Understanding Magnetic Fields and Charges - AP Physics C: Electricity and Magnetism
Card 1 of 55
A proton traveling 
enters a uniform magnetic field and experiences a magnetic force, causing it to travel in a circular path. Taking the magnetic field to be 
, what is the radius of this circular path (shown in red)?
A proton traveling
Tap to reveal answer
To calculate the magnetic force of a single charge, we use 
, where 
is the charge of the proton, 
is its velocity, 
is the uniform magnetic field.
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
is the mass of the proton and 
is the radius of the circular path. Solve for 
.
Using the values given in the question, we can solve for the radius.
To calculate the magnetic force of a single charge, we use
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
Using the values given in the question, we can solve for the radius.
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Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Tap to reveal answer
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
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A particle of charge 
and mass 
moves with a speed of 
perpendicular to a uniform magnetic field, 
. What is the period of the particle's orbit in the field?
A particle of charge
Tap to reveal answer
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance, 
, traveled in one revolution, which is the circumference of a circle of radius 
:
Plug this distance and velocity into 
, to solve for the period 
:
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance,
Plug this distance and velocity into
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Consider a current-carrying loop with current 
, radius 
, and center 
.
A particle with charge 
flies through the center and into the page with velocity 
. What is the total electromagnetic force on the particle at the instant that it flies through the loop, in terms of the variables given?
Consider a current-carrying loop with current
A particle with charge
Tap to reveal answer
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
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Consider two long, straight, current-carrying wires at distance 
from each other, each with a current of magnitude 
going in opposite directions.
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Consider two long, straight, current-carrying wires at distance
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Tap to reveal answer
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
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A proton traveling enters a uniform magnetic field and experiences a magnetic force, causing it to travel in a circular path. Taking the magnetic field to be , what is the radius of this circular path (shown in red)?
A proton traveling
Tap to reveal answer
To calculate the magnetic force of a single charge, we use , where is the charge of the proton, is its velocity, is the uniform magnetic field.
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
is the mass of the proton and is the radius of the circular path. Solve for .
Using the values given in the question, we can solve for the radius.
To calculate the magnetic force of a single charge, we use
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
Using the values given in the question, we can solve for the radius.
← Didn't Know|Knew It →
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Tap to reveal answer
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
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A particle of charge and mass moves with a speed of perpendicular to a uniform magnetic field, . What is the period of the particle's orbit in the field?
A particle of charge
Tap to reveal answer
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance, , traveled in one revolution, which is the circumference of a circle of radius :
Plug this distance and velocity into , to solve for the period :
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance,
Plug this distance and velocity into
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Consider a current-carrying loop with current , radius , and center .
A particle with charge flies through the center and into the page with velocity . What is the total electromagnetic force on the particle at the instant that it flies through the loop, in terms of the variables given?
Consider a current-carrying loop with current
A particle with charge
Tap to reveal answer
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
← Didn't Know|Knew It →
Consider two long, straight, current-carrying wires at distance from each other, each with a current of magnitude going in opposite directions.
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Consider two long, straight, current-carrying wires at distance
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Tap to reveal answer
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
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A proton traveling enters a uniform magnetic field and experiences a magnetic force, causing it to travel in a circular path. Taking the magnetic field to be , what is the radius of this circular path (shown in red)?
A proton traveling
Tap to reveal answer
To calculate the magnetic force of a single charge, we use , where is the charge of the proton, is its velocity, is the uniform magnetic field.
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
is the mass of the proton and is the radius of the circular path. Solve for .
Using the values given in the question, we can solve for the radius.
To calculate the magnetic force of a single charge, we use
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
Using the values given in the question, we can solve for the radius.
← Didn't Know|Knew It →
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Tap to reveal answer
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
← Didn't Know|Knew It →
A particle of charge and mass moves with a speed of perpendicular to a uniform magnetic field, . What is the period of the particle's orbit in the field?
A particle of charge
Tap to reveal answer
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance, , traveled in one revolution, which is the circumference of a circle of radius :
Plug this distance and velocity into , to solve for the period :
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance,
Plug this distance and velocity into
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Consider a current-carrying loop with current , radius , and center .
A particle with charge flies through the center and into the page with velocity . What is the total electromagnetic force on the particle at the instant that it flies through the loop, in terms of the variables given?
Consider a current-carrying loop with current
A particle with charge
Tap to reveal answer
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
← Didn't Know|Knew It →
Consider two long, straight, current-carrying wires at distance from each other, each with a current of magnitude going in opposite directions.
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Consider two long, straight, current-carrying wires at distance
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Tap to reveal answer
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
← Didn't Know|Knew It →
A proton traveling enters a uniform magnetic field and experiences a magnetic force, causing it to travel in a circular path. Taking the magnetic field to be , what is the radius of this circular path (shown in red)?
A proton traveling
Tap to reveal answer
To calculate the magnetic force of a single charge, we use , where is the charge of the proton, is its velocity, is the uniform magnetic field.
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
is the mass of the proton and is the radius of the circular path. Solve for .
Using the values given in the question, we can solve for the radius.
To calculate the magnetic force of a single charge, we use
Since this magnetic force causes the proton to travel in a circular path, we set this magnetic force equation equal to the centripetal force equation.
Using the values given in the question, we can solve for the radius.
← Didn't Know|Knew It →
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Which of the following best describes the net magnetic flux through a closed sphere, in the presence of a magnet?
Tap to reveal answer
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
The net magnetic flux (or net field flowing in and out) through any closed surface must always be zero. This is because magnetic field lines have no starting or ending points, so any field line going into the surface must also come out. In other words, "there are no magnetic monopoles."
← Didn't Know|Knew It →
A particle of charge and mass moves with a speed of perpendicular to a uniform magnetic field, . What is the period of the particle's orbit in the field?
A particle of charge
Tap to reveal answer
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance, , traveled in one revolution, which is the circumference of a circle of radius :
Plug this distance and velocity into , to solve for the period :
Relevant equations:
Set the magnetic force equal to the centripetal force, since the magnetic force is directed towards the center of the particle's circular path and centripetal force is defined as the net force towards the center of a circular path.
Rearrange to isolate the velocity:
Determine the distance,
Plug this distance and velocity into
← Didn't Know|Knew It →
Consider a current-carrying loop with current , radius , and center .
A particle with charge flies through the center and into the page with velocity . What is the total electromagnetic force on the particle at the instant that it flies through the loop, in terms of the variables given?
Consider a current-carrying loop with current
A particle with charge
Tap to reveal answer
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
The correct answer is zero. To calculate the force of a magnetic field on a moving charged particle, we use the cross product. We know that if the magnetic field is parallel to the velocity vector of the particle, then the force produced is zero.
Because our magnetic field in this case is going in the same direction as the velocity of the particle, we know that the magnetic force on the particle is zero.
← Didn't Know|Knew It →
Consider two long, straight, current-carrying wires at distance from each other, each with a current of magnitude going in opposite directions.
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Consider two long, straight, current-carrying wires at distance
If the two wires described are not held in place, what motion will result from the magnetic fields produced?
Tap to reveal answer
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
The answer is that the wires will move from each other. Using our right hand rule, we know that the magnetic fields produced by each wire are in the same direction, as long as their currents oppose. Using the right hand rule again to determine the direction of the force exerted on each wire by the magnetic field with which they are interacting yields a force in the direction away from the other wire for each wire.
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