Study Zeros Of Polynomials To Construct Graphs in Algebra with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: What is the y-intercept of y=f(x) written using f(0)?
Answer: The y-intercept is (0,f(0)). Found by substituting x=0 into the function.
Flashcard 2: Identify the x-intercepts of f(x)=−(x+2)2(x−3).
Answer: (−2,0) and (3,0). X-intercepts occur where each distinct zero is located.
Flashcard 3: What does an odd multiplicity zero do to the graph at x=r?
Answer: The graph crosses the x-axis at x=r. Odd multiplicities cause the graph to pass through.
Flashcard 4: Identify the zeros of f(x)=(x−5)2 and state the multiplicity.
Answer: x=5 with multiplicity 2. Only one distinct zero from the squared factor.
Flashcard 5: Identify the zeros of f(x)=x4−16 by factoring completely over reals.
Answer: x=2 and x=−2. Factor as difference of squares twice: (x2−4)(x2+4)=(x−2)(x+2)(x2+4).
Flashcard 6: Identify the zeros of f(x)=(3x+6)(x−2).
Answer: x=−2 and x=2. Factor out the common factor: 3(x+2)(x−2)=0.
Flashcard 7: Identify the zeros of f(x)=(2x−1)(x+4).
Answer: x=21 and x=−4. Set each factor equal to zero: 2x−1=0 and x+4=0.
Flashcard 8: What is the end behavior if degree is odd and leading coefficient is negative?
Answer: As x→−∞, f(x)→∞; as x→∞, f(x)→−∞. Odd degree with negative lead: left up, right down.
Flashcard 9: What is the maximum number of real zeros a degree n polynomial can have?
Answer: At most n real zeros. Fundamental Theorem of Algebra applied to real zeros.
Flashcard 10: What is a zero of a polynomial function f(x)?
Answer: A value r such that f(r)=0. When the function equals zero at that input value.
Flashcard 11: Identify whether f(x)=−(x+2)2(x−3) crosses or touches at x=−2.
Answer: Touches and turns at x=−2. Even multiplicity 2 means touch and turn behavior.
Flashcard 12: Identify the zeros of f(x)=2x2−8x by factoring.
Answer: x=0 and x=4. Factor out 2x: 2x(x−4)=0.
Flashcard 13: What is the end behavior if degree is odd and leading coefficient is positive?
Answer: As x→−∞, f(x)→−∞; as x→∞, f(x)→∞. Odd degree with positive lead: left down, right up.
Flashcard 14: What is the maximum number of turning points a degree n polynomial can have?
Answer: At most n−1 turning points. Local maxima and minima occur between zeros.
Flashcard 15: Identify the zeros of f(x)=x2−9 by factoring.
Answer: x=3 and x=−3. Factor as difference of squares: (x−3)(x+3).
Flashcard 16: Which statement is true if f(x)=(x−2)(x+3) and x=2 is a zero?
Answer: The graph includes the x-intercept (2,0). Zeros correspond to x-intercepts on the graph.
Flashcard 17: Identify the zeros of f(x)=x3−4x2 by factoring.
Answer: x=0 (mult. 2) and x=4. Factor out x2: x2(x−4)=0.
Flashcard 18: Identify the zeros of f(x)=−(x)(x+4)3.
Answer: x=0 and x=−4 (mult. 3 at −4). Each distinct zero creates an x-intercept point.
Flashcard 19: What is the end behavior if degree is even and leading coefficient is negative?
Answer: As x→±∞, f(x)→−∞. Even degree with negative lead: both ends go down.
Flashcard 20: Identify whether f(x)=−(x+2)2(x−3) crosses or touches at x=3.
Answer: Crosses the x-axis at x=3. Odd multiplicity 1 means crossing behavior.
Flashcard 21: Identify the zeros of f(x)=(x2−1)(x2−9).
Answer: x=±1 and x=±3. Set each factor equal to zero and solve.
Flashcard 22: Identify the x-intercepts of f(x)=(x−1)(x−1)(x+2).
Answer: (1,0) and (−2,0). X-intercepts occur at distinct zero values.
Flashcard 23: Identify the zero and multiplicity for f(x)=(x−1)3(x+2) at x=1.
Answer: Zero x=1 with multiplicity 3. The factor (x−1)3 gives zero x=1 with multiplicity 3.
Flashcard 24: Identify the zeros of f(x)=(3x+6)(x−2).
Answer: x=−2 and x=2. Factor out the common factor: 3(x+2)(x−2)=0.
Flashcard 25: What is the y-intercept of y=f(x) written using f(0)?
Answer: The y-intercept is (0,f(0)). Found by substituting x=0 into the function.
