Equations involving derivatives - AP Calculus AB

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Question

Find the eqation of the line tangent to the graph of $y=x+x^{1/2}$ at point .

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Answer

$y=x+x^{1/2}$

$y'=1+\frac{1}{2}$x^{-1/2}$

$y'=1+\frac{1}{2(x^{1/2}$$)}

Now we plug in .

$y'=1+\frac{1}{2(4^{1/2}$$)} = 1+\frac{1}{4}$ = $\frac{5}{4}$ this is the slope.

Now use the point slope formula to find the tangent line.

y-6=\frac{5}{4}$(x-4)

y-6=\frac{5}{4}$x-5

y=\frac{5}{4}$x+1

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