AP Chemistry Flashcards: Common Ion Effect

Study Common Ion Effect in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Chemistry

Common Ion Effect

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QUESTION
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For CaF2(s)CaF_2(s), what happens to solubility when NaF(aq)NaF(aq) is added?

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ANSWER

Solubility decreases (common ion FF^-). Added fluoride shifts dissolution equilibrium left.

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Flashcard 1: For CaF2(s)CaF_2(s), what happens to solubility when NaF(aq)NaF(aq) is added?

Answer: Solubility decreases (common ion FF^-). Added fluoride shifts dissolution equilibrium left.

Flashcard 2: Which ion is the common ion when CH3COOH(aq)\text{CH}_3\text{COOH}(aq) is mixed with CH3COONa(aq)\text{CH}_3\text{COONa}(aq)?

Answer: CH3COO\text{CH}_3\text{COO}^-. Both solutions contain the acetate ion.

Flashcard 3: For AgCl(s)AgCl(s), what happens to solubility when NaCl(aq)NaCl(aq) is added?

Answer: Solubility decreases (common ion ClCl^-). Added chloride shifts dissolution equilibrium left.

Flashcard 4: In AgCl(s)Ag++Cl\text{AgCl}(s) \rightleftharpoons \text{Ag}^+ + \text{Cl}^-, what happens to [Ag+][\text{Ag}^+] when [Cl][\text{Cl}^-] is increased?

Answer: [Ag+][\text{Ag}^+] decreases. To maintain constant KspK_{sp}, [Ag+][\text{Ag}^+] must decrease.

Flashcard 5: Which ion is the common ion when NH4ClNH_4Cl is added to a solution containing NH3NH_3?

Answer: NH4+NH_4^+. Both NH4ClNH_4Cl and protonated NH3NH_3 contain ammonium ion.

Flashcard 6: What is the solubility-product expression for MX(s)M++X\text{MX}(s) \rightleftharpoons \text{M}^+ + \text{X}^-?

Answer: Ksp=[M+][X]K_{sp}=[\text{M}^+][\text{X}^-]. Product of ion concentrations at equilibrium.

Flashcard 7: Assuming [F]initial2s[\text{F}^-]_{\text{initial}} \gg 2s, what is ss for CaF2\text{CaF}_2 in [F][\text{F}^-] using KspK_{sp}?

Answer: sKsp[F]2s\approx\frac{K_{sp}}{[\text{F}^-]^2}. When common ion dominates, solve KspK_{sp} for cation concentration.

Flashcard 8: What is the solubility product expression for MX(s)M++XMX(s)\rightleftharpoons M^+ + X^-?

Answer: Ksp=[M+][X]K_{sp}=[M^+][X^-]. Product of ion concentrations for 1:1 salt dissolution.

Flashcard 9: Identify the direction of shift when NaOHNaOH is added to NH3(aq)NH_3(aq).

Answer: Shift left; NH3NH_3 forms less NH4+NH_4^+. Added OHOH^- shifts ammonia-water equilibrium left.

Flashcard 10: What happens to pHpH when AA^- (the conjugate base) is added to a buffer of HA/AHA/A^-?

Answer: pHpH increases. More conjugate base consumes H+H^+, raising pH.

Flashcard 11: Identify the direction of shift when CH3COONaCH_3COONa is added to CH3COOH(aq)CH_3COOH(aq).

Answer: Shift left; CH3COOHCH_3COOH ionizes less. Added acetate ion suppresses acetic acid dissociation.

Flashcard 12: State the equilibrium expression for a weak base BB with KbK_b.

Answer: Kb=[BH+][OH][B]K_b=\frac{[BH^+][OH^-]}{[B]}. Products over reactants for weak base protonation equilibrium.

Flashcard 13: Which relationship is correct for a conjugate pair: KaK_a and KbK_b at 25C25^\circ C?

Answer: KaKb=Kw=1.0×1014K_aK_b=K_w=1.0\times 10^{-14}. Conjugate acid-base pairs multiply to water's ion product.

Flashcard 14: What is the net effect on [OH][\text{OH}^-] when BHCl\text{BHCl} is added to a solution of weak base B\text{B}?

Answer: [OH][\text{OH}^-] decreases. Added BH+\text{BH}^+ shifts equilibrium left, reducing base ionization.

Flashcard 15: Identify the common ion when CaF2(s)\text{CaF}_2(s) is placed in a solution of NaF(aq)\text{NaF}(aq).

Answer: F\text{F}^-. Fluoride ion is present in both the solid and added salt.

Flashcard 16: Which ion is the common ion when NaFNaF is added to a solution containing HFHF?

Answer: FF^-. Both NaFNaF and HFHF contain fluoride ion in solution.

Flashcard 17: What is the net ionic equation for common-ion suppression of HAHA by adding AA^-?

Answer: HA(aq)H+(aq)+A(aq)HA(aq)\rightleftharpoons H^+(aq)+A^-(aq) shifts left. Added AA^- drives equilibrium toward undissociated HAHA.

Flashcard 18: State the equilibrium expression for a weak acid HAHA with KaK_a.

Answer: Ka=[H+][A][HA]K_a=\frac{[H^+][A^-]}{[HA]}. Products over reactants for weak acid dissociation equilibrium.

Flashcard 19: What is the buffer relationship between conjugate pairs: HA\text{HA} and A\text{A}^-, in terms of the common-ion effect?

