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  2. AP Calculus AB
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AP Calculus AB Flashcards: Exploring Accumulations Of Change

Study Exploring Accumulations Of Change in AP Calculus AB with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Exploring Accumulations Of Change, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus AB.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

AP Calculus AB Flashcards: Exploring Accumulations Of Change

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QUESTION

What is the integral of f(x)=sin⁡(x)f(x) = \sin(x)f(x)=sin(x) from 000 to π\piπ?

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ANSWER

∫0πsin⁡(x) dx=2\int_0^{\pi} \sin(x)\,dx = 2∫0π​sin(x)dx=2. Antiderivative is −cos⁡(x)-\cos(x)−cos(x), giving total area under sine curve.

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Flashcard 1: What is the integral of f(x)=sin⁡(x)f(x) = \sin(x)f(x)=sin(x) from 000 to π\piπ?

Answer: ∫0πsin⁡(x) dx=2\int_0^{\pi} \sin(x)\,dx = 2∫0π​sin(x)dx=2. Antiderivative is −cos⁡(x)-\cos(x)−cos(x), giving total area under sine curve.

Flashcard 2: What is the integral of f(x)=5xf(x) = 5xf(x)=5x from 000 to 333?

Answer: ∫035x dx=22.5\int_0^3 5x\,dx = 22.5∫03​5xdx=22.5. Linear function 5x5x5x has antiderivative 5x22\frac{5x^2}{2}25x2​.

Flashcard 3: What is the integral of f(x)=4x3f(x) = 4x^3f(x)=4x3 from 000 to 111?

Answer: ∫014x3 dx=1\int_0^1 4x^3\,dx = 1∫01​4x3dx=1. Power rule: antiderivative of x3x^3x3 is x44\frac{x^4}{4}4x4​.

Flashcard 4: What is the integral of f(x)=2xf(x) = 2xf(x)=2x from 111 to 333?

Answer: ∫132x dx=8\int_1^3 2x\,dx = 8∫13​2xdx=8. Antiderivative is x2x^2x2, evaluated from 1 to 3 gives 9−1=89-1=89−1=8.

Flashcard 5: Find the antiderivative of f(x)=5x4f(x) = 5x^4f(x)=5x4.

Answer: F(x)=x5+CF(x) = x^5 + CF(x)=x5+C. Power rule for antiderivatives: increase exponent by 1, divide by new exponent.

Flashcard 6: State the formula for the area under a curve using integration.

Answer: Area = ∫abf(x) dx\int_a^b f(x)\,dx∫ab​f(x)dx. Fundamental connection between integration and area under curves.

Flashcard 7: What is the integral of f(x)=exf(x) = e^xf(x)=ex from 000 to 111?

Answer: ∫01ex dx=e−1\int_0^1 e^x\,dx = e - 1∫01​exdx=e−1. Antiderivative is exe^xex, evaluated from 0 to 1 gives e−1e-1e−1.

Flashcard 8: What is the integral of f(x)=cos⁡(x)f(x) = \cos(x)f(x)=cos(x) from 000 to π2\frac{\pi}{2}2π​?

Answer: ∫0π2cos⁡(x) dx=1\int_0^{\frac{\pi}{2}} \cos(x)\,dx = 1∫02π​​cos(x)dx=1. Antiderivative is sin⁡(x)\sin(x)sin(x), evaluated from 0 to π2\frac{\pi}{2}2π​ gives 1−0=11-0=11−0=1.

Flashcard 9: What is the integral of f(x)=1f(x) = 1f(x)=1 from 000 to 555?

Answer: ∫051 dx=5\int_0^5 1\,dx = 5∫05​1dx=5. Integral of constant function equals constant times interval length.

Flashcard 10: State the definition of an antiderivative.

Answer: A function F(x)F(x)F(x) such that F′(x)=f(x)F'(x) = f(x)F′(x)=f(x) for all xxx in the domain. Function whose derivative equals the given function.

Flashcard 11: Compute ∫02(4x−x2) dx\int_0^2 (4x - x^2)\,dx∫02​(4x−x2)dx.

Answer: 163\frac{16}{3}316​. Quadratic function forming parabolic region with positive area.

Flashcard 12: Find ddx∫0xet2 dt\frac{d}{dx} \int_0^x e^{t^2}\,dtdxd​∫0x​et2dt.

Answer: ex2e^{x^2}ex2. By FTC Part 1, derivative equals the integrand with xxx substituted.

Flashcard 13: Compute ∫01(x2−x+1) dx\int_0^1 (x^2 - x + 1)\,dx∫01​(x2−x+1)dx.

Answer: 56\frac{5}{6}65​. Quadratic function integrated using power rule for each term.

Flashcard 14: Find ∫02(x3−3x2+3x) dx\int_0^2 (x^3 - 3x^2 + 3x)\,dx∫02​(x3−3x2+3x)dx.

Answer: 222. Cubic polynomial integrated using power rule for each term.