Flashcard 26: What is the multiplicity of a zero r if (x−r)k is a factor of f(x)?
Answer: Multiplicity is k. The power of the factor (x−r) in the factorization.
Flashcard 27: What is the end behavior if degree is even and leading coefficient is positive?
Answer: As x→±∞, f(x)→∞. Even degree with positive lead: both ends go up.
Flashcard 28: Identify the zeros of f(x)=(x2−1)(x2−9).
Answer: x=±1 and x=±3. Set each factor equal to zero and solve.
Flashcard 29: Which end behavior matches f(x)=−3(x−1)(x+2)(x−5)?
Answer: As x→−∞, f(x)→∞; as x→∞, f(x)→−∞. Degree 3 (odd) with negative leading coefficient.
Flashcard 30: Identify whether f(x)=−(x+2)2(x−3) crosses or touches at x=3.
Answer: Crosses the x-axis at x=3. Odd multiplicity 1 means crossing behavior.
Flashcard 31: Identify the zeros of f(x)=x2−6x+9 by factoring.
Answer: x=3 (multiplicity 2). Perfect square trinomial: (x−3)2=0.
Flashcard 32: What is the rough graph behavior at a zero with multiplicity 4?
Answer: The graph touches and turns (does not cross). Even multiplicities create touching/turning behavior.
Flashcard 33: What is the end behavior if degree is odd and leading coefficient is negative?
Answer: As x→−∞, f(x)→∞; as x→∞, f(x)→−∞. Odd degree with negative lead: left up, right down.
Flashcard 34: Identify the zeros of f(x)=x2+7x+12 by factoring.
Answer: x=−3 and x=−4. Factor the quadratic: (x+3)(x+4)=0.
Flashcard 35: What is the leading coefficient of f(x)=−2(x−4)(x+1)2?
Answer: Leading coefficient −2. Coefficient of the highest degree term when expanded.
Flashcard 36: Identify the zeros of f(x)=x3+x2−12x given f(x)=x(x+4)(x−3).
Answer: x=0, x=−4, and x=3. Use the given factorization to identify zeros.
Flashcard 37: Identify the zeros of f(x)=x2(x−1)(x+1).
Answer: x=0 (mult. 2), x=1, and x=−1. Set each factor equal to zero and solve.
Flashcard 38: Identify the zeros of f(x)=x2−2x−15 by factoring.
Answer: x=5 and x=−3. Factor the quadratic: (x−5)(x+3)=0.
Flashcard 39: Identify the zeros of f(x)=(x−3)(x+5).
Answer: x=3 and x=−5. Set each factor equal to zero and solve.
Flashcard 40: What is the end behavior if degree is odd and leading coefficient is positive?
Answer: As x→−∞, f(x)→−∞; as x→∞, f(x)→∞. Odd degree with positive lead: left down, right up.
Flashcard 41: Identify the zeros of f(x)=x2−9 by factoring.
Answer: x=3 and x=−3. Factor as difference of squares: (x−3)(x+3).
Flashcard 42: Identify the zero and multiplicity for f(x)=(x+4)2(x−6) at x=−4.
Answer: Zero x=−4 with multiplicity 2. The factor (x+4)2 gives zero x=−4 with multiplicity 2.
Flashcard 43: Identify the zeros of f(x)=x3−4x2 by factoring.
Answer: x=0 (mult. 2) and x=4. Factor out x2: x2(x−4)=0.
Flashcard 44: Identify whether f(x)=(x+1)2(x−3) crosses or touches at x=−1.
Answer: Touches and turns at x=−1. Even multiplicity 2 means the graph touches and turns.
Flashcard 45: What is the end behavior of f(x)=−x4+5x2?
Answer: As x→±∞, f(x)→−∞. Even degree 4 with negative leading coefficient.
Flashcard 46: What does it mean if (x−r) is a factor of f(x)?
Answer: r is a zero of f(x). Factor Theorem: (x−r) is a factor iff r is a zero.
Flashcard 47: What is the y-intercept of f(x)=(x−2)(x+5)?
Answer: (0,−10). Substitute x=0: f(0)=(0−2)(0+5)=−10.
Flashcard 48: What is the rough graph behavior at a zero with multiplicity 1?
Answer: The graph crosses the x-axis. Odd multiplicities create crossing behavior.
Flashcard 49: Identify the zeros of f(x)=x(x−7)(x+2).
Answer: x=0, x=7, and x=−2. Set each factor equal to zero and solve.
Flashcard 50: What is the x-intercept of the graph of y=f(x) in terms of zeros?
