All flashcards
Flashcard 1: What is an antiderivative of f(x)=3x2?
Answer: F(x)=x3+C. Power rule: increase exponent by 1, divide by new exponent.
Flashcard 2: Calculate ∫13(2x2−x)dx using the Fundamental Theorem.
Answer: 326. Use antiderivative 32x3−2x2, evaluate at bounds.
Flashcard 3: Evaluate ∫−22(x3+2x)dx using symmetry properties.
Answer: 0. Both functions are odd, so integral over symmetric interval is zero.
Flashcard 4: Evaluate ∫04(3x2+2)dx using the Fundamental Theorem.
Answer:
- Use antiderivative x3+2x, evaluate at bounds 4 and 0.
Flashcard 5: State the Fundamental Theorem of Calculus, Part 1.
Answer: If F is an antiderivative of f on [a,b], then ∫abf(x)dx=F(b)−F(a). This allows calculation of definite integrals using antiderivatives.
Flashcard 6: Determine ∫14x1dx.
Answer: ln(4). Antiderivative of x1 is ln(x).
Flashcard 7: For F(x)=∫0xetdt, find F′(x).
Answer: ex. By Part 2 of FTC, the derivative equals the integrand.
Flashcard 8: For F(x)=∫0xsin(t)dt, find F′(x).
Answer: sin(x). By Part 2 of FTC, derivative equals the integrand.
Flashcard 9: What does the second part of the Fundamental Theorem allow us to compute?
Answer: The derivative of an integral function. It gives the rate of change of the area function.
Flashcard 10: Determine ∫02x2dx using an antiderivative.
Answer: 38. Use antiderivative 3x3, evaluate at bounds.
Flashcard 11: Calculate ∫13(2x2−x)dx using the Fundamental Theorem.
Answer: 326. Use antiderivative 32x3−2x2, evaluate at bounds.
Flashcard 12: What is the integral of f(x)=ex over [0,1]?
Answer: e−1. Antiderivative of ex is ex; evaluate at bounds.
Flashcard 13: What is a definite integral's geometric interpretation?
Answer: Net area between the curve and the x-axis over [a,b]. Represents the signed area between curve and x-axis.
Flashcard 14: Find the derivative of F(x)=∫2xln(t)dt.
Answer: ln(x). By Part 2 of FTC, the derivative equals the integrand.
Flashcard 15: Find ∫02(4x3+x)dx using an antiderivative.
Answer:
- Use antiderivative x4+2x2, evaluate at bounds.
Flashcard 16: State the Fundamental Theorem of Calculus, Part 2.
Answer: If f is continuous on [a,b], then F(x)=∫axf(t)dt is differentiable and F′(x)=f(x). Shows that differentiation and integration are inverse operations.
Flashcard 17: What is the definite integral of a constant c over an interval [a,b]?
Answer: c(b−a). A constant function integrates to constant times interval length.
Flashcard 18: Compute ∫−11x3dx using symmetry properties.
Answer:
- Odd function over symmetric interval gives zero area.
Flashcard 19: Evaluate ∫012xdx using the Fundamental Theorem of Calculus.
Answer:
- Find antiderivative x2, then evaluate 12−02=1.
Flashcard 20: Determine ∫13x2dx using an antiderivative.
Answer: 26/3. Use antiderivative 3x3, then evaluate at bounds.
Flashcard 21: What does the Fundamental Theorem of Calculus connect?
Answer: It connects differentiation and integration. They are inverse operations of each other.
Flashcard 22: Evaluate ∫03(x2+x+1)dx using the Fundamental Theorem.
Answer:
- Use antiderivative 3x3+2x2+x, evaluate at bounds.
Flashcard 23: Find ∫04(x2−2)dx using the Fundamental Theorem.
Answer: 332. Use antiderivative 3x3−2x, evaluate at bounds.
Flashcard 24: Determine ∫01(5x2−3x)dx using an antiderivative.
Answer: 31. Use antiderivative 35x3−23x2, evaluate at bounds.
Flashcard 25: Evaluate ∫01(4x3−x)dx using the Fundamental Theorem.
Answer: 43. Use antiderivative x4−2x2, evaluate at bounds.
Flashcard 26: What is the result of ∫021dx?
Answer:
- Integral of constant 1 over interval length 2.
Flashcard 27: Find ∫01(x2+2x)dx using an antiderivative.
Answer: 37. Use antiderivative 3x3+x2, evaluate at bounds.
Flashcard 28: What is the integral of f(x)=cos(x) over [0,π]?
Answer:
- Antiderivative is sin(x); sin(π)−sin(0)=0.
Flashcard 29: What is the integral of f(x)=1/x over [1,e]?
Answer:
- Antiderivative of x1 is ln(x); ln(e)−ln(1)=1.
Flashcard 30: Calculate ∫01(x3+1)dx using the Fundamental Theorem.
Answer: 45. Use antiderivative 4x4+x, evaluate at bounds.