All flashcards
Flashcard 1: Find limx→0xsin(x21) using the Squeeze Theorem.
Answer: 0. Since −∣x∣≤xsin(x21)≤∣x∣ and both bounds approach 0.
Flashcard 2: Determine limx→0x3cos(x31) using the Squeeze Theorem.
Answer: 0. Since −x3≤x3cos(x31)≤x3 and both bounds approach 0.
Flashcard 3: What is limx→0x4sin(x31)?
Answer: 0. Since −x4≤x4sin(x31)≤x4 and both bounds approach 0.
Flashcard 4: Determine limx→0x4cos(x1) using the Squeeze Theorem.
Answer: 0. Since −x4≤x4cos(x1)≤x4 and both bounds approach 0.
Flashcard 5: Find limx→∞xsinx using the Squeeze Theorem.
Answer: 0. Since −x1≤xsinx≤x1 and both bounds approach 0.
Flashcard 6: What should g(x) and h(x) approach for limx→cf(x) to exist?
Answer: The same limit L. This ensures the squeezed function approaches the unique limit.
Flashcard 7: Find limx→0x2sin(x1) using the Squeeze Theorem.
Answer: 0. Since −∣x2∣≤x2sin(x1)≤∣x2∣ and both bounds approach 0.
Flashcard 8: Determine limx→0x2cos(x2) using the Squeeze Theorem.
Answer: 0. Since ∣x2cos(x2)∣≤x2 and x2→0.
Flashcard 9: Find limx→0x3sin(x1) using the Squeeze Theorem.
Answer: 0. Since −∣x3∣≤x3sin(x1)≤∣x3∣ and both bounds approach 0.
Flashcard 10: State the Squeeze Theorem in terms of f(x), g(x), h(x).
Answer: If g(x)≤f(x)≤h(x) and limx→cg(x)=limx→ch(x)=L, then limx→cf(x)=L. The fundamental statement of the Squeeze Theorem with three functions.
Flashcard 11: What is limx→0x3sin(x2) using the Squeeze Theorem?
Answer: 0. Since ∣x3sin(x2)∣≤x3 and x3→0.
Flashcard 12: Find limx→0x2cos(x1) using the Squeeze Theorem.
Answer: 0. Since −x2≤x2cos(x1)≤x2 and both bounds approach 0.
Flashcard 13: Find limx→0x5sin(x41) using the Squeeze Theorem.
Answer: 0. Since −x5≤x5sin(x41)≤x5 and both bounds approach 0.
Flashcard 14: What is the limit limx→0x2sin(x2)?
Answer: 0. Since ∣x2sin(x2)∣≤x2 and x2→0.
Flashcard 15: What is limx→0x4cos(x51)?
Answer: 0. Since −x4≤x4cos(x51)≤x4 and both bounds approach 0.
Flashcard 16: Determine limx→0x4sin(x1) using the Squeeze Theorem.
Answer: 0. Since −x4≤x4sin(x1)≤x4 and both bounds approach 0.
Flashcard 17: What inequality must f(x) satisfy in the Squeeze Theorem?
Answer: g(x)≤f(x)≤h(x). This defines the sandwich relationship between the three functions.
Flashcard 18: Find limx→0x2cosx using the Squeeze Theorem.
Answer: 0. Since ∣x2cosx∣≤x2 and x2→0.
Flashcard 19: Find limx→0x3sin(x2) using the Squeeze Theorem.
Answer: 0. Since −x3≤x3sin(x2)≤x3 and both bounds approach 0.
Flashcard 20: Determine limx→0x3cos(x4) using the Squeeze Theorem.
Answer: 0. Since ∣x3cos(x4)∣≤x3 and x3→0.
Flashcard 21: What is the Squeeze Theorem used for in calculus?
Answer: To determine the limit of a function. Forces a function between two bounds that approach the same limit.
Flashcard 22: What is the limit of xsin(x1) as x→0?
Answer: 0. Bounded between −∣x∣ and ∣x∣, both approaching 0.
Flashcard 23: What is the limit limx→0x2sin(x41)?
Answer: 0. Since −x2≤x2sin(x41)≤x2 and both bounds approach 0.
Flashcard 24: What is limx→0x2sinx?
Answer: 0. Since ∣x2sinx∣≤x2 and x2→0.
Flashcard 25: Is limx→0x2sin(x3) zero?
Answer: Yes. Since ∣x2sin(x3)∣≤x2 and x2→0.
Flashcard 26: Is limx→0x2sin(x1) finite?
Answer: Yes, it is 0. The limit equals 0, which is a finite value.
Flashcard 27: Is limx→0xsinx equal to zero?
Answer: Yes. Since ∣xsinx∣≤∣x∣ and ∣x∣→0.
Flashcard 28: Can the Squeeze Theorem be used if limx→cg(x)eqlimx→ch(x)?
Answer: No. The bounding functions must approach the same value for the theorem to work.
Flashcard 29: Determine limx→0x5sin(x61) using the Squeeze Theorem.
Answer: 0. Since −x5≤x5sin(x61)≤x5 and both bounds approach 0.
Flashcard 30: What is limx→0xsin(x2)?
Answer: 0. Bounded between −∣x∣ and ∣x∣, both approaching 0.