AP Precalculus Flashcards: Conic Sections

Study Conic Sections in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Precalculus

Conic Sections

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QUESTION
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Find the center of the circle (x3)2+(y+5)2=36(x-3)^2 + (y+5)^2 = 36.

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ANSWER

(3, -5). The center is at (h,k)(h,k) in the vertex form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.

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What this deck covers

This deck focuses on Conic Sections, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: Find the center of the circle (x3)2+(y+5)2=36(x-3)^2 + (y+5)^2 = 36.

Answer: (3, -5). The center is at (h,k)(h,k) in the vertex form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.

Flashcard 2: What is the formula for the semi-major axis of an ellipse?

Answer: aa in x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1. The larger denominator corresponds to the major axis length.

Flashcard 3: Identify the conic section: x2y2=16x^2 - y^2 = 16.

Answer: Hyperbola. Difference of squares with equal coefficients indicates a hyperbola.

Flashcard 4: Identify the conic section: y2=4xy^2 = 4x.

Answer: Parabola. Square term on yy with linear xx indicates a horizontal parabola.

Flashcard 5: What is the formula for the latus rectum of a parabola?

Answer: 4p|4p|. The chord through the focus perpendicular to the axis of symmetry.

Flashcard 6: State the formula for the area of an ellipse with semi-axes aa and bb.

Answer: A=πabA = \pi ab. Where aa and bb are the lengths of the semi-major and semi-minor axes.

Flashcard 7: What is the formula for the focal distance of an ellipse?

Answer: c=a2b2c = \sqrt{a^2 - b^2}. For an ellipse, c<ac < a since the foci are inside the ellipse.

Flashcard 8: Identify the conic section: x2+4x+y26y=12x^2 + 4x + y^2 - 6y = 12.

Answer: Circle. Complete the square to verify equal coefficients for x2x^2 and y2y^2.

Flashcard 9: Identify the conic section: x2+y24x+6y=12x^2 + y^2 - 4x + 6y = 12.

Answer: Circle. Complete the square to verify it has equal coefficients for x2x^2 and y2y^2 terms.

Flashcard 10: Find the foci of the hyperbola x29y24=1\frac{x^2}{9} - \frac{y^2}{4} = 1.

Answer: Foci: (±5,0)(\pm 5, 0). From c2=a2+b2=9+16=25c^2 = a^2 + b^2 = 9 + 16 = 25, so c=5c = 5.

Flashcard 11: Which conic section is represented by 4x29y2=364x^2 - 9y^2 = 36?

Answer: Hyperbola. Divide by 36 to get standard form with a2=9a^2 = 9 and b2=4b^2 = 4.

Flashcard 12: What is the definition of a circle?

Answer: A set of points equidistant from a fixed point (center). All points are the same distance from the center point.

Flashcard 13: Identify the conic section: x2+2x+y2+4y=1x^2 + 2x + y^2 + 4y = 1.

Answer: Circle. Complete the square to verify it has equal coefficients for squared terms.

Flashcard 14: Identify the conic section: 9x2+16y2=1449x^2 + 16y^2 = 144.

Answer: Ellipse. Divide by 144 to get standard form with positive coefficients.

Flashcard 15: What is the relationship between aa, bb, and cc in a hyperbola?

Answer: c2=a2+b2c^2 = a^2 + b^2. For hyperbolas, c>ac > a since the foci are outside the vertices.

Flashcard 16: What is the definition of a parabola?

Answer: A set of points equidistant from a point (focus) and a line (directrix). This property defines the parabola's unique geometric shape.

Flashcard 17: State the formula for the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2).

Answer: (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. Derived from the Pythagorean theorem in coordinate geometry.

Flashcard 18: Find the focus of the parabola y2=16xy^2 = 16x.

Answer: (4, 0). From y2=16xy^2 = 16x, we get 4p=164p = 16, so p=4p = 4 and focus is at (p,0)(p,0).

Flashcard 19: Identify the conic section: x2+6x+y24y=0x^2 + 6x + y^2 - 4y = 0.

Answer: Circle. Complete the square to verify it forms a circle equation.

