Algebra Flashcards: Function Notation And Evaluation

Study Function Notation And Evaluation in Algebra with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Algebra

Function Notation And Evaluation

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QUESTION
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What does it mean if an input xx is not in the domain of ff?

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ANSWER

f(x)f(x) is undefined for that input. The function cannot be evaluated at that input.

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What this deck covers

This deck focuses on Function Notation And Evaluation, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: What does it mean if an input xx is not in the domain of ff?

Answer: f(x)f(x) is undefined for that input. The function cannot be evaluated at that input.

Flashcard 2: Identify whether f(2)f(2) is defined if f(x)=1x2f(x)=\frac{1}{x-2}.

Answer: f(2)f(2) is undefined. Division by zero occurs when x=2x=2.

Flashcard 3: What is the domain of f(x)=1x+3f(x)=\frac{1}{x+3} in set notation?

Answer: All real xx such that x3x\neq -3. Denominator cannot equal zero, so exclude x=3x=-3.

Flashcard 4: What is the domain of a function in words?

Answer: The set of all allowable input values. Only these values can be substituted into the function.

Flashcard 5: What is the domain of f(x)=x5f(x)=\sqrt{x-5} in inequality form?

Answer: x5x\ge 5. Square root requires non-negative radicand.

Flashcard 6: Find the domain of f(x)=2xf(x)=\frac{2}{x} in restriction form.

Answer: All real xx such that x0x\neq 0. Denominator cannot equal zero.

Flashcard 7: Interpret P(5)=1200P(5)=1200 if P(t)P(t) is population after tt years.

Answer: After 55 years, the population is 12001200. Function output shows population at given time.

Flashcard 8: Find p(x1)p(x-1) if p(x)=x2p(x)=x^2.

Answer: p(x1)=(x1)2p(x-1)=(x-1)^2. Replace xx with (x1)(x-1): p(x1)=(x1)2p(x-1)=(x-1)^2.

Flashcard 9: Find f(2)f(-2) if f(x)=x+6f(x)=-x+6.

Answer: f(2)=8f(-2)=8. Substitute x=2x=-2: f(2)=(2)+6=8f(-2)=-(-2)+6=8.

Flashcard 10: What does the statement f(x)=0f(x)=0 ask you to find?

Answer: All inputs xx that make the output equal to 00. Find the zeros or roots of the function.

Flashcard 11: What is the difference between f(x)f(x) and fxf\,x in algebra?

Answer: f(x)f(x) is a function value; fxf\,x is multiplication. Parentheses indicate function evaluation, not multiplication.

Flashcard 12: Find q(2)q(-2) if q(x)=x2+4x+1q(x)=x^2+4x+1.

Answer: q(2)=3q(-2)=-3. Substitute x=2x=-2: q(2)=(2)2+4(2)+1=3q(-2)=(-2)^2+4(-2)+1=-3.

Flashcard 13: Find s(3)s(3) if s(x)=x+12s(x)=\frac{x+1}{2}.

Answer: s(3)=2s(3)=2. Substitute x=3x=3: s(3)=3+12=2s(3)=\frac{3+1}{2}=2.

Flashcard 14: Find g(x+2)g(x+2) if g(x)=3x1g(x)=3x-1.

Answer: g(x+2)=3x+5g(x+2)=3x+5. Replace xx with (x+2)(x+2): g(x+2)=3(x+2)1=3x+5g(x+2)=3(x+2)-1=3x+5.

Flashcard 15: What does the statement f(x)<0f(x)<0 describe?

Answer: Inputs xx where the function output is negative. The function is below the xx-axis at these inputs.

Flashcard 16: Find f(3)f(-3) if f(x)=x21f(x)=x^2-1.

Answer: f(3)=8f(-3)=8. Substitute x=3x=-3: f(3)=(3)21=8f(-3)=(-3)^2-1=8.

Flashcard 17: Find p(1)p(1) if p(x)=3x2+2xp(x)=3x^2+2x.

Answer: p(1)=5p(1)=5. Substitute x=1x=1: p(1)=3(1)2+2(1)=5p(1)=3(1)^2+2(1)=5.

Flashcard 18: Find r(5)r(5) if r(x)=102xr(x)=10-2x.

Answer: r(5)=0r(5)=0. Substitute x=5x=5: r(5)=102(5)=0r(5)=10-2(5)=0.

Flashcard 19: What does the statement f(x)>0f(x)>0 describe?

Answer: Inputs xx where the function output is positive. The function is above the xx-axis at these inputs.

