Study Creating Solving One Variable Equations Inequalities in Algebra with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: What is the definition of a solution to an inequality in one variable? Answer: A value that makes the inequality true. Substituting solution satisfies the inequality condition.
Flashcard 2: What is the rule for solving a x = b ax=b a x = b when a ≠ 0 a\neq 0 a = 0 ? Answer: x = b a x=\frac{b}{a} x = a b . Divide both sides by coefficient a a a to isolate x x x .
Flashcard 3: Solve by factoring: x 2 − 4 x − 12 = 0 x^2-4x-12=0 x 2 − 4 x − 12 = 0 . Answer: x = 6 x=6 x = 6 or x = − 2 x=-2 x = − 2 . Factor as ( x − 6 ) ( x + 2 ) = 0 (x-6)(x+2)=0 ( x − 6 ) ( x + 2 ) = 0 using zero-product property.
Flashcard 4: Identify the equation for "a number x x x decreased by 6 6 6 is the same as 2 x 2x 2 x ." Answer: x − 6 = 2 x x-6=2x x − 6 = 2 x . "Decreased by" means subtract, "same as" means equals.
Flashcard 5: What is the definition of a solution to an inequality in one variable? Answer: A value that makes the inequality true. Substituting solution satisfies the inequality condition.
Flashcard 6: Find the solution set of ∣ 2 x + 1 ∣ ≤ 5 |2x+1|\leq 5 ∣2 x + 1∣ ≤ 5 . Answer: − 3 ≤ x ≤ 2 -3\leq x\leq 2 − 3 ≤ x ≤ 2 . Distance condition gives − 5 ≤ 2 x + 1 ≤ 5 -5\leq 2x+1\leq 5 − 5 ≤ 2 x + 1 ≤ 5 .
Flashcard 7: Identify the equation that models "x x x is 5 5 5 more than y y y " in one variable x x x in terms of y y y . Answer: x = y + 5 x=y+5 x = y + 5 . "More than" means add 5 to the second variable.
Flashcard 8: Solve using the quadratic formula: x 2 − 2 x − 3 = 0 x^2-2x-3=0 x 2 − 2 x − 3 = 0 . Answer: x = 3 x=3 x = 3 or x = − 1 x=-1 x = − 1 . Apply formula with a = 1 a=1 a = 1 , b = − 2 b=-2 b = − 2 , c = − 3 c=-3 c = − 3 .
Flashcard 9: Solve by square roots: x 2 = 49 x^2=49 x 2 = 49 . Answer: x = 7 x=7 x = 7 or x = − 7 x=-7 x = − 7 . Take square root of both sides: x = ± 7 x=\pm 7 x = ± 7 .
Flashcard 10: What is the zero-product property for solving equations like ( x − 2 ) ( x + 5 ) = 0 (x-2)(x+5)=0 ( x − 2 ) ( x + 5 ) = 0 ? Answer: If a b = 0 ab=0 ab = 0 , then a = 0 a=0 a = 0 or b = 0 b=0 b = 0 . If product equals zero, at least one factor must be zero.
Flashcard 11: What is the form of a simple rational function in one variable x x x with a constant numerator? Answer: y = a x y=\frac{a}{x} y = x a . Inverse relationship with constant numerator and variable denominator.
Flashcard 12: Solve by square roots: ( x − 1 ) 2 = 16 (x-1)^2=16 ( x − 1 ) 2 = 16 . Answer: x = 5 x=5 x = 5 or x = − 3 x=-3 x = − 3 . Take square root: x − 1 = ± 4 x-1=\pm 4 x − 1 = ± 4 .
Flashcard 13: Find x x x if x 4 + 2 = 9 \frac{x}{4}+2=9 4 x + 2 = 9 . Answer: x = 28 x=28 x = 28 . Subtract 2, then multiply by 4: x 4 = 7 \frac{x}{4}=7 4 x = 7 , so x = 28 x=28 x = 28 .
Flashcard 14: What is the standard form of a quadratic equation in one variable x x x ? Answer: a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 . Standard quadratic with coefficients a a a , b b b , c c c where a ≠ 0 a\neq 0 a = 0 .
Flashcard 15: Create an equation for "a rectangle has perimeter 30 30 30 with length x x x and width 5 5 5 ." Answer: 2 x + 10 = 30 2x+10=30 2 x + 10 = 30 . Perimeter formula: P = 2 l + 2 w = 2 x + 2 ( 5 ) P=2l+2w=2x+2(5) P = 2 l + 2 w = 2 x + 2 ( 5 ) .
