Construct and Interpret Two-Way Tables

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8th Grade Math › Construct and Interpret Two-Way Tables

Questions 1 - 10
1

A neighborhood survey asked 100 families what type of home they live in and whether they have a pet.

  • Apartment: 15 have pets, 35 do not
  • House: 40 have pets, 10 do not

Which statement best describes the association (if any) between housing type and pet ownership?

Yes, there appears to be an association: $15/50=30%$ of apartment families have pets, while $40/50=80%$ of house families have pets.

No association, because the total number of families in apartments equals the total number in houses (50 each).

Yes, housing type causes pet ownership because 80% is larger than 30%.

No association, because $15+40=55$ families have pets.

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Row relatives show conditionals like 15/50 = 30% of apartments have pets versus 40/50 = 80% of houses, the large difference suggesting association between housing and pets, while equal rates indicate independence. For 100 families (equal 50 each housing), choice B correctly states association by comparing row relatives (30% vs 80%) without causation. This fits the conditional analysis. Errors: no association from equal totals (A), irrelevant sums (C), causation claim (D). Association via comparing relatives across rows. Mistakes: overlooking conditionals or confusing with cause.

2

A school counselor surveyed 50 students about whether they have a curfew and whether they have regular chores at home. Results:

  • Curfew: Yes (30 students): 20 with chores, 10 without chores
  • Curfew: No (20 students): 5 with chores, 15 without chores

Based on row relative frequencies, do curfew and chores appear to be associated?

No. The number of students with chores is 25 and the number without chores is 25, so the variables are independent.

No. About the same percent have chores in each curfew group ($20/50$ and $5/50$).

Yes. Having a curfew causes students to have chores.

Yes. A higher percent of students with a curfew have chores ($20/30\approx 67%$) than students without a curfew ($5/20=25%$).

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Row relatives show conditionals like 20/30 ≈ 67% of curfew students have chores versus 5/20 = 25% without, with the difference (67% vs 25%) suggesting association between curfew and chores, as similar rates would indicate independence. In this 50-student example, comparing row relatives (67% vs 25%) shows a higher percentage with curfew have chores, indicating association without claiming causation, as in choice B. This is the correct interpretation based on conditional rates. Errors include ignoring conditionals by using grand totals (20/50 and 5/50 in A), misinterpreting balanced totals as independence (C), or claiming causation (D). For association: compare row relatives across rows (differing suggests related variables). Mistakes: not comparing conditionals or confusing association with causation (association shows correlation, not cause).

3

A class surveyed 60 students about whether they prefer fiction or nonfiction and whether they read at least 20 minutes per day.

  • Fiction: 18 read 20+ minutes, 12 do not
  • Nonfiction: 10 read 20+ minutes, 20 do not

How many students in the survey read at least 20 minutes per day?

18

28

30

60

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Tables organize variables like preference (fiction/nonfiction) and reading time (20+ yes/no), with cells e.g., 18 fiction and 20+, totals enabling relatives like 18/30 = 60% of fiction preferers read 20+ vs 10/30 ≈ 33% nonfiction, difference suggesting association, similarity independence. For 60 students (fiction: 18 yes, 12 no, total 30; nonfiction: 10 yes, 20 no, total 30), total reading 20+ is column sum 18+10 = 28, as in B. This correctly adds the relevant cells. Errors: single cell (18 in A), wrong sum (30 in C), grand total (60 in D). Construction: fill cells, sum columns for totals like reading yes. Mistakes: adding incorrect cells or confusing variables.

4

A neighborhood survey asked 100 families what type of home they live in and whether they have a pet.

  • Apartment: 15 have pets, 35 do not
  • House: 40 have pets, 10 do not

What is the row relative frequency of having a pet for families who live in a house?

$\frac{50}{40}=125%$

$\frac{40}{50}=80%$

$\frac{40}{55}\approx 73%$

$\frac{40}{100}=40%$

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Row relatives are conditional, like for houses (50 total), 40/50 = 80% have pets versus 15/50 = 30% for apartments, differences suggesting association, similarity meaning independence. In this 100-family survey (house: 40 pets, 10 no), the row relative for pets in houses is 40/50 = 80%, as in B, using row total. This correctly conditions on housing type. Errors: grand total (40/100 = 40% in A), column total (40/55 ≈ 73% in C), inverted (50/40 = 125% in D). Calculate by dividing cell by row total; compare for association. Mistakes: wrong denominator or miscalculation.

