All flashcards
Flashcard 1: How do you find limx→5f(x) if f(x) is constant?
Answer: The constant value. Constant functions have the same value everywhere.
Flashcard 2: What is the limit of limx→−af(x) for f(x)=x2?
Answer: a2. (−a)2=a2 for any real number a.
Flashcard 3: What is limx→0x1?
Answer: Does not exist; approaches ∞ as x→0+ and −∞ as x→0−. Left and right limits differ, so the limit doesn't exist.
Flashcard 4: What is the graphical significance of limx→cf(x)=∞?
Answer: Vertical asymptote at x=c. Infinite limits create vertical asymptotes on graphs.
Flashcard 5: What does limx→0e−x approach?
Answer:
- e−x approaches e0=1 as x→0.
Flashcard 6: What is indicated by limx→cf(x)=f(c)?
Answer: A removable discontinuity at x=c. The limit exists but doesn't equal the function value.
Flashcard 7: What does limx→af(x) equal if f(x) is linear?
Answer: f(a). Linear functions are continuous everywhere.
Flashcard 8: Identify limx→0−x1.
Answer: −∞. Approaching from the left gives negative infinity.
Flashcard 9: Identify limx→−∞f(x) from the graph.
Answer: The left horizontal asymptote value if it exists. Check where the graph levels off on the left side.
Flashcard 10: What does limx→af(x)=f(a) imply?
Answer: Function is continuous at x=a. The limit equals the function value at that point.
Flashcard 11: How do you find limx→5f(x) if f(x) is constant?
Answer: The constant value. Constant functions have the same value everywhere.
Flashcard 12: How do you denote the limit of f(x) as x approaches a from the right?
Answer: limx→a+f(x). The plus superscript denotes right-hand limit notation.
Flashcard 13: What is the behavior of f(x) near x=a if limx→af(x)=L?
Answer: Approaches L as x approaches a. This describes the fundamental limit behavior.
Flashcard 14: What is limx→0sin(x1)?
Answer: The limit does not exist due to oscillation. The function oscillates infinitely near x=0.
Flashcard 15: What does a continuous graph imply about limits at all points?
Answer: Limits exist and equal the function values. Continuity guarantees limit existence everywhere.
Flashcard 16: Determine limx→∞x21 using a graph.
Answer:
- x21 approaches 0 as x becomes large.
Flashcard 17: Which term describes the behavior of f(x) as x→2+?
Answer: Right-hand limit. The + superscript indicates approach from the right side.
Flashcard 18: Determine limx→0x2 using a graph.
Answer:
- The function x2 approaches 0 as x approaches 0.
Flashcard 19: What is the result of limx→2−f(x) if f(x) jumps at x=2?
Answer: The y-value approaching from the left of x=2. One-sided limits can exist even with jump discontinuities.
Flashcard 20: Determine limx→4f(x) if f(x) is continuous at x=4.
Answer: f(4). Continuity means the limit equals the function value.
Flashcard 21: How does limx→0x21 behave?
Answer: Approaches ∞. x21 grows without bound near x=0.
Flashcard 22: What is limx→cf(x) if f(x) is undefined at x=c?
Answer: The y-value f(x) approaches as x nears c. Limits exist even when function values don't.
Flashcard 23: State the notation for the left-hand limit of f(x) at x=a.
Answer: limx→a−f(x). Standard notation for left-hand limits.
Flashcard 24: State the meaning of limx→cf(x)=L.
Answer: f(x) approaches L as x approaches c. This is the formal definition of a limit.
Flashcard 25: How do you denote the limit of f(x) as x approaches a on a graph?
Answer: limx→af(x). Standard mathematical notation for limits.
Flashcard 26: What does limx→c−f(x) represent?
Answer: Limit from the left of c. The minus superscript indicates approach from the left.
Flashcard 27: What does limx→∞x1 equal?
Answer:
- x1 approaches 0 as x becomes large.
Flashcard 28: How do you find limx→∞f(x) from a graph?
Answer: Identify the horizontal asymptote if it exists. Look for the horizontal line the graph approaches.
Flashcard 29: What is the limit as x→∞ of a linear function?
Answer: Does not exist; increases or decreases without bound. Linear functions grow without bound at infinity.
Flashcard 30: State the vertical asymptote implication for limits.
Answer: Limit does not exist at the vertical asymptote. Vertical asymptotes prevent limit existence.