Introduction to Equilibrium
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AP Chemistry › Introduction to Equilibrium
The reversible decomposition reaction $2\text{NOCl}(g) \rightleftharpoons 2\text{NO}(g)+\text{Cl}_2(g)$ is carried out in a sealed container at constant temperature. After some time, the measured concentrations remain constant.
Which statement correctly describes the system at equilibrium?
The forward reaction rate is greater than the reverse rate, but the net change is zero.
The concentrations are constant because the reaction has completely stopped.
The forward and reverse reaction rates are equal, so composition stays constant.
The concentrations are constant because the reactant and product concentrations are equal.
Only the reverse reaction occurs, preventing any further concentration change.
Explanation
This question assesses the description of equilibrium in terms of rates and concentrations for decomposition reactions. For 2NOCl(g) ⇌ 2NO(g) + Cl₂(g), constant concentrations at equilibrium mean the forward and reverse reaction rates are equal, preventing net changes in composition. This indicates ongoing decomposition and reformation at matching rates. The core principle is that equilibrium is dynamic, with continuous molecular activity. Choice A is a distractor suggesting the reaction has completely stopped, which stems from the misconception that constant concentrations imply no reaction, whereas reactions proceed but balance out. A strategy for these problems is to link macroscopic observations like constant concentrations to microscopic rate equality, aiding in distinguishing true equilibrium characteristics.
A student studies the reversible reaction $\text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g)+\text{Cl}_2(g)$ in a closed container at constant temperature. After sufficient time, the measured concentrations of all gases remain constant.
Which statement best describes the meaning of equilibrium for this system?
The equilibrium mixture must contain equal concentrations of all three gases.
The reverse reaction rate is zero because no more $\text{PCl}_5$ can form.
The system has reached equilibrium, so the reaction has stopped permanently.
The forward and reverse reactions still occur, and their rates are equal.
Only the decomposition of $\text{PCl}_5$ occurs once concentrations become constant.
Explanation
This question evaluates the meaning of equilibrium in a dissociation reaction context. For PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), constant gas concentrations mean the forward and reverse reactions occur at equal rates, with decomposition and recombination balancing out. This dynamic state keeps the system stable over time. The principle emphasizes that equilibrium involves persistent reactions in both directions, not a halt. Choice B distracts by implying equal concentrations of all gases, based on the misconception that equilibrium equates to equal amounts rather than just rate equality, as actual ratios depend on the equilibrium constant. A transferable approach is to interpret equilibrium as rate balance, using this to evaluate statements about reaction progress and system states.
A reversible reaction $\text{Br}_2(l) \rightleftharpoons \text{Br}_2(g)$ occurs in a closed container at constant temperature. Over time, the amount of liquid bromine and bromine vapor each becomes constant.
Which statement best describes equilibrium for this system?
Molecules stop moving between phases once equilibrium is reached.
Only condensation continues because the system has reached equilibrium.
Evaporation and condensation both occur, and their rates are equal.
The amounts of liquid and gas must be equal at equilibrium.
All bromine becomes gas, so there is no longer any liquid present.
Explanation
This question tests the concept of phase equilibrium in a closed system. For Br₂(l) ⇌ Br₂(g), when the amounts of liquid and vapor become constant, evaporation and condensation are both occurring, with their rates equal, maintaining a balance. This means liquid molecules continue to enter the gas phase while gas molecules return to liquid at the same rate. The principle is dynamic equilibrium, where phase changes persist but net transfer is zero. Choice C is a common distractor, suggesting equal amounts of liquid and gas, which comes from the misconception that equilibrium requires equal quantities in each phase, whereas it actually depends on vapor pressure and temperature, not equal masses. A transferable strategy is to recognize that equilibrium in any system, chemical or physical, involves equal rates of opposing processes, ensuring constant macroscopic properties.
A reversible reaction $\text{CO}(g)+\text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g)$ is allowed to proceed in a sealed container at constant temperature. After a period of time, the concentrations no longer change.
Which description best matches the system at equilibrium?
The reaction has stopped because the system has reached maximum product.
The forward reaction continues, but the reverse reaction has stopped.
The concentrations of all species are equal because the rates are equal.
Both reactions occur, and the forward and reverse rates are equal.
No molecular-level changes occur because particles stop moving at equilibrium.
