Given the function , what is the value of ?
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ACT Math Help: Function Definitions And Notation
Review real example questions for Function Definitions And Notation in ACT Math.
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Question 1
Given the function f(x)=x2−3x+4, what is the value of f(−2)?
- 2
- 6
- 10
- 14 (correct answer)
Explanation: The correct answer is D (14). Substitute x = −2 into the function: f(−2) = (−2)² − 3(−2) + 4 = 4 + 6 + 4 = 14. The three key steps are: (1) square the input: (−2)² = +4, not −4; (2) multiply: −3(−2) = +6, not −6; (3) add: 4 + 6 + 4 = 14. A (2) comes from treating −3(−2) as −6: 4 − 6 + 4 = 2. B (6) comes from treating (−2)² as −4: −4 + 6 + 4 = 6. C (10) comes from a partial sign error. Pro tip: when substituting a negative value, write every step explicitly — sign errors on squared terms and products are the most common mistakes in function evaluation.
Question 2
Given f(x)=2x2+3, which statement is true about f(x+1)?
- f(x+1)=2x2+2x+5
- f(x+1)=2x2+2x+3
- f(x+1)=2x2+4x+5 (correct answer)
- f(x+1)=2x2+4x+3
Explanation: This tests function notation with a shifted input, where f(x+1) means substitute the entire quantity x+1 everywhere x appears in f(x)=2x2+3. That substitution gives 2(x+1)2+3, and expanding the square first yields 2(x2+2x+1)+3; distributing the 2 across all three terms gives 2x2+4x+2+3, which simplifies to 2x2+4x+5. The version 2x2+4x+3 comes from distributing the 2 to x2 and 2x but forgetting that 2⋅1=2 must be added to the 3, and 2x2+2x+3 compounds that by also failing to double the middle term. The result 2x2+2x+5 shows the same undistributed middle term with the constant handled correctly, which is a partial-distribution error. When a function's input is an expression, wrap it in parentheses before you simplify, expand the power completely, and only then multiply through by the outside coefficient.
Question 3
A sequence is defined by a1=3 and an=2an−1−1 for n≥2. What is a5?
- 17
- 23
- 33 (correct answer)
- 65
Explanation: This is a recursive sequences question testing careful step-by-step application of a rule. Choice C (33) is correct — apply the rule aₙ = 2aₙ₋₁ − 1 repeatedly: a₁ = 3, a₂ = 2(3) − 1 = 5, a₃ = 2(5) − 1 = 9, a₄ = 2(9) − 1 = 17, a₅ = 2(17) − 1 = 33. Choice A (17) stops at a₄ — off by one term, likely from miscounting or starting the index at n = 0. Choice B (23) results from an arithmetic error at one step — perhaps computing a₃ = 2(5) + 1 = 11 (adding instead of subtracting): then a₄ = 2(11) − 1 = 21, a₅ = 2(21) − 1 = 41... or some other mid-sequence error. Choice D (65) comes from using aₙ = 2aₙ₋₁ + 1 throughout (adding instead of subtracting): a₂ = 7, a₃ = 15, a₄ = 31, a₅ = 63 ≈ 65. Pro tip: For recursive sequences, build a table of values term by term — there's no shortcut to jumping ahead. Write out each term explicitly: write the term number, then compute carefully. The −1 in this rule is easy to misread as +1, which produces very different values.
Question 4
A model rocket's height in feet after t seconds is modeled by h(t)=−16t2+96t. What is the height, in feet, 4 seconds after launch?
- 128 (correct answer)
- 256
- 384
- 512
Explanation: This is a function evaluation question testing substitution into a quadratic height model. Choice A (128) is correct — substitute t = 4: h(4) = −16(4²) + 96(4) = −16(16) + 384 = −256 + 384 = 128 feet. Choice B (256) comes from computing only the negative term: 16 × 16 = 256, or from adding the terms incorrectly: −256 + 384 treated as 256. Choice C (384) comes from evaluating only the positive term 96 × 4 = 384 and ignoring the −16t² term entirely. Choice D (512) likely comes from computing 96 × 4 + 16 × 4² but adding instead of subtracting: 384 + 256 = 640... or from −16(4) + 96(4) = −64 + 384 = 320, then some addition error. Pro tip: Evaluate each term of a polynomial function separately, then combine. The negative sign on the −16t² term is critical — squaring 4 first gives 16, then multiplying by −16 gives −256 (negative, not positive). The rocket is decelerating, so height at t = 4 should be less than at its peak, not more.
Question 5
If f(x)=7−x, what is f(3)?
- 4 (correct answer)
- 10
- 5
- 1
Explanation: We need to find f(3) when f(x) = 7 - x. To evaluate f(3), we substitute x = 3 into the function: f(3) = 7 - 3. Following order of operations, we calculate 7 - 3 = 4. Therefore, f(3) = 4.
Question 6
If f(x)=x2−1, what is f(x)+1?
- x2 (correct answer)
- (x+1)2−1
- x2−2
- x2+1
Explanation: We need to find f(x) + 1 when f(x) = x² - 1. Since f(x) = x² - 1, we have f(x) + 1 = (x² - 1) + 1 = x² - 1 + 1 = x². The answer is x².
Question 7
What is f(−2) if f(x)=5x−2?
- -12 (correct answer)
- -8
- 12
- 8
Explanation: We need to find f(-2) when f(x) = 5x - 2. To evaluate f(-2), we substitute x = -2 into the function: f(-2) = 5(-2) - 2. Following order of operations, we calculate 5(-2) = -10, then -10 - 2 = -12. Therefore, f(-2) = -12.
Question 8
If f(x)=2x−6, what is the value of f(0)?
Substitute x=0: f(0)=20−6.
- 3
- −3 (correct answer)
- −6
- 0
Explanation: We need to find f(0) when f(x) = (x - 6)/2. Substituting x = 0 into the function: f(0) = (0 - 6)/2 = -6/2 = -3. The answer is -3. Be careful with the negative sign: 0 - 6 = -6, and -6 divided by 2 is -3.
Question 9
Given the functions f(x)=2x2+1 and g(x)=x−3, what is the value of f(g(4))?
- 3 (correct answer)
- 9
- 17
- 33
Explanation: The correct answer is A (3). Evaluate from the inside out: first compute g(4) = 4 − 3 = 1. Then substitute into f: f(1) = 2(1)² + 1 = 2 + 1 = 3. B (9) comes from skipping g and computing f(4) directly: f(4) = 2(16) + 1 = 33... or computing f with x=4 using the wrong formula. C (17) likely comes from computing g(4) = 1 correctly but then applying f incorrectly. D (33) comes from computing f(4) = 2(4²) + 1 = 33, skipping g entirely. For composite functions f(g(x)), always evaluate the inner function first, then substitute that result into the outer function.
Question 10
If f(x)=2x2−3x+4, what is f(0)?
- 0
- 1
- 4 (correct answer)
- 2
Explanation: We need to find f(0) when f(x) = 2x² - 3x + 4. To evaluate f(0), we substitute x = 0 everywhere it appears: f(0) = 2(0)² - 3(0) + 4 = 0 - 0 + 4 = 4. The answer is 4.