AP Physics 1 Flashcards: Frequency And Period Of Shm

What this deck covers

This deck focuses on Frequency And Period Of Shm, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: What happens to the angular frequency if the period doubles?

Answer: Halves. Angular frequency is inversely proportional to period.

Flashcard 2: What is the dimension of period?

Answer: T. Period has units of time duration.

Flashcard 3: What is the period of a pendulum with length $1 \text{ m}$ on Earth?

Answer: $T = 2\pi \sqrt{\frac{1}{9.8}} \approx 2.01 \text{ s}$. Using the pendulum formula with $L = 1$ m and $g = 9.8$ m/s².

Flashcard 4: If a pendulum's length is quadrupled, how does its period change?

Answer: Doubles. Period scales with square root of length, so $\sqrt{4} = 2$.

Flashcard 5: What is the dimension of frequency?

Answer: T⁻¹. Frequency has units of inverse time.

Flashcard 6: For a mass-spring system, what is the effect of increasing mass on the period?

Answer: Increases the period. Period is proportional to square root of mass.

Flashcard 7: State the formula for frequency in terms of angular frequency.

Answer: $f = \frac{\omega}{2\pi}$. Derived from $\omega = 2\pi f$, solving for frequency.

Flashcard 8: If a mass-spring system oscillates at $10 \text{ Hz}$, what is its period?

Answer: $T = 0.1 \text{ s}$. Using $T = \frac{1}{f} = \frac{1}{10} = 0.1$ s.

Flashcard 9: How does the period of SHM change if the amplitude is doubled?

Answer: No change. Period is independent of amplitude in SHM.

Flashcard 10: What is the angular frequency of a system with $T = 2 \text{ s}$?

Answer: $\omega = \pi \text{ rad/s}$. Using $\omega = \frac{2\pi}{T} = \frac{2\pi}{2} = \pi$ rad/s.

Flashcard 11: Calculate the period for a simple pendulum on the Moon with $L = 1 \text{ m}$ and $g = 1.6 \text{ m/s}^2$.

Answer: $T = 2\pi \sqrt{\frac{1}{1.6}} \approx 4.97 \text{ s}$. Using the pendulum formula with Moon's gravity.

Flashcard 12: What determines the period of a simple harmonic oscillator?

Answer: Mass and spring constant. These are the only factors in the period formula for springs.

Flashcard 13: State the effect of increasing gravity on the period of a pendulum.

Answer: Decreases the period. Period is inversely proportional to square root of gravity.

Flashcard 14: For a spring-mass system, if $m = 9 \text{ kg}$ and $k = 36 \text{ N/m}$, find $T$.

Answer: $T = 2\pi \sqrt{\frac{9}{36}} \approx 3.14 \text{ s}$. Using the spring-mass formula with given values.

Flashcard 15: What is the period of a wave with a frequency of $20 \text{ Hz}$?

Answer: $T = 0.05 \text{ s}$. Using $T = \frac{1}{f} = \frac{1}{20} = 0.05$ s.

Flashcard 16: What is the equation for the position of a mass in SHM as a function of time?

Answer: $x(t) = A \cos(\omega t + \phi)$. General form for position in simple harmonic motion.

Flashcard 17: What is the period of oscillation for a spring with $k = 100 \text{ N/m}$ and $m = 4 \text{ kg}$?

Answer: $T = 2\pi \sqrt{\frac{4}{100}} \approx 1.26 \text{ s}$. Using the spring-mass formula with given values.

Flashcard 18: Calculate the period for a spring system with $k = 200 \text{ N/m}$ and $m = 0.5 \text{ kg}$.

Answer: $T = 2\pi \sqrt{\frac{0.5}{200}} \approx 0.31 \text{ s}$. Using the spring-mass formula with given values.

Flashcard 19: What is the frequency of SHM when the system completes $50$ cycles in $10 \text{ s}$?

Answer: $f = 5 \text{ Hz}$. Using $f = \frac{\text{cycles}}{\text{time}} = \frac{50}{10} = 5$ Hz.

Flashcard 20: What is the formula for angular frequency?

Answer: $\omega = 2\pi f = \frac{2\pi}{T}$. Angular frequency relates to linear frequency and period.

Flashcard 21: Identify the unit of period in the International System of Units.

Answer: Seconds (s). Standard SI unit for time duration of one complete cycle.

Flashcard 22: Find the frequency if the angular frequency is $6\pi \text{ rad/s}$.

Answer: $f = 3 \text{ Hz}$. Using $f = \frac{\omega}{2\pi} = \frac{6\pi}{2\pi} = 3$ Hz.

Flashcard 23: Calculate the angular frequency for a system with frequency $8 \text{ Hz}$.

Answer: $\omega = 16\pi \text{ rad/s}$. Using $\omega = 2\pi f = 2\pi(8) = 16\pi$ rad/s.

Flashcard 24: What is the frequency of a simple pendulum with period $5 \text{ s}$?

Answer: $f = 0.2 \text{ Hz}$. Using $f = \frac{1}{T} = \frac{1}{5} = 0.2$ Hz.

Flashcard 25: Find the frequency if the period is $0.5 \text{ s}$.

Answer: $f = 2 \text{ Hz}$. Using $f = \frac{1}{T} = \frac{1}{0.5} = 2$ Hz.

Flashcard 26: What is the relationship between period and length for a pendulum?

Answer: Directly proportional to $\sqrt{L}$. Period increases with square root of length.

Flashcard 27: Which factors affect the period of a simple pendulum?

Answer: Length and gravity. These are the only factors in the period formula for pendulums.

Flashcard 28: What is the formula for the period of a mass-spring system?

Answer: $T = 2\pi \sqrt{\frac{m}{k}}$. Period depends on mass and spring constant for elastic oscillations.

Flashcard 29: Identify the unit of frequency in the International System of Units.

Answer: Hertz (Hz). Standard SI unit for cycles per second.

Flashcard 30: What is the period of a pendulum with $L = 2 \text{ m}$ on Mars where $g = 3.7 \text{ m/s}^2$?

Answer: $T = 2\pi \sqrt{\frac{2}{3.7}} \approx 4.6 \text{ s}$. Using the pendulum formula with Mars gravity.