AP Physics 2 - Optics | Practice Hub

Light travels from air to diamond . If the angle of incidence is $75^\circ$ , determine the angle of refraction.

$23.5^\circ$

None of these

$47.5^\circ$

$56.0^\circ$

$18.9^\circ$

Explanation

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Using the following version of Snell's law and solving for the angle of refraction:

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

$sin^{-1}(\frac{n_1 sin\theta_1^\circ}{n_2})=\theta_2$

Plugging in values:

$sin^{-1}(\frac{1*sin75^\circ}{2.42})=\theta_2$

$23.5^\circ=\theta_2$

Light travels from air to diamond . If the angle of incidence is $75^\circ$ , determine the angle of refraction.

$23.5^\circ$

None of these

$47.5^\circ$

$56.0^\circ$

$18.9^\circ$

Explanation

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Using the following version of Snell's law and solving for the angle of refraction:

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

$sin^{-1}(\frac{n_1 sin\theta_1^\circ}{n_2})=\theta_2$

Plugging in values:

$sin^{-1}(\frac{1*sin75^\circ}{2.42})=\theta_2$

$23.5^\circ=\theta_2$

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $29^\circ$ . The angle of refraction is $10^\circ$ . What is the index of refraction of the unknown material?

None of these

Explanation

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Using the following version of Snell's law and solving for :

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

$n_1\frac{sin\theta_1}{sin\theta_2}=n_2$

Plugging in values

$1*\frac{sin29^\circ}{sin10^\circ}=n_2$

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $29^\circ$ . The angle of refraction is $10^\circ$ . What is the index of refraction of the unknown material?

None of these

Explanation

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Using the following version of Snell's law and solving for :

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

$n_1\frac{sin\theta_1}{sin\theta_2}=n_2$

Plugging in values

$1*\frac{sin29^\circ}{sin10^\circ}=n_2$

Light of wavelength goes from vacuum to an unknown liquid with an angle of incidence of $33^\circ$ and has an angle of diffraction of $15^\circ$ . Determine the index of refraction in the unknown liquid.

None of these

Explanation

Using Snell's law:

$\frac{n_1}{n_2}=\frac{v_2}{v_1}=\frac{sin\theta_2}{sin\theta_1}=\frac{\lambda_2}{\lambda_1}$

$\frac{1}{n_2}=\frac{sin15^\circ}{sin33^\circ}$

None of these

Explanation

Using Snell's law:

$\frac{n_1}{n_2}=\frac{v_2}{v_1}=\frac{sin\theta_2}{sin\theta_1}=\frac{\lambda_2}{\lambda_1}$

$\frac{1}{n_2}=\frac{sin15^\circ}{sin33^\circ}$

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $77^\circ$ . The angle of refraction is $68^\circ$ . What is the index of refraction of the unknown material?

Explanation

Snell's Law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{v_1}{v_2}=\frac{\lambda_1}{\lambda_2}=\frac{n_2}{n_1}$

Where

$\theta$ is the respective incident angle

is the respective velocity of the light

$\lambda$ is the respective wavelength

is the respective index of refraction

Snells law for varsity fixed

Use the following version of Snell's law:

$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$

Solving for

$n_1\frac{sin\theta_1}{sin\theta_2}=n_2$

Plugging in values

$1*\frac{sin77^\circ}{sin68^\circ}=n_2$

Light in a vacuum hits the surface of an unknown material with an angle of incidence of $77^\circ$ . The angle of refraction is $68^\circ$ . What is the index of refraction of the unknown material?