Flashcard 20: Find h(4)h(4) if h(x)=2(x1)h(x)=2(x-1).

Answer: h(4)=6h(4)=6. Substitute x=4x=4: h(4)=2(41)=6h(4)=2(4-1)=6.

Flashcard 21: Interpret C(10)=25C(10)=25 if C(d)C(d) is the cost in dollars for dd miles.

Answer: A 1010-mile trip costs 2525 dollars. Function notation describes real-world relationships.

Flashcard 22: What does f(x)f(a)f(x)-f(a) represent?

Answer: The difference between outputs at inputs xx and aa. Shows the change in function values between inputs.

Flashcard 23: What is the difference between f(x)f(x) and fxf\cdot x?

Answer: f(x)f(x) is a function value; fxf\cdot x is multiplication. Parentheses indicate function evaluation, not multiplication.

Flashcard 24: Find g(x+2)g(x+2) if g(x)=3x1g(x)=3x-1.

Answer: g(x+2)=3x+5g(x+2)=3x+5. Replace xx with (x+2)(x+2): g(x+2)=3(x+2)1=3x+5g(x+2)=3(x+2)-1=3x+5.

Flashcard 25: What is the range of a function in words?

Answer: The set of all possible output values. All values the function can produce as outputs.

Flashcard 26: Find t(1)t(-1) if t(x)=x+2t(x)=\lvert x\rvert+2.

Answer: t(1)=3t(-1)=3. Substitute x=1x=-1: t(1)=1+2=3t(-1)=\lvert-1\rvert+2=3.

Flashcard 27: Find f(2)f(2) if the table gives f(2)=9f(2)=9.

Answer: f(2)=9f(2)=9. Read function value directly from table.

Flashcard 28: Find the domain of f(x)=x+4f(x)=\sqrt{x+4} in inequality form.

Answer: x4x\ge -4. Square root requires x+40x+4\ge 0.

Flashcard 29: Find h(2x)h(2x) if h(x)=x24h(x)=x^2-4.

Answer: h(2x)=4x24h(2x)=4x^2-4. Replace xx with 2x2x: h(2x)=(2x)24=4x24h(2x)=(2x)^2-4=4x^2-4.

Flashcard 30: Find q(1)q(1) if q(x)=4x+1q(x)=\frac{4}{x+1}.

Answer: q(1)=2q(1)=2. Substitute x=1x=1: q(1)=41+1=2q(1)=\frac{4}{1+1}=2.

Flashcard 31: Find g(2)g(2) if g(x)=12x4g(x)=\frac{1}{2}x-4.

Answer: g(2)=3g(2)=-3. Substitute x=2x=2: g(2)=12(2)4=3g(2)=\frac{1}{2}(2)-4=-3.

Flashcard 32: What is the domain of f(x)=1x+3f(x)=\frac{1}{x+3} in set notation?

Answer: All real xx such that x3x\neq -3. Denominator cannot equal zero, so exclude x=3x=-3.

Flashcard 33: What is the meaning of the statement f(3)=7f(3)=7?

Answer: When x=3x=3, the function output is 77. Substitute x=3x=3 into the function to get output 77.

Flashcard 34: What does f(0)f(0) represent on the graph of y=f(x)y=f(x)?

Answer: The yy-intercept value. When x=0x=0, output gives yy-intercept.

Flashcard 35: Identify whether f(1)f(-1) is defined if f(x)=x+1f(x)=\sqrt{x+1}.

Answer: f(1)f(-1) is defined and equals 00. Square root of 00 is defined: f(1)=0=0f(-1)=\sqrt{0}=0.

Flashcard 36: Identify the input and output in the ordered pair (x,f(x))(x,f(x)).

Answer: Input is xx; output is f(x)f(x). First coordinate is input, second is output.

Flashcard 37: Find u(4)u(-4) if u(x)=x+1u(x)=\lvert x+1\rvert.

Answer: u(4)=3u(-4)=3. Substitute x=4x=-4: u(4)=4+1=3u(-4)=\lvert-4+1\rvert=3.

Flashcard 38: What is the domain of f(x)=2xf(x)=\sqrt{2-x} in inequality form?

Answer: x2x\le 2. Square root requires non-negative radicand.

Flashcard 39: Find h(0)h(0) if h(x)=53xh(x)=5-3x.

Answer: h(0)=5h(0)=5. Substitute x=0x=0: h(0)=53(0)=5h(0)=5-3(0)=5.

Flashcard 40: What is the domain of f(x)=5x29f(x)=\frac{5}{x^2-9} in restriction form?