5

A school counselor surveyed 50 students about whether they have a curfew and whether they have regular chores at home. Results:

  • Curfew: Yes (30 students): 20 with chores, 10 without chores
  • Curfew: No (20 students): 5 with chores, 15 without chores

What is the row relative frequency of students who have chores among students who have a curfew?

$\frac{20}{50}=0.40=40%$

$\frac{20}{25}=0.80=80%$

$\frac{30}{50}=0.60=60%$

$\frac{20}{30}\approx 0.67\approx 67%$

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Relative frequencies include row relatives, which show conditional probabilities, such as among students with curfew (30 total), 20/30 ≈ 67% have chores, versus 5/20 = 25% for those without curfew, with differing rates suggesting an association between curfew and chores, while similar rates would indicate independence. In this example with 50 students, the row relative frequency for chores among curfew students is 20/30 ≈ 67%, as calculated in choice B, using the row total as the denominator for the conditional percentage. This is the correct interpretation, as it focuses on the proportion within the curfew-yes row. A common error is using the wrong denominator, like the grand total (20/50 = 40% in A) or column total (20/25 = 80% in C), which computes a different relative frequency. To calculate row relatives: divide the cell count by its row total (e.g., 20/30 for curfew yes and chores yes); for association, compare these across rows. Mistakes include confusing row with column relatives or arithmetic errors, such as misdividing (e.g., treating 30/50 = 60% as the row relative in D).

6

A student club surveyed 100 students about grade level and whether they participate in an after-school activity.

  • 6th grade: 25 participate, 15 do not
  • 8th grade: 30 participate, 10 do not

Which statement best describes the association (if any) between grade level and participating in an after-school activity?

There is no association because 6th grade has 40 students and 8th grade has 40 students.

There is no association because $25/100=25%$ and $30/100=30%$ are close.

There appears to be an association because $30/40=75%$ of 8th graders participate, compared with $25/40=62.5%$ of 6th graders.

There is an association because being in 8th grade causes students to join activities.

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Row relatives indicate conditionals, such as 30/40 = 75% of 8th graders participate versus 25/40 = 62.5% of 6th graders, with the 12.5% difference suggesting association between grade and participation, while equal rates imply independence. For this 100-student survey (totals: 6th 40, 8th 40), choice A correctly identifies association by comparing row relatives (75% vs 62.5%) without causation. This matches the data's conditional rates. Errors: claiming no association from equal group sizes (B), using grand totals (25/100, 30/100 in C), or causation (D). For association: compare relatives across rows (differences suggest relation). Mistakes: ignoring conditionals or equating association with cause.

7

A student club surveyed 100 students about grade level and whether they participate in an after-school activity.

  • 6th grade: 25 participate, 15 do not
  • 8th grade: 30 participate, 10 do not

What percentage of 8th graders participate in an after-school activity?

$\frac{40}{30}\approx 133%$

$\frac{30}{40}=75%$

$\frac{30}{55}\approx 55%$

$\frac{30}{100}=30%$

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Row relatives are conditional, like for 8th graders (40 total), $30/40 = 75%$ participate in activities versus $25/40 = 62.5%$ for 6th graders, with differences suggesting association, while similarity means independence. Here, with 100 students (6th: 25 participate, 15 not, total 40; 8th: 30 participate, 10 not, total 40), the row relative for 8th graders participating is $30/40 = 75%$, as in B. This uses the correct row total denominator for the conditional percentage. Common errors: using grand total ($30/100 = 30%$ in A), inverting fraction ($40/30 \approx 133%$ in C), or wrong row total ($30/55 \approx 55%$ in D, perhaps miscounting). To calculate: divide cell by row total ($30/40$); compare for association. Mistakes include wrong denominators or arithmetic slips.

8

A school counselor surveyed 50 students about whether they have a curfew and whether they have regular chores at home. Results:

  • Curfew: Yes (30 students): 20 with chores, 10 without chores
  • Curfew: No (20 students): 5 with chores, 15 without chores

What is the column relative frequency of students who have a curfew among students who have chores?

