Newton's Second Law - AP Physics C: Mechanics
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Determine the net force: $m = 6 \text{ kg}$, $a = 3 \text{ m/s}^2$.
Determine the net force: $m = 6 \text{ kg}$, $a = 3 \text{ m/s}^2$.
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$F = 18 \text{ N}$. Apply $F = ma$: $6 \times 3 = 18$ N.
$F = 18 \text{ N}$. Apply $F = ma$: $6 \times 3 = 18$ N.
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Find $F$: $m = 7 \text{ kg}$, $a = 1 \text{ m/s}^2$.
Find $F$: $m = 7 \text{ kg}$, $a = 1 \text{ m/s}^2$.
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$F = 7 \text{ N}$. Use $F = ma$: $7 \times 1 = 7$ N.
$F = 7 \text{ N}$. Use $F = ma$: $7 \times 1 = 7$ N.
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Find $F$: $m = 10 \text{ kg}$, $a = 2 \text{ m/s}^2$.
Find $F$: $m = 10 \text{ kg}$, $a = 2 \text{ m/s}^2$.
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$F = 20 \text{ N}$. Use $F = ma$: $10 \times 2 = 20$ N.
$F = 20 \text{ N}$. Use $F = ma$: $10 \times 2 = 20$ N.
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Identify the expression for force from $F = ma$.
Identify the expression for force from $F = ma$.
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$F = ma$. This is Newton's Second Law in its standard form.
$F = ma$. This is Newton's Second Law in its standard form.
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Determine the net force: $m = 8 \text{ kg}$, $a = 1.5 \text{ m/s}^2$.
Determine the net force: $m = 8 \text{ kg}$, $a = 1.5 \text{ m/s}^2$.
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$F = 12 \text{ N}$. Apply $F = ma$: $8 \times 1.5 = 12$ N.
$F = 12 \text{ N}$. Apply $F = ma$: $8 \times 1.5 = 12$ N.
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Calculate $F$: $m = 9 \text{ kg}$, $a = 2 \text{ m/s}^2$.
Calculate $F$: $m = 9 \text{ kg}$, $a = 2 \text{ m/s}^2$.
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$F = 18 \text{ N}$. Use $F = ma$: $9 \times 2 = 18$ N.
$F = 18 \text{ N}$. Use $F = ma$: $9 \times 2 = 18$ N.
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What is the relationship between force and acceleration?
What is the relationship between force and acceleration?
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Force is directly proportional to acceleration. From $F = ma$, doubling force doubles acceleration when mass is constant.
Force is directly proportional to acceleration. From $F = ma$, doubling force doubles acceleration when mass is constant.
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Find $m$: $F = 10 \text{ N}$, $a = 2 \text{ m/s}^2$.
Find $m$: $F = 10 \text{ N}$, $a = 2 \text{ m/s}^2$.
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$m = 5 \text{ kg}$. Rearrange to $m = F/a$: $10/2 = 5$ kg.
$m = 5 \text{ kg}$. Rearrange to $m = F/a$: $10/2 = 5$ kg.
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Identify the expression for acceleration from $F = ma$.
Identify the expression for acceleration from $F = ma$.
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$a = \frac{F}{m}$. Divide both sides of $F = ma$ by mass $m$.
$a = \frac{F}{m}$. Divide both sides of $F = ma$ by mass $m$.
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Calculate $a$: $F = 60 \text{ N}$, $m = 20 \text{ kg}$.
Calculate $a$: $F = 60 \text{ N}$, $m = 20 \text{ kg}$.
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$a = 3 \text{ m/s}^2$. Apply $a = F/m$: $60/20 = 3$ m/s².
$a = 3 \text{ m/s}^2$. Apply $a = F/m$: $60/20 = 3$ m/s².
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Calculate $F$: $m = 3 \text{ kg}$, $a = 4 \text{ m/s}^2$.
Calculate $F$: $m = 3 \text{ kg}$, $a = 4 \text{ m/s}^2$.
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$F = 12 \text{ N}$. Apply $F = ma$: $3 \times 4 = 12$ N.
$F = 12 \text{ N}$. Apply $F = ma$: $3 \times 4 = 12$ N.
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Determine the net force: $m = 6 \text{ kg}$, $a = 3 \text{ m/s}^2$.
Determine the net force: $m = 6 \text{ kg}$, $a = 3 \text{ m/s}^2$.
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$F = 18 \text{ N}$. Apply $F = ma$: $6 \times 3 = 18$ N.
$F = 18 \text{ N}$. Apply $F = ma$: $6 \times 3 = 18$ N.
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Determine $m$: $F = 40 \text{ N}$, $a = 8 \text{ m/s}^2$.
Determine $m$: $F = 40 \text{ N}$, $a = 8 \text{ m/s}^2$.
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$m = 5 \text{ kg}$. Use $m = F/a$: $40/8 = 5$ kg.
$m = 5 \text{ kg}$. Use $m = F/a$: $40/8 = 5$ kg.
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Describe the net force in a system at equilibrium.
Describe the net force in a system at equilibrium.
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The net force is zero. Equilibrium means no net force and no acceleration.
The net force is zero. Equilibrium means no net force and no acceleration.
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Find $a$: $F = 45 \text{ N}$, $m = 15 \text{ kg}$.