Flashcard 20: What is the definition of an ellipse?

Answer: A set of points where the sum of distances to two foci is constant. The sum equals 2a2a, where aa is the semi-major axis length.

Flashcard 21: What is the definition of an ellipse?

Answer: A set of points where the sum of distances to two foci is constant. The sum equals 2a2a, where aa is the semi-major axis length.

Flashcard 22: Identify the conic section: 9x2+16y2=1449x^2 + 16y^2 = 144.

Answer: Ellipse. Divide by 144 to get standard form with positive coefficients.

Flashcard 23: What is the formula for the latus rectum of a parabola?

Answer: 4p|4p|. The chord through the focus perpendicular to the axis of symmetry.

Flashcard 24: What is the standard form of an ellipse centered at origin?

Answer: x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1. Where aa and bb are the semi-major and semi-minor axis lengths.

Flashcard 25: Find the vertex of the parabola y=3(x2)2+5y = 3(x-2)^2 + 5.

Answer: (2, 5). The vertex form shows the vertex at (h,k)(h,k) where the parabola turns.

Flashcard 26: Which conic section has an eccentricity e>1e > 1?

Answer: Hyperbola. Eccentricity greater than 1 distinguishes hyperbolas from other conics.

Flashcard 27: Identify the conic section: 25x2+25y2=62525x^2 + 25y^2 = 625.

Answer: Circle. Equal coefficients (25) for x2x^2 and y2y^2 terms indicate a circle.

Flashcard 28: Which conic section is represented by x2y2=1x^2 - y^2 = 1?

Answer: Hyperbola. Difference of squares form indicates a hyperbola with a2=b2=1a^2 = b^2 = 1.

Flashcard 29: Find the center of the circle (x3)2+(y+5)2=36(x-3)^2 + (y+5)^2 = 36.

Answer: (3, -5). The center is at (h,k)(h,k) in the vertex form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.

Flashcard 30: What is the standard form of a hyperbola centered at origin?

Answer: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1. Subtraction between squared terms indicates a hyperbola opening horizontally.

Flashcard 31: State the general form of a conic section equation.

Answer: Ax2+Bxy+Cy2+Dx+Ey+F=0Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0. The discriminant B24ACB^2 - 4AC determines the conic type.

Flashcard 32: What is the definition of a hyperbola?

Answer: A set of points where the difference of distances to two foci is constant. The absolute value of the difference equals 2a2a, where aa is the semi-major axis.

Flashcard 33: Find the foci of the hyperbola x29y24=1\frac{x^2}{9} - \frac{y^2}{4} = 1.

Answer: Foci: (±5,0)(\pm 5, 0). From c2=a2+b2=9+16=25c^2 = a^2 + b^2 = 9 + 16 = 25, so c=5c = 5.

Flashcard 34: State the formula for the area of an ellipse with semi-axes aa and bb.

Answer: A=πabA = \pi ab. Where aa and bb are the lengths of the semi-major and semi-minor axes.

Flashcard 35: What is the standard form of a hyperbola centered at origin?

Answer: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1. Subtraction between squared terms indicates a hyperbola opening horizontally.

Flashcard 36: Identify the conic section: x2+y24x+6y=12x^2 + y^2 - 4x + 6y = 12.

Answer: Circle. Complete the square to verify it has equal coefficients for x2x^2 and y2y^2 terms.

Flashcard 37: Find the focus of the parabola y2=16xy^2 = 16x.

Answer: (4, 0). From y2=16xy^2 = 16x, we get 4p=164p = 16, so p=4p = 4 and focus is at (p,0)(p,0).

Flashcard 38: Identify the conic section: x2+6x+y24y=0x^2 + 6x + y^2 - 4y = 0.

Answer: Circle. Complete the square to verify it forms a circle equation.

Flashcard 39: Find the equation of the directrix of the parabola x2=8yx^2 = 8y.

Answer: y=2y = -2. From x2=8yx^2 = 8y, we have 4p=84p = 8, so p=2p = 2 and directrix is y=py = -p.

Flashcard 40: Identify the conic section: y2=4xy^2 = 4x.

