Understanding the limiting process. - AP Calculus AB
Card 1 of 385
Find the derivative.
y = sec (5x3)
Find the derivative.
y = sec (5x3)
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The derivative of the function y = sec(x) is sec(x)tan(x). First take the derivative of the outside of the function: y = sec(4x3) : y' = sec(5x3)tan(5x3). Then take the derivative of the inside of the function: 5x3 becomes 15x2. So your final answer is: y' = ec(5x3)tan(5x3)15x2
The derivative of the function y = sec(x) is sec(x)tan(x). First take the derivative of the outside of the function: y = sec(4x3) : y' = sec(5x3)tan(5x3). Then take the derivative of the inside of the function: 5x3 becomes 15x2. So your final answer is: y' = ec(5x3)tan(5x3)15x2
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Find the slope of the tangent line to the graph of f at x = 9, given that f(x) = –x2 + 5√(x)
Find the slope of the tangent line to the graph of f at x = 9, given that f(x) = –x2 + 5√(x)
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First find the derivative of the function.
f(x) = –x2 + 5√(x)
f'(x) = –2x + 5(1/2)x–1/2
Simplify the problem
f'(x) = –2x + (5/2x1/2)
Plug in 9.
f'(3) = –2(9) + (5/2(9)1/2)
= –18 + 5/(6)
First find the derivative of the function.
f(x) = –x2 + 5√(x)
f'(x) = –2x + 5(1/2)x–1/2
Simplify the problem
f'(x) = –2x + (5/2x1/2)
Plug in 9.
f'(3) = –2(9) + (5/2(9)1/2)
= –18 + 5/(6)
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Find the derivative
(x + 1)/(x – 1)
Find the derivative
(x + 1)/(x – 1)
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Rewrite problem.
(x + 1)/(x – 1)
Use quotient rule to solve this derivative.
((x – 1)(1) – (x + 1)(1))/(x – 1)2
(x – 1) – x – 1)/(x – 1)2
–2/(x – 1)2
Rewrite problem.
(x + 1)/(x – 1)
Use quotient rule to solve this derivative.
((x – 1)(1) – (x + 1)(1))/(x – 1)2
(x – 1) – x – 1)/(x – 1)2
–2/(x – 1)2
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What is the derivative of $(2+3cos(3x))^pi$?
What is the derivative of $(2+3cos(3x))^pi$?
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Need to use the power rule which states: $$\frac{d}{dx}$u^n$$=nu^{n-1}$$\frac{du}{dx}$
In our problem $\frac{du}{dx}$=-3sin(3x)
Need to use the power rule which states: $$\frac{d}{dx}$u^n$$=nu^{n-1}$$\frac{du}{dx}$
In our problem $\frac{du}{dx}$=-3sin(3x)
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Find the derivative of

Find the derivative of
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The answer is
. It is easy to solve if we multiply everything together first before taking the derivative.




The answer is . It is easy to solve if we multiply everything together first before taking the derivative.
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If
, then 
If , then
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The correct answer is
.
We must use the product rule to solve. Remember that the derivative of
is
.


The correct answer is .
We must use the product rule to solve. Remember that the derivative of is
.
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This question is asking to evaluate a one-sided equation of a function. Specifically, the limit of the function to the left of
. When
is substituted into the function the result is indeterminate. This means it is in the form zero over zero.
Since the question is looking for a one-sided limit, let us substitute in a value that is slightly less than
.


This question is asking to evaluate a one-sided equation of a function. Specifically, the limit of the function to the left of . When
is substituted into the function the result is indeterminate. This means it is in the form zero over zero.
Since the question is looking for a one-sided limit, let us substitute in a value that is slightly less than .
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Use the chain rule and the formula

Use the chain rule and the formula
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Find
if
.
Find if
.
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We will have to find the first derivative of
with respect to
using implicit differentiation. Then, we can find
, which is the second derivative of
with respect to
.

We will apply the chain rule on the left side.


We now solve for the first derivative with respect to
.

