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This deck focuses on Atomic Structure And Electron Configuration, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Atomic Structure And Electron Configuration in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Determine the number of electrons in a magnesium ion (Mg2+).
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10 electrons. Magnesium loses 2 electrons to form Mg2+, leaving 10 electrons.
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This deck focuses on Atomic Structure And Electron Configuration, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 10 electrons. Magnesium loses 2 electrons to form Mg2+, leaving 10 electrons.
Answer: Neutrons = Mass number - Atomic number. Mass number includes both protons and neutrons, so subtract protons to get neutrons.
Answer: Azimuthal quantum number (l). The l value determines whether an orbital is s, p, d, or f type.
Answer: +21 or −21. Represents the two possible spin orientations of an electron.
Answer: Chlorine (Cl). The configuration [Ne]3s23p5 indicates 17 total electrons, which is chlorine.
Answer: Neutral charge (0). Neutrons are electrically neutral particles in the nucleus.
Answer: 1s2. Helium has 2 electrons, both filling the 1s orbital.
Answer: 8 electrons. The n=2 level has 2s and 2p subshells: 2+6=8 electrons total.
Answer: 9 orbitals. The n=3 level has s, p, and d subshells: 1+3+5=9 orbitals.
Answer: 9 orbitals. The n=3 level has s, p, and d subshells: 1+3+5=9 orbitals.
Answer: Chlorine (Cl). The configuration [Ne]3s23p5 indicates 17 total electrons, which is chlorine.
Answer: 1s22s22p63s23p6. Argon has 18 electrons completely filling through the 3p subshell.
Answer: 1s22s22p6. Oxide ion gains 2 electrons, achieving neon's electron configuration.
Answer: Orientation of an orbital. Describes which specific orbital within a subshell the electron occupies.
Answer: Azimuthal quantum number (l). The l value determines whether an orbital is s, p, d, or f type.
Answer: 32 electrons. The n=4 level can hold 2n2=2(4)2=32 electrons total.
Answer: 1s2. Helium has 2 electrons, both filling the 1s orbital.
Answer: 2 unpaired electrons. Carbon's 2p subshell has 2 electrons, both unpaired by Hund's rule.
Answer: 1s22s22p6. Neon has 10 electrons filling through the 2p subshell completely.
Answer: 9 orbitals. The n=3 level has s, p, and d subshells: 1+3+5=9 orbitals.
Answer: Orientation of an orbital. Describes which specific orbital within a subshell the electron occupies.
Answer: Chlorine (Cl). The configuration [Ne]3s23p5 indicates 17 total electrons, which is chlorine.
Answer: 1s22s22p63s23p4. Sulfur has 16 electrons, with 4 electrons in the 3p subshell.
Answer: 1s22s22p6. Oxide ion gains 2 electrons, achieving neon's electron configuration.
Answer: Neutrons = Mass number - Atomic number. Mass number includes both protons and neutrons, so subtract protons to get neutrons.
Answer: 10 electrons. Neon's atomic number is 10, so neutral atoms have 10 electrons.
Answer: l=1. P orbitals correspond to l=1 in the azimuthal quantum number system.
Answer: 1s22s22p63s1. Sodium has 11 electrons, filling through 3s with one electron.
Answer: 1s22s22p63s23p64s1. Potassium has 19 electrons, with the last electron in the 4s orbital.
Answer: 1s22s22p63s23p6. Argon has 18 electrons completely filling through the 3p subshell.
Answer: 1s22s22p6. Fluoride ion gains one electron, achieving neon's electron configuration.
Answer: Electron filling order in orbitals. Electrons fill lowest energy orbitals first before higher energy ones.
Answer: 32 electrons. The n=4 level can hold 2n2=2(4)2=32 electrons total.
Answer: 8 electrons. The n=2 level has 2s and 2p subshells: 2+6=8 electrons total.
Answer: 1s22s22p6. Fluoride ion gains one electron, achieving neon's electron configuration.
Answer: n. The principal quantum number indicates the energy level or shell.
Answer: Pauli Exclusion Principle. Each electron must have a unique set of four quantum numbers.
Answer: 5 orbitals. The d subshell contains 5 degenerate orbitals.
Answer: 1s22s22p6. Neon has 10 electrons filling through the 2p subshell completely.
Answer: 1s22s22p2. Carbon has 6 electrons: 2 in 1s, 2 in 2s, and 2 in 2p.
Answer: 1s22s22p6. Neon has 10 electrons filling through the 2p subshell completely.
Answer: The number of protons in the nucleus. Defines the element's identity and equals the number of electrons in neutral atoms.
Answer: 1s2. Helium has 2 electrons, both filling the 1s orbital.
Answer: Azimuthal quantum number (l). The l value determines whether an orbital is s, p, d, or f type.
Answer: 10 electrons. Magnesium loses 2 electrons to form Mg2+, leaving 10 electrons.
Answer: 1s22s22p63s23p4. Sulfur has 16 electrons, with 4 electrons in the 3p subshell.
Answer: 14 electrons. The f subshell has 7 orbitals, each holding 2 electrons maximum.
Answer: 5 orbitals. The d subshell contains 5 degenerate orbitals.
Answer: Spherical. All s orbitals have spherical symmetry around the nucleus.
