All flashcards
Flashcard 1: What is the acceleration formula for SHM at time t?
Answer: a(t)=−Aω2cos(ωt+ϕ). Acceleration is the time derivative of velocity function.
Flashcard 2: Calculate the maximum speed if A=0.2 m and ω=5 rad/s.
Answer: vmax=1 m/s. Maximum speed occurs at equilibrium position.
Flashcard 3: Identify the point of maximum acceleration in SHM.
Answer: At maximum displacement. Restoring force and acceleration are greatest at amplitude.
Flashcard 4: Identify a real-world example of SHM.
Answer: A swinging pendulum. Pendulums exhibit simple harmonic motion for small angles.
Flashcard 5: Calculate the frequency if T=0.25 s.
Answer: f=4 Hz. Use f=T1 to convert period to frequency.
Flashcard 6: What is the formula for angular frequency in SHM?
Answer: ω=2πf. Angular frequency is 2π times the regular frequency.
Flashcard 7: Find the period of a pendulum with L=1 m and g=9.8 m/s².
Answer: T≈2.01 s. Use pendulum formula with given values.
Flashcard 8: Find the displacement formula for SHM at time t.
Answer: x(t)=Acos(ωt+ϕ). General solution with amplitude, angular frequency, and phase constant.
Flashcard 9: Calculate the period given f=5 Hz.
Answer: T=0.2 s. Use T=f1 to find period from frequency.
Flashcard 10: Which graph represents displacement in SHM?
Answer: A sine or cosine wave. Displacement varies sinusoidally with time in SHM.
Flashcard 11: Identify the phase difference between displacement and velocity in SHM.
Answer: 2π radians. Velocity leads displacement by 90 degrees in phase.
Flashcard 12: Find the velocity at equilibrium position in SHM.
Answer: v=vmax. At equilibrium, all energy is kinetic, reaching maximum speed.
Flashcard 13: Define the amplitude of oscillation.
Answer: The maximum displacement from equilibrium. Amplitude represents the extent or range of oscillation.
Flashcard 14: Define simple harmonic motion (SHM).
Answer: Motion where acceleration is proportional to displacement and directed towards equilibrium. Restoring force follows F=−kx, creating sinusoidal motion.
Flashcard 15: What is the role of damping in SHM?
Answer: Damping reduces amplitude over time. Energy loss causes oscillation amplitude to decrease gradually.
Flashcard 16: Find the angular frequency if T=0.5 s.
Answer: ω=4π rad/s. Use ω=T2π to convert period to angular frequency.
Flashcard 17: Identify the relationship between frequency and period.
Answer: f=T1. Frequency and period are reciprocals of each other.
Flashcard 18: What is the phase relationship between velocity and acceleration in SHM?
Answer: π radians out of phase. Acceleration and velocity are opposite in phase.
Flashcard 19: Find the displacement if A=2 m, ω=π rad/s, t=1 s, ϕ=0.
Answer: x(1)=0. Use x(t)=Acos(ωt) with given values.
Flashcard 20: Name the energy types involved in SHM.
Answer: Kinetic and potential energy. Energy continuously converts between these two forms during oscillation.
Flashcard 21: How does amplitude affect the period in SHM?
Answer: Amplitude does not affect the period. Period depends only on system parameters, not initial conditions.
Flashcard 22: State the relationship between energy and amplitude in SHM.
Answer: Energy is proportional to the square of amplitude. From E=21kA2, energy increases with A2.
Flashcard 23: Determine the effect of length on the pendulum's period.
Answer: Longer length increases period. Period increases with square root of length.
Flashcard 24: What is the displacement at t=0 if ϕ=0?
Answer: x(0)=A. At t=0 with ϕ=0, cos(0)=1, so displacement equals amplitude.
Flashcard 25: Explain the effect of mass on the period of a pendulum.
Answer: Mass does not affect the period. Pendulum period depends only on length and gravity.
Flashcard 26: Find the total mechanical energy in SHM.
Answer: E=21kA2. Total energy equals maximum potential energy at amplitude.
Flashcard 27: What is resonance in the context of SHM?
Answer: When driving frequency matches natural frequency, maximizing amplitude. External driving at natural frequency causes large amplitude oscillations.
Flashcard 28: What is the kinetic energy at maximum displacement?
Answer: Zero. At maximum displacement, all energy is potential, none kinetic.
Flashcard 29: Find the velocity formula for SHM at time t.
Answer: v(t)=−Aωsin(ωt+ϕ). Velocity is the time derivative of displacement function.
Flashcard 30: What does the graph of velocity against time look like in SHM?
Answer: A sine wave. Velocity varies sinusoidally, 90 degrees ahead of displacement.