What this deck covers
This deck focuses on Graphing Linear Inequalities And Systems, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra.
Study Graphing Linear Inequalities And Systems in Algebra with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Does the point (2,1) satisfy y≥x?
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No, because 1≥2 is false. Substitute (2,1): 1≥2 is false.
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This deck focuses on Graphing Linear Inequalities And Systems, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: No, because 1≥2 is false. Substitute (2,1): 1≥2 is false.
Answer: Shade below y=0. y<0 means negative y-values only.
Answer: No, because 2>4 is false. Check: 2>4 is false, so point fails system.
Answer: There are infinitely many solutions extending without end. The solution region extends infinitely in some direction.
Answer: Above the line y=−x+4. y>−x+4 means above the boundary line.
Answer: Dashed boundary line. Strict inequality (<) excludes the boundary.
Answer: No, because 3≤2 is false. Substitute (3,−1): 3≤2 is false.
Answer: The line 2x−5y=10. Set the inequality to equality form.
Answer: Shade to the left of x=−1 (including the line). x≤−1 includes points with x-values ≤−1.
Answer: The horizontal line y=−2. Horizontal line where all points have y=−2.
Answer: To the right of x=2 (including the line). x≥2 includes points with x-values ≥2.
Answer: Shade below the line (including the line). y≤mx+b includes points on and below the line.
Answer: The boundary line y=mx+b. The boundary line from the inequality's equation form.
Answer: Points on the line are not included in the solution set. The boundary doesn't satisfy the strict inequality.
Answer: Solid line (boundary included). Non-strict inequalities include the boundary points.
Answer: Solid boundary line. Non-strict inequality (≥) includes the boundary.
Answer: Do not use (0,0); choose a different point. (0,0) on the boundary would give 0=0, not helpful.
Answer: Test a point (often (0,0)) in the inequality. If the test point satisfies the inequality, shade that side.
Answer: Shade the side that contains (0,0). Test (0,0): 0+0≤4 is true, so shade that side.
Answer: All points on the line y=0. Both inequalities are satisfied only on y=0.
Answer: A half-plane (all points that satisfy the inequality). It includes all points making the inequality true.
Answer: All points with x≤−1. The more restrictive condition x≤−1 determines the solution.
Answer: Shade above the line (including the line). y≥mx+b includes points on and above the line.
Answer: Shade below the line. y<mx+b means y-values less than the line.
Answer: Points on the line are included in the solution set. The boundary satisfies the inequality condition.
Answer: Yes, because −2>−3 is true. Substitute (−2,5): −2>−3 is true.
Answer: Dashed line (boundary not included). Strict inequalities exclude the boundary points.
Answer: Yes, because 5≥1 and 5<6. Check: 5≥1 and 5<6 are both true.
Answer: Dashed line. Strict inequality (>) excludes the boundary.
Answer: Yes, because 3<4 is true. Substitute (−1,3): 3<2(−1)+6=4 is true.
Answer: Yes, because 2≥1 and 2≤3. Check: 2≥1 and 2≤3 are both true.
Answer: The vertical line x=3. Vertical line where all points have x=3.
Answer: y≥−2x+1. Solid line with above shading indicates ≥.
Answer: The line y=−3x+2. Set the inequality to equality form.
Answer: Shade to the right of x=4. x>4 means x-values greater than 4.
Answer: Use (0,0) as the test point. Origin is convenient when not on the boundary line.
Answer: Strict symbols: < or >. Strict symbols create open boundaries (dashed lines).
Answer: Shade the side that does not contain (0,0). Test (0,0): 0+0≥6 is false, so shade opposite.
Answer: Below y=−4. y<−4 means y-values less than −4.
Answer: The intersection of the half-planes for all inequalities. Only points satisfying all inequalities simultaneously.
Answer: Inclusive symbols: ≤ or ≥. Inclusive symbols create closed boundaries (solid lines).
Answer: Points that satisfy both inequalities at the same time. Intersection means 'and' - both conditions must hold.
Answer: y<3x−4. Dashed line with below shading indicates <.
Answer: Graph the boundary line 2x+3y=6. Draw the boundary by setting the inequality to equality.
Answer: No solution (empty intersection). No x-value can be both >1 and <1.
Answer: Solid line. Non-strict inequality (≤) includes the boundary.
Answer: Shade above the line. y>mx+b means y-values greater than the line.
Answer: Below y=−4. y<−4 means y-values less than −4.
Answer: Below the line y=21x−3 (including it). y≤21x−3 includes on and below the line.
Answer: All points with y≥3. The more restrictive condition y≥3 determines the solution.
Answer: Not a linear inequality; y=2x+1 is not half-plane form. = creates two regions, not a single half-plane.
Answer: It satisfies every inequality in the system. The point makes all system inequalities true.
Answer: The system has no solution (empty intersection). No points satisfy all inequalities simultaneously.
Answer: No, because 0≤−2 is false. Substitute (0,0): 0≤0−2=−2 is false.
Answer: Yes, because 0>−1 is true. Substitute (0,0): 0>2(0)−1=−1 is true.
Answer: Shade above y=5 (including the line). y≥5 includes points with y-values ≥5.
Answer: No, because 6<6 is false. Check: 6<6 is false, so point fails system.