Newton's Second Law - AP Physics 1
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When does an object experience no net force according to Newton's Second Law?
When does an object experience no net force according to Newton's Second Law?
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When at rest or constant velocity. Net force equals zero when acceleration is zero.
When at rest or constant velocity. Net force equals zero when acceleration is zero.
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What does the symbol $F$ represent in $F = ma$?
What does the symbol $F$ represent in $F = ma$?
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Force. The net force applied to the object, measured in Newtons.
Force. The net force applied to the object, measured in Newtons.
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If force is tripled, what happens to acceleration (mass constant)?
If force is tripled, what happens to acceleration (mass constant)?
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Triples. From $a = F/m$, tripling force triples acceleration.
Triples. From $a = F/m$, tripling force triples acceleration.
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Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.
Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.
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$5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.
$5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.
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Calculate acceleration of $10 \text{ kg}$ object with $50 \text{ N}$ force.
Calculate acceleration of $10 \text{ kg}$ object with $50 \text{ N}$ force.
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$5 \text{ m/s}^2$. Using $a = F/m$: $a = 50/10 = 5 \text{ m/s}^2$.
$5 \text{ m/s}^2$. Using $a = F/m$: $a = 50/10 = 5 \text{ m/s}^2$.
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Find the mass if $F = 9 \text{ N}$ and $a = 3 \text{ m/s}^2$.
Find the mass if $F = 9 \text{ N}$ and $a = 3 \text{ m/s}^2$.
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$3 \text{ kg}$. Using $m = F/a$: $m = 9/3 = 3 \text{ kg}$.
$3 \text{ kg}$. Using $m = F/a$: $m = 9/3 = 3 \text{ kg}$.
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Calculate force for $3 \text{ kg}$ object with $6 \text{ m/s}^2$ acceleration.
Calculate force for $3 \text{ kg}$ object with $6 \text{ m/s}^2$ acceleration.
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$18 \text{ N}$. Using $F = ma$: $F = 3 \times 6 = 18 \text{ N}$.
$18 \text{ N}$. Using $F = ma$: $F = 3 \times 6 = 18 \text{ N}$.
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State the effect of increasing force on acceleration for constant mass.
State the effect of increasing force on acceleration for constant mass.
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Acceleration increases. From $a = F/m$, larger numerator gives larger result.
Acceleration increases. From $a = F/m$, larger numerator gives larger result.
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Calculate acceleration for $20 \text{ kg}$ object with $100 \text{ N}$ force.
Calculate acceleration for $20 \text{ kg}$ object with $100 \text{ N}$ force.
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$5 \text{ m/s}^2$. Using $a = F/m$: $a = 100/20 = 5 \text{ m/s}^2$.
$5 \text{ m/s}^2$. Using $a = F/m$: $a = 100/20 = 5 \text{ m/s}^2$.
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What is the formula for Newton's Second Law?
What is the formula for Newton's Second Law?
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$F = ma$. The fundamental equation relating net force, mass, and acceleration.
$F = ma$. The fundamental equation relating net force, mass, and acceleration.
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Identify the SI unit for mass.
Identify the SI unit for mass.
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Kilogram (kg). Base SI unit for the amount of matter in an object.
Kilogram (kg). Base SI unit for the amount of matter in an object.
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Identify the SI unit for acceleration.
Identify the SI unit for acceleration.
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Meters per second squared ($\text{m/s}^2$). The rate of velocity change per unit time.
Meters per second squared ($\text{m/s}^2$). The rate of velocity change per unit time.
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If mass is halved and force is constant, what happens to acceleration?
If mass is halved and force is constant, what happens to acceleration?
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Doubles. From $a = F/m$, halving mass doubles acceleration: $a = F/(m/2) = 2F/m$.
Doubles. From $a = F/m$, halving mass doubles acceleration: $a = F/(m/2) = 2F/m$.
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What is the relationship between mass and acceleration in $F = ma$?
What is the relationship between mass and acceleration in $F = ma$?
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Inversely proportional. Greater mass produces smaller acceleration when force is constant.
Inversely proportional. Greater mass produces smaller acceleration when force is constant.
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If force is zero, what is the state of motion according to Newton's Second Law?
If force is zero, what is the state of motion according to Newton's Second Law?
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No acceleration (constant velocity). Zero force means zero acceleration, so velocity remains constant.
No acceleration (constant velocity). Zero force means zero acceleration, so velocity remains constant.
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State the effect of increasing mass on acceleration for constant force.
State the effect of increasing mass on acceleration for constant force.
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Acceleration decreases. From $a = F/m$, larger denominator gives smaller result.
Acceleration decreases. From $a = F/m$, larger denominator gives smaller result.
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Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.
Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.
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$5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.
$5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.
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What does the symbol $m$ represent in $F = ma$?
What does the symbol $m$ represent in $F = ma$?
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Mass. The amount of matter in the object, measured in kilograms.
Mass. The amount of matter in the object, measured in kilograms.
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Determine the net force if $m = 4 \text{ kg}$ and $a = 2 \text{ m/s}^2$.
Determine the net force if $m = 4 \text{ kg}$ and $a = 2 \text{ m/s}^2$.
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$8 \text{ N}$. Using $F = ma$: $F = 4 \times 2 = 8 \text{ N}$.
$8 \text{ N}$. Using $F = ma$: $F = 4 \times 2 = 8 \text{ N}$.
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What happens to acceleration if both mass and force are doubled?
What happens to acceleration if both mass and force are doubled?
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Remains the same. From $a = F/m$, doubling both cancels out: $a = 2F/2m = F/m$.
Remains the same. From $a = F/m$, doubling both cancels out: $a = 2F/2m = F/m$.
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Calculate the mass: $F = 15 \text{ N}$, $a = 5 \text{ m/s}^2$.
Calculate the mass: $F = 15 \text{ N}$, $a = 5 \text{ m/s}^2$.
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$3 \text{ kg}$. Using $m = F/a$: $m = 15/5 = 3 \text{ kg}$.
$3 \text{ kg}$. Using $m = F/a$: $m = 15/5 = 3 \text{ kg}$.
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Calculate force needed to accelerate $5 \text{ kg}$ object at $4 \text{ m/s}^2$.
Calculate force needed to accelerate $5 \text{ kg}$ object at $4 \text{ m/s}^2$.
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$20 \text{ N}$. Using $F = ma$: $F = 5 \times 4 = 20 \text{ N}$.
$20 \text{ N}$. Using $F = ma$: $F = 5 \times 4 = 20 \text{ N}$.
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Calculate net force for $8 \text{ kg}$ object accelerating at $3 \text{ m/s}^2$.
Calculate net force for $8 \text{ kg}$ object accelerating at $3 \text{ m/s}^2$.
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$24 \text{ N}$. Using $F = ma$: $F = 8 \times 3 = 24 \text{ N}$.
$24 \text{ N}$. Using $F = ma$: $F = 8 \times 3 = 24 \text{ N}$.
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Calculate the force: $m = 2 \text{ kg}$, $a = 3 \text{ m/s}^2$.
Calculate the force: $m = 2 \text{ kg}$, $a = 3 \text{ m/s}^2$.
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$6 \text{ N}$. Using $F = ma$: $F = 2 \times 3 = 6 \text{ N}$.
$6 \text{ N}$. Using $F = ma$: $F = 2 \times 3 = 6 \text{ N}$.
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If mass is doubled and force is constant, what happens to acceleration?
If mass is doubled and force is constant, what happens to acceleration?
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Halves. From $a = F/m$, doubling mass halves acceleration.
Halves. From $a = F/m$, doubling mass halves acceleration.
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Find force if $m = 12 \text{ kg}$ and $a = 2 \text{ m/s}^2$.
Find force if $m = 12 \text{ kg}$ and $a = 2 \text{ m/s}^2$.
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$24 \text{ N}$. Using $F = ma$: $F = 12 \times 2 = 24 \text{ N}$.
$24 \text{ N}$. Using $F = ma$: $F = 12 \times 2 = 24 \text{ N}$.
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What does the symbol $a$ represent in $F = ma$?
What does the symbol $a$ represent in $F = ma$?
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Acceleration. The rate of change of velocity, measured in $\text{m/s}^2$.
Acceleration. The rate of change of velocity, measured in $\text{m/s}^2$.
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What is the effect of zero net force on an object's motion?
What is the effect of zero net force on an object's motion?
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Constant velocity. Zero net force means zero acceleration, so velocity stays constant.
Constant velocity. Zero net force means zero acceleration, so velocity stays constant.
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How does Newton's Second Law explain the effect of doubling mass on acceleration?
How does Newton's Second Law explain the effect of doubling mass on acceleration?
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Acceleration is halved. Mass inversely affects acceleration according to $a = F/m$.
Acceleration is halved. Mass inversely affects acceleration according to $a = F/m$.
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Calculate acceleration of $15 \text{ kg}$ object with $75 \text{ N}$ force.
Calculate acceleration of $15 \text{ kg}$ object with $75 \text{ N}$ force.
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$5 \text{ m/s}^2$. Using $a = F/m$: $a = 75/15 = 5 \text{ m/s}^2$.
$5 \text{ m/s}^2$. Using $a = F/m$: $a = 75/15 = 5 \text{ m/s}^2$.
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