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  1. Subjects ›
  2. ACT ›
  3. Question of the Day

ACT Question of the Day

ACT Question of the Day

Answer today's ACT question, reveal the full explanation, then keep the streak going with a new question every day.

What is f(0)f(0)f(0) for the piecewise function f(x)={2x+4if x<1x2−6if x≥1f(x) = \begin{cases} 2x + 4 & \text{if } x < 1 \\ x^2 - 6 & \text{if } x \geq 1 \end{cases}f(x)={2x+4x2−6​if x<1if x≥1​?

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Question of the Day

What is f(0)f(0)f(0) for the piecewise function f(x)={2x+4if x<1x2−6if x≥1f(x) = \begin{cases} 2x + 4 & \text{if } x < 1 \\ x^2 - 6 & \text{if } x \geq 1 \end{cases}f(x)={2x+4x2−6​if x<1if x≥1​?

  1. 4 (correct answer)
  2. 2
  3. 6
  4. 0

Explanation: For x = 0, we check the intervals: Is 0 < 1? Yes. So we use the first piece: f(x)=2x+4f(x) = 2x + 4f(x)=2x+4. Substituting x = 0: f(0)=2(0)+4=0+4=4f(0) = 2(0) + 4 = 0 + 4 = 4f(0)=2(0)+4=0+4=4. Choice B would result from using the second piece incorrectly.