This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. For inequalities, words like 'at most,' 'maximum,' 'no more than' signal ≤ (less than or equal), while 'at least,' 'minimum,' 'no less than' signal ≥ (greater than or equal). 'More than' means > (strict), and 'less than' means <. These key phrases tell you which inequality symbol to use! The context 'tickets cost $9 each with a $4 fee, at most $40' uses the phrase 'at most,' which signals ≤. Setting up: cost per ticket times number plus fee ≤ total available, so 9t + 4 ≤ 40. Solving: subtract 4 → 9t ≤ 36, divide by 9 → t ≤ 4. This means Jordan can buy a maximum of 4 whole tickets. Choice A is correct because it properly sets up the inequality from the context with the fee added and uses ≤ for 'at most,' giving t ≤ 4 tickets within budget. Choice D sets up the inequality incorrectly: it switches the variables to 4t + 9 ≤ 40, which would be like $4 per ticket and $9 fee, but the problem says $9 tickets and $4 fee—reading carefully for relationships is key! For inequalities, make a quick reference card: 'at most/maximum/no more than' → ≤ (can equal or be less), 'at least/minimum/no less than' → ≥ (can equal or be more), 'more than/over' → > (strictly greater), 'less than/under' → < (strictly less). Having these memorized means you'll never use the wrong symbol!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. For rate problems like this, we set up: when working together, rates add. Pump A's rate is 1/10 tank per hour, Pump B's rate is 1/x tank per hour, and together they fill at 1/6 tank per hour. This gives us 1/10 + 1/x = 1/6. Solving: 1/x = 1/6 - 1/10 = 5/30 - 3/30 = 2/30 = 1/15. Therefore x = 15. Interpreting: Pump B alone takes 15 hours to fill the tank. Choice B is correct because it properly sets up the rate equation from context and solves correctly, giving x = 15 hours for Pump B alone. Choice A would mean Pump B works faster than the combined rate, which is impossible—two pumps together must work faster than either alone! When solving rate problems, remember that rates add when working together. Different contexts = different equation types: constant rates and simple relationships → linear, area and projectile motion → quadratic, working together and rate problems → rational, growth/decay over time → exponential. Recognizing these patterns helps you set up the right type of equation immediately!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. This is an area problem, which means quadratic! Let w = width. The relationship 'length is 5 more than width, area 84' translates to w(w + 5) = 84, or w² + 5w - 84 = 0. Using quadratic formula, discriminant 25 + 336 = 361 = 19², so w = [-5 ± 19]/2, giving w = 7 or w = -12 (discard negative). So valid solution w = 7 with interpretation: the garden is 7 feet wide and 12 feet long. Choice A is correct because it properly sets up the quadratic from the area context, solves correctly, and interprets appropriately, giving w = 7 feet that makes sense. Choice C solves the equation correctly but doesn't check the context: w = 12 would imply length = 17, but that's swapping variables— the question asks for width, which is the smaller one. Always ask: does my answer make sense in the real world? This catches a lot of mistakes! The 'reality check' is your best friend: after solving, substitute your answer back into the original equation (math check), then ask 'does this make sense?' (reality check). Can dimensions be negative? Can you buy 7.3 shirts? Can there be -4 hours? The context tells you what's possible and what's not!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. This is a motion problem, which means quadratic! Let t = time in seconds. The relationship 'height after t seconds is given by h = -16t² + 64t' and 'when the ball is on the ground' translates to set h=0: -16t² + 64t = 0. Using factoring, -16t(t - 4) = 0, so t=0 or t=4. Checking context: both make sense—at t=0 (start) and t=4 (lands). Interpreting: the ball is on the ground at 0 seconds and after 4 seconds. Choice B is correct because it properly sets up the quadratic equation from context, solves correctly, and interprets appropriately, giving t=0 and t=4 seconds. Choice D finds one solution to the quadratic but misses the other: solving gives two values, but perhaps they ignored t=0 since it's the start. For quadratics, always check both solutions against the real-world situation! The 'reality check' is your best friend: after solving, substitute your answer back into the original equation (math check), then ask 'does this make sense?' (reality check). Can dimensions be negative? Can you buy 7.3 shirts? Can there be -4 hours? The context tells you what's possible and what's not!