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AP Chemistry Flashcards: Gibbs Free Energy And Thermodynamic Favorability

Study Gibbs Free Energy And Thermodynamic Favorability in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Gibbs Free Energy And Thermodynamic Favorability, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Chemistry Flashcards: Gibbs Free Energy And Thermodynamic Favorability

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QUESTION

Which variable in ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta SΔG=ΔH−TΔS is affected by temperature changes?

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ANSWER

The TΔST\Delta STΔS term. Only the entropy term TΔST\Delta STΔS contains temperature as a variable.

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Flashcard 1: Which variable in ΔG=ΔH−TΔS\Delta G = \Delta H - T\Delta SΔG=ΔH−TΔS is affected by temperature changes?

Answer: The TΔST\Delta STΔS term. Only the entropy term TΔST\Delta STΔS contains temperature as a variable.

Flashcard 2: State the relationship between KeqK_{eq}Keq​ and ΔG∘\Delta G^\circΔG∘.

Answer: ΔG∘=−RTln⁡Keq\Delta G^\circ = -RT \ln K_{eq}ΔG∘=−RTlnKeq​. This equation connects equilibrium constants to standard free energy changes.

Flashcard 3: Explain the effect of ΔS>0\Delta S > 0ΔS>0 on a reaction's spontaneity.

Answer: It favors spontaneity. Positive entropy change makes the −TΔS-T\Delta S−TΔS term negative, favoring spontaneity.

Flashcard 4: What is the standard state temperature for ΔG∘\Delta G^\circΔG∘ calculations?

Answer: 298 K298 \text{ K}298 K. Standard temperature for thermodynamic calculations is 25°C or 298 K.

Flashcard 5: What does a positive ΔG∘\Delta G^\circΔG∘ indicate about a reaction?

Answer: The reaction is non-spontaneous. Positive standard free energy means unfavorable under standard conditions.

Flashcard 6: How is ΔG\Delta GΔG calculated for a reaction not at equilibrium?

Answer: ΔG=ΔG∘+RTln⁡Q\Delta G = \Delta G^\circ + RT \ln QΔG=ΔG∘+RTlnQ. This equation accounts for non-standard conditions using the reaction quotient.

Flashcard 7: In terms of enthalpy and entropy, when is a process always spontaneous?

Answer: ΔH<0\Delta H < 0ΔH<0 and ΔS>0\Delta S > 0ΔS>0. Exothermic with positive entropy ensures ΔG\Delta GΔG is always negative.

Flashcard 8: Identify the units of Gibbs free energy change, ΔG\Delta GΔG.

Answer: Joules (J) or kilojoules (kJ). Energy units since ΔG\Delta GΔG represents energy change per mole of reaction.

Flashcard 9: Is a reaction with Keq>1K_{eq} > 1Keq​>1 product-favored or reactant-favored?

Answer: Product-favored. Large equilibrium constants indicate reactions favor product formation.

Flashcard 10: When is a process never spontaneous at any temperature?

Answer: ΔH>0\Delta H > 0ΔH>0 and ΔS<0\Delta S < 0ΔS<0. Endothermic with negative entropy makes ΔG\Delta GΔG always positive.

Flashcard 11: What is the significance of TΔST\Delta STΔS in the Gibbs free energy equation?

Answer: It represents the temperature-dependent entropy term. This term quantifies the entropy contribution weighted by temperature.

Flashcard 12: Identify the role of catalysts in altering ΔG\Delta GΔG.

Answer: Catalysts do not alter ΔG\Delta GΔG. Catalysts only affect reaction rates, not thermodynamic quantities.

Flashcard 13: What is the value of RRR in the equation ΔG∘=−RTln⁡Keq\Delta G^\circ = -RT \ln K_{eq}ΔG∘=−RTlnKeq​?

Answer: 8.314 J/(mol·K). The universal gas constant in SI units for thermodynamic calculations.

Flashcard 14: Which term in the Gibbs free energy equation accounts for disorder?

Answer: ΔS\Delta SΔS. Entropy measures the randomness or disorder of the system.

