwise has the form R=[0 -1 0; 1 0 0; 0 0 1], which rotates points in the xy-plane while keeping the z-coordinate unchanged. In this scenario, applying the rotation matrix R to vector ⟨2,1,5⟩ involves matrix multiplication: R⟨2,1,5⟩ = [0 -1 0; 1 0 0; 0 0 1]⟨2,1,5⟩ = ⟨0(2)+(-1)(1)+0(5), 1(2)+0(1)+0(5), 0(2)+0(1)+1(5)⟩ = ⟨-1,2,5⟩. Choice A is correct because it accurately reflects the result of the matrix multiplication, showing that the point (2,1) rotates to (-1,2) while z=5 remains unchanged. Choice B is incorrect because it shows an incorrect rotation direction, suggesting clockwise rotation instead of counterclockwise. To help students: Visualize rotations in 3D space and remember that positive rotations are counterclockwise when viewed from the positive axis. Practice matrix multiplication step-by-step to avoid calculation errors.

3

A graphics filter shears horizontally using $H=1\ 2;\ 0\ 1$. Using the given transformation, what is $H\langle 1,3\rangle$?

$\langle -5,3\rangle$

$\langle 5,1\rangle$

$\langle 7,3\rangle$

$\langle 1,5\rangle$

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A horizontal shear matrix has the form H=[1 k; 0 1], where k is the shear factor that adds k times the y-coordinate to the x-coordinate. In this scenario, the transformation matrix H=[1 2; 0 1] applies a horizontal shear with factor 2 to vector ⟨1,3⟩. Choice A is correct because H⟨1,3⟩ = [1 2; 0 1]⟨1,3⟩ = ⟨1(1)+2(3), 0(1)+1(3)⟩ = ⟨1+6, 3⟩ = ⟨7,3⟩, showing that the x-coordinate becomes 1+2(3)=7 while the y-coordinate remains 3. Choice B is incorrect because it suggests minimal change to the coordinates, failing to apply the shear transformation properly. To help students: Remember that horizontal shear keeps y-coordinates fixed while modifying x-coordinates based on the y-value. Visualize shearing as slanting a shape horizontally.

4

A navigation system reflects a heading across the $x$-axis using $M=1\ 0;\ 0\ -1$. Using the given transformation, what is $M\langle 4,-3\rangle$?

$\langle -4,-3\rangle$

$\langle 4,-3\rangle$

$\langle 4,3\rangle$

$\langle -4,3\rangle$

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A reflection matrix across the x-axis has the form M=[1 0; 0 -1], which keeps the x-coordinate unchanged while negating the y-coordinate. In this scenario, the transformation matrix M is applied to vector ⟨4,-3⟩, demonstrating how reflection across the x-axis affects a point's position. Choice B is correct because M⟨4,-3⟩ = [1 0; 0 -1]⟨4,-3⟩ = ⟨1(4)+0(-3), 0(4)+(-1)(-3)⟩ = ⟨4,3⟩, showing that the x-coordinate remains 4 while the y-coordinate changes from -3 to 3. Choice A is incorrect because it negates both coordinates, which would represent a reflection through the origin rather than across the x-axis. To help students: Remember that reflection across the x-axis only changes the sign of the y-coordinate. Visualize the geometric transformation to verify algebraic results.

5

A design tool reflects vectors across the line $y=x$ using $M=0\ 1;\ 1\ 0$. Based on the scenario, what is $M\langle -2,5\rangle$?

$\langle -2,5\rangle$

$\langle 5,-2\rangle$

$\langle -2,-5\rangle$

$\langle -5,2\rangle$

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A reflection matrix across the line y=x has the form M=[0 1; 1 0], which swaps the x and y coordinates of any point. In this scenario, the transformation matrix M is applied to vector ⟨-2,5⟩, demonstrating how reflection across y=x exchanges coordinate positions. Choice B is correct because M⟨-2,5⟩ = [0 1; 1 0]⟨-2,5⟩ = ⟨0(-2)+1(5), 1(-2)+0(5)⟩ = ⟨5,-2⟩, showing that the coordinates are swapped from (-2,5) to (5,-2). Choice C is incorrect because it negates the x-coordinate after swapping, which is not part of the reflection across y=x. To help students: Remember that reflection across y=x simply exchanges x and y coordinates. Visualize this as folding the plane along the line y=x.

6

A camera effect applies vertical shear using $V=1\ 0;\ -3\ 1$. Based on the scenario, what is $V\langle 2,1\rangle$?

$\langle 2,7\rangle$

$\langle 2,-5\rangle$

$\langle -6,1\rangle$

$\langle -1,1\rangle$

Explanation

This question tests AP Precalculus skills, specifically linear transformations and matrices. A vertical shear matrix has the form V=[1 0; k 1], where k is the shear factor that adds k times the x-coordinate to the y-coordinate. In this scenario, the transformation matrix V=[1 0; -3 1] applies a vertical shear with factor -3 to vector ⟨2,1⟩. Choice A is correct because V⟨2,1⟩ = [1 0; -3 1]⟨2,1⟩ = ⟨1(2)+0(1), -3(2)+1(1)⟩ = ⟨2, -6+1⟩ = ⟨2,-5⟩, showing that the x-coordinate remains 2 while the y-coordinate becomes -3(2)+1=-5. Choice C is incorrect because it suggests a positive y-coordinate, failing to account for the negative shear factor. To help students: Remember that vertical shear keeps x-coordinates fixed while modifying y-coordinates based on the x-value. Pay attention to the sign of the shear factor.