All flashcards
Flashcard 1: What is the momentum of a 2 kg object at rest?
Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.
Flashcard 2: How does momentum change if velocity doubles and mass stays constant?
Answer: Momentum doubles. Momentum is directly proportional to velocity.
Flashcard 3: Calculate the momentum of a 3 kg object traveling at 4 m/s.
Answer: p=12 kg·m/s. Using p=mv=3×4=12 kg·m/s.
Flashcard 4: Identify the variable representing impulse.
Answer: Impulse is represented by J. Standard physics notation for impulse.
Flashcard 5: What is the momentum change if a 3 kg object accelerates from 0 to 3 m/s?
Answer: 9 kg·m/s. Change is 3×3−3×0=9 kg·m/s.
Flashcard 6: How does friction affect momentum in a system?
Answer: Friction can reduce momentum. Friction is an external force that affects momentum.
Flashcard 7: If a system has two objects at rest, what is the total momentum?
Answer: 0 kg·m/s. Rest means zero velocity for both objects.
Flashcard 8: Determine the change in momentum for a 4 kg object increasing speed from 2 m/s to 5 m/s.
Answer: 12 kg·m/s. Change is 4×5−4×2=20−8=12 kg·m/s.
Flashcard 9: Find momentum if mass is 7 kg and velocity is 3 m/s.
Answer: p=21 kg·m/s. Using p=mv=7×3=21 kg·m/s.
Flashcard 10: What is the effect on momentum if mass is halved and velocity is doubled?
Answer: Momentum stays the same. The mass and velocity changes cancel out.
Flashcard 11: State the relationship between force and change in momentum.
Answer: Force equals the rate of change of momentum. This is Newton's second law in momentum form.
Flashcard 12: Find the velocity if momentum is 30 kg·m/s and mass is 5 kg.
Answer: v=6 m/s. Rearranging p=mv gives v=p/m=30/5.
Flashcard 13: What is the formula for impulse?
Answer: J=F×△t. Force multiplied by time interval gives impulse.
Flashcard 14: What is the effect on momentum if mass is halved and velocity is doubled?
Answer: Momentum stays the same. The mass and velocity changes cancel out.
Flashcard 15: What is the impulse if a force of 6 N acts for 3 s?
Answer: J=18 Ns. Using J=F×Δt=6×3=18 Ns.
Flashcard 16: Identify the variable for momentum in equations.
Answer: Momentum is represented by p. Standard physics notation for momentum.
Flashcard 17: How does momentum change if mass doubles and velocity stays constant?
Answer: Momentum doubles. Momentum is directly proportional to mass.
Flashcard 18: Calculate momentum for a 4 kg object at 5 m/s.
Answer: p=20 kg·m/s. Using p=mv=4×5=20 kg·m/s.
Flashcard 19: Find momentum if mass is 7 kg and velocity is 3 m/s.
Answer: p=21 kg·m/s. Using p=mv=7×3=21 kg·m/s.
Flashcard 20: What is conserved in an elastic collision?
Answer: Both momentum and kinetic energy. These are the two conserved quantities in elastic collisions.
Flashcard 21: If momentum is 20 kg·m/s and velocity is 4 m/s, find the mass.
Answer: m=5 kg. Rearranging p=mv gives m=p/v=20/4.
Flashcard 22: What is the resulting force if a 15 Ns impulse occurs over 3 s?
Answer: F=5 N. Rearranging J=F×Δt gives F=J/Δt=15/3.
Flashcard 23: Define momentum.
Answer: Momentum is the product of mass and velocity. This definition follows directly from p=mv.
Flashcard 24: State the unit for impulse.
Answer: Newton second (Ns). Newton second is equivalent to kg·m/s.
Flashcard 25: Identify the variable representing impulse.
Answer: Impulse is represented by J. Standard physics notation for impulse.
Flashcard 26: What is the momentum change if a 3 kg object accelerates from 0 to 3 m/s?
Answer: 9 kg·m/s. Change is 3×3−3×0=9 kg·m/s.
Flashcard 27: How does friction affect momentum in a system?
Answer: Friction can reduce momentum. Friction is an external force that affects momentum.
Flashcard 28: If a system has two objects at rest, what is the total momentum?
Answer: 0 kg·m/s. Rest means zero velocity for both objects.
Flashcard 29: Determine the change in momentum for a 4 kg object increasing speed from 2 m/s to 5 m/s.
Answer: 12 kg·m/s. Change is 4×5−4×2=20−8=12 kg·m/s.
Flashcard 30: What is the momentum of a 2 kg object at rest?
Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.