Flashcard 15: What is the thermodynamic favorability of a reaction with ΔG∘=−40 kJ/mol\Delta G^\circ = -40 \text{ kJ/mol}ΔG∘=−40 kJ/mol?

Answer: Favorable. Large negative ΔG∘\Delta G^\circΔG∘ values indicate highly favorable reactions.

Flashcard 16: What condition must be met for a process to be spontaneous?

Answer: ΔG<0\Delta G < 0ΔG<0. Spontaneous processes have negative free energy changes.

Flashcard 17: What does ΔG=0\Delta G = 0ΔG=0 signify for a system at equilibrium?

Answer: The system is at equilibrium. Zero ΔG\Delta GΔG indicates no net driving force for change in either direction.

Flashcard 18: How does ΔG\Delta GΔG relate to the maximum useful work a system can perform?

Answer: ΔG\Delta GΔG equals the maximum useful work. The magnitude of ΔG\Delta GΔG represents maximum work extractable from the process.

Flashcard 19: What is the expression for ΔSuniv\Delta S_{univ}ΔSuniv​ in terms of ΔG\Delta GΔG?

Answer: ΔSuniv=−ΔGT\Delta S_{univ} = -\frac{\Delta G}{T}ΔSuniv​=−TΔG​. This relates universal entropy change to Gibbs free energy change.

Flashcard 20: Given ΔG=−10 kJ/mol\Delta G = -10 \text{ kJ/mol}ΔG=−10 kJ/mol, is the reaction spontaneous?

Answer: Yes, it is spontaneous. Negative ΔG\Delta GΔG values always indicate spontaneous processes.

Flashcard 21: For which ΔH\Delta HΔH and ΔS\Delta SΔS values is spontaneity temperature-dependent?

Answer: ΔH\Delta HΔH and ΔS\Delta SΔS both positive or both negative. Temperature determines which term dominates in the Gibbs equation.

Flashcard 22: What does ΔG>0\Delta G > 0ΔG>0 indicate about a system's state?

Answer: It is non-spontaneous. Positive ΔG\Delta GΔG means the process requires energy input to proceed.

Flashcard 23: When is ΔG=ΔG∘\Delta G = \Delta G^\circΔG=ΔG∘ true?

Answer: When the reaction is at standard state conditions. Standard conditions mean all species at 1 M concentration or 1 atm pressure.

Flashcard 24: What does a negative ΔG\Delta GΔG indicate about a reaction?

Answer: The reaction is thermodynamically favorable. Negative ΔG\Delta GΔG means the process can occur spontaneously without external work.

Flashcard 25: What is the significance of ΔG∘=0\Delta G^\circ = 0ΔG∘=0?

Answer: The reaction is in equilibrium under standard conditions. Zero standard free energy means Keq=1K_{eq} = 1Keq​=1 at standard conditions.

Flashcard 26: What happens to ΔG\Delta GΔG when a reaction is reversed?

Answer: The sign of ΔG\Delta GΔG is reversed. Reversing a reaction changes the sign of all thermodynamic quantities.

Flashcard 27: What is the standard state temperature for ΔG∘\Delta G^\circΔG∘ calculations?

Answer: 298 K298 \text{ K}298 K. Standard temperature for thermodynamic calculations is 25°C or 298 K.

Flashcard 28: Identify the units of Gibbs free energy change, ΔG\Delta GΔG.

Answer: Joules (J) or kilojoules (kJ). Energy units since ΔG\Delta GΔG represents energy change per mole of reaction.

Flashcard 29: What is the expression for ΔSuniv\Delta S_{univ}ΔSuniv​ in terms of ΔG\Delta GΔG?

Answer: ΔSuniv=−ΔGT\Delta S_{univ} = -\frac{\Delta G}{T}ΔSuniv​=−TΔG​. This relates universal entropy change to Gibbs free energy change.

Flashcard 30: What is the relationship between ΔG\Delta GΔG and reaction rate?

Answer: ΔG\Delta GΔG does not affect reaction rate. ΔG\Delta GΔG determines thermodynamic favorability, not kinetic rate.