AP Calculus AB Flashcards: Exploring Accumulations Of Change

Study Exploring Accumulations Of Change in AP Calculus AB with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus AB

Exploring Accumulations Of Change

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What is the integral of f(x)=cos(x)f(x) = \cos(x) from 00 to π2\frac{\pi}{2}?

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ANSWER

0π2cos(x)dx=1\int_0^{\frac{\pi}{2}} \cos(x)\,dx = 1. Antiderivative is sin(x)\sin(x), evaluated from 0 to π2\frac{\pi}{2} gives 10=11-0=1.

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Flashcard 1: What is the integral of f(x)=cos(x)f(x) = \cos(x) from 00 to π2\frac{\pi}{2}?

Answer: 0π2cos(x)dx=1\int_0^{\frac{\pi}{2}} \cos(x)\,dx = 1. Antiderivative is sin(x)\sin(x), evaluated from 0 to π2\frac{\pi}{2} gives 10=11-0=1.

Flashcard 2: Compute 04(x2)dx\int_0^4 (x - 2)\,dx.

Answer: 00. Linear function with zero net area due to symmetry about x=2x=2.

Flashcard 3: State the definition of a definite integral.

Answer: The limit of Riemann sums: limni=1nf(xi)Δx\lim_{n\to\infty} \sum_{i=1}^{n} f(x_i^*)\Delta x. Formal definition using limit of approximating rectangular areas.

Flashcard 4: What is the integral of f(x)=exf(x) = e^x from 00 to 11?

Answer: 01exdx=e1\int_0^1 e^x\,dx = e - 1. Antiderivative is exe^x, evaluated from 0 to 1 gives e1e-1.

Flashcard 5: What is the integral of f(x)=1f(x) = 1 from 00 to 55?

Answer: 051dx=5\int_0^5 1\,dx = 5. Integral of constant function equals constant times interval length.

Flashcard 6: What is the average value of f(x)=x2f(x) = x^2 on [0,3][0, 3]?

Answer: 1303x2dx=3\frac{1}{3} \int_0^3 x^2\,dx = 3. Average value formula: 1baabf(x)dx\frac{1}{b-a}\int_a^b f(x)dx applied to x2x^2 on [0,3][0,3].

Flashcard 7: What is the integral of f(x)=exf(x) = e^x from 00 to 11?

Answer: 01exdx=e1\int_0^1 e^x\,dx = e - 1. Antiderivative is exe^x, evaluated from 00 to 11 gives e1e-1.

Flashcard 8: State the definition of an antiderivative.

Answer: A function F(x)F(x) such that F(x)=f(x)F'(x) = f(x) for all xx in the domain. Function whose derivative equals the given function.

Flashcard 9: Evaluate 12(x2+x)dx\int_1^2 (x^2 + x)\,dx.

Answer: 73\frac{7}{3}. Sum of power functions integrated using power rule.

Flashcard 10: State the formula for the area under a curve using integration.

Answer: Area = abf(x)dx\int_a^b f(x)\,dx. Fundamental connection between integration and area under curves.

Flashcard 11: Find 02(x33x2+3x)dx\int_0^2 (x^3 - 3x^2 + 3x)\,dx.

Answer: 22. Cubic polynomial integrated using power rule for each term.

Flashcard 12: State the definition of an antiderivative.

Answer: A function F(x)F(x) such that F(x)=f(x)F'(x) = f(x) for all xx in the domain. Function whose derivative equals the given function.

Flashcard 13: Compute 04(x2)dx\int_0^4 (x - 2)\,dx.

Answer: 00. Linear function with zero net area due to symmetry about x=2x=2.

Flashcard 14: Find the antiderivative of f(x)=5x4f(x) = 5x^4.

Answer: F(x)=x5+CF(x) = x^5 + C. Power rule for antiderivatives: increase exponent by 1, divide by new exponent.

Flashcard 15: What is the integral of f(x)=2xf(x) = 2x from 11 to 33?

Answer: 132xdx=8\int_1^3 2x\,dx = 8. Antiderivative is x2x^2, evaluated from 1 to 3 gives 91=89-1=8.

Flashcard 16: Find ddx0xln(t)dt\frac{d}{dx} \int_0^x \ln(t)\,dt.

Answer: ln(x)\ln(x). By FTC Part 1, derivative of integral equals integrand.

Flashcard 17: What is the integral of f(x)=sin(x)f(x) = \sin(x) from 00 to π\pi?

Answer: 0πsin(x)dx=2\int_0^{\pi} \sin(x)\,dx = 2. Antiderivative is cos(x)-\cos(x), giving total area under sine curve.

Flashcard 18: Evaluate 0πsin(x)dx\int_0^{\pi} \sin(x)\,dx.