In order to get the second derivative, we will differentiate
with respect to
. This will require us to employ the Quotient Rule.

We will replace
with
.

But, from the original equation,
. Also, if we solve for
, we obtain
.

The answer is
.
We will have to find the first derivative of with respect to
using implicit differentiation. Then, we can find
, which is the second derivative of
with respect to
.
We will apply the chain rule on the left side.
We now solve for the first derivative with respect to .
In order to get the second derivative, we will differentiate with respect to
. This will require us to employ the Quotient Rule.
We will replace with
.
But, from the original equation, . Also, if we solve for
, we obtain
.
The answer is .
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Differentiate
.
Differentiate .
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The derivative of
is equal to
therefore the first part of the equation remains the same.
The second part requires regular differential rules.

Therefore when differentiating
you get
.
Combining the first and second part we get the final derivative:
.
The derivative of is equal to
therefore the first part of the equation remains the same.
The second part requires regular differential rules.
Therefore when differentiating you get
.
Combining the first and second part we get the final derivative:
.
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Differentiate
.
Differentiate .
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The rule for taking the derivative of
.
For this problem we need to remember to use the Chain Rule.
Since we are taking the derivative of,
we need to take the derivative of the outside piece
keeping the inside piece the same
, and then multiply the whole thing by the derivative of the inside piece
.
Therefore the solution becomes:
,
.
The rule for taking the derivative of .
For this problem we need to remember to use the Chain Rule.
Since we are taking the derivative of,
we need to take the derivative of the outside piece
keeping the inside piece the same
, and then multiply the whole thing by the derivative of the inside piece
.
Therefore the solution becomes:
,
.
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Evaluate:
.
Evaluate:
.
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The derivative of
is
.
Therefore the integral of
where C is some constant.
The derivative of is
.
Therefore the integral of
where C is some constant.
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If
what is
?
If what is
?
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The derivative of,
.
The derivative of

Therefore, using the Chain Rule the derivative of the function will become the derivative of the outside piece keeping the original inside piece. Then multiplying that by the derivative of the inside piece.

The derivative of,
.
The derivative of
Therefore, using the Chain Rule the derivative of the function will become the derivative of the outside piece keeping the original inside piece. Then multiplying that by the derivative of the inside piece.
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Differentiate
.
Differentiate .
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Using the power rule, multiply the coefficient by the power and subtract the power by 1.



Using the power rule, multiply the coefficient by the power and subtract the power by 1.
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Differentiate
.
Differentiate .
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Use the product rule:


Use the product rule:
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Differentiate: 
Differentiate:
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Use the product rule to find the derivative of the function.



Use the product rule to find the derivative of the function.
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Differentiate: 
Differentiate:
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The derivative of any function of e to any exponent is equal to the function multiplied by the derivative of the exponent.

The derivative of any function of e to any exponent is equal to the function multiplied by the derivative of the exponent.
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Find the second derivative of
.
Find the second derivative of .
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Factoring out an x gives you
.

Factoring out an x gives you .
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Consider:

The 99th derivative of
is:
Consider:
The 99th derivative of is:
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For
, the nth derivative is
. As an example, consider
. The first derivative is
, the second derivative is
, and the third derivative is
. For the question being asked, the 99th derivative of
would be
. The 66th derivative of
would be
, and any higher derivative would be zero, since the derivative of any constant is zero. Thus, for the given function, the 99th derivative is
.
For , the nth derivative is
. As an example, consider
. The first derivative is
, the second derivative is
, and the third derivative is
. For the question being asked, the 99th derivative of
would be
. The 66th derivative of
would be
, and any higher derivative would be zero, since the derivative of any constant is zero. Thus, for the given function, the 99th derivative is
.
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Consider the function
.
Which of the following is true when
?
Consider the function .
Which of the following is true when ?
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, meaning
is increasing when 
.
, meaning
is concave up when 
.
, meaning
is increasing when
.
, meaning
is concave up when
.
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