Explanation
This question assesses the understanding of what occurs at equilibrium in a reversible reaction system. In the reaction CO(g) + Cl₂(g) ⇌ COCl₂(g), once concentrations no longer change in a sealed container, both the forward and reverse reactions are proceeding, but their rates are equal, leading to no net concentration changes. This dynamic equilibrium means molecules are constantly reacting in both directions at the same rate. The principle highlights that equilibrium is not a cessation of reaction but a balance of opposing processes. Choice C is a common distractor, suggesting all species have equal concentrations because rates are equal, which arises from the misconception that rate equality implies concentration equality, whereas actual concentrations are determined by the equilibrium constant. When analyzing equilibrium questions, always recall that constant concentrations result from equal forward and reverse rates, not from reactions stopping or concentrations being identical.
A student investigates the reversible reaction $\text{Fe}^{3+}(aq)+\text{SCN}^-(aq) \rightleftharpoons \text{FeSCN}^{2+}(aq)$ in a closed beaker at constant temperature. After mixing, the solution’s composition becomes constant with time.
Which statement best describes the equilibrium state?
The reaction stops, so no ions form or break apart anymore.
The reverse reaction rate is zero because complex formation is complete.
The concentrations of $\text{Fe}^{3+}$ and $\text{FeSCN}^{2+}$ must be equal.
The system contains only $\text{FeSCN}^{2+}$ once equilibrium is reached.
The forward reaction rate equals the reverse reaction rate.
Explanation
This question examines the rate perspective of equilibrium in complex ion formation. In Fe³⁺(aq) + SCN⁻(aq) ⇌ FeSCN²⁺(aq), constant composition means the forward rate of complex formation equals the reverse rate of dissociation, so both processes continue equally. This balance keeps the concentrations stable despite ongoing reactions. The dynamic equilibrium principle underscores that ions are constantly associating and dissociating at the same rate. Choice C tempts by claiming Fe³⁺ and FeSCN²⁺ concentrations must be equal, reflecting the misconception that equilibrium demands equal reactant and product amounts, but concentrations are governed by the equilibrium constant, not equality. When solving equilibrium questions, emphasize that rate equality, not concentration equality or reaction stoppage, defines the state.
In a sealed flask at constant temperature, the reversible reaction $\text{CH}_3\text{COOH}(aq) \rightleftharpoons \text{H}^+(aq)+\text{CH}_3\text{COO}^-(aq)$ is monitored. After some time, the concentrations of all species remain constant.
What does this indicate about the forward and reverse processes at equilibrium?
The reaction has stopped, so the forward and reverse rates are both zero.
The forward rate is greater than the reverse rate, but changes are too small to detect.
The concentrations of $\text{H}^+$ and $\text{CH}_3\text{COO}^-$ must equal the concentration of $\text{CH}_3\text{COOH}$.
The forward rate equals the reverse rate, so concentrations remain constant.
Only the reverse reaction occurs once equilibrium is reached.
Explanation
This question probes the understanding of forward and reverse processes in acid dissociation equilibrium. In the reaction CH₃COOH(aq) ⇌ H⁺(aq) + CH₃COO⁻(aq), constant concentrations indicate equilibrium, where the forward dissociation rate equals the reverse recombination rate, resulting in no net change. This means acetic acid molecules continue to ionize while ions reform the acid at the same rate. The principle of dynamic equilibrium applies, emphasizing ongoing reactions in both directions. Choice A is a tempting distractor, stating the reaction has stopped with zero rates, which embodies the misconception that equilibrium is static rather than a dynamic balance of rates. To tackle equilibrium problems, identify constant concentrations as a sign of rate equality, not reaction termination, and apply this to predict system behavior.
The reversible reaction $\text{CO}(g) + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g)$ occurs in a sealed vessel at constant temperature. After some time, the amounts of reactants and product remain unchanged. Which statement best describes the molecular-level situation at equilibrium?
The reaction has stopped, so no $\text{COCl}_2$ molecules form or break apart.
The reverse reaction rate is greater than the forward reaction rate, but concentrations stay constant.
The amounts of reactants and products are equal, so the rates must be equal.
The forward and reverse reactions continue at equal rates, maintaining constant concentrations.
Only molecules with the highest kinetic energy continue reacting at equilibrium.