Answer: All real xx such that x3x\neq 3 and x3x\neq -3. Factor: x29=(x3)(x+3)x^2-9=(x-3)(x+3), exclude both zeros.

Flashcard 41: What point corresponds to f(a)=bf(a)=b on the graph of y=f(x)y=f(x)?

Answer: The point (a,b)(a,b). Function notation corresponds to coordinate pairs.

Flashcard 42: What is the meaning of the statement f(a)=bf(a)=b?

Answer: When x=ax=a, the function output is bb. General form showing input aa produces output bb.

Flashcard 43: Find f(4)f(4) if f(x)=2x+5f(x)=2x+5.

Answer: f(4)=13f(4)=13. Substitute x=4x=4: f(4)=2(4)+5=13f(4)=2(4)+5=13.

Flashcard 44: Find the domain of f(x)=xf(x)=\sqrt{x} in inequality form.

Answer: x0x\ge 0. Square root requires non-negative radicand.

Flashcard 45: Find p(0)p(0) if p(x)=x32xp(x)=x^3-2x.

Answer: p(0)=0p(0)=0. Substitute x=0x=0: p(0)=032(0)=0p(0)=0^3-2(0)=0.

Flashcard 46: Find p(x1)p(x-1) if p(x)=x2p(x)=x^2.

Answer: p(x1)=(x1)2p(x-1)=(x-1)^2. Replace xx with (x1)(x-1): p(x1)=(x1)2p(x-1)=(x-1)^2.

Flashcard 47: Find g(6)g(6) if g(x)=x3+1g(x)=\frac{x}{3}+1.

Answer: g(6)=3g(6)=3. Substitute x=6x=6: g(6)=63+1=3g(6)=\frac{6}{3}+1=3.

Flashcard 48: Find the domain of f(x)=x+1x7f(x)=\frac{x+1}{x-7} in restriction form.

Answer: All real xx such that x7x\neq 7. Denominator cannot equal zero.

Flashcard 49: What does f(x+h)f(x+h) mean in function notation?

Answer: The output when the input is x+hx+h. Substitute the entire expression (x+h)(x+h) for xx.

Flashcard 50: Interpret T(3)=68T(3)=68 if T(h)T(h) is temperature after hh hours.

Answer: After 33 hours, the temperature is 6868 degrees. Function value represents temperature at specific time.

Flashcard 51: Find p(0)p(0) if p(x)=x32xp(x)=x^3-2x.

Answer: p(0)=0p(0)=0. Substitute x=0x=0: p(0)=032(0)=0p(0)=0^3-2(0)=0.

Flashcard 52: Find t(1)t(-1) if t(x)=x+2t(x)=\lvert x\rvert+2.

Answer: t(1)=3t(-1)=3. Substitute x=1x=-1: t(1)=1+2=3t(-1)=\lvert-1\rvert+2=3.

Flashcard 53: Find the domain of f(x)=1(x1)(x+2)f(x)=\frac{1}{(x-1)(x+2)} in restriction form.

Answer: All real xx such that x1x\neq 1 and x2x\neq -2. Both factors in denominator cannot equal zero.

Flashcard 54: Find f(a)f(a) if f(x)=x2+3f(x)=x^2+3.

Answer: f(a)=a2+3f(a)=a^2+3. Replace xx with aa in the function expression.

Flashcard 55: What is the standard notation for the output variable of f(x)f(x)?

Answer: y=f(x)y=f(x). Standard way to represent function output.

Flashcard 56: Interpret d(2.5)=150d(2.5)=150 if d(t)d(t) is distance in miles after tt hours.

Answer: After 2.52.5 hours, the distance traveled is 150150 miles. Function describes distance as function of time.

Flashcard 57: What does the notation f(x)f(x) represent in function notation?

Answer: f(x)f(x) is the output value of function ff for input xx. Function notation shows the input-output relationship.

Flashcard 58: Find f(a)f(a) if f(x)=x2+3f(x)=x^2+3.

Answer: f(a)=a2+3f(a)=a^2+3. Replace xx with aa in the function expression.

Flashcard 59: Identify xx if f(x)=12f(x)=12 and the table shows f(4)=12f(4)=12.

Answer: x=4x=4. Find input that produces given output.

Flashcard 60: Find m(3)m(3) if m(x)=x+1m(x)=\sqrt{x+1}.

Answer: m(3)=2m(3)=2. Substitute x=3x=3: m(3)=3+1=2m(3)=\sqrt{3+1}=2.