AP Physics 1 Flashcards: Translational Kinetic Energy

What this deck covers

This deck focuses on Translational Kinetic Energy, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What does $m$ represent in the translational kinetic energy formula?

Answer: Mass of the object. Mass is the scalar quantity representing the amount of matter in the object.

Flashcard 2: Determine the kinetic energy if mass is 10 kg and velocity is 0.

Answer: $KE = 0 \text{ J}$. Any object at rest has zero kinetic energy.

Flashcard 3: What is the kinetic energy formula rearranged for velocity?

Answer: $v = \sqrt{\frac{2KE}{m}}$. Solve $KE = \frac{1}{2}mv^2$ for $v$ by isolating the velocity term.

Flashcard 4: If kinetic energy is 200 J and velocity is 4 m/s, find the mass.

Answer: $m = 25 \text{ kg}$. $200 = \frac{1}{2}m(4^2)$, so $m = \frac{2(200)}{16} = 25$ kg.

Flashcard 5: A car increases speed from 10 m/s to 20 m/s. By what factor does its kinetic energy increase?

Answer: Increases by a factor of 4. Velocity doubles, so $KE$ increases by $(2)^2 = 4$ times.

Flashcard 6: If velocity is doubled, how does kinetic energy change?

Answer: Increases by a factor of 4. Since $v^2$ appears in the formula, doubling $v$ increases $KE$ by $2^2 = 4$.

Flashcard 7: Find kinetic energy: mass = 0.5 kg, velocity = 10 m/s.

Answer: $KE = 25 \text{ J}$. $KE = \frac{1}{2}(0.5)(10^2) = \frac{1}{2}(0.5)(100) = 25$ J.

Flashcard 8: State the relationship between kinetic energy and velocity.

Answer: Proportional to the square of velocity. The $v^2$ term creates a quadratic relationship with velocity.

Flashcard 9: What are the SI units of translational kinetic energy?

Answer: Joules (J). Energy units derived from $kg \cdot m^2/s^2$ in the SI system.

Flashcard 10: Convert 1 Joule into base SI units.

Answer: $1 \text{ J} = 1 \text{ kg} \times \text{m}^2/\text{s}^2$. Breaking down the joule into fundamental SI base units.

Flashcard 11: Calculate the mass of an object with 50 J of kinetic energy moving at 5 m/s.

Answer: $m = 4 \text{ kg}$. $50 = \frac{1}{2}m(5^2)$, so $m = \frac{2(50)}{25} = 4$ kg.

Flashcard 12: If mass is tripled and velocity is constant, how does $KE$ change?

Answer: Triples. Kinetic energy scales linearly with mass when velocity is constant.

Flashcard 13: A 1 kg object moves at 3 m/s. Find its kinetic energy.

Answer: $KE = 4.5 \text{ J}$. $KE = \frac{1}{2}(1)(3^2) = \frac{1}{2}(1)(9) = 4.5$ J.

Flashcard 14: What is the kinetic energy formula rearranged for velocity?

Answer: $v = \text{sqrt}(\frac{2KE}{m})$. Solve $KE = \frac{1}{2}mv^2$ for $v$ by isolating the velocity term.

Flashcard 15: Calculate velocity: kinetic energy = 18 J, mass = 2 kg.

Answer: $v = 3 \text{ m/s}$. $18 = \frac{1}{2}(2)v^2$, so $v = \sqrt{\frac{36}{2}} = 3$ m/s.

Flashcard 16: A car increases speed from 10 m/s to 20 m/s. By what factor does its kinetic energy increase?

Answer: Increases by a factor of 4. Velocity doubles, so $KE$ increases by $(2)^2 = 4$ times.

Flashcard 17: Convert 100 J to kilojoules (kJ).

Answer: $0.1 \text{ kJ}$. Divide by 1000 to convert joules to kilojoules.

Flashcard 18: A 0.5 kg object has 8 J of kinetic energy. What is its velocity?

Answer: $v = 4 \text{ m/s}$. $8 = \frac{1}{2}(0.5)v^2$, so $v = \sqrt{\frac{16}{0.5}} = 4$ m/s.

Flashcard 19: What factor affects translational kinetic energy the most?

Answer: Velocity, as $v$ is squared. The squared term makes velocity changes more impactful than mass changes.

Flashcard 20: What is the formula to find mass from kinetic energy and velocity?

