Pre-Equilibrium Approximation - AP Chemistry
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What do we assume about intermediate concentration in pre-equilibrium approximation?
What do we assume about intermediate concentration in pre-equilibrium approximation?
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Concentration remains constant over time. Equilibrium established faster than consumption in slow step.
Concentration remains constant over time. Equilibrium established faster than consumption in slow step.
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In pre-equilibrium, what balances the rate of intermediate formation and consumption?
In pre-equilibrium, what balances the rate of intermediate formation and consumption?
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Equilibrium condition. Forward and reverse rates equal in fast step.
Equilibrium condition. Forward and reverse rates equal in fast step.
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What is the first step in applying pre-equilibrium approximation?
What is the first step in applying pre-equilibrium approximation?
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Identify the fast equilibrium step. Required before deriving rate law from mechanism.
Identify the fast equilibrium step. Required before deriving rate law from mechanism.
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What role does the equilibrium constant $K$ play in pre-equilibrium approximation?
What role does the equilibrium constant $K$ play in pre-equilibrium approximation?
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Relates intermediate and reactant concentrations. Links intermediate concentration to initial reactants.
Relates intermediate and reactant concentrations. Links intermediate concentration to initial reactants.
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How is the rate constant $k'$ related to $k$ and $K$ in pre-equilibrium?
How is the rate constant $k'$ related to $k$ and $K$ in pre-equilibrium?
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$k' = k \times K$. Product of rate constant and equilibrium constant.
$k' = k \times K$. Product of rate constant and equilibrium constant.
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What is a critical assumption about intermediate concentration in pre-equilibrium?
What is a critical assumption about intermediate concentration in pre-equilibrium?
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It remains nearly constant. Equilibrium condition maintains stable intermediate concentration.
It remains nearly constant. Equilibrium condition maintains stable intermediate concentration.
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What is a key characteristic of the intermediate in pre-equilibrium?
What is a key characteristic of the intermediate in pre-equilibrium?
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Rapidly forms and decomposes. Fast equilibration between formation and decomposition reactions.
Rapidly forms and decomposes. Fast equilibration between formation and decomposition reactions.
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Which assumption is critical for pre-equilibrium approximation?
Which assumption is critical for pre-equilibrium approximation?
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Intermediate is in equilibrium with reactants. Fast step equilibrium before slow step determines rate.
Intermediate is in equilibrium with reactants. Fast step equilibrium before slow step determines rate.
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What do we assume about intermediate concentration in pre-equilibrium approximation?
What do we assume about intermediate concentration in pre-equilibrium approximation?
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Concentration remains constant over time. Equilibrium established faster than consumption in slow step.
Concentration remains constant over time. Equilibrium established faster than consumption in slow step.
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Find the error: 'Pre-equilibrium approximation assumes steady state.'
Find the error: 'Pre-equilibrium approximation assumes steady state.'
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Correct: 'assumes equilibrium, not steady state.'. Pre-equilibrium involves equilibrium, not steady-state conditions.
Correct: 'assumes equilibrium, not steady state.'. Pre-equilibrium involves equilibrium, not steady-state conditions.
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State the typical rate law form derived using pre-equilibrium approximation.
State the typical rate law form derived using pre-equilibrium approximation.
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Rate = $k'[\text{reactants}]^{\text{coefficients}}$. Combined rate and equilibrium constants for overall reaction.
Rate = $k'[\text{reactants}]^{\text{coefficients}}$. Combined rate and equilibrium constants for overall reaction.
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What is the relationship between $k'$ and $K$ in a derived rate law?
What is the relationship between $k'$ and $K$ in a derived rate law?
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$k' = k \times K$. Effective rate constant combines kinetic and equilibrium factors.
$k' = k \times K$. Effective rate constant combines kinetic and equilibrium factors.
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Find the error: 'Pre-equilibrium applies to irreversible reactions.'
Find the error: 'Pre-equilibrium applies to irreversible reactions.'
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Correct: 'applies to reversible reactions.'. Pre-equilibrium requires reversible steps to establish equilibrium.
Correct: 'applies to reversible reactions.'. Pre-equilibrium requires reversible steps to establish equilibrium.
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What is one advantage of using pre-equilibrium approximation?
What is one advantage of using pre-equilibrium approximation?
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Simplifies calculation of rate laws. Reduces complex mechanisms to simple rate expressions.
Simplifies calculation of rate laws. Reduces complex mechanisms to simple rate expressions.
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Identify the error: 'Pre-equilibrium applies to steady-state conditions.'
Identify the error: 'Pre-equilibrium applies to steady-state conditions.'
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Correct: 'applies to equilibrium conditions.'. Pre-equilibrium requires equilibrium conditions, not steady-state.