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. This is an area problem, which means quadratic! Let w = width. The relationship 'length that is 5 feet more than its width' and 'area of the garden is 84 square feet' translates to w(w + 5) = 84, or w² + 5w - 84 = 0. Using factoring, we get (w + 12)(w - 7) = 0, so w = -12 or w = 7. But wait—checking context: negative width doesn't make sense, so w = 7 feet. Interpreting: the width is 7 feet, length 12 feet, area 84 sq ft. Choice A is correct because it properly sets up the quadratic equation from context, solves correctly, and interprets appropriately, giving w=7 feet. Choice B finds one solution to the quadratic but misses the other (or keeps an extraneous one): solving gives w=7 and w=-12, but perhaps they took the positive non-valid or switched length/width. For quadratics, always check both solutions against the real-world situation! The 'reality check' is your best friend: after solving, substitute your answer back into the original equation (math check), then ask 'does this make sense?' (reality check). Can dimensions be negative? Can you buy 7.3 shirts? Can there be -4 hours? The context tells you what's possible and what's not!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. For inequalities, words like 'at most,' 'maximum,' 'no more than' signal ≤ (less than or equal), while 'at least,' 'minimum,' 'no less than' signal ≥ (greater than or equal). 'More than' means > (strict), and 'less than' means <. These key phrases tell you which inequality symbol to use! The context 'at most $50 to spend' uses the phrase 'at most,' which signals ≤. Setting up: cost of notebooks ≤ money available, so 4n ≤ 50. Solving: n ≤ 12.5. This means a maximum of 12 whole notebooks (can't buy half a notebook!). Choice B is correct because it properly sets up the inequality from context, solves correctly, and interprets appropriately in the real world, giving maximum n = 12 notebooks. Choice C would cost 4(13) = $52, which exceeds the $50 budget. When dealing with discrete items like notebooks, always round down to stay within the constraint! For inequalities, make a quick reference card: 'at most/maximum/no more than' → ≤ (can equal or be less), 'at least/minimum/no less than' → ≥ (can equal or be more), 'more than/over' → > (strictly greater), 'less than/under' → < (strictly less). Having these memorized means you'll never use the wrong symbol!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. This is an area problem, which means quadratic! Let w = width in feet. The relationship 'length is 5 feet more than width' translates to length = w + 5. Since area = length × width = 84, we get w(w + 5) = 84. Expanding: w² + 5w = 84, so w² + 5w - 84 = 0. Using factoring: (w + 12)(w - 7) = 0, we get w = -12 or w = 7. But wait—checking context: width can't be negative! So w = 7 feet with interpretation: the garden is 7 feet wide and 12 feet long. Choice A is correct because it properly sets up the quadratic equation from the area context, solves correctly, and eliminates the extraneous negative solution, giving w = 7 feet. Choice B would give a length of 14 feet and area of 9 × 14 = 126 square feet, not 84. When solving quadratics from real-world contexts, always check both solutions—one often doesn't make physical sense! The 'reality check' is your best friend: after solving, substitute your answer back into the original equation (math check), then ask 'does this make sense?' (reality check). Can dimensions be negative? Can you buy 7.3 shirts? Can there be -4 hours? The context tells you what's possible and what's not!