Practice Test 1

$\lim_{x\to\infty} q(x)=1$, so $x=1$ is a vertical asymptote

$\lim_{x\to4^-} q(x)=-\infty$ and $\lim_{x\to4^+} q(x)=+\infty$, so $x=4$ is a vertical asymptote

$\lim_{x\to4^-} q(x)=+\infty$ and $\lim_{x\to4^+} q(x)=-\infty$, so $y=4$ is a vertical asymptote

$\lim_{x\to4} q(x)=0$, so there is a removable discontinuity at $x=4$

$\lim_{x\to4} q(x)=1$, so $y=1$ is a vertical asymptote