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Algebra 2 Flashcards: Solving Linear Quadratic Systems

Study Solving Linear Quadratic Systems in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Solving Linear Quadratic Systems, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Solving Linear Quadratic Systems

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QUESTION

What are the intersection points of y=2xy=2xy=2x and y=x2y=x^2y=x2?

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ANSWER

(0,0)(0,0)(0,0) and (2,4)(2,4)(2,4). Substitute y=2xy = 2xy=2x into y=x2y = x^2y=x2.

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Flashcard 1: What are the intersection points of y=2xy=2xy=2x and y=x2y=x^2y=x2?

Answer: (0,0)(0,0)(0,0) and (2,4)(2,4)(2,4). Substitute y=2xy = 2xy=2x into y=x2y = x^2y=x2.

Flashcard 2: What method solves a linear–quadratic system by combining equations to eliminate a variable?

Answer: Elimination (after rewriting equations as needed). Combine equations to cancel out one variable.

Flashcard 3: What is the standard form of a horizontal parabola opening left or right?

Answer: x=ay2+by+cx=ay^2+by+cx=ay2+by+c. Standard parabola form with horizontal axis of symmetry.

Flashcard 4: What are the intersection points of y=x−2y=x-2y=x−2 and y=x2−4y=x^2-4y=x2−4?

Answer: (−1,−3)(-1,-3)(−1,−3) and (2,0)(2,0)(2,0). Set x−2=x2−4x - 2 = x^2 - 4x−2=x2−4 and solve.

Flashcard 5: What is the standard form of a vertical parabola opening up or down?

Answer: y=ax2+bx+cy=ax^2+bx+cy=ax2+bx+c. Standard parabola form with vertical axis of symmetry.

Flashcard 6: What does b2−4ac=0b^2-4ac=0b2−4ac=0 mean for the number of intersection points?

Answer: There is 111 real intersection point (tangent). Zero discriminant means one repeated intersection.

Flashcard 7: What does b2−4ac>0b^2-4ac>0b2−4ac>0 mean for the number of intersection points?

Answer: There are 222 real intersection points. Positive discriminant means two distinct intersections.

Flashcard 8: What does the discriminant tell you about real intersections after substitution?

Answer: Sign of b2−4acb^2-4acb2−4ac gives 000, 111, or 222 real solutions. Discriminant determines intersection count possibilities.

Flashcard 9: What must every solution to a linear–quadratic system be written as?

Answer: An ordered pair (x,y)(x,y)(x,y). Solutions are coordinate points (x,y)(x,y)(x,y).

Flashcard 10: What must you do after finding xxx-values from a substituted quadratic equation?

Answer: Substitute into the line to find corresponding yyy-values. Back-substitute xxx-values to complete solution pairs.

Flashcard 11: What is the key algebraic step after substituting a linear equation into a quadratic equation?

Answer: Solve the resulting quadratic in one variable. Use quadratic formula or factoring methods.

Flashcard 12: What is the standard form of a circle centered at (h,k)(h,k)(h,k) with radius rrr?

Answer: (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2(x−h)2+(y−k)2=r2. Circle equation with center and radius parameters.

Flashcard 13: What is the standard form of a horizontal parabola opening left or right?

Answer: x=ay2+by+cx=ay^2+by+cx=ay2+by+c. Standard parabola form with horizontal axis of symmetry.

Flashcard 14: What is the substituted equation after using y=7−2xy=7-2xy=7−2x in y=x2y=x^2y=x2?

Answer: x2=7−2xx^2=7-2xx2=7−2x. Set the two expressions for yyy equal.

Flashcard 15: What should you do first to solve 2x+y=72x+y=72x+y=7 with y=x2y=x^2y=x2 by substitution?

Answer: Rewrite the line as y=7−2xy=7-2xy=7−2x. Solve for yyy to enable substitution method.

Flashcard 16: What method solves a linear–quadratic system by replacing a variable using the linear equation?

Answer: Substitution. Replace one variable using the linear equation.

Flashcard 17: What method solves a linear–quadratic system by combining equations to eliminate a variable?

Answer: Elimination (after rewriting equations as needed). Combine equations to cancel out one variable.

Flashcard 18: What does it mean if a line and a parabola intersect at two points?

Answer: The system has 222 real solutions. Two intersection points means two solution pairs.

Flashcard 19: What does it mean if a line is tangent to a circle in a linear–quadratic system?

Answer: The system has exactly 111 real solution. Tangency creates one point of contact.

Flashcard 20: What does it mean if a line does not intersect a circle on the coordinate plane?

Answer: The system has 000 real solutions. No intersection means no real solution pairs.

Flashcard 21: What is the general form of a linear equation in two variables?

Answer: Ax+By=CAx+By=CAx+By=C. Standard form for any line equation.

Flashcard 22: What is the slope-intercept form of a line used for substitution?

Answer: y=mx+by=mx+by=mx+b. Isolates yyy for easy substitution into quadratics.

Flashcard 23: Identify the correct solution set type if a line intersects a parabola at exactly one point.

Answer: One real solution (the line is tangent to the parabola). Discriminant equals zero for tangent intersections.

Flashcard 24: What are the intersection points of y=−2y=-2y=−2 and x2+y2=5x^2+y^2=5x2+y2=5?

Answer: (1,−2)(1,-2)(1,−2) and (−1,−2)(-1,-2)(−1,−2). Set y=−2y = -2y=−2 in x2+y2=5x^2 + y^2 = 5x2+y2=5.

Flashcard 25: What are the intersection points of y=2y=2y=2 and x2+y2=5x^2+y^2=5x2+y2=5?

Answer: (1,2)(1,2)(1,2) and (−1,2)(-1,2)(−1,2). Set y=2y = 2y=2 in x2+y2=5x^2 + y^2 = 5x2+y2=5.

Flashcard 26: What are the intersection points of y=−1y=-1y=−1 and x2+y2=5x^2+y^2=5x2+y2=5?

Answer: (2,−1)(2,-1)(2,−1) and (−2,−1)(-2,-1)(−2,−1). Set y=−1y = -1y=−1 in x2+y2=5x^2 + y^2 = 5x2+y2=5.

Flashcard 27: What are the intersection points of y=1y=1y=1 and x2+y2=5x^2+y^2=5x2+y2=5?

Answer: (2,1)(2,1)(2,1) and (−2,1)(-2,1)(−2,1). Set y=1y = 1y=1 in x2+y2=5x^2 + y^2 = 5x2+y2=5.

Flashcard 28: What is the standard form of a vertical parabola opening up or down?

Answer: y=ax2+bx+cy=ax^2+bx+cy=ax2+bx+c. Standard parabola form with vertical axis of symmetry.

Flashcard 29: What are the intersection points of y=−xy=-xy=−x and x2+y2=8x^2+y^2=8x2+y2=8?

Answer: (2,−2)(2,-2)(2,−2) and (−2,2)(-2,2)(−2,2). Substitute y=−xy = -xy=−x into circle equation.

Flashcard 30: What are the intersection points of y=xy=xy=x and x2+y2=8x^2+y^2=8x2+y2=8?

Answer: (2,2)(2,2)(2,2) and (−2,−2)(-2,-2)(−2,−2). Substitute y=xy = xy=x into circle equation.