What this deck covers
This deck focuses on Acid Base Titrations, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Acid Base Titrations in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
0% Complete
Which option describes a buffer solution?
Tap card or press Space to flip
Resists changes in pH upon addition of acid or base. Contains conjugate acid-base pair to maintain pH stability.
How well did you know it?
Card 1 / 39
Space to flip · ← / → to move · once flipped, → Got it · ← Still learning
This deck focuses on Acid Base Titrations, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Resists changes in pH upon addition of acid or base. Contains conjugate acid-base pair to maintain pH stability.
Answer: Where moles of acid equal moles of base. Stoichiometric neutralization point on titration curve.
Answer: pH = 2. Strong acid: pH = −log(0.01)=−log(10−2)=2.
Answer: pH=7. Equal concentrations of H+ and OH− at 25°C.
Answer: 8.2 to 10.0. Indicator's transition range for color change.
Answer: pH ≈ 11.1. Use Kb expression: [OH−]=Kb×C then find pH.
Answer: 50 mL. Equal molarity and volume means 1:1 mole ratio requires equal volume.
Answer: Phenolphthalein. Changes color at pH 8.2-10, ideal for strong acid-base endpoints.
Answer: [H+]=10−pH. Inverse relationship: pH is negative log of [H+].
Answer: The solution added from the burette. Standard solution delivered from burette during analysis.
Answer: Not always; depends on the strength of acid and base. Only true for strong acid-strong base; weak acids/bases differ.
Answer: Colorless to pink. Phenolphthalein is colorless in acid, pink in base.
Answer: Partially ionizes in solution. Incomplete dissociation results in equilibrium with undissociated acid.
Answer: To measure and transfer a specific volume of solution. Precision instrument for accurate volume transfer.
Answer: To determine the concentration of an unknown solution. Uses known titrant to find unknown concentration via stoichiometry.
Answer: pH+pOH=14. Fundamental relationship for aqueous solutions at 25°C.
Answer: A solution of known concentration used in titration. Standard solution added from burette to determine analyte concentration.
Answer: Graph of pH versus volume of titrant added. Visual representation showing pH changes during titration process.
Answer: Slight increase in pH. Buffer components consume added base, minimizing pH change.
Answer: Increases the pH. Dilution decreases [H+], raising pH toward neutral.
Answer: Slight decrease in pH. Buffer components consume added acid, minimizing pH change.
Answer: Analyte. The unknown solution whose concentration is being determined.
Answer: M=liters of solutionmoles of solute. Defines concentration as moles of solute per liter of solution.
Answer: Weak acid-strong base. Weak acid-strong base gives basic equivalence point (pH > 7).
Answer: 0.0025 moles. Convert volume to L (0.025 L), multiply by molarity (0.1 M).
Answer: Neutralization. Acid and base react to form salt and water.
Answer: pH = 7. Equal amounts of strong acid and base neutralize to neutral pH.
Answer: The point at which the indicator changes color. Visual signal used to determine when to stop adding titrant.
Answer: pH = 11. pOH = −log(10−3)=3, so pH = 14−3=11.
Answer: To deliver a precise volume of titrant. Graduated tube allows controlled addition and volume measurement.
Answer: Completely ionizes in solution. Dissociates nearly 100% in aqueous solution.
Answer: The point where the indicator changes color. Observable color change indicating approximate equivalence point.
Answer: A solution of known concentration. Precisely known concentration for quantitative analysis.
Answer: pH = 6. pH is defined as −log[H+]=−log(10−6)=6.
Answer: [OH−]=10−pOH. Inverse relationship: pOH is negative log of [OH−].
Answer: Higher Ka indicates a stronger acid. Larger Ka means greater ionization and stronger acid.
Answer: To signal the endpoint of the titration. Color change marks approximate equivalence point.
Answer: pOH=−log[OH−]. Negative logarithm relationship for hydroxide concentration.
Answer: pOH = 2. Strong base: pOH = −log(0.01)=2.