Algebra Flashcards: Combine Different Function Types
Study Combine Different Function Types in Algebra with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
Algebra
Combine Different Function Types
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QUESTION
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Find h(x) if f(x)=x and g(x)=x and h(x)=f(x)g(x).
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ANSWER
h(x)=xx. Multiply the expressions: x⋅x=xx.
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This deck focuses on Combine Different Function Types, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra.
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Flashcard 1: Find h(x) if f(x)=x and g(x)=x and h(x)=f(x)g(x).
Answer: h(x)=xx. Multiply the expressions: x⋅x=xx.
Flashcard 2: Simplify (f+g)(x) if f(x)=3x and g(x)=2⋅3x.
Answer: (f+g)(x)=3⋅3x. Factor out 3x: 3x+2⋅3x=3⋅3x.
Flashcard 3: What is the vertical scaling of f(x) when forming cf(x)?
Answer: Multiply all outputs by c. Each output value is multiplied by the constant c.
Flashcard 4: Identify the exponential part in h(x)=4+2x.
Answer: 2x. The exponential function has the form a⋅bx.
Flashcard 5: What is (f+g)(2) if f(2)=7 and g(2)=−3?
Answer: 4. Add the function values: 7+(−3)=4.
Flashcard 6: Find (gf)(x) if f(x)=x+1 and g(x)=x−2.
Answer: (gf)(x)=x−2x+1. Form the quotient of the two expressions.
Flashcard 7: What is the domain of (f+g)(x) in terms of the domains of f and g?
Answer: Dom(f+g)=Dom(f)∩Dom(g). Domain is the intersection of both individual domains.
Flashcard 8: What is the domain of h(x)=xx?
Answer: x≥0. Square root function requires x≥0.
Flashcard 9: If T(t)=A+Be−kt with k>0, what is limt→∞T(t)?
Answer: A. The exponential term approaches zero as t approaches infinity.
Flashcard 10: What is the result of adding a constant c to a function f(x)?
Answer: f(x)+c. Adding a constant shifts the function vertically by c units.
Flashcard 11: What function type is T(t)=A+Be−kt when k>0?
Answer: Constant plus decaying exponential. Models cooling behavior approaching a constant temperature A.
Flashcard 12: What is (f−g)(−1) if f(−1)=5 and g(−1)=12?
Answer: −7. Subtract the function values: 5−12=−7.
Flashcard 13: Find h(x) if f(x)=x2−1 and g(x)=3 and h(x)=f(x)+g(x).
Answer: h(x)=x2+2. Add the expressions: (x2−1)+3=x2+2.
Flashcard 14: What is (gf)(4) if f(4)=10 and g(4)=−5?
Answer: −2. Divide the function values: −510=−2.
Flashcard 15: Find h(x) if f(x)=x and g(x)=x and h(x)=f(x)g(x).
Answer: h(x)=xx. Multiply the expressions: x⋅x=xx.
Flashcard 16: What is the definition of (f−g)(x) in terms of f(x) and g(x)?
Answer: (f−g)(x)=f(x)−g(x). Subtract the second function's output from the first at each input.
Flashcard 17: For f(x)=abx, which condition on b gives exponential growth?
Answer: b>1. Base greater than 1 creates increasing exponential behavior.
Flashcard 18: Simplify (fg)(x) if f(x)=2x and g(x)=3x.
Answer: (fg)(x)=6x. Use property (ab)x=axbx: 2x⋅3x=(2⋅3)x=6x.
Flashcard 19: In T(t)=A+Be−kt for cooling, what does the constant A represent?
Answer: Ambient (surrounding) temperature. The final temperature the object approaches as time goes to infinity.
Flashcard 20: What is h(0) for h(x)=4+2x?
Answer: 5. Substitute x=0: 4+20=4+1=5.
Flashcard 21: Find the domain of h(x)=x2−92x.
Answer: All real x except x=−3 and x=3. Denominator x2−9=(x−3)(x+3) cannot equal zero.
Flashcard 22: What is the key restriction added to the domain when forming (gf)(x)?
Answer: Exclude inputs where g(x)=0. Division by zero is undefined, so these points are excluded.
Flashcard 23: For f(x)=abx, which condition on b gives exponential growth?
Answer: b>1. Base greater than 1 creates increasing exponential behavior.
Flashcard 24: What is the domain of h(x)=x−2x+1?
Answer: All real x except x=2. Denominator cannot be zero, so exclude x=2.
Flashcard 25: Build T(t) if ambient is 20 and initial is 80 with decay factor 0.8 per hour.
Answer: T(t)=20+60(0.8)t. Initial difference is 80−20=60, so T(t)=20+60(0.8)t.
Flashcard 26: Find (f−g)(x) if f(x)=x2+4 and g(x)=3x.
Answer: (f−g)(x)=x2−3x+4. Subtract the expressions: (x2+4)−3x=x2−3x+4.