Flashcard 16: Find the solution set of ∣ x − 3 ∣ = 5 |x-3|=5 ∣ x − 3∣ = 5 . Answer: x = 8 x=8 x = 8 or x = − 2 x=-2 x = − 2 . Distance from 3 is 5, so x − 3 = 5 x-3=5 x − 3 = 5 or x − 3 = − 5 x-3=-5 x − 3 = − 5 .
Flashcard 17: Create an inequality for "twice a number x x x is at least 15 15 15 ." Answer: 2 x ≥ 15 2x\geq 15 2 x ≥ 15 . "Twice" means multiply by 2, "at least" means ≥ \geq ≥ .
Flashcard 18: Identify the excluded value for 5 x + 3 \frac{5}{x+3} x + 3 5 . Answer: x ≠ − 3 x\neq -3 x = − 3 . Denominator cannot equal zero, so x + 3 ≠ 0 x+3\neq 0 x + 3 = 0 .
Flashcard 19: Create an equation for "7 7 7 less than a number n n n is 20 20 20 ." Answer: n − 7 = 20 n-7=20 n − 7 = 20 . "Less than" means subtract 7 from the number.
Flashcard 20: Solve the rational equation x x − 1 = 2 \frac{x}{x-1}=2 x − 1 x = 2 with x ≠ 1 x\neq 1 x = 1 . Answer: x = 2 x=2 x = 2 . Cross-multiply: x = 2 ( x − 1 ) x=2(x-1) x = 2 ( x − 1 ) , so x = 2 x − 2 x=2x-2 x = 2 x − 2 .
Flashcard 21: What is the definition of a solution to an equation in one variable? Answer: A value that makes the equation true. Substituting solution makes left side equal right side.
Flashcard 22: What inequality symbol represents "at most"? Answer: ≤ \leq ≤ . "At most" means less than or equal to.
Flashcard 23: Create an inequality for "a number x x x is at most 12 12 12 ." Answer: x ≤ 12 x\leq 12 x ≤ 12 . "At most" translates to less than or equal.
Flashcard 24: Identify the property used to rewrite x + 7 = 12 x+7=12 x + 7 = 12 as x = 12 − 7 x=12-7 x = 12 − 7 . Answer: Subtraction property of equality. Subtract same value from both sides to maintain equality.
Flashcard 25: Create an equation for "7 7 7 less than a number n n n is 20 20 20 ." Answer: n − 7 = 20 n-7=20 n − 7 = 20 . "Less than" means subtract 7 from the number.
Flashcard 26: What is the slope-intercept form of a linear equation in one variable y y y versus x x x ? Answer: y = m x + b y=mx+b y = m x + b . Standard form where m m m is slope and b b b is y-intercept.
Flashcard 27: Find and correct the inequality error: from − 2 x < 6 -2x<6 − 2 x < 6 to x < − 3 x< -3 x < − 3 . Answer: Correct: x > − 3 x>-3 x > − 3 . Must reverse inequality when dividing by negative.
Flashcard 28: What is the standard form of a quadratic equation in one variable x x x ? Answer: a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 . Standard quadratic with coefficients a a a , b b b , c c c where a ≠ 0 a\neq 0 a = 0 .
Flashcard 29: Solve the inequality − 3 x > 12 -3x>12 − 3 x > 12 . Answer: x < − 4 x<-4 x < − 4 . Divide by − 3 -3 − 3 and flip inequality sign.
Flashcard 30: Solve the exponential equation 3 x = 1 9 3^{x}=\frac{1}{9} 3 x = 9 1 . Answer: x = − 2 x=-2 x = − 2 . Since 1 9 = 3 − 2 \frac{1}{9}=3^{-2} 9 1 = 3 − 2 , we need x = − 2 x=-2 x = − 2 .
Flashcard 31: Create an inequality for "a number x x x is at most 12 12 12 ." Answer: x ≤ 12 x\leq 12 x ≤ 12 . "At most" translates to less than or equal.
Flashcard 32: What is the quadratic formula for solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: x = − b ± b 2 − 4 a c 2 a x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} x = 2 a − b ± b 2 − 4 a c . Derived from completing the square on a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 .
Flashcard 33: Find and correct the equation error: from x 3 = 4 \frac{x}{3}=4 3 x = 4 to x = 4 3 x=\frac{4}{3} x = 3 4 . Answer: Correct: x = 12 x=12 x = 12 . Must multiply by 3, not divide by 3.