Answer: Any point (r,0) where r is a zero of f(x). Zeros create x-intercepts where the graph crosses the x-axis.
Flashcard 51: Identify the zeros of f(x)=(x−3)(x+5).
Answer: x=3 and x=−5. Set each factor equal to zero and solve.
Flashcard 52: What is the leading coefficient of f(x)=−2(x−4)(x+1)2?
Answer: Leading coefficient −2. Coefficient of the highest degree term when expanded.
Flashcard 53: What is the multiplicity of the zero x=0 for f(x)=x2(x−1)(x+1)?
Answer: Multiplicity 2. The factor x2 gives multiplicity 2 at zero.
Flashcard 54: Identify the zeros of f(x)=(2x−1)(x+4).
Answer: x=21 and x=−4. Set each factor equal to zero: 2x−1=0 and x+4=0.
Flashcard 55: What is the Factor Theorem stated using f(r) and (x−r)?
Answer: (x−r) is a factor of f(x) iff f(r)=0. The fundamental connection between factors and zeros.
Flashcard 56: What is the degree of f(x)=(x−1)2(x+3)?
Answer: Degree 3. Count the highest power when expanded.
Flashcard 57: Identify the zeros of f(x)=x2+5x by factoring.
Answer: x=0 and x=−5. Factor out common x: x(x+5)=0.
Flashcard 58: What are the x-intercepts of f(x)=(x−4)(x+1)(x+1)?
Answer: (4,0) and (−1,0). X-intercepts occur where each distinct zero equals zero.
Flashcard 59: What is the end behavior of f(x)=x5−2x?
Answer: As x→−∞, f(x)→−∞; as x→∞, f(x)→∞. Odd degree 5 with positive leading coefficient.
Flashcard 60: Identify the zeros of f(x)=x4−16 by factoring completely over reals.
Answer: x=2 and x=−2. Factor as difference of squares twice: (x2−4)(x2+4)=(x−2)(x+2)(x2+4).
Flashcard 61: Identify the zero and multiplicity for f(x)=(x−1)3(x+2) at x=1.
Answer: Zero x=1 with multiplicity 3. The factor (x−1)3 gives zero x=1 with multiplicity 3.
Flashcard 62: What is the y-intercept of f(x)=(x+4)3?
Answer: (0,64). Substitute x=0: f(0)=(0+4)3=64.
Flashcard 63: Which end behavior matches f(x)=−3(x−1)(x+2)(x−5)?
Answer: As x→−∞, f(x)→∞; as x→∞, f(x)→−∞. Degree 3 (odd) with negative leading coefficient.
Flashcard 64: What determines end behavior for a polynomial f(x)?
Answer: The leading term (degree and leading coefficient). The highest degree term controls behavior as x→±∞.
Flashcard 65: Identify the zeros of f(x)=x2−2x−15 by factoring.
Answer: x=5 and x=−3. Factor the quadratic: (x−5)(x+3)=0.
Flashcard 66: Identify whether f(x)=(x+1)2(x−3) crosses or touches at x=−1.
Answer: Touches and turns at x=−1. Even multiplicity 2 means the graph touches and turns.
Flashcard 67: What is the multiplicity of the zero x=0 for f(x)=x2(x−1)(x+1)?
Answer: Multiplicity 2. The factor x2 gives multiplicity 2 at zero.
Flashcard 68: Identify the zeros of f(x)=x2+5x by factoring.
Answer: x=0 and x=−5. Factor out common x: x(x+5)=0.
Flashcard 69: What does it mean if (x−r) is a factor of f(x)?
Answer: r is a zero of f(x). Factor Theorem: (x−r) is a factor iff r is a zero.
Flashcard 70: What is the rough graph behavior at a zero with multiplicity 4?
Answer: The graph touches and turns (does not cross). Even multiplicities create touching/turning behavior.
Flashcard 71: Identify the zero and multiplicity for f(x)=(x+4)2(x−6) at x=−4.
Answer: Zero x=−4 with multiplicity 2. The factor (x+4)2 gives zero x=−4 with multiplicity 2.
Flashcard 72: What is a zero of a polynomial function f(x)?
Answer: A value r such that f(r)=0. When the function equals zero at that input value.
Flashcard 73: Which statement is true if f(x)=(x−2)(x+3) and x=2 is a zero?
Answer: The graph includes the x-intercept (2,0). Zeros correspond to x-intercepts on the graph.
Flashcard 74: Identify the zeros of f(x)=(x−5)2 and state the multiplicity.
Answer: x=5 with multiplicity 2. Only one distinct zero from the squared factor.
Flashcard 75: Identify whether f(x)=−(x+2)2(x−3) crosses or touches at x=−2.