Find $a$: $F = 45 \text{ N}$, $m = 15 \text{ kg}$.
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$a = 3 \text{ m/s}^2$. Use $a = F/m$: $45/15 = 3$ m/s².
$a = 3 \text{ m/s}^2$. Use $a = F/m$: $45/15 = 3$ m/s².
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Identify the expression for mass from $F = ma$.
Identify the expression for mass from $F = ma$.
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$m = \frac{F}{a}$. Divide both sides of $F = ma$ by acceleration $a$.
$m = \frac{F}{a}$. Divide both sides of $F = ma$ by acceleration $a$.
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Identify the expression for force from $F = ma$.
Identify the expression for force from $F = ma$.
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$F = ma$. This is Newton's Second Law in its standard form.
$F = ma$. This is Newton's Second Law in its standard form.
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Calculate the force: $m = 5 \text{ kg}$, $a = 3 \text{ m/s}^2$.
Calculate the force: $m = 5 \text{ kg}$, $a = 3 \text{ m/s}^2$.
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$F = 15 \text{ N}$. Apply $F = ma$: $5 \times 3 = 15$ N.
$F = 15 \text{ N}$. Apply $F = ma$: $5 \times 3 = 15$ N.
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What is the acceleration if net force is zero?
What is the acceleration if net force is zero?
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Acceleration is zero. From $F = ma$, zero force produces zero acceleration.
Acceleration is zero. From $F = ma$, zero force produces zero acceleration.
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If $F = 24 \text{ N}$, $m = 8 \text{ kg}$, find $a$.
If $F = 24 \text{ N}$, $m = 8 \text{ kg}$, find $a$.
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$a = 3 \text{ m/s}^2$. Apply $a = F/m$: $24/8 = 3$ m/s².
$a = 3 \text{ m/s}^2$. Apply $a = F/m$: $24/8 = 3$ m/s².
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What is the effect on acceleration if force doubles and mass is constant?
What is the effect on acceleration if force doubles and mass is constant?
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Acceleration doubles. From $a = F/m$, doubling $F$ doubles $a$ when $m$ is constant.
Acceleration doubles. From $a = F/m$, doubling $F$ doubles $a$ when $m$ is constant.
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Find $m$: $F = 10 \text{ N}$, $a = 2 \text{ m/s}^2$.
Find $m$: $F = 10 \text{ N}$, $a = 2 \text{ m/s}^2$.
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$m = 5 \text{ kg}$. Rearrange to $m = F/a$: $10/2 = 5$ kg.
$m = 5 \text{ kg}$. Rearrange to $m = F/a$: $10/2 = 5$ kg.
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Explain the role of mass in Newton's Second Law.
Explain the role of mass in Newton's Second Law.
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Mass acts as a measure of an object's inertia. Greater mass means greater resistance to acceleration.
Mass acts as a measure of an object's inertia. Greater mass means greater resistance to acceleration.
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If $F = 20 \text{ N}$ and $m = 4 \text{ kg}$, find $a$.
If $F = 20 \text{ N}$ and $m = 4 \text{ kg}$, find $a$.
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$a = 5 \text{ m/s}^2$. Rearrange to $a = F/m$: $20/4 = 5$ m/s².
$a = 5 \text{ m/s}^2$. Rearrange to $a = F/m$: $20/4 = 5$ m/s².
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Calculate the force: $m = 5 \text{ kg}$, $a = 3 \text{ m/s}^2$.
Calculate the force: $m = 5 \text{ kg}$, $a = 3 \text{ m/s}^2$.
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$F = 15 \text{ N}$. Apply $F = ma$: $5 \times 3 = 15$ N.
$F = 15 \text{ N}$. Apply $F = ma$: $5 \times 3 = 15$ N.
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Identify the unit of force in the International System of Units (SI).
Identify the unit of force in the International System of Units (SI).
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The unit of force is the newton (N). One newton equals one kilogram-meter per second squared.
The unit of force is the newton (N). One newton equals one kilogram-meter per second squared.
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What does $a$ signify in the equation $F = ma$?
What does $a$ signify in the equation $F = ma$?
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$a$ signifies the acceleration of the object. Acceleration is the rate of change of velocity.
$a$ signifies the acceleration of the object. Acceleration is the rate of change of velocity.
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Find $a$: $F = 25 \text{ N}$, $m = 5 \text{ kg}$.
Find $a$: $F = 25 \text{ N}$, $m = 5 \text{ kg}$.
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$a = 5 \text{ m/s}^2$. Use $a = F/m$: $25/5 = 5$ m/s².
$a = 5 \text{ m/s}^2$. Use $a = F/m$: $25/5 = 5$ m/s².
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State Newton's Second Law of Motion.
State Newton's Second Law of Motion.
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The net force equals mass times acceleration, $F = ma$. This is the fundamental equation relating force, mass, and acceleration.
The net force equals mass times acceleration, $F = ma$. This is the fundamental equation relating force, mass, and acceleration.
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What does $F$ represent in the equation $F = ma$?
What does $F$ represent in the equation $F = ma$?
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$F$ represents the net force acting on an object. The net or total force causes acceleration in the object.
$F$ represents the net force acting on an object. The net or total force causes acceleration in the object.
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