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AP Chemistry Flashcards: Common Ion Effect

Study Common Ion Effect in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Common Ion Effect, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Chemistry Flashcards: Common Ion Effect

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QUESTION

State the equilibrium expression for a weak acid HAHAHA with KaK_aKa​.

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ANSWER

Ka=[H+][A−][HA]K_a=\frac{[H^+][A^-]}{[HA]}Ka​=[HA][H+][A−]​. Products over reactants for weak acid dissociation equilibrium.

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Flashcard 1: State the equilibrium expression for a weak acid HAHAHA with KaK_aKa​.

Answer: Ka=[H+][A−][HA]K_a=\frac{[H^+][A^-]}{[HA]}Ka​=[HA][H+][A−]​. Products over reactants for weak acid dissociation equilibrium.

Flashcard 2: What happens to [H+][H^+][H+] when a strong acid is added to a weak acid solution?

Answer: [H+][H^+][H+] increases; weak acid ionization decreases. Strong acid fully dissociates, suppressing weak acid's partial ionization.

Flashcard 3: What is the common-ion effect in aqueous equilibrium systems?

Answer: Added common ion shifts equilibrium left, reducing dissociation/solubility. Excess product ions drive equilibrium backward per Le Châtelier's principle.

Flashcard 4: For AgCl(s)AgCl(s)AgCl(s), what happens to solubility when NaCl(aq)NaCl(aq)NaCl(aq) is added?

Answer: Solubility decreases (common ion Cl−Cl^-Cl−). Added chloride shifts dissolution equilibrium left.

Flashcard 5: What happens to pHpHpH when A−A^-A− (the conjugate base) is added to a buffer of HA/A−HA/A^-HA/A−?

Answer: pHpHpH increases. More conjugate base consumes H+H^+H+, raising pH.

Flashcard 6: For CaF2(s)CaF_2(s)CaF2​(s), what happens to solubility when NaF(aq)NaF(aq)NaF(aq) is added?

Answer: Solubility decreases (common ion F−F^-F−). Added fluoride shifts dissolution equilibrium left.

Flashcard 7: Identify the direction of shift when NaOHNaOHNaOH is added to NH3(aq)NH_3(aq)NH3​(aq).

Answer: Shift left; NH3NH_3NH3​ forms less NH4+NH_4^+NH4+​. Added OH−OH^-OH− shifts ammonia-water equilibrium left.

Flashcard 8: Identify the direction of shift when CH3COONaCH_3COONaCH3​COONa is added to CH3COOH(aq)CH_3COOH(aq)CH3​COOH(aq).

Answer: Shift left; CH3COOHCH_3COOHCH3​COOH ionizes less. Added acetate ion suppresses acetic acid dissociation.

Flashcard 9: Which ion is the common ion when NH4ClNH_4ClNH4​Cl is added to a solution containing NH3NH_3NH3​?

Answer: NH4+NH_4^+NH4+​. Both NH4ClNH_4ClNH4​Cl and protonated NH3NH_3NH3​ contain ammonium ion.

Flashcard 10: Which ion is the common ion when NaFNaFNaF is added to a solution containing HFHFHF?

Answer: F−F^-F−. Both NaFNaFNaF and HFHFHF contain fluoride ion in solution.

Flashcard 11: What is the effect on molar solubility when a common ion is added to a sparingly soluble salt?

Answer: Molar solubility decreases. Common ion shifts dissolution equilibrium left, reducing dissolved ions.

Flashcard 12: Which relationship is correct for a conjugate pair: KaK_aKa​ and KbK_bKb​ at 25∘C25^\circ C25∘C?

Answer: KaKb=Kw=1.0×10−14K_aK_b=K_w=1.0\times 10^{-14}Ka​Kb​=Kw​=1.0×10−14. Conjugate acid-base pairs multiply to water's ion product.

Flashcard 13: What is the solubility product expression for M(OH)2(s)⇌M2++2OH−M(OH)_2(s)\rightleftharpoons M^{2+}+2OH^-M(OH)2​(s)⇌M2++2OH−?

Answer: Ksp=[M2+][OH−]2K_{sp}=[M^{2+}][OH^-]^2Ksp​=[M2+][OH−]2. Includes squared [OH−][OH^-][OH−] due to stoichiometry coefficient of 2.

Flashcard 14: What is the solubility product expression for MX(s)⇌M++X−MX(s)\rightleftharpoons M^+ + X^-MX(s)⇌M++X−?

Answer: Ksp=[M+][X−]K_{sp}=[M^+][X^-]Ksp​=[M+][X−]. Product of ion concentrations for 1:1 salt dissolution.

Flashcard 15: What is the net ionic equation for common-ion suppression of BBB by adding BH+BH^+BH+?

Answer: B(aq)+H2O(l)⇌BH+(aq)+OH−(aq)B(aq)+H_2O(l)\rightleftharpoons BH^+(aq)+OH^-(aq)B(aq)+H2​O(l)⇌BH+(aq)+OH−(aq) shifts left. Added BH+BH^+BH+ drives equilibrium toward unprotonated BBB.

Flashcard 16: What is the net ionic equation for common-ion suppression of HAHAHA by adding A−A^-A−?

