Momentum and Impulse - AP Physics C: Electricity and Magnetism

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Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

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Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

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Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

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Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

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Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

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Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

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Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

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Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

← Didn't Know|Knew It →

Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

← Didn't Know|Knew It →

Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

← Didn't Know|Knew It →

Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

← Didn't Know|Knew It →

Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

← Didn't Know|Knew It →

Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

← Didn't Know|Knew It →

Question

A baseball player hits a $\small 150g$ baseball initially moving at $\small 35$\frac{m}{s}$$ , returning it at a speed of $\small 45$\frac{m}{s}$$ along the same path. If the ball was in contact with the bat for $\small 1ms$ , what magnitude of force did the ball experience during the moment of contact?

Tap to reveal answer

Answer

Relevant equations:

$J = m\Delta v$

$J = $F_{avg}$\Delta t$

Evaluate the impulse based on the mass and change of velocity.

$J = m\Delta v = (0.150kg)(80$\frac{m}{s}$)=12 $\frac{kg*m}{s}$$

Use the total impulse and time in the second equation.

$m\Delta v = $F_{avg}$\Delta t$

Solve for the average force.

← Didn't Know|Knew It →

Question

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Tap to reveal answer

Answer

To calculate the impulse, know that it is equal to the change in momentum.

$\textbf{J}=\Delta\textbf{p}=\textbf{p}_f-\textbf{p}_i$

Write the impulse equation in terms of mass and velocity.

$\textbf{J}=m\textbf{v}_f-m\textbf{v}_i$

In our case, the initial velocity of the baseball is $\textbf{v}_i=40\ $\text{m/s}$$ and its final velocity is $\textbf{v}_f=-45\ $\text{m/s}$$ , where the negative sign indicates that the ball is traveling in the opposite direction. Also, m = 0.15kg. The impulse on the ball can be calculated below.

$\textbf{J}=(0.15\ $\text{kg}$)(-45\ $\text{m/s}$)-(0.15\ $\text{kg}$)(40\ $\text{m/s}$)=-12.75{N\cdot s}$

The negative sign tells that the force on the baseball is opposed to the original momentum.

← Didn't Know|Knew It →

Question

Which of the following could be used as units of impulse?

Tap to reveal answer

Answer

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

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Momentum and Impulse - AP Physics C: Electricity and Magnetism

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A baseball player hits a baseball initially moving at , returning it at a speed of along the same path. If the ball was in contact with the bat for , what magnitude of force did the ball experience during the moment of contact?

Relevant equations: Evaluate the impulse based on the mass and change of velocity. Use the total impulse and time in the second equation. Solve for the average force.

A pitcher throws a 0.15kg baseball at towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of . Calculate the impulse experienced by the baseball.

Which of the following could be used as units of impulse?

Relevant equations: Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$

A pitcher throws a 0.15kg baseball at $40$\frac{m}{s}$$ towards the batter and the batter hits the ball with his bat. The ball leaves the bat in the opposite direction at a speed of $45$\frac{m}{s}$$ . Calculate the impulse experienced by the baseball.

Relevant equations:

$J = \Delta p = m\Delta v$

$J = F \Delta t$

Impulse is defined as change in momentum, so has the same units as momentum. These units can easily be found using the given equations.

$J=m\Delta v=(kg)($\frac{m}{s}$)=\frac{kgm}{s}$$

$J=F\Delta t=(N)(s)=Ns$