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  1. Subjects ›
  2. AP Physics 1 ›
  3. Question of the Day

AP Physics 1 Question of the Day

AP Physics 1 Question of the Day

Answer today's AP Physics 1 question, reveal the full explanation, then keep the streak going with a new question every day.

A wheel starts with ω0=3 rad/s\omega_0=3\,\text{rad/s}ω0​=3rad/s and has constant α=2 rad/s2\alpha=2\,\text{rad/s}^2α=2rad/s2 for 2 s2\,\text{s}2s. Find Δθ\Delta\thetaΔθ.

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Question of the Day

A wheel starts with ω0=3 rad/s\omega_0=3\,\text{rad/s}ω0​=3rad/s and has constant α=2 rad/s2\alpha=2\,\text{rad/s}^2α=2rad/s2 for 2 s2\,\text{s}2s. Find Δθ\Delta\thetaΔθ.

  1. 10 rad10\,\text{rad}10rad (correct answer)
  2. 7 rad/s7\,\text{rad/s}7rad/s
  3. 14 rad14\,\text{rad}14rad
  4. 4 rad/s24\,\text{rad/s}^24rad/s2

Explanation: This problem involves calculating angular displacement with constant acceleration. Using the kinematic equation Δθ = ω₀t + ½αt², with ω₀ = 3 rad/s, α = 2 rad/s², and t = 2 s, we get Δθ = 3(2) + ½(2)(2²) = 6 + ½(2)(4) = 6 + 4 = 10 rad. The first term (6 rad) represents displacement due to initial velocity, while the second term (4 rad) is the additional displacement from acceleration. Choice B (7 rad/s) confuses final velocity with displacement, while choice C (14 rad) might come from incorrect calculation. For constant acceleration problems, use the complete kinematic equation including both velocity and acceleration terms.