AP Biology › Understand steps of transcription
Which of the following proteins play a role in proofreading during transcription?
RNA polymerase
Activators
Transcription factors
RNA ligase
Proofreading occurs during the elongation phase of transcription. RNA polymerase's movement over the DNA template strand includes a backtracking motion that allows RNA polymerase to proofread the newly synthesized RNA transcript.
What type of chromatin would be found in telomeres and centromeres?
Heterochromatin
Euchromatin
Both heterochromatin and euchromatin
Either heterochromatin or euchromatin, depending on the cell type
Neither heterochromatin nor euchromatin
Telomeres and centromeres are composed of heterochromatin. In contrast to euchromatin, heterochromatin's genes are generally in an inactive state. This is because the genetic material is highly condensed. Often, heterochromatin is thought of as "junk DNA". Since telomeres are slowly being degraded during DNA replication, the cell does not want to have active or important genes in this area. Same goes for centromeres, where there is the possibility of chromatids not separating evenly across the centromere in anaphase.
A DNA template is composed of the following nucleotide sequence:
5'-TACGCATT-3'
What is the mRNA transcript for this template?
5'-AAUGCGUA-3'
5'-TTACGCAT-3'
5'-UACGCAUU-3'
5'-AATGCGTA-3'
5'-AUGCGUAA-3'
When finding the mRNA transcript from a template, there are two things to keep in mind:
1. The template strand will be complementary to the transcript, so it will be read in the opposite direction
2. Since the template strand is made from DNA, it will have thymine bases instead of uracil (which is found in RNA in place of thymine).
First, we can reverse the direction of our given DNA sequence.
5'-TACGCATT-3'
3'-TTACGCAT-5'
Then, complete each base pair. Guanine (G) and cytosine (C) always pair, and adenine (A) and thymine (T) always pair. In this case, since we are dealing with RNA, uracil (U) will have an adenine complement.
5'-AAUGCGUA-3'
RNA polymerase transcribes the following sequence of DNA:
5'-ATGCCCAT-3'
What is the resulting RNA sequence from 5' to 3'?
5'-AUGGGCAU-3'
5'-UACGGGUA-3'
5'-ATGGGCAT-3'
5'-TACGGGTA-3'
None of these
RNA polymerase transcribes a DNA template in the 3' to 5' direction, creating an RNA molecule 5' to 3'. The DNA sequence given in the question therefore needs to be flipped around and read in the 3' to 5' direction in order to determine the resulting what the RNA sequence will be 5' to 3'. Additionally, the nitrogenous base thymine (T) is replaced by uracil (U) in RNA, so every location where a T would go in the RNA sequence needs to be replaced by a U.
Which of the following choices is not a true characteristic of the promoter sequence?
It is the start of transcription
It binds to transcription factors
It is a part of the pre-initiation complex
A well-characterized example of a promoter is the TATA box
Promoter sequences are regions of DNA located upstream of transcription start sites. Transcription factors bind to the promoter sequence, which promotes the binding of RNA polymerase and initiation of transcription. Together, along with activators and repressors, these make up the pre-initiation complex. A well-characterized promoter sequence is called the TATA box, which is present within promoters of of human genes.
What is the central dogma of molecular biology?
DNA, RNA, Protein
RNA, DNA, Protein
Protien, DNA, RNA
RNA, Protein, DNA
DNA, Protein, RNA
Proteins are coded for by RNA, which is coded for by DNA. The central dogma of molecular biology is the general sequence for the flow of information in coding for a protein. An mRNA strand is created using the DNA strand as a template. This new strand of mRNA then leaves the nucleus and is used as a template for 3-pronged tRNA molecules carrying amino acids to create a chain, which will eventually create a protein.
The central dogma of molecular biology is the general sequence of DNA to RNA to protein.
Which of the following is not an example of post-transcriptional modification of a primary strand of mRNA?
Insertion of exons
Addition of the poly-A tail
Addition of the 5' cap
Removal of introns
All of these are post-transcriptional modifications of mRNA
Following DNA transcription, the resulting RNA molecule must be modified before leaving the nucleus. Proteins in the nucleus add a 5' cap to the 5' end of the RNA strand, and a poly-A tail to the 3' end. These additions help prevent degradation of the transcript by any hydrolytic enzymes in the cytosol. Protein complexes called spliceosomes interact with the transcript to remove segments of non-coding RNA called introns. The remaining transcript following the excision of introns is composed only of coding segments of RNA, known as exons.
Though introns are removed during post-transcriptional modification, exons are not inserted. Rather, they are simply the remaining RNA sequences after the introns have been spliced out.
The process by which the genetic code of DNA is copied into a strand of messenger RNA is called __________.
transcription
translation
transformation
replication
The process by which the genetic code of DNA is copied into a strand of messenger RNA is called transcription. Translation uses messenger RNA, transfer RNA, and ribosomal RNA to create a chain of amino acids that become a protein. Replication is the reproduction of two strands of DNA that are used in a new cell.
Major histocompatibility molecules (MHC) are critical for the functioning of the immune system. These proteins are utilized allow for communication between the immune system and the cells. MHC I are utilized to show which cells are in fact part of the body and which are foreign. MHC II are utilized to show the immune system when there is an intruder.
MHC I molecules are derived from chromosome 6. On chromosome 6, there is a specific gene that encodes for the molecule. On the gene, there are 3 locus (A, B, C) which allows for variability in the binding site of the MHC I molecule. The MHC gene is co-dominance and therefore adds to its diversity. During development, the gene is transcribed into MHC I molecules. However, some of these are broken down and react with a particular MHC I molecule. The reaction allows for the MHC I molecule to surface onto the cellular membrane and to self-identify the protein for the cytotoxic T-cell.
After translation, MHC II molecules are transported to the endosome. When a pathogen binds to the proper MHC II binding site, these molecules are then presented to T-Helper cells. In comparison, MHC I molecules interact with endogenous antigens whereas MHC II molecules interact with exogenous antigens.
Based on the passage, where are MHC molecules transcribed?
Nucleus
Ribosome
Rough endoplasmic reticulum
Smooth endoplasmic reticulum
Cytoplasm
From the passage, chromosome 6 carries the information for the MHC molecules. The chromosomes are stored in the nucleus of the cell. Therefore, transcription occurs in the nucleus.
Which of the following choices describes coding sequences?
They are the sequence of DNA that will be translated into a protein
They have an upstream 3' UTR
They describe only the promoter
They are the sequenes that do not code for proteins
A coding sequence is the sequence of DNA that will code for a particular protein. In this process an messenger or mRNA molecule is transcribed from DNA and later translated into a protein by ribosomes. Messenger or mRNA is flanked by an upstream 5’ UTR untranslated leader sequence and a downstream 3’ UTR untranslated region that follows the termination codon of the synthesized protein.