$\frac{20}{25}=0.80=80%$

$\frac{20}{30}\approx 0.67\approx 67%$

$\frac{25}{50}=0.50=50%$

$\frac{20}{50}=0.40=40%$

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Relative frequencies include column relatives, which are conditional, such as among students with chores (25 total), 20/25 = 80% have curfew versus 10/25 = 40% without chores, with differences suggesting association, while similarity implies independence. For this 50-student survey, the column relative frequency of curfew among chores students is 20/25 = 80%, as in choice C, using the column total as the denominator. This correctly answers the question by conditioning on the chores-yes column. Errors often involve wrong denominators, like row total (20/30 ≈ 67% in A) or grand total (20/50 = 40% in B). To compute column relatives: divide cell by column total (e.g., 20/25); compare across columns for association. Common mistakes: mixing row/column (e.g., 25/50 = 50% in D) or not recognizing conditional nature.

9

A school counselor surveyed 50 students about whether they have a curfew and whether they have regular chores at home. The results were:

  • 30 students have a curfew: 20 have chores and 10 do not.
  • 20 students do not have a curfew: 5 have chores and 15 do not.

Which two-way table correctly shows the frequencies (counts) and totals?

Rows = Chores (Yes/No), Columns = Curfew (Yes/No)

Curfew: YesCurfew: NoTotal
Chores: Yes20525
Chores: No101525
Total302050

Rows = Curfew (Yes/No), Columns = Chores (Yes/No)

Chores: YesChores: NoTotal
Curfew: Yes201020
Curfew: No51530
Total252550

Rows = Curfew (Yes/No), Columns = Chores (Yes/No)

Chores: YesChores: NoTotal
Curfew: Yes201030
Curfew: No15520
Total351550

Rows = Curfew (Yes/No), Columns = Chores (Yes/No)

Chores: YesChores: NoTotal
Curfew: Yes201030
Curfew: No51520
Total252550

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. A two-way table organizes data with rows for one variable (e.g., curfew: yes/no) and columns for the other (e.g., chores: yes/no), where cells show joint frequencies like 20 students with curfew and chores. Relative frequencies include row relatives, which are conditional probabilities, such as 20/30 ≈ 67% of students with curfew having chores compared to 5/20 = 25% without curfew, indicating an association if rates differ substantially, while similar rates suggest independence. For this survey of 50 students, the table should have rows for curfew (yes: 20 chores yes, 10 no, total 30; no: 5 yes, 15 no, total 20) and columns for chores, with totals 25 yes, 25 no, and grand total 50, matching choice D. Common errors include switching row and column variables (as in A), miscalculating totals (as in B), swapping cell values (as in C), or incorrect cell counts. To construct the table: (1) identify variables (curfew yes/no, chores yes/no), (2) fill cells with given counts (e.g., curfew yes and chores yes: 20), (3) add row and column totals (e.g., curfew yes total: 30), (4) verify grand total (50). Mistakes often involve confusing row/column assignments or arithmetic errors in totals, but here D correctly represents the data without such issues.

10

A neighborhood survey asked 100 families what type of home they live in (Apartment or House) and whether they have a pet (Yes/No).

  • Apartment: 15 have pets, 35 do not (50 total)
  • House: 40 have pets, 10 do not (50 total)

Which conclusion is best supported by the data?

Pet ownership appears associated with housing type because $\frac{15}{50}=30%$ of apartment families have pets, but $\frac{40}{50}=80%$ of house families have pets.

There is no association because the number of apartment families (50) equals the number of house families (50).

There is no association because $15+40=55$ families have pets, which is more than half.

Housing type causes families to get pets.

Explanation

This question tests constructing two-way tables for categorical data, calculating row/column relative frequencies (percentages), and identifying associations by comparing conditional rates. Two-way table: rows for one variable (housing: apartment/house), columns for other (pet: yes/no), cells show counts (15: apartment yes). Relative frequencies: row relatives show conditional—of apartment families, 15/50=30% have pets vs 40/50=80% of house families. Different rates (30% vs 80%) suggest association: housing type relates to pet ownership (houses more likely). Similar rates suggest independence. The correct conclusion is association due to differing rates, as in choice B, without claiming causation. A common error is claiming causation like in choice C, or misinterpreting equal row totals as no association in choice A.

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