Flashcard 34: What inequality symbol represents "less than"? Answer: < < < . Strict inequality excludes the boundary value.
Flashcard 35: Solve the inequality x 2 − 4 ≥ 0 x^2-4\geq 0 x 2 − 4 ≥ 0 . Answer: x ≤ − 2 x\leq -2 x ≤ − 2 or x ≥ 2 x\geq 2 x ≥ 2 . Parabola opens up with zeros at x = ± 2 x=\pm 2 x = ± 2 .
Flashcard 36: What is the form of a simple rational function in one variable x x x with a constant numerator? Answer: y = a x y=\frac{a}{x} y = x a . Inverse relationship with constant numerator and variable denominator.
Flashcard 37: Solve the rational equation 6 x = 2 \frac{6}{x}=2 x 6 = 2 with x ≠ 0 x\neq 0 x = 0 . Answer: x = 3 x=3 x = 3 . Cross-multiply to get 6 = 2 x 6=2x 6 = 2 x , so x = 3 x=3 x = 3 .
Flashcard 38: Solve by square roots: x 2 = 49 x^2=49 x 2 = 49 . Answer: x = 7 x=7 x = 7 or x = − 7 x=-7 x = − 7 . Take square root of both sides: x = ± 7 x=\pm 7 x = ± 7 .
Flashcard 39: Solve the exponential equation 5 ⋅ 2 x = 40 5\cdot 2^x=40 5 ⋅ 2 x = 40 . Answer: x = 3 x=3 x = 3 . Divide by 5: 2 x = 8 = 2 3 2^x=8=2^3 2 x = 8 = 2 3 , so x = 3 x=3 x = 3 .
Flashcard 40: Find x x x if 2 x + 3 = 3 x − 5 2x+3=3x-5 2 x + 3 = 3 x − 5 . Answer: x = 8 x=8 x = 8 . Move variables to one side: − x = − 8 -x=-8 − x = − 8 , so x = 8 x=8 x = 8 .
Flashcard 41: Solve the inequality 2 x + 1 ≤ 9 2x+1\leq 9 2 x + 1 ≤ 9 . Answer: x ≤ 4 x\leq 4 x ≤ 4 . Subtract 1, then divide by 2: 2 x ≤ 8 2x\leq 8 2 x ≤ 8 .
Flashcard 42: Solve the inequality x − 2 ≥ 5 \frac{x}{-2}\geq 5 − 2 x ≥ 5 . Answer: x ≤ − 10 x\leq -10 x ≤ − 10 . Multiply by − 2 -2 − 2 and flip inequality sign.
Flashcard 43: Create a quadratic equation for "the area of a square is 49 49 49 " using side length s s s . Answer: s 2 = 49 s^2=49 s 2 = 49 . Area of square equals side length squared.
Flashcard 44: Create an equation for "the product of 4 4 4 and x x x increased by 9 9 9 is 25 25 25 ." Answer: 4 x + 9 = 25 4x+9=25 4 x + 9 = 25 . "Product increased by" means multiply then add.
Flashcard 45: Find x x x if 3 x − 5 = 16 3x-5=16 3 x − 5 = 16 . Answer: x = 7 x=7 x = 7 . Add 5, then divide by 3: 3 x = 21 3x=21 3 x = 21 , so x = 7 x=7 x = 7 .
Flashcard 46: Find the solution set of ∣ x − 3 ∣ = 5 |x-3|=5 ∣ x − 3∣ = 5 . Answer: x = 8 x=8 x = 8 or x = − 2 x=-2 x = − 2 . Distance from 3 is 5, so x − 3 = 5 x-3=5 x − 3 = 5 or x − 3 = − 5 x-3=-5 x − 3 = − 5 .
Flashcard 47: Create a rational equation for "12 12 12 divided by x x x equals 3 3 3 ," with x ≠ 0 x\neq 0 x = 0 . Answer: 12 x = 3 \frac{12}{x}=3 x 12 = 3 . Direct translation of division statement into equation.
Flashcard 48: Solve by factoring: x 2 + 5 x = 0 x^2+5x=0 x 2 + 5 x = 0 . Answer: x = 0 x=0 x = 0 or x = − 5 x=-5 x = − 5 . Factor out x x x : x ( x + 5 ) = 0 x(x+5)=0 x ( x + 5 ) = 0 .
