All flashcards
Flashcard 1: Find the limit: limx→3(2x+1).
Answer: 7. Direct substitution works for polynomial functions.
Flashcard 2: Find limx→2(x2−4)/(x−2). Is it continuous at x=2?
Answer: Limit is 4, not continuous without f(2) defined. Use L'Hôpital's rule or factor: limit is 4, but function undefined.
Flashcard 3: Is f(x)=x1 continuous at x=0? Why or why not?
Answer: No, f(x) is undefined at x=0. Division by zero makes the function undefined at that point.
Flashcard 4: Find the value of c that makes f(x)=cx+1 continuous at x=2 if f(2)=5.
Answer: c=2. Set 2c+1=5 and solve: c=2.
Flashcard 5: What is the definition of continuity at a point x=a?
Answer: A function f(x) is continuous at x=a if limx→af(x)=f(a). The limit must exist and equal the function value at that point.
Flashcard 6: Is h(x)=x−11 continuous at x=1?
Answer: No, h(x) is undefined at x=1. Vertical asymptote creates an infinite discontinuity.
Flashcard 7: State the Intermediate Value Theorem.
Answer: If f(x) is continuous on [a,b], f(a)<N<f(b) then exists c such that f(c)=N. Guarantees all intermediate values exist for continuous functions on closed intervals.
Flashcard 8: What is the first step in confirming continuity at a point?
Answer: Verify f(a) is defined. Cannot check continuity if the function value doesn't exist.
Flashcard 9: What is the definition of a jump discontinuity?
Answer: When limx→a−f(x)=limx→a+f(x). Left and right approaches yield different limit values.
Flashcard 10: Determine if f(x)=x−3x2−9 is continuous at x=3.
Answer: No, f(x) has a removable discontinuity. Factor: x−3(x+3)(x−3)=x+3, but f(3) undefined.
Flashcard 11: What must be true for f(x) to be continuous from the right at x=a?
Answer: limx→a+f(x)=f(a). Right-hand limit must equal the function value.
Flashcard 12: What is a point of discontinuity?
Answer: A point where f(x) is not continuous. Where any of the three continuity conditions fail.
Flashcard 13: If f(x)=x−2x2−4, what value must f(2) be for continuity at x=2?
Answer: 4. Factor and simplify: x−2(x+2)(x−2)=x+2, so limit is 4.
Flashcard 14: What must be true about limx→a−f(x) and limx→a+f(x) for continuity at x=a?
Answer: They must both exist and be equal to f(a). Left and right limits must converge to the same value as the function.
Flashcard 15: Is g(x)=ln(x) continuous for x>0?
Answer: Yes, g(x) is continuous for x>0. Natural logarithm is continuous on its entire domain.
Flashcard 16: What is the limit limx→23x+1?
Answer: 7. Direct substitution: 3(2)+1=7.
Flashcard 17: Identify the type of discontinuity if limx→af(x) does not exist.
Answer: This is an infinite or jump discontinuity. When limits don't exist, the function has a break or approaches infinity.
Flashcard 18: If f(x) is continuous on [0,1] and f(0)=3, can f(1)=0?
Answer: Yes, if f(x) decreases continuously. IVT guarantees all values between f(0) and f(1) are achieved.
Flashcard 19: If limx→af(x)=L and f(a)=L, is f(x) continuous at x=a?
Answer: Yes, f(x) is continuous at x=a. All three conditions for continuity are satisfied.
Flashcard 20: Find limx→0xsin(x).
Answer: 1. Standard trigonometric limit used in derivative of sine.
Flashcard 21: For f(x)=x−2x3−8, does f(x) have a removable discontinuity at x=2?
Answer: Yes, f(x) has a removable discontinuity. Factor: x−2(x−2)(x2+2x+4)=x2+2x+4, limit exists.
Flashcard 22: What type of discontinuity is present if f(x) is undefined at x=a?
Answer: It could be a removable or infinite discontinuity. Depends on whether the function approaches infinity or has a finite limit.
Flashcard 23: State the condition for f(x) to be continuous at an endpoint a of [a,b].
Answer: limx→a+f(x)=f(a). Only right-hand continuity needed at left endpoint.
Flashcard 24: Which theorem guarantees a root exists in [a,b] if f(a)×f(b)<0?
Answer: The Intermediate Value Theorem. Sign change guarantees a zero by IVT for continuous functions.
Flashcard 25: What is the condition for continuity from the left at x=a?
Answer: limx→a−f(x)=f(a). Left-hand limit must equal the function value.
Flashcard 26: For g(x)=x−1x2−1, does g(x) have a removable discontinuity at x=1?
Answer: Yes, g(x) has a removable discontinuity. Factor: x−1(x+1)(x−1)=x+1, limit exists at x=1.
Flashcard 27: Identify the discontinuity: limx→af(x) exists but f(a) is not defined.
Answer: Removable discontinuity. The 'hole' can be filled by defining the function at that point.
Flashcard 28: If f(x)=x3, is f(x) continuous on (−\textinfty,\textinfty)?
Answer: Yes, f(x) is continuous everywhere. Polynomial functions are continuous everywhere in their domain.
Flashcard 29: What is a removable discontinuity?
Answer: A point where a function is not defined, but the limit exists. Can be 'fixed' by defining or redefining the function at that point.
Flashcard 30: What ensures a function is continuous on a closed interval [a,b]?
Answer: Continuous on (a,b), right at a, left at b. Requires continuity at all interior points plus endpoint conditions.