AP Physics 1 Flashcards: Newtons Second Law

What this deck covers

This deck focuses on Newtons Second Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What is the effect of zero net force on an object's motion?

Answer: Constant velocity. Zero net force means zero acceleration, so velocity stays constant.

Flashcard 2: If force is tripled, what happens to acceleration (mass constant)?

Answer: Triples. From $a = F/m$, tripling force triples acceleration.

Flashcard 3: Identify the SI unit for mass.

Answer: Kilogram (kg). Base SI unit for the amount of matter in an object.

Flashcard 4: If force is zero, what is the state of motion according to Newton's Second Law?

Answer: No acceleration (constant velocity). Zero force means zero acceleration, so velocity remains constant.

Flashcard 5: Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.

Answer: $5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.

Flashcard 6: What is the effect of zero net force on an object's motion?

Answer: Constant velocity. Zero net force means zero acceleration, so velocity stays constant.

Flashcard 7: Identify the SI unit for force.

Answer: Newton (N). Equivalent to $\text{kg} \cdot \text{m/s}^2$ in base units.

Flashcard 8: Determine the net force if $m = 4 \text{ kg}$ and $a = 2 \text{ m/s}^2$.

Answer: $8 \text{ N}$. Using $F = ma$: $F = 4 \times 2 = 8 \text{ N}$.

Flashcard 9: What happens to acceleration if both mass and force are doubled?

Answer: Remains the same. From $a = F/m$, doubling both cancels out: $a = 2F/2m = F/m$.

Flashcard 10: What is the relationship between force and acceleration in $F = ma$?

Answer: Directly proportional. Greater force produces greater acceleration when mass is constant.

Flashcard 11: What is the relationship between force and acceleration in $F = ma$?

Answer: Directly proportional. Greater force produces greater acceleration when mass is constant.

Flashcard 12: If two objects have different masses but same force, which has higher acceleration?

Answer: Object with smaller mass. From $a = F/m$, smaller mass gives larger acceleration.

Flashcard 13: If force is zero, what is the state of motion according to Newton's Second Law?

Answer: No acceleration (constant velocity). Zero force means zero acceleration, so velocity remains constant.

Flashcard 14: Find force if $m = 12 \text{ kg}$ and $a = 2 \text{ m/s}^2$.

Answer: $24 \text{ N}$. Using $F = ma$: $F = 12 \times 2 = 24 \text{ N}$.

Flashcard 15: What does the symbol $m$ represent in $F = ma$?

Answer: Mass. The amount of matter in the object, measured in kilograms.

Flashcard 16: Calculate force needed to accelerate $5 \text{ kg}$ object at $4 \text{ m/s}^2$.

Answer: $20 \text{ N}$. Using $F = ma$: $F = 5 \times 4 = 20 \text{ N}$.

Flashcard 17: What does the symbol $a$ represent in $F = ma$?

Answer: Acceleration. The rate of change of velocity, measured in $\text{m/s}^2$.

Flashcard 18: If mass is halved and force is constant, what happens to acceleration?

Answer: Doubles. From $a = F/m$, halving mass doubles acceleration: $a = F/(m/2) = 2F/m$.

Flashcard 19: If net force is zero, what is the acceleration of the object?

Answer: Zero. No net force means no change in velocity ($a = F/m = 0/m = 0$).

Flashcard 20: Calculate mass of object if $F = 40 \text{ N}$ and $a = 4 \text{ m/s}^2$.

Answer: $10 \text{ kg}$. Using $m = F/a$: $m = 40/4 = 10 \text{ kg}$.

Flashcard 21: Calculate acceleration of $15 \text{ kg}$ object with $75 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 75/15 = 5 \text{ m/s}^2$.

Flashcard 22: What does the symbol $F$ represent in $F = ma$?

Answer: Force. The net force applied to the object, measured in Newtons.

Flashcard 23: State the effect of increasing mass on acceleration for constant force.

Answer: Acceleration decreases. From $a = F/m$, larger denominator gives smaller result.

Flashcard 24: If force is tripled, what happens to acceleration (mass constant)?

Answer: Triples. From $a = F/m$, tripling force triples acceleration.

Flashcard 25: State the effect of increasing mass on acceleration for constant force.

Answer: Acceleration decreases. From $a = F/m$, larger denominator gives smaller result.

Flashcard 26: Calculate force for $3 \text{ kg}$ object with $6 \text{ m/s}^2$ acceleration.

Answer: $18 \text{ N}$. Using $F = ma$: $F = 3 \times 6 = 18 \text{ N}$.

