~22 min
Section 8 of 8
Default • ALGEBRA-1

Decode Expressions: Terms, Factors & Coefficients

Difficulty 2/5
Summary
  • Core idea (what matters most): An expression is built from terms (pieces separated by ++ or −-), and each term is built from factors (things multiplied). A coefficient is the number factor attached to a variable factor. Example: in −3x2y-3x^2y, the coefficient is −3-3, and the factors are −3-3, x2 x^2, and y y.

  • How to apply it (method): First, circle the plus/minus signs that separate terms (like splitting 3x2+5x−73x^2 + 5x - 7 into three terms). Then, inside each term, break multiplication into factors (including parentheses): in 5(x−2)y5(x-2)y, the factors are 55, (x−2)(x-2), and y y. To find the coefficient, look for the numeric multiplier of the variable part (remember: x x means 1x1x, and −x-x means −1x-1x).

  • Common pitfalls to avoid: Don't treat subtraction as multiplication—x−2 x-2 is one term (two terms inside, but the whole parenthesis is a single factor when multiplied). Don't miss hidden 1s and negative signs: −(x+3)-(x+3) has coefficient −1-1 on the factor (x+3)(x+3). Exponents don't create new terms: 3x23x^2 is still one term.

  • Quick test-day strategy (fast + accurate): Use the "Split, then Factor" rule: (1) split into terms by ++ / −-, (2) factor each term by multiplication, (3) name the coefficient as the number factor. If the question asks for "a factor," parentheses like (x−2)(x-2) absolutely count.

Quick check — Before you answer, verify…

  • Did I split terms only at top-level ++ / −- (not inside parentheses)?
  • Did I include all factors (numbers, variables, parentheses) for the chosen term?
  • Did I handle signs and hidden coefficients (11, −1-1) correctly?
  • Am I mixing up "term" (add/subtract) with "factor" (multiply)?

As with combining like terms, structure comes first: identify the pieces correctly, then do the math. With a quick split-and-factor scan, you can nail these problems confidently.

Section 8 of 8

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