Explanation
This question evaluates knowledge of the molecular-level behavior at chemical equilibrium for reversible reactions. In the system CO(g) + Cl₂(g) ⇌ COCl₂(g), the unchanged amounts of reactants and product signify that equilibrium has been established. At this point, the forward and reverse reactions continue but at identical rates, ensuring constant concentrations without net change. The underlying principle is that equilibrium is a dynamic state where molecular collisions and reactions persist in both directions equally. Choice C tempts by suggesting equal amounts imply equal rates, but this misinterprets equilibrium as requiring stoichiometric equality instead of rate balance. A useful strategy is to differentiate between static cessation and dynamic balance when describing equilibrium conditions.
A closed container holds the reversible reaction $\text{Fe}^{3+}(aq) + \text{SCN}^-(aq) \rightleftharpoons \text{FeSCN}^{2+}(aq)$. After mixing, the solution’s color becomes constant and stays constant at a fixed temperature. What does equilibrium mean in terms of the processes occurring in solution?
Formation and dissociation occur at equal rates, so concentrations remain constant.
Complex formation continues while dissociation stops, keeping the color constant.
Particles stop moving between states because equilibrium eliminates collisions.
The concentrations of $\text{Fe}^{3+}$ and $\text{FeSCN}^{2+}$ must be equal.
All ions have been converted to complex, so no further reaction can occur.
Explanation
This question examines the equilibrium dynamics in complex ion formation. For Fe³⁺(aq) + SCN⁻(aq) ⇌ FeSCN²⁺(aq), the constant color after mixing shows equilibrium, as color relates to the concentration of the red complex. At equilibrium, the rates of complex formation and dissociation are equal, maintaining steady concentrations and thus constant color. The dynamic equilibrium principle means ions continue to form and break apart the complex, but with no net change observable. Choice D is a common error, suggesting equal concentrations of Fe³⁺ and FeSCN²⁺, which confuses the equilibrium condition with stoichiometric balance instead of rate equality. For equilibrium problems involving observables like color, link stability to equal opposing rates as a key strategy.
A closed container holds the reversible reaction $\text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g)$ at constant temperature. After a period of time, the measured concentrations of all species remain constant. What does this indicate about the reaction at equilibrium?
The reaction has stopped because the reactants have been completely used up.
The concentrations of $\text{H}_2$, $\text{I}_2$, and $\text{HI}$ must be equal.
Only product molecules react at equilibrium, converting back to reactants.
The forward and reverse reactions occur at equal rates, so there is no net change.
The collision frequency becomes zero, preventing further reaction.
Explanation
This question assesses the concept of dynamic equilibrium where reaction rates equalize in a closed system. For the reaction H₂(g) + I₂(g) ⇌ 2HI(g), the constant concentrations after time indicate that the system has reached equilibrium. This occurs because the rate of the forward reaction equals the rate of the reverse reaction, leading to no net change in the amounts of reactants and products. The principle of chemical equilibrium emphasizes that this balance is dynamic, with continuous formation and decomposition of HI molecules. Choice C is a common distractor, wrongly assuming concentrations must be equal at equilibrium, which confuses equilibrium with equal amounts rather than equal rates. When analyzing equilibrium questions, focus on rate equality rather than concentration equality to identify the correct description.
In a closed container, $\text{NH}_3(g)$ and $\text{HCl}(g)$ undergo the reversible reaction $\text{NH}_3(g)+\text{HCl}(g)\rightleftharpoons \text{NH}_4\text{Cl}(s)$. After some time, the observable amounts of gas and solid remain constant. What best explains equilibrium in this system?
Equilibrium occurs only if the amounts of $\text{NH}_3$ and $\text{HCl}$ are equal.
The forward and reverse processes occur at equal rates, so amounts stay constant.
The gases have been completely consumed, so no further change is possible.
The solid stops forming, but the solid continues decomposing into gases.
All particle motion ceases, preventing additional reaction.
Explanation
This question tests understanding of equilibrium in heterogeneous systems involving gases and solids. At equilibrium, NH₃ and HCl gases continue to combine to form solid NH₄Cl, while the solid simultaneously sublimes back into gaseous NH₃ and HCl, with both processes occurring at equal rates. This dynamic balance maintains constant amounts of both gaseous and solid phases. Choice B incorrectly suggests solid formation stops while decomposition continues, which would lead to decreasing solid and increasing gas amounts. Remember that equilibrium in heterogeneous systems still involves equal rates of opposing processes, regardless of the phases involved.