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This deck focuses on Representing And Analyzing Shm, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Representing And Analyzing Shm in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the role of damping in SHM?
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Damping reduces amplitude over time. Energy loss causes oscillation amplitude to decrease gradually.
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This deck focuses on Representing And Analyzing Shm, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Damping reduces amplitude over time. Energy loss causes oscillation amplitude to decrease gradually.
Answer: x(1)=0. Use x(t)=Acos(ωt) with given values.
Answer: At maximum displacement. Restoring force and acceleration are greatest at amplitude.
Answer: E=21kA2. Total energy equals maximum potential energy at amplitude.
Answer: A sine or cosine wave. Displacement varies sinusoidally with time in SHM.
Answer: f=4 Hz. Use f=T1 to convert period to frequency.
Answer: T=0.2 s. Use T=f1 to find period from frequency.
Answer: Zero. At maximum displacement, all energy is potential, none kinetic.
Answer: vmax=Aω. Occurs at equilibrium where all energy is kinetic.
Answer: vmax=Aω. Occurs at equilibrium where all energy is kinetic.
Answer: π radians out of phase. Acceleration and velocity are opposite in phase.
Answer: Kinetic and potential energy. Energy continuously converts between these two forms during oscillation.
Answer: ω=2πf. Angular frequency is 2π times the regular frequency.
Answer: Mass does not affect the period. Pendulum period depends only on length and gravity.
Answer: At maximum displacement. Restoring force and acceleration are greatest at amplitude.
Answer: f=4 Hz. Use f=T1 to convert period to frequency.
Answer: v(t)=−Aωsin(ωt+ϕ). Velocity is the time derivative of displacement function.
Answer: A sine wave. Velocity varies sinusoidally, 90 degrees ahead of displacement.
Answer: Motion where acceleration is proportional to displacement and directed towards equilibrium. Restoring force follows F=−kx, creating sinusoidal motion.
Answer: amax=Aω2. Occurs at maximum displacement where restoring force is greatest.
Answer: F=−kx. Force is proportional to displacement with negative sign for restoring nature.
Answer: T≈2.01 s. Use pendulum formula with given values.
Answer: vmax=1 m/s. Maximum speed occurs at equilibrium position.
Answer: ω=4π rad/s. Use ω=T2π to convert period to angular frequency.
Answer: U=21kx2. Energy stored increases with square of displacement from equilibrium.
Answer: f=T1. Frequency and period are reciprocals of each other.
Answer: v=vmax. At equilibrium, all energy is kinetic, reaching maximum speed.
Answer: When driving frequency matches natural frequency, maximizing amplitude. External driving at natural frequency causes large amplitude oscillations.
Answer: x(t)=Acos(ωt+ϕ). General solution with amplitude, angular frequency, and phase constant.
Answer: The maximum displacement from equilibrium. Amplitude represents the extent or range of oscillation.
Answer: Amplitude does not affect the period. Period depends only on system parameters, not initial conditions.
Answer: A swinging pendulum. Pendulums exhibit simple harmonic motion for small angles.
Answer: Longer length increases period. Period increases with square root of length.
Answer: U=1.25 J. Use U=21kA2 at maximum displacement.
Answer: Energy is proportional to the square of amplitude. From E=21kA2, energy increases with A2.
Answer: T=2πkm. Period increases with mass and decreases with spring stiffness.
Answer: T≈2.01 s. Use pendulum formula with given values.
Answer: a(t)=−Aω2cos(ωt+ϕ). Acceleration is the time derivative of velocity function.
Answer: The maximum displacement from equilibrium. Amplitude represents the extent or range of oscillation.
Answer: x(0)=A. At t=0 with ϕ=0, cos(0)=1, so displacement equals amplitude.
Answer: 2π radians. Velocity leads displacement by 90 degrees in phase.