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AP Physics 1 Flashcards: Circular Motion

Study Circular Motion in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Circular Motion, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Physics 1 Flashcards: Circular Motion

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QUESTION

Find frequency: T=0.1T=0.1T=0.1 s.

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ANSWER

101010 Hz. Using f=1/T=1/0.1=10f = 1/T = 1/0.1 = 10f=1/T=1/0.1=10 Hz.

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Flashcard 1: Find frequency: T=0.1T=0.1T=0.1 s.

Answer: 101010 Hz. Using f=1/T=1/0.1=10f = 1/T = 1/0.1 = 10f=1/T=1/0.1=10 Hz.

Flashcard 2: What is the relationship between period and angular velocity?

Answer: ω=2πT\omega = \frac{2\pi}{T}ω=T2π​. One complete revolution takes period TTT.

Flashcard 3: Identify the force responsible for circular motion.

Answer: Centripetal force. Net inward force maintains circular path.

Flashcard 4: Calculate period: f=0.5f=0.5f=0.5 Hz.

Answer: 222 s. Using T=1/f=1/0.5=2T = 1/f = 1/0.5 = 2T=1/f=1/0.5=2 s.

Flashcard 5: Calculate frequency: T=0.25T=0.25T=0.25 s.

Answer: 444 Hz. Using f=1/T=1/0.25=4f = 1/T = 1/0.25 = 4f=1/T=1/0.25=4 Hz.

Flashcard 6: What is centripetal acceleration?

Answer: Acceleration directed towards the center of circular path. Always points inward, creating circular motion.

Flashcard 7: What is angular velocity?

Answer: Rate of change of angular displacement. How fast angle changes with time.

Flashcard 8: Define period in circular motion.

Answer: Time to complete one full revolution. Complete cycle duration in circular motion.

Flashcard 9: State the formula for angular displacement.

Answer: θ=ωt\theta = \omega tθ=ωt. Angle equals angular velocity times time.

Flashcard 10: State the relationship between period and frequency.

Answer: T=1fT = \frac{1}{f}T=f1​. Period and frequency are reciprocals.

Flashcard 11: Calculate tangential velocity: r=3r=3r=3 m, ω=2\omega=2ω=2 rad/s.

Answer: 666 m/s. Using v=rω=3×2=6v = r\omega = 3 \times 2 = 6v=rω=3×2=6 m/s.

Flashcard 12: What is the relationship between tangential speed and radius?

Answer: Directly proportional. Larger radius gives higher tangential speed.

Flashcard 13: Identify the cause of centripetal acceleration.

Answer: Change in direction of velocity. Velocity direction changes continuously in circles.

Flashcard 14: Define radial acceleration.

Answer: Acceleration towards the center of circular path. Same as centripetal acceleration definition.

Flashcard 15: Find the force: m=3m=3m=3 kg, ac=4a_c=4ac​=4 m/s².

Answer: 121212 N. Using F=ma=3×4=12F = ma = 3 \times 4 = 12F=ma=3×4=12 N.

Flashcard 16: State the formula for angular velocity.

Answer: ω=ΔθΔt\omega = \frac{\Delta\theta}{\Delta t}ω=ΔtΔθ​. Change in angle divided by time interval.

Flashcard 17: Calculate centripetal force: m=2m=2m=2 kg, v=3v=3v=3 m/s, r=1r=1r=1 m.

Answer: 181818 N. Using Fc=mv2/r=2(32)/1=18F_c = mv^2/r = 2(3^2)/1 = 18Fc​=mv2/r=2(32)/1=18 N.

Flashcard 18: Describe the relationship between frequency and angular velocity.

Answer: ω=2πf\omega = 2\pi fω=2πf. One revolution equals 2π2\pi2π radians.

Flashcard 19: Find the period given frequency of 2 Hz.

Answer: 0.5 s. Using T=1/f=1/2=0.5T = 1/f = 1/2 = 0.5T=1/f=1/2=0.5 s.

Flashcard 20: State the formula for centripetal force.

Answer: Fc=mv2rF_c = \frac{mv^2}{r}Fc​=rmv2​. Newton's second law applied to circular motion.

Flashcard 21: What is uniform circular motion?

Answer: Motion in a circle with constant speed. Constant speed but changing direction.

Flashcard 22: What is the unit of angular velocity?

Answer: Radians per second (rad/s). Standard unit for rotational speed.

Flashcard 23: Define angular displacement.

Answer: Angle through which a point or line is rotated. Measures rotational position change.

Flashcard 24: State the formula for centripetal acceleration.

Answer: ac=v2ra_c = \frac{v^2}{r}ac​=rv2​. Speed squared divided by radius gives centripetal acceleration.

Flashcard 25: What is the direction of centripetal force?

Answer: Towards the center of the circular path. Always points inward to maintain circular path.

Flashcard 26: Define frequency in circular motion.

Answer: Number of revolutions per unit time. How many cycles occur per second.

Flashcard 27: What is tangential velocity?

Answer: Velocity tangent to the circular path. Speed along the circular path's edge.

Flashcard 28: Calculate centripetal acceleration: v=4v=4v=4 m/s, r=2r=2r=2 m.

Answer: 888 m/s². Using ac=v2/r=42/2=8a_c = v^2/r = 4^2/2 = 8ac​=v2/r=42/2=8 m/s².

Flashcard 29: Find angular velocity: θ=π/2\theta=\pi/2θ=π/2 rad, t=2t=2t=2 s.

Answer: π/4\pi/4π/4 rad/s. Using ω=θ/t=(π/2)/2=π/4\omega = \theta/t = (\pi/2)/2 = \pi/4ω=θ/t=(π/2)/2=π/4 rad/s.

Flashcard 30: What is the effect of increasing radius on centripetal force?

Answer: Decreases centripetal force for constant velocity. Force inversely proportional to radius.