Flashcard 27: Calculate acceleration of $10 \text{ kg}$ object with $50 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 50/10 = 5 \text{ m/s}^2$.

Flashcard 28: When does an object experience no net force according to Newton's Second Law?

Answer: When at rest or constant velocity. Net force equals zero when acceleration is zero.

Flashcard 29: Calculate the force: $m = 2 \text{ kg}$, $a = 3 \text{ m/s}^2$.

Answer: $6 \text{ N}$. Using $F = ma$: $F = 2 \times 3 = 6 \text{ N}$.

Flashcard 30: Find the mass if $F = 9 \text{ N}$ and $a = 3 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 9/3 = 3 \text{ kg}$.

Flashcard 31: Calculate the mass: $F = 15 \text{ N}$, $a = 5 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 15/5 = 3 \text{ kg}$.

Flashcard 32: Calculate acceleration for $20 \text{ kg}$ object with $100 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 100/20 = 5 \text{ m/s}^2$.

Flashcard 33: Determine the net force if $m = 4 \text{ kg}$ and $a = 2 \text{ m/s}^2$.

Answer: $8 \text{ N}$. Using $F = ma$: $F = 4 \times 2 = 8 \text{ N}$.

Flashcard 34: Calculate net force for $8 \text{ kg}$ object accelerating at $3 \text{ m/s}^2$.

Answer: $24 \text{ N}$. Using $F = ma$: $F = 8 \times 3 = 24 \text{ N}$.

Flashcard 35: What does the symbol $a$ represent in $F = ma$?

Answer: Acceleration. The rate of change of velocity, measured in $\text{m/s}^2$.

Flashcard 36: Find the mass if $F = 9 \text{ N}$ and $a = 3 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 9/3 = 3 \text{ kg}$.

Flashcard 37: If mass is doubled and force is constant, what happens to acceleration?

Answer: Halves. From $a = F/m$, doubling mass halves acceleration.

Flashcard 38: How does Newton's Second Law explain the effect of doubling mass on acceleration?

Answer: Acceleration is halved. Mass inversely affects acceleration according to $a = F/m$.

Flashcard 39: If mass is halved and force is constant, what happens to acceleration?

Answer: Doubles. From $a = F/m$, halving mass doubles acceleration: $a = F/(m/2) = 2F/m$.

Flashcard 40: Calculate the mass: $F = 15 \text{ N}$, $a = 5 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 15/5 = 3 \text{ kg}$.

Flashcard 41: If two objects have different masses but same force, which has higher acceleration?

Answer: Object with smaller mass. From $a = F/m$, smaller mass gives larger acceleration.

Flashcard 42: Determine mass of an object with $25 \text{ N}$ force and $5 \text{ m/s}^2$ acceleration.

Answer: $5 \text{ kg}$. Using $m = F/a$: $m = 25/5 = 5 \text{ kg}$.

Flashcard 43: Calculate acceleration of $15 \text{ kg}$ object with $75 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 75/15 = 5 \text{ m/s}^2$.

Flashcard 44: What is the relationship between mass and acceleration in $F = ma$?

Answer: Inversely proportional. Greater mass produces smaller acceleration when force is constant.

Flashcard 45: If mass is doubled and force is constant, what happens to acceleration?

Answer: Halves. From $a = F/m$, doubling mass halves acceleration.

Flashcard 46: What is the net force if acceleration is zero?

Answer: Zero. From $F = ma$, zero acceleration means zero net force.

Flashcard 47: Identify the SI unit for mass.

Answer: Kilogram (kg). Base SI unit for the amount of matter in an object.

Flashcard 48: When does an object experience no net force according to Newton's Second Law?

Answer: When at rest or constant velocity. Net force equals zero when acceleration is zero.

Flashcard 49: Calculate force needed to accelerate $5 \text{ kg}$ object at $4 \text{ m/s}^2$.

Answer: $20 \text{ N}$. Using $F = ma$: $F = 5 \times 4 = 20 \text{ N}$.

Flashcard 50: Calculate acceleration of $10 \text{ kg}$ object with $50 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 50/10 = 5 \text{ m/s}^2$.

Flashcard 51: What is the formula for Newton's Second Law?

Answer: $F = ma$. The fundamental equation relating net force, mass, and acceleration.

Flashcard 52: What happens to acceleration if both mass and force are doubled?

Answer: Remains the same. From $a = F/m$, doubling both cancels out: $a = 2F/2m = F/m$.

Flashcard 53: Find the acceleration if $F = 20 \text{ N}$ and $m = 4 \text{ kg}$.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 20/4 = 5 \text{ m/s}^2$.