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Different contexts lead to different equation types: constant rates give linear equations (like cost = rate × quantity + fee), area problems often give quadratics (like length × width = area), and growth over time gives exponentials (like population = initial × (growth $rate)^time$). The context clues tell you which form to use. For rate problems like this, we set up: rates add when working together, so Pump A rate 1/12 + Pump B rate 1/x = combined rate 1/8. This gives us 1/12 + 1/x = 1/8. Solving: subtract 1/12 → 1/x = 1/8 - 1/12 = (3-2)/24 = 1/24, so x=24. Interpreting: Pump B takes 24 hours alone. Choice B is correct because it properly sets up the rational equation from context, solves correctly, and interprets appropriately, giving x=24 hours. Choice A makes an arithmetic error: perhaps in subtracting fractions, doing 1/8 - 1/12 = (3-2)/24=1/24 correctly but then misinterpreting. With all the steps in solving word problems—setting up, solving, interpreting—it's easy for calculation errors to slip in. Double-checking arithmetic is always worth it! The foolproof word problem strategy: (1) Read carefully and identify what's unknown—that's your variable, (2) Find what you know—those are your numbers, (3) Look for relationships—how are quantities connected? This gives you the equation, (4) Solve the equation using appropriate methods, (5) Check: does your answer satisfy the equation AND make sense in context? Following these steps systematically prevents most mistakes!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Creating an equation from a word problem means identifying the unknown quantity (your variable h), finding what you know (the numbers), and writing an equation that captures the relationship the problem describes. For example, 'a plumber charges $55 plus $35 per hour for a $195 job' becomes $55 + 35h = 195$, where h is hours worked. Let's break down 'A plumber charges a $55 service fee plus $35 per hour. The total bill was $195$': We need to find hours worked, so let h = hours. From the context, fixed fee plus rate per hour times hours equals total means $55 + 35h = 195$. Solving: subtract 55 from both sides → $35h = 140$, divide by 35 → $h = 4$. In context: the plumber worked 4 hours. Choice A is correct because it properly sets up the equation from context and solves correctly, giving $h=4$, meaning 4 hours for the job. Choice B sets up the equation incorrectly: it forgets the fixed fee, perhaps doing $35h=195$ → $h ≈ 5.57$ (rounding to 5), but when the context says 'plus $55 service fee,' that means add 55, not ignore it. Reading carefully for relationships is key! The foolproof word problem strategy: (1) Read carefully and identify what's unknown—that's your variable, (2) Find what you know—those are your numbers, (3) Look for relationships—how are quantities connected? This gives you the equation, (4) Solve the equation using appropriate methods, (5) Check: does your answer satisfy the equation AND make sense in context? Following these steps systematically prevents most mistakes!

This question tests your ability to translate a real-world situation into a mathematical equation or inequality, solve it, and interpret the result in the original context. Creating an equation from a word problem means identifying the unknown quantity (your variable x), finding what you know (the numbers), and writing an equation that captures the relationship the problem describes. For example, 'mixing solutions' often uses weighted averages for concentrations. Let's break down 'You are mixing a sports drink that should be 30% juice. You have 2 liters of a 60% juice mix and you will add x liters of water (0% juice)': We need to find liters of water, so let x = liters added. From the context, total juice equals desired percent times total volume means 0.6×2 + 0×x = 0.3×(2 + x). Solving: 1.2 = 0.3(2 + x) → 1.2 = 0.6 + 0.3x → 0.6 = 0.3x → x = 2. In context: add 2 liters of water to get 30% juice. Choice C is correct because it properly sets up the equation from context and solves correctly, giving x=2 liters. Choice B makes an arithmetic error: perhaps setting up as 0.6×(2 + x) = 0.3×2 or reversing, leading to wrong x=3. With all the steps in solving word problems—setting up, solving, interpreting—it's easy for calculation errors to slip in. Double-checking arithmetic is always worth it! The foolproof word problem strategy: (1) Read carefully and identify what's unknown—that's your variable, (2) Find what you know—those are your numbers, (3) Look for relationships—how are quantities connected? This gives you the equation, (4) Solve the equation using appropriate methods, (5) Check: does your answer satisfy the equation AND make sense in context? Following these steps systematically prevents most mistakes!