Answer: 22. Antiderivative is cos(x)-\cos(x), evaluated from 0 to π\pi gives (1)(1)=2-(-1)-(-1)=2.

Flashcard 19: State the definition of a definite integral.

Answer: The limit of Riemann sums: limni=1nf(xi)Δx\lim_{n\to\infty} \sum_{i=1}^{n} f(x_i^*)\Delta x. Formal definition using limit of approximating rectangular areas.

Flashcard 20: What is the integral of f(x)=3x2f(x) = 3x^2 from 11 to 44?

Answer: 143x2dx=63\int_1^4 3x^2\,dx = 63. Antiderivative is x3x^3, so F(4)F(1)=641=63F(4) - F(1) = 64 - 1 = 63.

Flashcard 21: Evaluate 01(x4x2+1)dx\int_0^1 (x^4 - x^2 + 1)\,dx.

Answer: 56\frac{5}{6}. Sum of power functions integrated using standard power rule.

Flashcard 22: Find ddx0xet2dt\frac{d}{dx} \int_0^x e^{t^2}\,dt.

Answer: ex2e^{x^2}. By FTC Part 1, derivative equals the integrand with xx substituted.

Flashcard 23: What is the integral of f(x)=5xf(x) = 5x from 00 to 33?

Answer: 035xdx=22.5\int_0^3 5x\,dx = 22.5. Linear function 5x5x has antiderivative 5x22\frac{5x^2}{2}.

Flashcard 24: Find ddx0xsin(t)dt\frac{d}{dx} \int_0^x \sin(t)\,dt.

Answer: sin(x)\sin(x). By FTC Part 1, derivative of integral with variable upper limit equals integrand.

Flashcard 25: State the Mean Value Theorem for Integrals.

Answer: c[a,b]\exists c \in [a, b] such that f(c)=1baabf(x)dxf(c) = \frac{1}{b-a}\int_a^b f(x)\,dx. Guarantees existence of point where function equals its average value.

Flashcard 26: What is the integral of f(x)=1f(x) = 1 from 00 to 55?

Answer: 051dx=5\int_0^5 1\,dx = 5. Integral of constant function equals constant times interval length.

Flashcard 27: What is the integral of f(x)=4x3f(x) = 4x^3 from 00 to 11?

Answer: 014x3dx=1\int_0^1 4x^3\,dx = 1. Power rule: antiderivative of x3x^3 is x44\frac{x^4}{4}.

Flashcard 28: Compute 02(4xx2)dx\int_0^2 (4x - x^2)\,dx.

Answer: 163\frac{16}{3}. Quadratic function forming parabolic region with positive area.

Flashcard 29: What is the Fundamental Theorem of Calculus, Part 2?

Answer: abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b) - F(a), where FF is an antiderivative of ff. States that definite integral equals antiderivative evaluated at bounds.

Flashcard 30: Compute 01(x2x+1)dx\int_0^1 (x^2 - x + 1)\,dx.

Answer: 56\frac{5}{6}. Quadratic function integrated using power rule for each term.

Flashcard 31: Evaluate 0πsin(x)dx\int_0^{\pi} \sin(x)\,dx.

Answer: 22. Antiderivative is cos(x)-\cos(x), evaluated from 0 to π\pi gives (1)(1)=2-(-1)-(-1)=2.

Flashcard 32: Find ddx0xsin(t)dt\frac{d}{dx} \int_0^x \sin(t)\,dt.

Answer: sin(x)\sin(x). By FTC Part 1, derivative of integral with variable upper limit equals integrand.

Flashcard 33: What is the integral of f(x)=2xf(x) = 2x from 11 to 33?

Answer: 132xdx=8\int_1^3 2x\,dx = 8. Antiderivative is x2x^2, evaluated from 1 to 3 gives 91=89-1=8.

Flashcard 34: What is the average value of f(x)=x2f(x) = x^2 on [0,3][0, 3]?

Answer: 1303x2dx=3\frac{1}{3} \int_0^3 x^2\,dx = 3. Average value formula: 1baabf(x)dx\frac{1}{b-a}\int_a^b f(x)dx applied to x2x^2 on [0,3][0,3].

Flashcard 35: What is the integral of f(x)=3x2f(x) = 3x^2 from 11 to 44?

Answer: 143x2dx=63\int_1^4 3x^2\,dx = 63. Antiderivative is x3x^3, so F(4)F(1)=641=63F(4) - F(1) = 64 - 1 = 63.

Flashcard 36: Find the antiderivative of f(x)=5x4f(x) = 5x^4.

Answer: F(x)=x5+CF(x) = x^5 + C. Power rule for antiderivatives: increase exponent by 1, divide by new exponent.

