AP Physics 1 Flashcards: Translational Kinetic Energy

What this deck covers

This deck focuses on Translational Kinetic Energy, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What is the kinetic energy of a 2 kg object moving at 0 m/s?

Answer: $KE = 0 \text{ J}$. Zero velocity results in zero kinetic energy.

Flashcard 2: What happens to kinetic energy if both mass and velocity are doubled?

Answer: Increases by a factor of 8. Mass doubles ($\times 2$) and velocity squared doubles ($\times 4$): $2 \times 4 = 8$.

Flashcard 3: State the relationship between kinetic energy and mass.

Answer: Directly proportional. Doubling mass doubles kinetic energy when velocity is constant.

Flashcard 4: If kinetic energy is 200 J and velocity is 4 m/s, find the mass.

Answer: $m = 25 \text{ kg}$. $200 = \frac{1}{2}m(4^2)$, so $m = \frac{2(200)}{16} = 25$ kg.

Flashcard 5: State the formula for translational kinetic energy.

Answer: $KE = \frac{1}{2}mv^2$. Fundamental formula where kinetic energy equals half the product of mass and velocity squared.

Flashcard 6: What is the kinetic energy formula rearranged for velocity?

Answer: $v = \text{sqrt}(\frac{2KE}{m})$. Solve $KE = \frac{1}{2}mv^2$ for $v$ by isolating the velocity term.

Flashcard 7: Find kinetic energy: mass = 0.5 kg, velocity = 10 m/s.

Answer: $KE = 25 \text{ J}$. $KE = \frac{1}{2}(0.5)(10^2) = \frac{1}{2}(0.5)(100) = 25$ J.

Flashcard 8: What does $v$ represent in the translational kinetic energy formula?

Answer: Velocity of the object. Velocity is the vector quantity representing the object's speed and direction.

Flashcard 9: If mass is tripled and velocity is constant, how does $KE$ change?

Answer: Triples. Kinetic energy scales linearly with mass when velocity is constant.

Flashcard 10: If velocity remains constant, how does kinetic energy change as mass increases?

Answer: Increases linearly. Direct proportional relationship when velocity remains constant.

Flashcard 11: If mass is halved, how does kinetic energy change?

Answer: Halved. Kinetic energy is directly proportional to mass.

Flashcard 12: A 10 kg object moves at 0 m/s. What is its kinetic energy?

Answer: $KE = 0 \text{ J}$. Zero velocity means zero kinetic energy regardless of mass.

Flashcard 13: Calculate velocity: kinetic energy = 18 J, mass = 2 kg.

Answer: $v = 3 \text{ m/s}$. $18 = \frac{1}{2}(2)v^2$, so $v = \sqrt{\frac{36}{2}} = 3$ m/s.

Flashcard 14: Identify the SI unit for velocity in the kinetic energy formula.

Answer: Meters per second (m/s). SI derived unit combining distance per unit time.

Flashcard 15: What does $m$ represent in the translational kinetic energy formula?

Answer: Mass of the object. Mass is the scalar quantity representing the amount of matter in the object.

Flashcard 16: What are the SI units of translational kinetic energy?

Answer: Joules (J). Energy units derived from $kg \cdot m^2/s^2$ in the SI system.

Flashcard 17: How is translational kinetic energy related to work done?

Answer: Equal to work done to bring object to current speed. Work-energy theorem states work done equals change in kinetic energy.

Flashcard 18: Convert 100 J to kilojoules (kJ).

Answer: $0.1 \text{ kJ}$. Divide by 1000 to convert joules to kilojoules.

Flashcard 19: Identify the SI unit for mass used in the kinetic energy formula.

Answer: Kilogram (kg). Standard SI base unit for measuring the amount of matter.

Flashcard 20: If velocity is doubled, how does kinetic energy change?

Answer: Increases by a factor of 4. Since $v^2$ appears in the formula, doubling $v$ increases $KE$ by $2^2 = 4$.

Flashcard 21: Calculate the kinetic energy: mass = 4 kg, velocity = 5 m/s.

Answer: $KE = 50 \text{ J}$. $KE = \frac{1}{2}(4)(5^2) = \frac{1}{2}(4)(25) = 50$ J.

Flashcard 22: Calculate the mass of an object with 50 J of kinetic energy moving at 5 m/s.

Answer: $m = 4 \text{ kg}$. $50 = \frac{1}{2}m(5^2)$, so $m = \frac{2(50)}{25} = 4$ kg.

Flashcard 23: A car increases speed from 10 m/s to 20 m/s. By what factor does its kinetic energy increase?

Answer: Increases by a factor of 4. Velocity doubles, so $KE$ increases by $(2)^2 = 4$ times.

Flashcard 24: What is the kinetic energy of a 3 kg object moving at 2 m/s?

Answer: $KE = 6 \text{ J}$. $KE = \frac{1}{2}(3)(2^2) = \frac{1}{2}(3)(4) = 6$ J.

Flashcard 25: A 0.5 kg object has 8 J of kinetic energy. What is its velocity?

Answer: $v = 4 \text{ m/s}$. $8 = \frac{1}{2}(0.5)v^2$, so $v = \sqrt{\frac{16}{0.5}} = 4$ m/s.

Flashcard 26: What factor affects translational kinetic energy the most?

Answer: Velocity, as $v$ is squared. The squared term makes velocity changes more impactful than mass changes.

Flashcard 27: What is the formula to find mass from kinetic energy and velocity?

Answer: $m = \frac{2KE}{v^2}$. Rearrange $KE = \frac{1}{2}mv^2$ to solve for mass.

Flashcard 28: Determine the kinetic energy change if velocity triples.

Answer: Increases by a factor of 9. Tripling velocity increases $KE$ by $(3)^2 = 9$ times.

Flashcard 29: A 1 kg object moves at 3 m/s. Find its kinetic energy.

Answer: $KE = 4.5 \text{ J}$. $KE = \frac{1}{2}(1)(3^2) = \frac{1}{2}(1)(9) = 4.5$ J.

Flashcard 30: A 6 kg object moving at 2 m/s. Calculate its kinetic energy.

Answer: $KE = 12 \text{ J}$. $KE = \frac{1}{2}(6)(2^2) = \frac{1}{2}(6)(4) = 12$ J.