Answer: A\text{A}^- suppresses ionization of HA\text{HA}. Conjugate base reduces conjugate acid ionization.

Flashcard 20: What is the net ionic equation for common-ion suppression of BB by adding BH+BH^+?

Answer: B(aq)+H2O(l)BH+(aq)+OH(aq)B(aq)+H_2O(l)\rightleftharpoons BH^+(aq)+OH^-(aq) shifts left. Added BH+BH^+ drives equilibrium toward unprotonated BB.

Flashcard 21: Which ion is the common ion when NH3(aq)\text{NH}_3(aq) is mixed with NH4Cl(aq)\text{NH}_4\text{Cl}(aq)?

Answer: NH4+\text{NH}_4^+. Both solutions contain the conjugate acid of ammonia.

Flashcard 22: What happens to [OH][OH^-] when a strong base is added to a weak base solution?

Answer: [OH][OH^-] increases; weak base ionization decreases. Strong base fully dissociates, suppressing weak base's partial ionization.

Flashcard 23: What is the molar solubility ss of AgCl\text{AgCl} in pure water in terms of KspK_{sp}?

Answer: s=Ksps=\sqrt{K_{sp}}. For 1:1 salt, Ksp=s2K_{sp}=s^2 where ss is molar solubility.

Flashcard 24: Identify the common ion when BaSO4(s)\text{BaSO}_4(s) is placed in a solution of Na2SO4(aq)\text{Na}_2\text{SO}_4(aq).

Answer: SO42\text{SO}_4^{2-}. Sulfate ion is present in both the solid and added salt.

Flashcard 25: What is the equilibrium expression for a weak acid HA\text{HA}: HAH++A\text{HA} \rightleftharpoons \text{H}^+ + \text{A}^-?

Answer: Ka=[H+][A][HA]K_a=\frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}. Products over reactants for weak acid dissociation.

Flashcard 26: What happens to [H+][H^+] when a strong acid is added to a weak acid solution?

Answer: [H+][H^+] increases; weak acid ionization decreases. Strong acid fully dissociates, suppressing weak acid's partial ionization.

Flashcard 27: What is the net effect on [H+][\text{H}^+] when NaA\text{NaA} is added to a solution of weak acid HA\text{HA}?

Answer: [H+][\text{H}^+] decreases. Added A\text{A}^- shifts equilibrium left, reducing acid dissociation.

Flashcard 28: Which direction does HAH++A\text{HA} \rightleftharpoons \text{H}^+ + \text{A}^- shift when [A][\text{A}^-] is increased?

Answer: Left (toward HA\text{HA}). Excess product drives equilibrium toward reactants.

Flashcard 29: What is the effect on molar solubility when a common ion is added to a sparingly soluble salt?

Answer: Molar solubility decreases. Common ion shifts dissolution equilibrium left, reducing dissolved ions.

Flashcard 30: What happens to the molar solubility of AgCl(s)\text{AgCl}(s) when Cl\text{Cl}^- is added from NaCl\text{NaCl}?

Answer: Molar solubility decreases. Common ion shifts dissolution equilibrium left.

Flashcard 31: What is the equilibrium expression for a weak base B\text{B}: B+H2OBH++OH\text{B}+\text{H}_2\text{O} \rightleftharpoons \text{BH}^+ + \text{OH}^-?

Answer: Kb=[BH+][OH][B]K_b=\frac{[\text{BH}^+][\text{OH}^-]}{[\text{B}]}. Products over reactants for weak base protonation.

Flashcard 32: What is the common-ion effect in aqueous equilibrium systems?

Answer: Added common ion shifts equilibrium left, reducing dissociation/solubility. Excess product ions drive equilibrium backward per Le Châtelier's principle.

Flashcard 33: What is the molar solubility ss of CaF2\text{CaF}_2 in pure water in terms of KspK_{sp}?

Answer: s=(Ksp4)13s=\left(\frac{K_{sp}}{4}\right)^{\frac{1}{3}}. For 1:2 salt, Ksp=s(2s)2=4s3K_{sp}=s(2s)^2=4s^3.

Flashcard 34: Which direction does B+H2OBH++OH\text{B}+\text{H}_2\text{O} \rightleftharpoons \text{BH}^+ + \text{OH}^- shift when [BH+][\text{BH}^+] is increased?

Answer: Left (toward B\text{B}). Excess product drives equilibrium toward reactants.

Flashcard 35: Assuming [Cl]initials[\text{Cl}^-]_{\text{initial}} \gg s, what is ss for AgCl\text{AgCl} in [Cl][\text{Cl}^-] using KspK_{sp}?

Answer: sKsp[Cl]s\approx\frac{K_{sp}}{[\text{Cl}^-]}. When common ion dominates, solve KspK_{sp} for remaining ion.

Flashcard 36: What is the common-ion effect in aqueous equilibrium systems?

Answer: Adding a shared ion shifts equilibrium left, reducing ionization/solubility. Le Châtelier's principle: system responds to minimize disturbance.

Flashcard 37: What is the solubility product expression for M(OH)2(s)M2++2OHM(OH)_2(s)\rightleftharpoons M^{2+}+2OH^-?

Answer: Ksp=[M2+][OH]2K_{sp}=[M^{2+}][OH^-]^2. Includes squared [OH][OH^-] due to stoichiometry coefficient of 2.