Answer: Parabola. Square term on yy with linear xx indicates a horizontal parabola.

Flashcard 41: State the formula for the eccentricity of an ellipse.

Answer: e=cae = \frac{c}{a} where c=a2b2c = \sqrt{a^2 - b^2}. For ellipses, 0<e<10 < e < 1 since c<ac < a always.

Flashcard 42: Which conic section is represented by 4x29y2=364x^2 - 9y^2 = 36?

Answer: Hyperbola. Divide by 36 to get standard form with a2=9a^2 = 9 and b2=4b^2 = 4.

Flashcard 43: State the formula for the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2).

Answer: (x2x1)2+(y2y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. Derived from the Pythagorean theorem in coordinate geometry.

Flashcard 44: What is the relationship between aa, bb, and cc in a hyperbola?

Answer: c2=a2+b2c^2 = a^2 + b^2. For hyperbolas, c>ac > a since the foci are outside the vertices.

Flashcard 45: What is the standard form equation of a vertical parabola?

Answer: x2=4pyx^2 = 4py. Where pp is the distance from vertex to focus and directrix.

Flashcard 46: Find the equation of the directrix of the parabola x2=8yx^2 = 8y.

Answer: y=2y = -2. From x2=8yx^2 = 8y, we have 4p=84p = 8, so p=2p = 2 and directrix is y=py = -p.

Flashcard 47: What is the standard form equation of a parabola with vertex at origin?

Answer: y=ax2y = ax^2. Where aa determines the width and opens vertically.

Flashcard 48: State the general form of a conic section equation.

Answer: Ax2+Bxy+Cy2+Dx+Ey+F=0Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0. The discriminant B24ACB^2 - 4AC determines the conic type.

Flashcard 49: What is the definition of a hyperbola?

Answer: A set of points where the difference of distances to two foci is constant. The absolute value of the difference equals 2a2a, where aa is the semi-major axis.

Flashcard 50: Which conic section is represented by x2y2=1x^2 - y^2 = 1?

Answer: Hyperbola. Difference of squares form indicates a hyperbola with a2=b2=1a^2 = b^2 = 1.

Flashcard 51: What is the equation of a circle with center (h,k)(h,k) and radius rr?

Answer: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2. Standard form for any circle with center and radius specified.

Flashcard 52: Identify the conic section: x2+4x+y26y=12x^2 + 4x + y^2 - 6y = 12.

Answer: Circle. Complete the square to verify equal coefficients for x2x^2 and y2y^2.

Flashcard 53: What is the directrix of a parabola?

Answer: A fixed line used to define the parabola. Points on the parabola are equidistant from focus and directrix.

Flashcard 54: State the formula for the eccentricity of an ellipse.

Answer: e=cae = \frac{c}{a} where c=a2b2c = \sqrt{a^2 - b^2}. For ellipses, 0<e<10 < e < 1 since c<ac < a always.

Flashcard 55: What is the definition of a circle?

Answer: A set of points equidistant from a fixed point (center). All points are the same distance from the center point.

Flashcard 56: What is the equation for the asymptotes of a hyperbola x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1?

Answer: y=±baxy = \pm \frac{b}{a}x. The slopes are ±ba\pm\frac{b}{a} for the standard hyperbola form.

Flashcard 57: Identify the conic section: x2y2=16x^2 - y^2 = 16.

Answer: Hyperbola. Difference of squares with equal coefficients indicates a hyperbola.

Flashcard 58: What is the definition of a parabola?

Answer: A set of points equidistant from a point (focus) and a line (directrix). This property defines the parabola's unique geometric shape.

Flashcard 59: What is the formula for the semi-major axis of an ellipse?

Answer: aa in x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1. The larger denominator corresponds to the major axis length.

Flashcard 60: What is the equation for a parabola with vertex (h,k)(h, k) and focus (h,k+p)(h, k+p)?

Answer: (xh)2=4p(yk)(x-h)^2 = 4p(y-k). Vertex form for vertical parabolas with vertex at (h,k)(h,k).

Flashcard 61: Identify the conic section: x2+2x+y2+4y=1x^2 + 2x + y^2 + 4y = 1.