Flashcard 37: What is the integral of f(x)=4x3f(x) = 4x^3 from 00 to 11?

Answer: 014x3dx=1\int_0^1 4x^3\,dx = 1. Power rule: antiderivative of x3x^3 is x44\frac{x^4}{4}.

Flashcard 38: Evaluate 12(x2+x)dx\int_1^2 (x^2 + x)\,dx.

Answer: 73\frac{7}{3}. Sum of power functions integrated using power rule.

Flashcard 39: What is the integral of f(x)=cos(x)f(x) = \cos(x) from 00 to π2\frac{\pi}{2}?

Answer: 0π2cos(x)dx=1\int_0^{\frac{\pi}{2}} \cos(x)\,dx = 1. Antiderivative is sin(x)\sin(x), evaluated from 0 to π2\frac{\pi}{2} gives 10=11-0=1.

Flashcard 40: What is the integral of f(x)=3f(x) = 3 from 00 to 22?

Answer: 023dx=6\int_0^2 3\,dx = 6. Integral of constant equals constant times interval width.

Flashcard 41: Compute 01(x2x+1)dx\int_0^1 (x^2 - x + 1)\,dx.

Answer: 56\frac{5}{6}. Quadratic function integrated using power rule for each term.

Flashcard 42: Find 02(x33x2+3x)dx\int_0^2 (x^3 - 3x^2 + 3x)\,dx.

Answer: 22. Cubic polynomial integrated using power rule for each term.

Flashcard 43: Compute 02(3x2+2x)dx\int_0^2 (3x^2 + 2x)\,dx.

Answer: 1212. Antiderivative is x3+x2x^3 + x^2, evaluated from 0 to 2 gives 8+4=128 + 4 = 12.

Flashcard 44: Compute 02(3x2+2x)dx\int_0^2 (3x^2 + 2x)\,dx.

Answer: 1212. Antiderivative is x3+x2x^3 + x^2, evaluated from 0 to 2 gives 8+4=128 + 4 = 12.

Flashcard 45: Find ddx0xet2dt\frac{d}{dx} \int_0^x e^{t^2}\,dt.

Answer: ex2e^{x^2}. By FTC Part 1, derivative equals the integrand with xx substituted.

Flashcard 46: What is the Fundamental Theorem of Calculus, Part 2?

Answer: abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b) - F(a), where FF is an antiderivative of ff. States that definite integral equals antiderivative evaluated at bounds.

Flashcard 47: What is the integral of f(x)=x3f(x) = x^3 from 1-1 to 11?

Answer: 00. Odd function over symmetric interval gives zero due to cancellation.

Flashcard 48: What is the integral of f(x)=sin(x)f(x) = \sin(x) from 00 to π\pi?

Answer: 0πsin(x)dx=2\int_0^{\pi} \sin(x)\,dx = 2. Antiderivative is cos(x)-\cos(x), giving total area under sine curve.

Flashcard 49: What is the integral of f(x)=5xf(x) = 5x from 00 to 33?

Answer: 035xdx=22.5\int_0^3 5x\,dx = 22.5. Linear function 5x5x has antiderivative 5x22\frac{5x^2}{2}.

Flashcard 50: State the formula for the area under a curve using integration.

Answer: Area = abf(x)dx\int_a^b f(x)\,dx. Fundamental connection between integration and area under curves.

Flashcard 51: Compute 02(4xx2)dx\int_0^2 (4x - x^2)\,dx.

Answer: 163\frac{16}{3}. Quadratic function forming parabolic region with positive area.

Flashcard 52: What is the integral of f(x)=3f(x) = 3 from 00 to 22?

Answer: 023dx=6\int_0^2 3\,dx = 6. Integral of constant equals constant times interval width.

Flashcard 53: What is the integral of f(x)=x3f(x) = x^3 from 1-1 to 11?

Answer: 00. Odd function over symmetric interval gives zero due to cancellation.

Flashcard 54: Evaluate 01(x4x2+1)dx\int_0^1 (x^4 - x^2 + 1)\,dx.

Answer: 56\frac{5}{6}. Sum of power functions integrated using standard power rule.

Flashcard 55: State the Mean Value Theorem for Integrals.

Answer: c[a,b]\exists c \in [a, b] such that f(c)=1baabf(x)dxf(c) = \frac{1}{b-a}\int_a^b f(x)\,dx. Guarantees existence of point where function equals its average value.

Flashcard 56: Find ddx0xln(t)dt\frac{d}{dx} \int_0^x \ln(t)\,dt.

Answer: ln(x)\ln(x). By FTC Part 1, derivative of integral equals integrand.