Flashcard 54: Calculate the acceleration: $F = 10 \text{ N}$, $m = 2 \text{ kg}$.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 10/2 = 5 \text{ m/s}^2$.

Flashcard 55: Identify the SI unit for acceleration.

Answer: Meters per second squared ($\text{m/s}^2$). The rate of velocity change per unit time.

Flashcard 56: Identify the SI unit for acceleration.

Answer: Meters per second squared ($\text{m/s}^2$). The rate of velocity change per unit time.

Flashcard 57: Calculate the acceleration: $F = 10 \text{ N}$, $m = 2 \text{ kg}$.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 10/2 = 5 \text{ m/s}^2$.

Flashcard 58: Find acceleration if $F = 18 \text{ N}$ and $m = 3 \text{ kg}$.

Answer: $6 \text{ m/s}^2$. Using $a = F/m$: $a = 18/3 = 6 \text{ m/s}^2$.

Flashcard 59: Identify the SI unit for force.

Answer: Newton (N). Equivalent to $\text{kg} \cdot \text{m/s}^2$ in base units.

Flashcard 60: What is the formula for Newton's Second Law?

Answer: $F = ma$. The fundamental equation relating net force, mass, and acceleration.

Flashcard 61: What is the net force if acceleration is zero?

Answer: Zero. From $F = ma$, zero acceleration means zero net force.

Flashcard 62: Find the acceleration if $F = 20 \text{ N}$ and $m = 4 \text{ kg}$.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 20/4 = 5 \text{ m/s}^2$.

Flashcard 63: Calculate force for $3 \text{ kg}$ object with $6 \text{ m/s}^2$ acceleration.

Answer: $18 \text{ N}$. Using $F = ma$: $F = 3 \times 6 = 18 \text{ N}$.

Flashcard 64: What does the symbol $m$ represent in $F = ma$?

Answer: Mass. The amount of matter in the object, measured in kilograms.

Flashcard 65: Find acceleration if $F = 18 \text{ N}$ and $m = 3 \text{ kg}$.

Answer: $6 \text{ m/s}^2$. Using $a = F/m$: $a = 18/3 = 6 \text{ m/s}^2$.

Flashcard 66: Find mass if $F = 30 \text{ N}$ and $a = 10 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 30/10 = 3 \text{ kg}$.

Flashcard 67: Calculate the force: $m = 2 \text{ kg}$, $a = 3 \text{ m/s}^2$.

Answer: $6 \text{ N}$. Using $F = ma$: $F = 2 \times 3 = 6 \text{ N}$.

Flashcard 68: State the effect of increasing force on acceleration for constant mass.

Answer: Acceleration increases. From $a = F/m$, larger numerator gives larger result.

Flashcard 69: What does the symbol $F$ represent in $F = ma$?

Answer: Force. The net force applied to the object, measured in Newtons.

Flashcard 70: What is the relationship between mass and acceleration in $F = ma$?

Answer: Inversely proportional. Greater mass produces smaller acceleration when force is constant.

Flashcard 71: Find mass if $F = 30 \text{ N}$ and $a = 10 \text{ m/s}^2$.

Answer: $3 \text{ kg}$. Using $m = F/a$: $m = 30/10 = 3 \text{ kg}$.

Flashcard 72: Calculate acceleration for $20 \text{ kg}$ object with $100 \text{ N}$ force.

Answer: $5 \text{ m/s}^2$. Using $a = F/m$: $a = 100/20 = 5 \text{ m/s}^2$.

Flashcard 73: Find force if $m = 12 \text{ kg}$ and $a = 2 \text{ m/s}^2$.

Answer: $24 \text{ N}$. Using $F = ma$: $F = 12 \times 2 = 24 \text{ N}$.

Flashcard 74: State the effect of increasing force on acceleration for constant mass.

Answer: Acceleration increases. From $a = F/m$, larger numerator gives larger result.

Flashcard 75: Calculate net force for $8 \text{ kg}$ object accelerating at $3 \text{ m/s}^2$.

Answer: $24 \text{ N}$. Using $F = ma$: $F = 8 \times 3 = 24 \text{ N}$.

Flashcard 76: If net force is zero, what is the acceleration of the object?

Answer: Zero. No net force means no change in velocity ($a = F/m = 0/m = 0$).

Flashcard 77: How does Newton's Second Law explain the effect of doubling mass on acceleration?

Answer: Acceleration is halved. Mass inversely affects acceleration according to $a = F/m$.