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This deck focuses on Forces And Free Body Diagrams, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Forces And Free Body Diagrams in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify the main force that acts at a distance without contact.
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Gravitational force. Gravity acts between all masses without physical contact.
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This deck focuses on Forces And Free Body Diagrams, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Gravitational force. Gravity acts between all masses without physical contact.
Answer: Newton (N). Named after Isaac Newton; equivalent to kg⋅m/s2.
Answer: F=98 N. Using W=mg=10×9.8=98 N.
Answer: N m2kg−2. Units derived from F=Gr2m1m2 dimensional analysis.
Answer: Acceleration doubles. From F=ma; doubling force doubles acceleration for constant mass.
Answer: T=m(g+a). Tension must overcome weight plus provide upward acceleration force.
Answer: An object in motion stays in motion unless acted on by a net external force. Also called the law of inertia; objects resist changes in motion.
Answer: Net force is 0 N. Equal and opposite forces cancel completely.
Answer: F=ma. Force equals mass times acceleration; fundamental dynamics equation.
Answer: 5 N to the right. Net force: 8 N−3 N=5 N rightward.
Answer: N m2kg−2. Units derived from F=Gr2m1m2 dimensional analysis.
Answer: Towards the center of the circle. Centripetal force always points toward the center of circular motion.
Answer: Gravitational force increases. Force is proportional to both masses in gravitational equation.
Answer: fk=μkN. Kinetic friction equals coefficient times normal force.
Answer: Net force is 2 N in the direction of the larger force. Subtract opposing forces: 5 N−3 N=2 N.
Answer: Electrostatic force. Coulomb force between charges; can be attractive or repulsive.
Answer: Component of gravitational force parallel to the plane. Component mgsinθ acts parallel to inclined surface.
Answer: 25 N in the direction of both forces. Add forces in same direction: 10 N+15 N=25 N.
Answer: Friction doubles. Friction is directly proportional to normal force.
Answer: N=mgcosθ. Normal force is weight component perpendicular to inclined plane.
Answer: N=mgcosθ. Normal force is weight component perpendicular to inclined plane.
Answer: Frictional force. Kinetic and static friction resist sliding between contact surfaces.
Answer: Frictional force. Friction always opposes relative motion between surfaces in contact.
Answer: 25 N in the direction of both forces. Add forces in same direction: 10 N+15 N=25 N.
Answer: Centripetal force. The net inward force required for circular motion.
Answer: F=Gr2m1m2. Newton's law of universal gravitation relates force to masses and distance squared.
Answer: 5 N to the right. Net force: 8 N−3 N=5 N rightward.
Answer: For every action, there is an equal and opposite reaction. Forces always occur in equal and opposite pairs between objects.
Answer: Component of gravitational force parallel to the plane. Component mgsinθ acts parallel to inclined surface.
Answer: fk=15 N. Using fk=μkN=0.3×50=15 N.
Answer: Frictional force. Kinetic and static friction resist sliding between contact surfaces.
Answer: Frictional force. Friction always opposes relative motion between surfaces in contact.
Answer: For every action, there is an equal and opposite reaction. Forces always occur in equal and opposite pairs between objects.
Answer: Gravitational force increases. Force is proportional to both masses in gravitational equation.
Answer: Gravitational force. Earth's gravity provides centripetal force for orbital motion.
Answer: Tension equal to weight. Tension balances weight when elevator moves at constant velocity.
Answer: N=98 N. Normal force equals weight on horizontal surface: N=mg.
Answer: F=Gr2m1m2. Newton's law of universal gravitation relates force to masses and distance squared.
Answer: Net force is 0 N. Equal and opposite forces cancel completely.
Answer: Normal force. Normal force acts perpendicular to contact surfaces, preventing penetration.
Answer: Fc=rmv2. Force needed to maintain circular motion at constant speed.
Answer: T=m(g+a). Tension must overcome weight plus provide upward acceleration force.
Answer: Normal force. Normal force provides upward support equal to object's weight.
Answer: Tension equal to weight. Tension balances weight when elevator moves at constant velocity.
Answer: T=49 N. At rest, tension equals weight: T=mg=5×9.8=49 N.
Answer: Fc=rmv2. Force needed to maintain circular motion at constant speed.
Answer: Normal force. Normal force provides upward support equal to object's weight.
Answer: F=ma. Force equals mass times acceleration; fundamental dynamics equation.
Answer: W=mg. Weight equals mass times gravitational acceleration (g=9.8 m/s2).
Answer: fs≤μsN. Static friction can vary up to maximum value μsN.
Answer: F=−kx. Hooke's law; negative sign indicates force opposes displacement.
Answer: fs≤μsN. Static friction can vary up to maximum value μsN.
Answer: Towards the center of the circle. Centripetal force always points toward the center of circular motion.
Answer: Gravitational force. Gravity acts between all masses without physical contact.
Answer: Friction doubles. Friction is directly proportional to normal force.
Answer: fk=μkN. Kinetic friction equals coefficient times normal force.
Answer: Acceleration doubles. From F=ma; doubling force doubles acceleration for constant mass.
Answer: T=49 N. At rest, tension equals weight: T=mg=5×9.8=49 N.
Answer: Net force is 0 N. In equilibrium, all forces cancel out, resulting in zero net force.
Answer: Newton (N). Named after Isaac Newton; equivalent to kg⋅m/s2.
Answer: Fnet=mgsinθ−f. Gravity component minus friction determines net acceleration down plane.
Answer: fk=15 N. Using fk=μkN=0.3×50=15 N.
Answer: Normal force. Normal force acts perpendicular to contact surfaces, preventing penetration.
Answer: Fnet=mgsinθ−f. Gravity component minus friction determines net acceleration down plane.
Answer: Directly proportional. From Newton's second law: a=mF.
Answer: Weight is mass times gravitational acceleration. Mass is intrinsic; weight depends on gravitational field strength.
Answer: Weight is mass times gravitational acceleration. Mass is intrinsic; weight depends on gravitational field strength.
Answer: N=98 N. Normal force equals weight on horizontal surface: N=mg.
Answer: Centripetal force. The net inward force required for circular motion.
Answer: Gravitational force. Earth's gravity provides centripetal force for orbital motion.
Answer: F=−kx. Hooke's law; negative sign indicates force opposes displacement.
Answer: Net force is 0 N. In equilibrium, all forces cancel out, resulting in zero net force.
Answer: F=98 N. Using W=mg=10×9.8=98 N.
Answer: W=mg. Weight equals mass times gravitational acceleration (g=9.8 m/s2).
Answer: Electrostatic force. Coulomb force between charges; can be attractive or repulsive.
Answer: Net force is 2 N in the direction of the larger force. Subtract opposing forces: 5 N−3 N=2 N.
Answer: Directly proportional. From Newton's second law: a=mF.