This question tests understanding of specific heat and thermal conductivity. When equal masses of different materials absorb the same amount of thermal energy Q, their temperature changes are inversely proportional to their specific heats: ΔT = Q/(mc). Water has a much higher specific heat (4186 J/kg·K) than cooking oil (approximately 2000 J/kg·K), so water's temperature will increase less. Thermal conductivity affects how quickly the heat distributes within each liquid but not the final average temperature. Choice C incorrectly states that smaller specific heat leads to smaller temperature change, revealing the misconception of confusing the inverse relationship in the heat capacity equation. Remember: higher specific heat means smaller temperature change for the same energy input.

This question tests understanding of specific heat and thermal conductivity. Wrapping a rod with foam insulation reduces heat loss to the surrounding air by creating a barrier with low thermal conductivity. This doesn't change the rod's intrinsic properties (specific heat, thermal conductivity, or mass) but reduces the rate of heat transfer from the rod's surface to the air. The foam acts as thermal resistance in the heat flow path. Choice A incorrectly suggests the rod's specific heat changes, but material properties don't change with insulation. The key principle: insulation reduces heat transfer rate without changing material properties.

This question tests understanding of specific heat and thermal conductivity. In steady-state heat conduction through a slab, the heat transfer rate depends on thermal conductivity according to Q/t = kA(ΔT)/L. Glass has much higher thermal conductivity than foam (glass ~1 W/m·K, foam ~0.03 W/m·K), so glass allows a much greater heat transfer rate. Specific heat only affects how long the materials take to reach steady state, not the steady-state heat flow. Choice A incorrectly attributes heat transfer rate to specific heat, revealing the misconception that heat capacity affects conduction rate rather than just temperature change. For steady heat flow problems, thermal conductivity is the key property, not specific heat.

This question tests understanding of specific heat and thermal conductivity. Thermal conductivity k determines the rate of heat transfer through a material according to Fourier's law: heat current = kA(ΔT)/L. Specific heat affects how much a material's temperature changes when absorbing energy, but does not directly determine the rate of heat flow through the material. Since rods A and B have identical geometry and experience the same temperature difference initially, the rod with higher thermal conductivity (rod A) will transfer heat faster. Choice C incorrectly claims that specific heat increases heat transfer rate, confusing the role of specific heat with thermal conductivity. To determine heat transfer rates through materials, use thermal conductivity; specific heat only affects temperature changes.

This question tests understanding of specific heat and thermal conductivity. Specific heat c determines the temperature change when a material absorbs thermal energy: Q = mcΔT, which rearranges to ΔT = Q/(mc). Thermal conductivity is irrelevant here since we're not considering heat flow through the blocks, only their temperature change from absorbed energy. With equal masses and equal heat absorbed (600 J), the block with higher specific heat will have a smaller temperature increase. Block P has c = 900 J/(kg·K) while block Q has c = 450 J/(kg·K), so block P experiences half the temperature rise of block Q and ends cooler. Choice A incorrectly claims lower specific heat leads to smaller temperature increase, reversing the relationship. Remember: higher specific heat means smaller temperature change for the same heat absorbed.

This question tests understanding of specific heat and thermal conductivity. Specific heat determines how much thermal energy a material releases per degree of temperature change, while thermal conductivity affects how quickly thermal equilibrium is reached. When the hot spheres cool from 80°C to final temperature T_f, sphere P releases Q_P = mc_P(80-T_f) and sphere Q releases Q_Q = mc_Q(80-T_f). Since c_Q = 900 J/(kg·K) is three times c_P = 300 J/(kg·K), sphere Q releases three times more energy for the same temperature drop. This greater energy release causes the water to heat up more when sphere Q is added. Choice C incorrectly focuses on conductivity, which only affects how quickly equilibrium is reached, not the final equilibrium temperature. Remember: specific heat affects temperature change; conductivity affects transfer rate.

This question tests understanding of specific heat and thermal conductivity. Thermal conductivity determines the rate of steady-state heat flow through a material under a temperature gradient, while specific heat affects temperature changes during transient processes. For steady heat flow through a slab, the heat current is P = kA(ΔT)/L, where k is thermal conductivity. Since both slabs have the same area, thickness, and temperature difference, the heat current is directly proportional to thermal conductivity. The insulation, with much smaller thermal conductivity than glass, has a much smaller heat current flowing through it. Choice C incorrectly suggests specific heat matters for steady heat flow, but specific heat only affects how materials respond to energy changes, not steady-state conduction. Remember: specific heat affects temperature change; conductivity affects transfer rate.

This question tests understanding of specific heat and thermal conductivity. The temperature change when absorbing heat is given by Q = mcΔT, which rearranges to ΔT = Q/(mc). Since both spheres are made of the same material, they have identical specific heat c and thermal conductivity k. With sphere B having twice the mass of sphere A (mB = 2mA) and both absorbing the same heat Q, sphere B's temperature change is ΔTB = Q/(2mA·c) while sphere A's is ΔTA = Q/(mA·c). Therefore, sphere B has half the temperature change of sphere A. Choice D incorrectly claims thermal conductivity determines temperature change for heat absorption, confusing it with specific heat's role. For temperature changes from heat absorption, use Q = mcΔT; conductivity only affects heat flow rates.

This question tests understanding of specific heat and thermal conductivity. When a fixed amount of heat is lost, the temperature change is determined by Q = mcΔT, giving ΔT = Q/(mc). Thermal conductivity would affect the rate of heat loss but not the temperature change for a given amount of heat already lost. Since both liquids have the same mass (0.20 kg) and lose the same heat (400 J), the liquid with larger specific heat will experience a smaller temperature drop. Liquid R, with larger specific heat, cools less than liquid S. Choice A incorrectly claims smaller specific heat leads to smaller temperature change, reversing the correct relationship. For fixed heat transfer, remember: larger specific heat means smaller temperature change.

This question tests understanding of specific heat and thermal conductivity. In steady-state heat conduction through materials in series, the heat current must be the same through both sections. From Fourier's law, heat current = kA(dT/dx), where dT/dx is the temperature gradient. Since the heat current and area A are the same for both sections, the temperature gradient is inversely proportional to thermal conductivity: lower k requires larger gradient. Section Y, with lower thermal conductivity than section X, must have a larger temperature gradient to maintain the same heat flow. Choice A incorrectly claims higher conductivity requires larger gradient, reversing the inverse relationship. In series thermal conduction, remember: lower conductivity means steeper temperature gradient for the same heat flow.