Practice Test 11

Consider the expression a && b || c && d. Due to operator precedence, this expression is evaluated as (a && b) || (c && d). If you wanted to force the evaluation to be a && (b || c) && d, which parentheses placement would be correct?

In Java, short-circuit evaluation means that in the expression a && b, if a is false, then b is not evaluated. Consider the expression (x != 0) && (y / x > 5). Why is short-circuit evaluation particularly important in this case?