Answer: HA(aq)⇌H+(aq)+A−(aq)HA(aq)\rightleftharpoons H^+(aq)+A^-(aq)HA(aq)⇌H+(aq)+A−(aq) shifts left. Added A−A^-A− drives equilibrium toward undissociated HAHAHA.

Flashcard 17: State the equilibrium expression for a weak base BBB with KbK_bKb​.

Answer: Kb=[BH+][OH−][B]K_b=\frac{[BH^+][OH^-]}{[B]}Kb​=[B][BH+][OH−]​. Products over reactants for weak base protonation equilibrium.

Flashcard 18: What happens to [OH−][OH^-][OH−] when a strong base is added to a weak base solution?

Answer: [OH−][OH^-][OH−] increases; weak base ionization decreases. Strong base fully dissociates, suppressing weak base's partial ionization.

Flashcard 19: What is the equilibrium expression for a weak acid HA\text{HA}HA: HA⇌H++A−\text{HA} \rightleftharpoons \text{H}^+ + \text{A}^-HA⇌H++A−?

Answer: Ka=[H+][A−][HA]K_a=\frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}Ka​=[HA][H+][A−]​. Products over reactants for weak acid dissociation.

Flashcard 20: What is the common-ion effect in aqueous equilibrium systems?

Answer: Adding a shared ion shifts equilibrium left, reducing ionization/solubility. Le Châtelier's principle: system responds to minimize disturbance.

Flashcard 21: What is the molar solubility sss of CaF2\text{CaF}_2CaF2​ in pure water in terms of KspK_{sp}Ksp​?

Answer: s=(Ksp4)13s=\left(\frac{K_{sp}}{4}\right)^{\frac{1}{3}}s=(4Ksp​​)31​. For 1:2 salt, Ksp=s(2s)2=4s3K_{sp}=s(2s)^2=4s^3Ksp​=s(2s)2=4s3.

Flashcard 22: Assuming [F−]initial≫2s[\text{F}^-]_{\text{initial}} \gg 2s[F−]initial​≫2s, what is sss for CaF2\text{CaF}_2CaF2​ in [F−][\text{F}^-][F−] using KspK_{sp}Ksp​?

Answer: s≈Ksp[F−]2s\approx\frac{K_{sp}}{[\text{F}^-]^2}s≈[F−]2Ksp​​. When common ion dominates, solve KspK_{sp}Ksp​ for cation concentration.

Flashcard 23: What is the molar solubility sss of AgCl\text{AgCl}AgCl in pure water in terms of KspK_{sp}Ksp​?

Answer: s=Ksps=\sqrt{K_{sp}}s=Ksp​​. For 1:1 salt, Ksp=s2K_{sp}=s^2Ksp​=s2 where sss is molar solubility.

Flashcard 24: Which direction does B+H2O⇌BH++OH−\text{B}+\text{H}_2\text{O} \rightleftharpoons \text{BH}^+ + \text{OH}^-B+H2​O⇌BH++OH− shift when [BH+][\text{BH}^+][BH+] is increased?

Answer: Left (toward B\text{B}B). Excess product drives equilibrium toward reactants.

Flashcard 25: Assuming [Cl−]initial≫s[\text{Cl}^-]_{\text{initial}} \gg s[Cl−]initial​≫s, what is sss for AgCl\text{AgCl}AgCl in [Cl−][\text{Cl}^-][Cl−] using KspK_{sp}Ksp​?

Answer: s≈Ksp[Cl−]s\approx\frac{K_{sp}}{[\text{Cl}^-]}s≈[Cl−]Ksp​​. When common ion dominates, solve KspK_{sp}Ksp​ for remaining ion.

Flashcard 26: In AgCl(s)⇌Ag++Cl−\text{AgCl}(s) \rightleftharpoons \text{Ag}^+ + \text{Cl}^-AgCl(s)⇌Ag++Cl−, what happens to [Ag+][\text{Ag}^+][Ag+] when [Cl−][\text{Cl}^-][Cl−] is increased?

Answer: [Ag+][\text{Ag}^+][Ag+] decreases. To maintain constant KspK_{sp}Ksp​, [Ag+][\text{Ag}^+][Ag+] must decrease.

Flashcard 27: Which direction does HA⇌H++A−\text{HA} \rightleftharpoons \text{H}^+ + \text{A}^-HA⇌H++A− shift when [A−][\text{A}^-][A−] is increased?

Answer: Left (toward HA\text{HA}HA). Excess product drives equilibrium toward reactants.

Flashcard 28: What is the buffer relationship between conjugate pairs: HA\text{HA}HA and A−\text{A}^-A−, in terms of the common-ion effect?

Answer: A−\text{A}^-A− suppresses ionization of HA\text{HA}HA. Conjugate base reduces conjugate acid ionization.

Flashcard 29: Identify the common ion when BaSO4(s)\text{BaSO}_4(s)BaSO4​(s) is placed in a solution of Na2SO4(aq)\text{Na}_2\text{SO}_4(aq)Na2​SO4​(aq).

Answer: SO42−\text{SO}_4^{2-}SO42−​. Sulfate ion is present in both the solid and added salt.

Flashcard 30: Identify the common ion when CaF2(s)\text{CaF}_2(s)CaF2​(s) is placed in a solution of NaF(aq)\text{NaF}(aq)NaF(aq).

Answer: F−\text{F}^-F−. Fluoride ion is present in both the solid and added salt.