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AP Chemistry Flashcards: Introduction To Solubility Equilibria

Study Introduction To Solubility Equilibria in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Introduction To Solubility Equilibria, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Chemistry Flashcards: Introduction To Solubility Equilibria

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QUESTION

How does KspK_{sp}Ksp​ change with temperature for exothermic reactions?

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ANSWER

KspK_{sp}Ksp​ decreases with temperature. Lower temperature favors exothermic dissolution process.

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Flashcard 1: How does KspK_{sp}Ksp​ change with temperature for exothermic reactions?

Answer: KspK_{sp}Ksp​ decreases with temperature. Lower temperature favors exothermic dissolution process.

Flashcard 2: Determine KspK_{sp}Ksp​ for Ag2SAg_2SAg2​S if [Ag+]=2x[Ag^+] = 2x[Ag+]=2x and [S2−]=x[S^{2-}] = x[S2−]=x at equilibrium.

Answer: Ksp=4x3K_{sp} = 4x^3Ksp​=4x3. Substitute equilibrium concentrations: (2x)2(x)=4x3(2x)^2(x) = 4x^3(2x)2(x)=4x3.

Flashcard 3: How does KspK_{sp}Ksp​ change with temperature for exothermic reactions?

Answer: KspK_{sp}Ksp​ decreases with temperature. Lower temperature favors exothermic dissolution process.

Flashcard 4: What is the relationship between KspK_{sp}Ksp​ and QspQ_{sp}Qsp​?

Answer: Precipitation occurs if Qsp>KspQ_{sp} > K_{sp}Qsp​>Ksp​. QspQ_{sp}Qsp​ compares current ion concentrations to equilibrium values.

Flashcard 5: What does a large KspK_{sp}Ksp​ value indicate about solubility?

Answer: Compound is more soluble. Higher KspK_{sp}Ksp​ means more ions can dissolve at equilibrium.

Flashcard 6: What is the effect of adding NH3NH_3NH3​ to AgClAgClAgCl solubility?

Answer: Increases due to complexation. NH3NH_3NH3​ forms [Ag(NH3)2]+[Ag(NH_3)_2]^+[Ag(NH3​)2​]+ complex, removing Ag+Ag^+Ag+ ions.

Flashcard 7: What is the effect of pHpHpH on the solubility of Mg(OH)2Mg(OH)_2Mg(OH)2​?

Answer: Solubility decreases at higher pHpHpH. Higher pHpHpH increases [OH−][OH^-][OH−], shifting equilibrium toward solid.

Flashcard 8: Identify the KspK_{sp}Ksp​ expression for Ca3(PO4)2Ca_3(PO_4)_2Ca3​(PO4​)2​.

Answer: Ksp=[Ca2+]3[PO43−]2K_{sp} = [Ca^{2+}]^3[PO_4^{3-}]^2Ksp​=[Ca2+]3[PO43−​]2. Stoichiometry: 3 Ca2+Ca^{2+}Ca2+ and 2 PO43−PO_4^{3-}PO43−​ per formula unit.

Flashcard 9: How does the presence of a common ion affect solubility?

Answer: Decreases solubility. Le Chatelier's principle: excess ion shifts equilibrium toward solid.

Flashcard 10: What is the KspK_{sp}Ksp​ expression for Al(OH)3Al(OH)_3Al(OH)3​?

Answer: Ksp=[Al3+][OH−]3K_{sp} = [Al^{3+}][OH^-]^3Ksp​=[Al3+][OH−]3. Aluminum hydroxide: 1 Al3+Al^{3+}Al3+ and 3 OH−OH^-OH− ions.

Flashcard 11: Identify the KspK_{sp}Ksp​ expression for BaSO4BaSO_4BaSO4​.

Answer: Ksp=[Ba2+][SO42−]K_{sp} = [Ba^{2+}][SO_4^{2-}]Ksp​=[Ba2+][SO42−​]. 1:1 stoichiometry gives simple product of ion concentrations.

Flashcard 12: What is the solubility product constant (KspK_{sp}Ksp​) expression for AgClAgClAgCl?

Answer: Ksp=[Ag+][Cl−]K_{sp} = [Ag^+][Cl^-]Ksp​=[Ag+][Cl−]. Product of ion concentrations at equilibrium for the saturated solution.

Flashcard 13: Identify the KspK_{sp}Ksp​ expression for CuSCuSCuS.

Answer: Ksp=[Cu2+][S2−]K_{sp} = [Cu^{2+}][S^{2-}]Ksp​=[Cu2+][S2−]. 1:1 stoichiometry for copper(II) sulfide dissolution.

Flashcard 14: How does complex ion formation affect solubility?

Answer: Increases solubility. Complex formation removes free metal ions from solution.

Flashcard 15: Identify the KspK_{sp}Ksp​ expression for PbSO4PbSO_4PbSO4​.

Answer: Ksp=[Pb2+][SO42−]K_{sp} = [Pb^{2+}][SO_4^{2-}]Ksp​=[Pb2+][SO42−​]. 1:1 stoichiometry for lead(II) sulfate dissolution.