Answer: $m = \frac{2KE}{v^2}$. Rearrange $KE = \frac{1}{2}mv^2$ to solve for mass.

Flashcard 21: Calculate the kinetic energy: mass = 4 kg, velocity = 5 m/s.

Answer: $KE = 50 \text{ J}$. $KE = \frac{1}{2}(4)(5^2) = \frac{1}{2}(4)(25) = 50$ J.

Flashcard 22: What is the kinetic energy of a 3 kg object moving at 2 m/s?

Answer: $KE = 6 \text{ J}$. $KE = \frac{1}{2}(3)(2^2) = \frac{1}{2}(3)(4) = 6$ J.

Flashcard 23: If mass is halved, how does kinetic energy change?

Answer: Halved. Kinetic energy is directly proportional to mass.

Flashcard 24: What is the kinetic energy of a 5 kg object at rest?

Answer: $KE = 0 \text{ J}$. Zero velocity means zero kinetic energy regardless of mass.

Flashcard 25: Calculate the kinetic energy: mass = 4 kg, velocity = 5 m/s.

Answer: $KE = 50 \text{ J}$. $KE = \frac{1}{2}(4)(5^2) = \frac{1}{2}(4)(25) = 50$ J.

Flashcard 26: A 3 kg object has 27 J of kinetic energy. Find its velocity.

Answer: $v = 3 \text{ m/s}$. $27 = \frac{1}{2}(3)v^2$, so $v = \sqrt{\frac{54}{3}} = 3$ m/s.

Flashcard 27: If kinetic energy is 200 J and velocity is 4 m/s, find the mass.

Answer: $m = 25 \text{ kg}$. $200 = \frac{1}{2}m(4^2)$, so $m = \frac{2(200)}{16} = 25$ kg.

Flashcard 28: Determine the kinetic energy if mass is 10 kg and velocity is 0.

Answer: $KE = 0 \text{ J}$. Any object at rest has zero kinetic energy.

Flashcard 29: Determine the kinetic energy change if velocity triples.

Answer: Increases by a factor of 9. Tripling velocity increases $KE$ by $(3)^2 = 9$ times.

Flashcard 30: If kinetic energy is 64 J and mass is 4 kg, what is the velocity?

Answer: $v = 4 \text{ m/s}$. $64 = \frac{1}{2}(4)v^2$, so $v = \sqrt{\frac{128}{4}} = 4$ m/s.

Flashcard 31: Identify the SI unit for mass used in the kinetic energy formula.

Answer: Kilogram (kg). Standard SI base unit for measuring the amount of matter.

Flashcard 32: Find kinetic energy: mass = 0.5 kg, velocity = 10 m/s.

Answer: $KE = 25 \text{ J}$. $KE = \frac{1}{2}(0.5)(10^2) = \frac{1}{2}(0.5)(100) = 25$ J.

Flashcard 33: If velocity remains constant, how does kinetic energy change as mass increases?

Answer: Increases linearly. Direct proportional relationship when velocity remains constant.

Flashcard 34: What factor affects translational kinetic energy the most?

Answer: Velocity, as $v$ is squared. The squared term makes velocity changes more impactful than mass changes.

Flashcard 35: A 10 kg object moves at 0 m/s. What is its kinetic energy?

Answer: $KE = 0 \text{ J}$. Zero velocity means zero kinetic energy regardless of mass.

Flashcard 36: Convert 100 J to kilojoules (kJ).

Answer: $0.1 \text{ kJ}$. Divide by 1000 to convert joules to kilojoules.

Flashcard 37: What is the kinetic energy of a 3 kg object moving at 2 m/s?

Answer: $KE = 6 \text{ J}$. $KE = \frac{1}{2}(3)(2^2) = \frac{1}{2}(3)(4) = 6$ J.

Flashcard 38: What are the SI units of translational kinetic energy?

Answer: Joules (J). Energy units derived from $kg \cdot m^2/s^2$ in the SI system.

Flashcard 39: If velocity remains constant, how does kinetic energy change as mass increases?

Answer: Increases linearly. Direct proportional relationship when velocity remains constant.

Flashcard 40: If kinetic energy is 64 J and mass is 4 kg, what is the velocity?

Answer: $v = 4 \text{ m/s}$. $64 = \frac{1}{2}(4)v^2$, so $v = \sqrt{\frac{128}{4}} = 4$ m/s.

Flashcard 41: Identify the SI unit for velocity in the kinetic energy formula.