Answer: Orientation of an orbital. Describes which specific orbital within a subshell the electron occupies.
Answer: The number of protons in the nucleus. Defines the element's identity and equals the number of electrons in neutral atoms.
Answer: 1s22s22p2. Carbon has 6 electrons: 2 in 1s, 2 in 2s, and 2 in 2p.
Answer: 6 valence electrons. Oxygen is in group 16, so it has 6 electrons in its outermost shell.
Answer: Pauli Exclusion Principle. Each electron must have a unique set of four quantum numbers.
Answer: 0 to n−1. For a given n, the azimuthal quantum number ranges from 0 to n−1.
Answer: Lead (Pb). The configuration ends in 6p2, characteristic of lead in group 14.
Answer: Neutral charge (0). Neutrons are electrically neutral particles in the nucleus.
Answer: 5 valence electrons. Nitrogen is in group 15, so it has 5 valence electrons.
Answer: +21 or −21. Represents the two possible spin orientations of an electron.
Answer: 6 valence electrons. Oxygen is in group 16, so it has 6 electrons in its outermost shell.
Answer: 17 electrons. Chlorine's atomic number is 17, so neutral atoms have 17 electrons.
Answer: 1s22s22p63s23p6. Calcium loses 2 electrons to form Ca2+, giving argon's configuration.
Answer: 2 unpaired electrons. Carbon's 2p subshell has 2 electrons, both unpaired by Hund's rule.
Answer: 17 electrons. Chlorine's atomic number is 17, so neutral atoms have 17 electrons.
Answer: 1s22s22p63s1. Sodium has 11 electrons, filling through 3s with one electron.
Answer: Neutral charge (0). Neutrons are electrically neutral particles in the nucleus.
Answer: l=1. P orbitals correspond to l=1 in the azimuthal quantum number system.
Answer: 1s22s22p63s23p6. Argon has 18 electrons completely filling through the 3p subshell.
Answer: 10 electrons. Magnesium loses 2 electrons to form Mg2+, leaving 10 electrons.
Answer: 2 unpaired electrons. Oxygen's 2p subshell has 4 electrons: 2 paired and 2 unpaired by Hund's rule.
Answer: 0 to n−1. For a given n, the azimuthal quantum number ranges from 0 to n−1.
Answer: 14 electrons. The f subshell has 7 orbitals, each holding 2 electrons maximum.
Answer: Lead (Pb). The configuration ends in 6p2, characteristic of lead in group 14.
Answer: 32 electrons. The n=4 level can hold 2n2=2(4)2=32 electrons total.
Answer: 5 valence electrons. Nitrogen is in group 15, so it has 5 valence electrons.
Answer: 17 electrons. Chlorine's atomic number is 17, so neutral atoms have 17 electrons.
Answer: 2 unpaired electrons. Oxygen's 2p subshell has 4 electrons: 2 paired and 2 unpaired by Hund's rule.
Answer: 1s22s22p63s23p1. Aluminum has 13 electrons, with 1 electron in the 3p subshell.
Answer: 1s22s22p63s23p6. Calcium loses 2 electrons to form Ca2+, giving argon's configuration.
Answer: 1s22s22p63s23p6. Calcium loses 2 electrons to form Ca2+, giving argon's configuration.
Answer: 10 electrons. Magnesium loses 2 electrons to form Mg2+, leaving 10 electrons.
Answer: n. The principal quantum number indicates the energy level or shell.
Answer: 5 valence electrons. Nitrogen is in group 15, so it has 5 valence electrons.
Answer: Spherical. All s orbitals have spherical symmetry around the nucleus.
Answer: Pauli Exclusion Principle. Each electron must have a unique set of four quantum numbers.
Answer: 1s22s22p6. Oxide ion gains 2 electrons, achieving neon's electron configuration.
Answer: The number of protons in the nucleus. Defines the element's identity and equals the number of electrons in neutral atoms.
Answer: 8 electrons. The n=2 level has 2s and 2p subshells: 2+6=8 electrons total.
Answer: 2 electrons. Maximum capacity per orbital due to Pauli Exclusion Principle.
Answer: 1s22s22p63s23p4. Sulfur has 16 electrons, with 4 electrons in the 3p subshell.
Answer: 1s22s22p63s23p64s1. Potassium has 19 electrons, with the last electron in the 4s orbital.
Answer: 0 to n−1. For a given n, the azimuthal quantum number ranges from 0 to n−1.
Answer: Lead (Pb). The configuration ends in 6p2, characteristic of lead in group 14.
Answer: n. The principal quantum number indicates the energy level or shell.
Answer: 2 unpaired electrons. Carbon's 2p subshell has 2 electrons, both unpaired by Hund's rule.
Answer: 10 electrons. Neon's atomic number is 10, so neutral atoms have 10 electrons.
Answer: Electron filling order in orbitals. Electrons fill lowest energy orbitals first before higher energy ones.
Answer: 1s22s22p2. Carbon has 6 electrons: 2 in 1s, 2 in 2s, and 2 in 2p.
Answer: Hund's Rule. Maximizes unpaired electrons before pairing to minimize electron-electron repulsion.
Answer: 1s22s22p63s23p64s1. Potassium has 19 electrons, with the last electron in the 4s orbital.