Flashcard 49: Solve the inequality ( x − 1 ) ( x + 2 ) < 0 (x-1)(x+2)<0 ( x − 1 ) ( x + 2 ) < 0 . Answer: − 2 < x < 1 -2<x<1 − 2 < x < 1 . Product negative when factors have opposite signs.
Flashcard 50: What inequality symbol represents "at least"? Answer: ≥ \geq ≥ . "At least" means greater than or equal to.
Flashcard 51: What happens to an inequality when you multiply both sides by a negative number? Answer: Reverse the inequality sign. Multiplying by negative changes direction of inequality.
Flashcard 52: What inequality symbol represents "greater than"? Answer: > > > . Strict inequality excludes the boundary value.
Flashcard 53: What does Δ < 0 \Delta<0 Δ < 0 imply about the solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: No real solutions. Negative discriminant means parabola doesn't cross x-axis.
Flashcard 54: Solve the inequality 4 − 2 x < 10 4-2x<10 4 − 2 x < 10 . Answer: x > − 3 x>-3 x > − 3 . Subtract 4, divide by − 2 -2 − 2 , and flip inequality.
Flashcard 55: What inequality symbol represents "greater than"? Answer: > > > . Strict inequality excludes the boundary value.
Flashcard 56: Create a quadratic equation for "the area of a square is 49 49 49 " using side length s s s . Answer: s 2 = 49 s^2=49 s 2 = 49 . Area of square equals side length squared.
Flashcard 57: Identify the property used to rewrite x 5 = 3 \frac{x}{5}=3 5 x = 3 as x = 15 x=15 x = 15 . Answer: Multiplication property of equality. Multiply both sides by reciprocal to isolate variable.
Flashcard 58: Solve by factoring: x 2 − 9 = 0 x^2-9=0 x 2 − 9 = 0 . Answer: x = 3 x=3 x = 3 or x = − 3 x=-3 x = − 3 . Difference of squares: ( x − 3 ) ( x + 3 ) = 0 (x-3)(x+3)=0 ( x − 3 ) ( x + 3 ) = 0 .
Flashcard 59: Find x x x if 5 ( x − 3 ) = 20 5(x-3)=20 5 ( x − 3 ) = 20 . Answer: x = 7 x=7 x = 7 . Distribute: 5 x − 15 = 20 5x-15=20 5 x − 15 = 20 , then 5 x = 35 5x=35 5 x = 35 , so x = 7 x=7 x = 7 .
Flashcard 60: What does Δ > 0 \Delta>0 Δ > 0 imply about the solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: 2 2 2 distinct real solutions. Positive discriminant means two x-intercepts.
Flashcard 61: What does Δ = 0 \Delta=0 Δ = 0 imply about the solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: 1 1 1 real double solution. Zero discriminant means one repeated root (vertex on x-axis).
Flashcard 62: What is the vertex form of a quadratic function in one variable x x x ? Answer: y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k . Shows vertex at ( h , k ) (h,k) ( h , k ) and vertical stretch/compression a a a .
Flashcard 63: Create an exponential equation for "a population starts at 200 200 200 and triples in t t t periods." Answer: P = 200 ⋅ 3 t P=200\cdot 3^t P = 200 ⋅ 3 t . Exponential growth model with initial value and growth factor.
Flashcard 64: Find x x x if x 4 + 2 = 9 \frac{x}{4}+2=9 4 x + 2 = 9 . Answer: x = 28 x=28 x = 28 . Subtract 2, then multiply by 4: x 4 = 7 \frac{x}{4}=7 4 x = 7 , so x = 28 x=28 x = 28 .
Flashcard 65: Solve the exponential equation 2 x = 8 2^x=8 2 x = 8 . Answer: x = 3 x=3 x = 3 . Since 8 = 2 3 8=2^3 8 = 2 3 , we need x = 3 x=3 x = 3 .
Flashcard 66: What is the exponent form of a simple exponential function in one variable x x x ? Answer: y = a ⋅ b x y=a\cdot b^x y = a ⋅ b x . Initial value a a a with base b b b raised to power x x x .
Flashcard 67: Solve by factoring: x 2 + 5 x = 0 x^2+5x=0 x 2 + 5 x = 0 . Answer: x = 0 x=0 x = 0 or x = − 5 x=-5 x = − 5 . Factor out x x x : x ( x + 5 ) = 0 x(x+5)=0 x ( x + 5 ) = 0 .
Flashcard 68: What is the standard form of a linear equation in x x x and y y y ? Answer: A x + B y = C Ax+By=C A x + B y = C . General linear form with integer coefficients A A A , B B B , C C C .