All flashcards
Flashcard 1: Calculate ΔG if n=2 and E=0.25 V (use F=96485 C mol−1).
Answer: ΔG=−4.82×104 J mol−1. ΔG=−(2)(96485)(0.25)=−48242.5 J/mol.
Flashcard 2: Calculate E∘ at 25∘C if K=1.0×106 and n=2.
Answer: E∘=0.178 V. E∘=20.0592log(106)=0.0296×6.
Flashcard 3: Calculate K at 25∘C if E∘=0.30 V and n=2.
Answer: K=1.4×1010. 0.30=20.0592logK; logK=10.14.
Flashcard 4: Find Q at 25∘C if E∘=0.50 V, E=0.44 V, and n=2.
Answer: Q=4.0×102. 0.44=0.50−20.0592logQ; solve for Q.
Flashcard 5: Calculate E at 25∘C if E∘=0.80 V, n=1, and Q=102.
Answer: E=0.68 V. E=0.80−0.0592log(100)=0.80−0.118.
Flashcard 6: Calculate E at 25∘C if E∘=1.10 V, n=2, and Q=10−4.
Answer: E=1.22 V. E=1.10−20.0592log(10−4)=1.10+0.118.
Flashcard 7: What is n in the Nernst equation, and how is it determined from the reaction?
Answer: n is moles of electrons transferred in the balanced redox reaction. Count electrons in half-reactions after balancing.
Flashcard 8: What is the relationship between E and E∘ when Q=1?
Answer: E=E∘. Standard conditions: all activities equal 1.
Flashcard 9: What is the sign of the Nernst correction when Q<1 (relative to E∘)?
Answer: E>E∘. Reactants favored, so potential increases from standard.
Flashcard 10: What is the sign of the Nernst correction when Q>1 (relative to E∘)?
Answer: E<E∘. Products favored, so potential decreases from standard.
Flashcard 11: State the relationship between cell potential and Gibbs free energy under any conditions.
Answer: ΔG=−nFE. Negative sign shows spontaneous reactions have E>0.
Flashcard 12: Identify which species are omitted from Q: pure solids, pure liquids, aqueous ions, or gases.
Answer: Pure solids and pure liquids are omitted from Q. Only dissolved species and gases affect cell potential.
Flashcard 13: What does Q represent in the Nernst equation for an electrochemical cell?
Answer: Reaction quotient from activities in the balanced net ionic equation. Ratio of products to reactants raised to stoichiometric powers.
Flashcard 14: State the relationship between standard cell potential and standard Gibbs free energy.
Answer: ΔG∘=−nFE∘. Links thermodynamics to electrochemistry at standard state.
Flashcard 15: State the relationship between E∘ and the equilibrium constant K at 25∘C.
Answer: E∘=n0.0592logK. Derived from ΔG∘=−RTlnK=−nFE∘.
Flashcard 16: What is the cell potential at equilibrium, and what is the corresponding value of Q?
Answer: E=0 and Q=K. No driving force at equilibrium; ΔG=0.
Flashcard 17: Identify the direction of spontaneity when E>0 for the cell reaction as written.
Answer: Spontaneous as written. Positive E means ΔG<0.
Flashcard 18: Identify the direction of spontaneity when E<0 for the cell reaction as written.
Answer: Nonspontaneous as written; spontaneous in reverse. Negative E means ΔG>0 forward.
Flashcard 19: State the Nernst equation at 25∘C using base-10 logarithms.
Answer: E=E∘−n0.0592logQ. Simplified form at 298 K using log instead of ln.
Flashcard 20: State the formula for the cell potential under nonstandard conditions (Nernst equation).
Answer: E=E∘−nFRTlnQ. Modifies standard potential by concentration effects via lnQ term.
Flashcard 21: Identify the condition on Q when E=0 for a cell at equilibrium.
Answer: Q=K. At equilibrium, E=0 and reaction quotient equals equilibrium constant.
Flashcard 22: State the relationship between E∘ and the equilibrium constant K at 25∘C.
Answer: E∘=n0.0592logK. Derived from E=0 when Q=K in Nernst equation.
Flashcard 23: State the general relationship between ΔG and cell potential E.
Answer: ΔG=−nFE. Relates electrical work to thermodynamic spontaneity.
Flashcard 24: State the relationship between ΔG∘ and the equilibrium constant K.
Answer: ΔG∘=−RTlnK. Fundamental thermodynamic relationship at equilibrium.
Flashcard 25: Identify how E changes when Q increases (with E∘, T, and n constant).
Answer: E decreases. Larger Q means more products, driving reverse reaction.
Flashcard 26: Calculate logK at 25∘C if E∘=0.30 V and n=3.
Answer: logK≈15.2. 0.30=30.0592logK; logK=0.05920.90≈15.2.
Flashcard 27: State the formula for cell potential under nonstandard conditions (Nernst equation).
Answer: E=E∘−nFRTlnQ. Modified by reaction quotient Q and temperature; n is electrons transferred.
Flashcard 28: State the Nernst equation at 25∘C using base-10 logarithms.
Answer: E=E∘−n0.0592logQ. Simplified form at 298 K using F2.303RT=0.0592 V.
Flashcard 29: What does Q represent in the Nernst equation for an electrochemical cell?
Answer: Reaction quotient, products over reactants using activities. Measures reaction progress; equals K at equilibrium.
Flashcard 30: What does n represent in the Nernst equation for a galvanic cell?
Answer: Moles of electrons transferred in the balanced redox reaction. Count electrons in half-reaction balancing.