Flashcard 15: Evaluate ∫01(x4−x2+1) dx\int_0^1 (x^4 - x^2 + 1)\,dx∫01​(x4−x2+1)dx.

Answer: 56\frac{5}{6}65​. Sum of power functions integrated using standard power rule.

Flashcard 16: Compute ∫04(x−2) dx\int_0^4 (x - 2)\,dx∫04​(x−2)dx.

Answer: 000. Linear function with zero net area due to symmetry about x=2x=2x=2.

Flashcard 17: Find ddx∫0xln⁡(t) dt\frac{d}{dx} \int_0^x \ln(t)\,dtdxd​∫0x​ln(t)dt.

Answer: ln⁡(x)\ln(x)ln(x). By FTC Part 1, derivative of integral equals integrand.

Flashcard 18: Evaluate ∫12(x2+x) dx\int_1^2 (x^2 + x)\,dx∫12​(x2+x)dx.

Answer: 73\frac{7}{3}37​. Sum of power functions integrated using power rule.

Flashcard 19: State the Mean Value Theorem for Integrals.

Answer: ∃c∈[a,b]\exists c \in [a, b]∃c∈[a,b] such that f(c)=1b−a∫abf(x) dxf(c) = \frac{1}{b-a}\int_a^b f(x)\,dxf(c)=b−a1​∫ab​f(x)dx. Guarantees existence of point where function equals its average value.

Flashcard 20: Compute ∫02(3x2+2x) dx\int_0^2 (3x^2 + 2x)\,dx∫02​(3x2+2x)dx.

Answer: 121212. Antiderivative is x3+x2x^3 + x^2x3+x2, evaluated from 0 to 2 gives 8+4=128 + 4 = 128+4=12.

Flashcard 21: State the definition of a definite integral.

Answer: The limit of Riemann sums: lim⁡n→∞∑i=1nf(xi∗)Δx\lim_{n\to\infty} \sum_{i=1}^{n} f(x_i^*)\Delta xlimn→∞​∑i=1n​f(xi∗​)Δx. Formal definition using limit of approximating rectangular areas.

Flashcard 22: What is the integral of f(x)=3x2f(x) = 3x^2f(x)=3x2 from 111 to 444?

Answer: ∫143x2 dx=63\int_1^4 3x^2\,dx = 63∫14​3x2dx=63. Antiderivative is x3x^3x3, so F(4)−F(1)=64−1=63F(4) - F(1) = 64 - 1 = 63F(4)−F(1)=64−1=63.

Flashcard 23: Find ddx∫0xsin⁡(t) dt\frac{d}{dx} \int_0^x \sin(t)\,dtdxd​∫0x​sin(t)dt.

Answer: sin⁡(x)\sin(x)sin(x). By FTC Part 1, derivative of integral with variable upper limit equals integrand.

Flashcard 24: What is the Fundamental Theorem of Calculus, Part 2?

Answer: ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)∫ab​f(x)dx=F(b)−F(a), where FFF is an antiderivative of fff. States that definite integral equals antiderivative evaluated at bounds.

Flashcard 25: What is the integral of f(x)=x3f(x) = x^3f(x)=x3 from −1-1−1 to 111?

Answer: 000. Odd function over symmetric interval gives zero due to cancellation.

Flashcard 26: What is the average value of f(x)=x2f(x) = x^2f(x)=x2 on [0,3][0, 3][0,3]?

Answer: 13∫03x2 dx=3\frac{1}{3} \int_0^3 x^2\,dx = 331​∫03​x2dx=3. Average value formula: 1b−a∫abf(x)dx\frac{1}{b-a}\int_a^b f(x)dxb−a1​∫ab​f(x)dx applied to x2x^2x2 on [0,3][0,3][0,3].

Flashcard 27: Evaluate ∫0πsin⁡(x) dx\int_0^{\pi} \sin(x)\,dx∫0π​sin(x)dx.

Answer: 222. Antiderivative is −cos⁡(x)-\cos(x)−cos(x), evaluated from 0 to π\piπ gives −(−1)−(−1)=2-(-1)-(-1)=2−(−1)−(−1)=2.

Flashcard 28: What is the integral of f(x)=3f(x) = 3f(x)=3 from 000 to 222?

Answer: ∫023 dx=6\int_0^2 3\,dx = 6∫02​3dx=6. Integral of constant equals constant times interval width.

Flashcard 29: What is the integral of f(x)=exf(x) = e^xf(x)=ex from 000 to 111?

Answer: ∫01ex dx=e−1\int_0^1 e^x\,dx = e - 1∫01​exdx=e−1. Antiderivative is exe^xex, evaluated from 000 to 111 gives e−1e-1e−1.

Flashcard 30: State the formula for the area under a curve using integration.

Answer: Area = ∫abf(x) dx\int_a^b f(x)\,dx∫ab​f(x)dx. Fundamental connection between integration and area under curves.