Answer: Meters per second (m/s). SI derived unit combining distance per unit time.

Flashcard 42: A 10 kg object moves at 0 m/s. What is its kinetic energy?

Answer: $KE = 0 \text{ J}$. Zero velocity means zero kinetic energy regardless of mass.

Flashcard 43: State the relationship between kinetic energy and mass.

Answer: Directly proportional. Doubling mass doubles kinetic energy when velocity is constant.

Flashcard 44: Calculate the kinetic energy of a 2 kg object moving at 3 m/s.

Answer: $KE = 9 \text{ J}$. $KE = \frac{1}{2}(2)(3^2) = \frac{1}{2}(2)(9) = 9$ J.

Flashcard 45: How is translational kinetic energy related to work done?

Answer: Equal to work done to bring object to current speed. Work-energy theorem states work done equals change in kinetic energy.

Flashcard 46: What is the kinetic energy of a 2 kg object moving at 0 m/s?

Answer: $KE = 0 \text{ J}$. Zero velocity results in zero kinetic energy.

Flashcard 47: Convert 1 Joule into base SI units.

Answer: $1 \text{ J} = 1 \text{ kg} \times \text{m}^2/\text{s}^2$. Breaking down the joule into fundamental SI base units.

Flashcard 48: State the relationship between kinetic energy and velocity.

Answer: Proportional to the square of velocity. The $v^2$ term creates a quadratic relationship with velocity.

Flashcard 49: A 0.5 kg object has 8 J of kinetic energy. What is its velocity?

Answer: $v = 4 \text{ m/s}$. $8 = \frac{1}{2}(0.5)v^2$, so $v = \sqrt{\frac{16}{0.5}} = 4$ m/s.

Flashcard 50: What happens to kinetic energy if both mass and velocity are doubled?

Answer: Increases by a factor of 8. Mass doubles ($\times 2$) and velocity squared doubles ($\times 4$): $2 \times 4 = 8$.

Flashcard 51: A 3 kg object has 27 J of kinetic energy. Find its velocity.

Answer: $v = 3 \text{ m/s}$. $27 = \frac{1}{2}(3)v^2$, so $v = \sqrt{\frac{54}{3}} = 3$ m/s.

Flashcard 52: What does $m$ represent in the translational kinetic energy formula?

Answer: Mass of the object. Mass is the scalar quantity representing the amount of matter in the object.

Flashcard 53: What does $v$ represent in the translational kinetic energy formula?

Answer: Velocity of the object. Velocity is the vector quantity representing the object's speed and direction.

Flashcard 54: State the formula for translational kinetic energy.

Answer: $KE = \frac{1}{2}mv^2$. Fundamental formula where kinetic energy equals half the product of mass and velocity squared.

Flashcard 55: What happens to kinetic energy if both mass and velocity are doubled?

Answer: Increases by a factor of 8. Mass doubles ($\times 2$) and velocity squared doubles ($\times 4$): $2 \times 4 = 8$.

Flashcard 56: Calculate velocity: kinetic energy = 18 J, mass = 2 kg.

Answer: $v = 3 \text{ m/s}$. $18 = \frac{1}{2}(2)v^2$, so $v = \sqrt{\frac{36}{2}} = 3$ m/s.

Flashcard 57: How is translational kinetic energy related to work done?

Answer: Equal to work done to bring object to current speed. Work-energy theorem states work done equals change in kinetic energy.

Flashcard 58: A 6 kg object moving at 2 m/s. Calculate its kinetic energy.

Answer: $KE = 12 \text{ J}$. $KE = \frac{1}{2}(6)(2^2) = \frac{1}{2}(6)(4) = 12$ J.

Flashcard 59: If mass is tripled and velocity is constant, how does $KE$ change?

Answer: Triples. Kinetic energy scales linearly with mass when velocity is constant.

Flashcard 60: Calculate the mass of an object with 50 J of kinetic energy moving at 5 m/s.

Answer: $m = 4 \text{ kg}$. $50 = \frac{1}{2}m(5^2)$, so $m = \frac{2(50)}{25} = 4$ kg.

Flashcard 61: Identify the SI unit for mass used in the kinetic energy formula.

Answer: Kilogram (kg). Standard SI base unit for measuring the amount of matter.

Flashcard 62: Determine the kinetic energy change if velocity triples.

Answer: Increases by a factor of 9. Tripling velocity increases $KE$ by $(3)^2 = 9$ times.