Flashcard 16: Which has higher solubility: BaSO4BaSO_4BaSO4​ or SrSO4SrSO_4SrSO4​?

Answer: SrSO4SrSO_4SrSO4​ (higher KspK_{sp}Ksp​ value). Compare KspK_{sp}Ksp​ values; larger value indicates higher solubility.

Flashcard 17: Which compound will precipitate first: AgClAgClAgCl or AgBrAgBrAgBr?

Answer: AgBrAgBrAgBr (lower KspK_{sp}Ksp​ value). Lower KspK_{sp}Ksp​ means less soluble, so precipitates first.

Flashcard 18: State the formula to calculate QspQ_{sp}Qsp​.

Answer: Qsp=[cation]m[anion]nQ_{sp} = [cation]^m[anion]^nQsp​=[cation]m[anion]n. Same form as KspK_{sp}Ksp​ but uses current concentrations, not equilibrium.

Flashcard 19: What is the KspK_{sp}Ksp​ expression for Fe(OH)3Fe(OH)_3Fe(OH)3​?

Answer: Ksp=[Fe3+][OH−]3K_{sp} = [Fe^{3+}][OH^-]^3Ksp​=[Fe3+][OH−]3. Stoichiometry: 1 Fe3+Fe^{3+}Fe3+ and 3 OH−OH^-OH− ions per formula unit.

Flashcard 20: Identify the KspK_{sp}Ksp​ expression for Hg2Cl2Hg_2Cl_2Hg2​Cl2​.

Answer: Ksp=[Hg22+][Cl−]2K_{sp} = [Hg_2^{2+}][Cl^-]^2Ksp​=[Hg22+​][Cl−]2. Dimeric mercury(I) ion has +2 charge with two chlorides.

Flashcard 21: Identify the effect of temperature on KspK_{sp}Ksp​ for endothermic dissolution.

Answer: KspK_{sp}Ksp​ increases with temperature. Higher temperature favors endothermic dissolution process.

Flashcard 22: How does pHpHpH affect solubility of compounds containing basic anions?

Answer: Increases solubility at lower pHpHpH. Acidic conditions protonate basic anions, reducing their concentration.

Flashcard 23: Which compound is more soluble: CaF2CaF_2CaF2​ or SrF2SrF_2SrF2​?

Answer: SrF2SrF_2SrF2​ (higher KspK_{sp}Ksp​ value). Compare KspK_{sp}Ksp​ values directly for same formula type.

Flashcard 24: What is KspK_{sp}Ksp​ for PbCl2PbCl_2PbCl2​ given solubility sss?

Answer: Ksp=4s3K_{sp} = 4s^3Ksp​=4s3. For PbCl2PbCl_2PbCl2​: Ksp=s(2s)2=4s3K_{sp} = s(2s)^2 = 4s^3Ksp​=s(2s)2=4s3.

Flashcard 25: Identify the common ion effect in solubility equilibria.

Answer: Reduction in solubility due to a common ion. Adding an ion already present shifts equilibrium toward solid formation.

Flashcard 26: Calculate KspK_{sp}Ksp​ for Ag2SAg_2SAg2​S with [Ag+]=2x[Ag^+] = 2x[Ag+]=2x and [S2−]=x[S^{2-}] = x[S2−]=x.

Answer: Ksp=4x3K_{sp} = 4x^3Ksp​=4x3. For Ag2SAg_2SAg2​S: Ksp=[Ag+]2[S2−]=(2x)2(x)=4x3K_{sp} = [Ag^+]^2[S^{2-}] = (2x)^2(x) = 4x^3Ksp​=[Ag+]2[S2−]=(2x)2(x)=4x3.

Flashcard 27: Identify the KspK_{sp}Ksp​ expression for CdSCdSCdS.

Answer: Ksp=[Cd2+][S2−]K_{sp} = [Cd^{2+}][S^{2-}]Ksp​=[Cd2+][S2−]. 1:1 stoichiometry for cadmium sulfide dissolution.

Flashcard 28: Determine KspK_{sp}Ksp​ for Ag2SAg_2SAg2​S if [Ag+]=2x[Ag^+] = 2x[Ag+]=2x and [S2−]=x[S^{2-}] = x[S2−]=x at equilibrium.

Answer: Ksp=4x3K_{sp} = 4x^3Ksp​=4x3. Substitute equilibrium concentrations: (2x)2(x)=4x3(2x)^2(x) = 4x^3(2x)2(x)=4x3.

Flashcard 29: Identify the KspK_{sp}Ksp​ expression for CdSCdSCdS.

Answer: Ksp=[Cd2+][S2−]K_{sp} = [Cd^{2+}][S^{2-}]Ksp​=[Cd2+][S2−]. 1:1 stoichiometry for cadmium sulfide dissolution.

Flashcard 30: What is the unit of KspK_{sp}Ksp​ for CaF2CaF_2CaF2​?

Answer: mol^3/L^3. Units from [Ca2+][F−]2[Ca^{2+}][F^-]^2[Ca2+][F−]2 concentration terms.