Answer: Touches and turns at x=−2. Even multiplicity 2 means touch and turn behavior.
Flashcard 76: What is the maximum number of turning points a degree n polynomial can have?
Answer: At most n−1 turning points. Local maxima and minima occur between zeros.
Flashcard 77: What is the end behavior of f(x)=−x4+5x2?
Answer: As x→±∞, f(x)→−∞. Even degree 4 with negative leading coefficient.
Flashcard 78: Identify the zeros of f(x)=x(x−7)(x+2).
Answer: x=0, x=7, and x=−2. Set each factor equal to zero and solve.
Flashcard 79: Identify the zeros of f(x)=x3+x2−12x given f(x)=x(x+4)(x−3).
Answer: x=0, x=−4, and x=3. Use the given factorization to identify zeros.
Flashcard 80: What is the y-intercept of f(x)=−(x−1)2(x+3)?
Answer: (0,−3). Substitute x=0: f(0)=−(0−1)2(0+3)=−3.
Flashcard 81: What is the degree of f(x)=(x−1)2(x+3)?
Answer: Degree 3. Count the highest power when expanded.
Flashcard 82: What is the y-intercept of f(x)=(x+4)3?
Answer: (0,64). Substitute x=0: f(0)=(0+4)3=64.
Flashcard 83: What is the x-intercept of the graph of y=f(x) in terms of zeros?
Answer: Any point (r,0) where r is a zero of f(x). Zeros create x-intercepts where the graph crosses the x-axis.
Flashcard 84: Identify the x-intercepts of f(x)=−(x+2)2(x−3).
Answer: (−2,0) and (3,0). X-intercepts occur where each distinct zero is located.
Flashcard 85: Identify the zeros of f(x)=x3−9x by factoring.
Answer: x=0, x=3, and x=−3. Factor out x: x(x2−9)=x(x−3)(x+3)=0.
Flashcard 86: What is the end behavior of f(x)=x5−2x?
Answer: As x→−∞, f(x)→−∞; as x→∞, f(x)→∞. Odd degree 5 with positive leading coefficient.
Flashcard 87: Identify the zeros of f(x)=−(x)(x+4)3.
Answer: x=0 and x=−4 (mult. 3 at −4). Each distinct zero creates an x-intercept point.
Flashcard 88: Identify the zeros of f(x)=x2(x−1)(x+1).
Answer: x=0 (mult. 2), x=1, and x=−1. Set each factor equal to zero and solve.
Flashcard 89: What is the y-intercept of f(x)=(x−2)(x+5)?
Answer: (0,−10). Substitute x=0: f(0)=(0−2)(0+5)=−10.
Flashcard 90: Identify the x-intercepts of f(x)=(x−1)(x−1)(x+2).
Answer: (1,0) and (−2,0). X-intercepts occur at distinct zero values.
Flashcard 91: What is the maximum number of real zeros a degree n polynomial can have?
Answer: At most n real zeros. Fundamental Theorem of Algebra applied to real zeros.
Flashcard 92: What is the end behavior if degree is even and leading coefficient is positive?
Answer: As x→±∞, f(x)→∞. Even degree with positive lead: both ends go up.
Flashcard 93: What is the rough graph behavior at a zero with multiplicity 1?
Answer: The graph crosses the x-axis. Odd multiplicities create crossing behavior.
Flashcard 94: What are the x-intercepts of f(x)=(x−4)(x+1)(x+1)?
Answer: (4,0) and (−1,0). X-intercepts occur where each distinct zero equals zero.
Flashcard 95: Identify the zeros of f(x)=2x2−8x by factoring.
Answer: x=0 and x=4. Factor out 2x: 2x(x−4)=0.
Flashcard 96: Identify the zeros of f(x)=x2+7x+12 by factoring.
Answer: x=−3 and x=−4. Factor the quadratic: (x+3)(x+4)=0.
Flashcard 97: Which end behavior matches f(x)=2(x+1)2(x−4)2?
Answer: As x→±∞, f(x)→∞. Degree 4 (even) with positive leading coefficient.
Flashcard 98: Which end behavior matches f(x)=2(x+1)2(x−4)2?
Answer: As x→±∞, f(x)→∞. Degree 4 (even) with positive leading coefficient.
Flashcard 99: Identify the zeros of f(x)=x3+2x2−x−2 given f(x)=(x+2)(x+1)(x−1).
Answer: x=−2, x=−1, and x=1. Use the given factorization to find zeros.
Flashcard 100: What is the end behavior if degree is even and leading coefficient is negative?
Answer: As x→±∞, f(x)→−∞. Even degree with negative lead: both ends go down.