ACT Math › How to add exponents
Solve for :
First, reduce all values to a common base using properties of exponents.
Plugging back into the equation-
Using the formula
We can reduce our equation to
So,
What is 23 + 22 ?
12
20
32
64
Using the rules of exponents, 23 + 22 = 8 + 4 = 12
Simplify: y3x4(yx3 + y2x2 + y15 + x22)
y4x7 + y5x6 + y18x4 + y3x26
y3x12 + y6x8 + y45x4 + y3x88
y3x12 + y6x8 + y45 + x88
2x4y4 + 7y15 + 7x22
y3x12 + y12x8 + y24x4 + y3x23
When you multiply exponents, you add the common bases:
y4 x7 + y5x6 + y18x4 + y3x26
Simplify the following expression:
When multiplying bases that have exponents, simply add the exponents. Note that you can only add the exponents if the bases are the same. Thus:
If , what is the value of
?
Since the base is 5 for each term, we can say 2 + n =12. Solve the equation for n by subtracting 2 from both sides to get n = 10.
If , what is the value of
?
Rewrite the term on the left as a product. Remember that negative exponents shift their position in a fraction (denominator to numerator).
The term on the right can be rewritten, as 27 is equal to 3 to the third power.
Exponent rules dictate that multiplying terms allows us to add their exponents, while one term raised to another allows us to multiply exponents.
We now know that the exponents must be equal, and can solve for .
Solve for where:
1
2
3
9
5
The only value of x where the two equations equal each other is 1. All you have to do is substitute the answer choices in for x.
Which expression is equivalent to the following?
None of these
The rule for adding exponents is . We can thus see that
and
are no more compatible for addition than
and
are.
You could combine the first two terms into , but note that PEMDAS prevents us from equating this to
(the exponent must solve before the distribution).
Express as a power of 2:
The expression cannot be rephrased as a power of 2.
Since the problem requires us to finish in a power of 2, it's easiest to begin by reducing all terms to powers of 2. Fortunately, we do not need to use logarithms to do so here.
Thus,
Simplify: hn + h–2n
h–2n = 1/h2n
hn + h–2n = hn + 1/h2n