Correct: 'applies to equilibrium conditions.'. Pre-equilibrium requires equilibrium conditions, not steady-state.
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Why is the pre-equilibrium approximation useful in complex reactions?
Why is the pre-equilibrium approximation useful in complex reactions?
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Simplifies the rate law expression. Eliminates need for complex intermediate concentration terms.
Simplifies the rate law expression. Eliminates need for complex intermediate concentration terms.
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Identify the step in a mechanism where pre-equilibrium is assumed.
Identify the step in a mechanism where pre-equilibrium is assumed.
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The fast initial step. The reversible step that reaches equilibrium quickly.
The fast initial step. The reversible step that reaches equilibrium quickly.
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What happens to intermediates in pre-equilibrium approximation?
What happens to intermediates in pre-equilibrium approximation?
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They quickly reach equilibrium with reactants. Fast equilibrium maintained throughout reaction course.
They quickly reach equilibrium with reactants. Fast equilibrium maintained throughout reaction course.
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Which condition must be met for using pre-equilibrium approximation?
Which condition must be met for using pre-equilibrium approximation?
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Fast step reaches equilibrium before slow step occurs. Fast equilibrium must precede slow rate-determining step.
Fast step reaches equilibrium before slow step occurs. Fast equilibrium must precede slow rate-determining step.
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What typically characterizes the initial step in pre-equilibrium?
What typically characterizes the initial step in pre-equilibrium?
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It is rapid and reversible. Fast forward and reverse rates establish equilibrium.
It is rapid and reversible. Fast forward and reverse rates establish equilibrium.
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What is the principle of pre-equilibrium approximation?
What is the principle of pre-equilibrium approximation?
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Assumes early equilibrium in a reaction mechanism. Fast step reaches equilibrium before proceeding to slow step.
Assumes early equilibrium in a reaction mechanism. Fast step reaches equilibrium before proceeding to slow step.
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Identify the key condition for using pre-equilibrium in a mechanism.
Identify the key condition for using pre-equilibrium in a mechanism.
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Initial step is fast and reversible. Fast reversible step required for equilibrium assumption.
Initial step is fast and reversible. Fast reversible step required for equilibrium assumption.
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How does pre-equilibrium approximation affect reaction mechanisms?
How does pre-equilibrium approximation affect reaction mechanisms?
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Simplifies complex mechanisms into rate laws. Makes complex multi-step reactions mathematically tractable.
Simplifies complex mechanisms into rate laws. Makes complex multi-step reactions mathematically tractable.
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What is an incorrect use of pre-equilibrium approximation?
What is an incorrect use of pre-equilibrium approximation?
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Applying to irreversible reactions. Requires reversible steps to establish equilibrium conditions.
Applying to irreversible reactions. Requires reversible steps to establish equilibrium conditions.
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What is the role of $K$ in pre-equilibrium rate laws?
What is the role of $K$ in pre-equilibrium rate laws?
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Relates initial concentrations and intermediate. Connects initial species concentrations to intermediate levels.
Relates initial concentrations and intermediate. Connects initial species concentrations to intermediate levels.
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State the main difference in assumptions between pre-equilibrium and steady-state.
State the main difference in assumptions between pre-equilibrium and steady-state.
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Equilibrium vs. constant concentration assumptions. Different underlying principles for each approximation method.
Equilibrium vs. constant concentration assumptions. Different underlying principles for each approximation method.
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What is the equilibrium constant expression in pre-equilibrium?
What is the equilibrium constant expression in pre-equilibrium?
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$K = \frac{[\text{products}]}{[\text{reactants}]}$. Ratio of product to reactant concentrations at equilibrium.
$K = \frac{[\text{products}]}{[\text{reactants}]}$. Ratio of product to reactant concentrations at equilibrium.
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In pre-equilibrium, how is the overall rate law determined?
In pre-equilibrium, how is the overall rate law determined?
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Derived from the slow step using equilibrium expressions. Rate law comes from slow step with equilibrium substitution.
Derived from the slow step using equilibrium expressions. Rate law comes from slow step with equilibrium substitution.
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How can pre-equilibrium approximation help in kinetics?
How can pre-equilibrium approximation help in kinetics?
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Allows simplification of complex mechanisms. Converts complex mechanisms into manageable rate expressions.
Allows simplification of complex mechanisms. Converts complex mechanisms into manageable rate expressions.
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What is the primary difference between steady-state and pre-equilibrium approximations?
What is the primary difference between steady-state and pre-equilibrium approximations?
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Steady-state assumes constant intermediate concentration. Pre-equilibrium assumes equilibrium, not steady state.
Steady-state assumes constant intermediate concentration. Pre-equilibrium assumes equilibrium, not steady state.
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