Answer: Circle. Complete the square to verify it has equal coefficients for squared terms.

Flashcard 62: Find the center and radii lengths of the ellipse 9x2+4y2=369x^2 + 4y^2 = 36.

Answer: Center: (0,0), a=2a=2, b=3b=3. Divide by 36: x24+y29=1\frac{x^2}{4} + \frac{y^2}{9} = 1, so a2=4a^2 = 4, b2=9b^2 = 9.

Flashcard 63: What is the directrix of a parabola?

Answer: A fixed line used to define the parabola. Points on the parabola are equidistant from focus and directrix.

Flashcard 64: What is the standard form of an ellipse centered at origin?

Answer: x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1. Where aa and bb are the semi-major and semi-minor axis lengths.

Flashcard 65: What is the equation for the asymptotes of a hyperbola centered at origin?

Answer: y=±baxy = \pm \frac{b}{a}x. Lines the hyperbola approaches as xx and yy approach infinity.

Flashcard 66: What is the equation for the asymptotes of a hyperbola x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1?

Answer: y=±baxy = \pm \frac{b}{a}x. The slopes are ±ba\pm\frac{b}{a} for the standard hyperbola form.

Flashcard 67: What is the standard form equation of a circle centered at origin?

Answer: x2+y2=r2x^2 + y^2 = r^2. Where rr is the radius from the center at (0,0)(0,0).

Flashcard 68: What is the standard form equation of a circle centered at origin?

Answer: x2+y2=r2x^2 + y^2 = r^2. Where rr is the radius from the center at (0,0)(0,0).

Flashcard 69: Find the center and radii lengths of the ellipse 9x2+4y2=369x^2 + 4y^2 = 36.

Answer: Center: (0,0), a=2a=2, b=3b=3. Divide by 36: x24+y29=1\frac{x^2}{4} + \frac{y^2}{9} = 1, so a2=4a^2 = 4, b2=9b^2 = 9.

Flashcard 70: What is the formula for the eccentricity of a conic section?

Answer: e=cae = \frac{c}{a}. Where cc is the focal distance and aa is the semi-major axis.

Flashcard 71: What is the formula for the focal distance of an ellipse?

Answer: c=a2b2c = \sqrt{a^2 - b^2}. For an ellipse, c<ac < a since the foci are inside the ellipse.

Flashcard 72: What is the equation of a circle with center (h,k)(h,k) and radius rr?

Answer: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2. Standard form for any circle with center and radius specified.

Flashcard 73: Find the vertex of the parabola y=3(x2)2+5y = 3(x-2)^2 + 5.

Answer: (2, 5). The vertex form shows the vertex at (h,k)(h,k) where the parabola turns.

Flashcard 74: Identify the conic section: 25x2+25y2=62525x^2 + 25y^2 = 625.

Answer: Circle. Equal coefficients (25) for x2x^2 and y2y^2 terms indicate a circle.

Flashcard 75: What is the standard form equation of a vertical parabola?

Answer: x2=4pyx^2 = 4py. Where pp is the distance from vertex to focus and directrix.

Flashcard 76: What is the formula for the eccentricity of a conic section?

Answer: e=cae = \frac{c}{a}. Where cc is the focal distance and aa is the semi-major axis.

Flashcard 77: What is the equation for the asymptotes of a hyperbola centered at origin?

Answer: y=±baxy = \pm \frac{b}{a}x. Lines the hyperbola approaches as xx and yy approach infinity.

Flashcard 78: Which conic section has an eccentricity e>1e > 1?

Answer: Hyperbola. Eccentricity greater than 1 distinguishes hyperbolas from other conics.

Flashcard 79: What is the equation for a parabola with vertex (h,k)(h, k) and focus (h,k+p)(h, k+p)?

Answer: (xh)2=4p(yk)(x-h)^2 = 4p(y-k). Vertex form for vertical parabolas with vertex at (h,k)(h,k).

Flashcard 80: What is the standard form equation of a parabola with vertex at origin?

Answer: y=ax2y = ax^2. Where aa determines the width and opens vertically.